I need to add some random html content with text before and after my input field.
I know I can use description decorator and set escape option to false - this way I can simply inject arbitrary html chunk as a decorator.
But this only accounts for 1 html chunk - I need a second one after input field. If I simply output description decorator again after input field - that will output the same description chucnk.
1) Is there a way to use description decorator multiple times with different content?
2) In label decorator - is there a way to use span tag instead of label tag?
3) Can I inject random html into HtmlTag decorator?
thanks!
update:
i solved my problem by creating simple custom decorator that allows me inject random html anywhere. Still -if someone knows quick and easy answers - plz post.
You could check out the AnyMarkup decorator:
http://www.zfsnippets.com/snippets/view/id/62/anymarkup-decorator
Related
I'd like to strip special Wicket tags (e.g. wicket:panel, wicket:child, etc.) from the output in development mode, but keep the wicket:id attribute.
In the WebApplications init one can set getMarkupSettings().setStripWicketTags(true); thus removing the special tags and attributes.
Is it possible to extend / modify Wicket at some point to keep the attribute when stripSpecialTags is set to true?
This is not possible at the moment.
Please file a ticket for improvement at https://issues.apache.org/jira/browse/WICKET!
Thank you!
Why do you want to keep the wicket:id attribute? For testing/selenium? Then you can use the DebugSettings::setComponentPathAttributeName method to output the wicket component path, which is usable in selenium.
I can't disable escaping in a Zend_Form_Element_Submit, so when the label has special characters it won't display it's value..
This is my actual Zend Form piece of code:
$this->submit = new Zend_Form_Element_Submit('submit');
$this->submit->setLabel('Iniciar Sesión');
$this->submit->setIgnore(true);
$this->addElement($this->submit);
I've tried $this->submit->getDecorator('Label')->setOption('escape', false); but I obtain an "non-object" error (maybe submit isn't using the "Label" Decorator)..
I've also tried as suggested $this->submit->setAttrib('escape', false); but no text will be shown either.. Any idea? Thanks
Should be as simple as doing this:
$element->addDecorator('Label', аrray('escape'=>false));
Or see setEscape(). http://framework.zend.com/manual/1.12/en/zend.form.standardDecorators.html
Regarding failure to retrieve named decorator... Try getDecorators() Do you see 'label' in the results?
There is no Label decorator for submit form element by default (this is why you get the error).
The $this->submit->setLabel('Iniciar Sesión'); value goes to Zend_View_Helper_FormSubmit, which always does escaping and uses the label as a value.
The helper used by the Submit element escapes by default. Unlike with the label decorator, submit labels are included in a HTML attribute so they need to be escaped.
Your label - Iniciar Sesión - is a perfectly valid UTF-8 string, so the escaped version of it will be the same. If your label is not appearing then something else is going wrong. I'd guess that your page is being served using a charset that doesn't match what Zend View is using (UTF-8 by default).
View the page source to see what actually gets output - that might give you some more clues. Alternatively if the page this form is on is public, if you can provide a URL we might be able to spot the issue.
I ran into a similar issue. In my instance, I added both a label and a description to a text field element. This line of code allowed me to turn off the html escaping for the description attached to that field element:
$form->getElement('txtUPC')->getDecorator('description')->setOption('escape', false);
In my testing, the setEscape() was not recognized by the form elements or their decorators.
I'm using sfDoctrineAllowPlugin. I need form which has Twitter's Bootstrap semantics. I looked into template and I found, that there is only $form, which is a <table>. How can I format it in my way? I don't want to use table, rows and cols.
There are plenty of render* functions available to display each item in your form.
renderRow
renderLabel
render
renderError
etc ...
But you can also define a decorator (a custom sfWidgetFormSchemaFormatter) for your form to define the way each item will be display. Check this example of adding * for each required field.
I have a need to create a <br/> tag in the display label for a menu item generated using Zend_navigation, but don't seem to be able to find a way to do so.
My navigation item is defined in the XML config as:
<registermachine>
<label>Register your Slitter Rewinder</label>
<controller>service</controller>
<action>register</action>
<route>default</route>
</registermachine>
I want to force a tag in the output HTML between 'your' and 'slitter', such that it appears on two line as below:
Register your
Slitter Rewinder
However, I can't seem to do it. obviously using in the XML breaks parsing, and using html entities means that the lable is displayed as:
Register your <br/>Slitter Rewinder
Has anyone had experience of this that can offer advice?
Thanks in advance!
there is no such option built-in you have to use a partial
$partial = array('menu.phtml', 'default');
$this->navigation()->menu()->setPartial($partial);
echo $this->navigation()->menu()->render();
http://framework.zend.com/manual/en/zend.view.helpers.html#zend.view.helpers.initial.navigation.menu
you may also try a hack with <label><![CDATA[Menu label<br/>Second line]]></label>
I found a (hacky) solution:
I updated my navigation.xml to use {br} tokens wherever a <br/> tag is required, and then amended the base Zend/View/Helper/Navigation/Menu.php file as follows:
within htmlify function, changed
$this->view->escape($label)
to
str_replace("{br}", "<br/>", $label)
I could (and probably will) override the Zend Library Menu View Helper with my own at some point, but this at least cover it for now.
there is a escapeLabels boolean used to convert html tags and it's true by default.
You can set your navigation like this
$this->navigation()
->menu()
->escapeLabels(false)
->...
http://framework.zend.com/apidoc/2.0/classes/Zend.View.Helper.Navigation.Menu.html#escapeLabels
I am extremely new to Zend Framework, In registration form, i need label text in two line. For Example:- In the case First name, I need to display like below:
First
Name:
How can i implement this? Please anyone help me!!!
By default, input fields labels are being escaped by Zend_View_Helper_FormLabel. However, you can easy switch this off:
$yourTextInputElement->getDecorator('label')->setOption('escape', false);
This way you can use labels as e.g. $yourTextInputElement->setLabel('First <br/> name');.
What about this nifty solution ?
http://jsfiddle.net/J67GD/
The best way is probably to use Description decorator, or subclass one of other standard ZF decorators.
Yanick's CSS solution might be a good choice too, depending what are you trying to do.