I have a need to create a <br/> tag in the display label for a menu item generated using Zend_navigation, but don't seem to be able to find a way to do so.
My navigation item is defined in the XML config as:
<registermachine>
<label>Register your Slitter Rewinder</label>
<controller>service</controller>
<action>register</action>
<route>default</route>
</registermachine>
I want to force a tag in the output HTML between 'your' and 'slitter', such that it appears on two line as below:
Register your
Slitter Rewinder
However, I can't seem to do it. obviously using in the XML breaks parsing, and using html entities means that the lable is displayed as:
Register your <br/>Slitter Rewinder
Has anyone had experience of this that can offer advice?
Thanks in advance!
there is no such option built-in you have to use a partial
$partial = array('menu.phtml', 'default');
$this->navigation()->menu()->setPartial($partial);
echo $this->navigation()->menu()->render();
http://framework.zend.com/manual/en/zend.view.helpers.html#zend.view.helpers.initial.navigation.menu
you may also try a hack with <label><![CDATA[Menu label<br/>Second line]]></label>
I found a (hacky) solution:
I updated my navigation.xml to use {br} tokens wherever a <br/> tag is required, and then amended the base Zend/View/Helper/Navigation/Menu.php file as follows:
within htmlify function, changed
$this->view->escape($label)
to
str_replace("{br}", "<br/>", $label)
I could (and probably will) override the Zend Library Menu View Helper with my own at some point, but this at least cover it for now.
there is a escapeLabels boolean used to convert html tags and it's true by default.
You can set your navigation like this
$this->navigation()
->menu()
->escapeLabels(false)
->...
http://framework.zend.com/apidoc/2.0/classes/Zend.View.Helper.Navigation.Menu.html#escapeLabels
Related
I built a form called: "clientlist":
I put a macro with where condition on click:
="IDclient_logindata=" & [Maschere]![clientlist]![IDclient]
this means that when I click on an id client, access will open another form with the respective IDclient. For example if I click on IDclient 3:
it open another form called "client_logindata" filter to IDclient_logindata 3.
Then, I built a navigational form:
using clientlist as subform. But when I click a record, any record, it open every time the client_logindata form with IDclient_logindata form = 1, why it doesn' works in a subform?
Design View of "Navigation Form":
Solved in this way: ="IDclient_logindata=" & [IDclient]
When using a subform, references to controls need to be relative to the main form where the subform is treated as a child control.
Consider adjusting the conditional to the following structure. Do note this is the English version:
="IDclient_logindata=" & Forms!myMainForm!mySubform.Form!mySubformControl
Or specifically tailored to yours (be sure to get exact spelling of all objects):
="IDclient_logindata=" & Forms!NavigationForm!clientlist.Form!IDclient
The OP has found a working solution which is much simpler than what follows. However, I was still interested to see if we could get something on the original model to work, and I'd guess that for users attempting to achieve the same thing using VBA rather than embedded macro's the following may still be useful.
The issue with the code in the original question is that the relevant form isn't open at the 'top level' but as a subform.
Form "normal" subforms, you'd refer to the control on the subform like this:
Forms!navform!clientlist.form!IDclient
Where navform is the name of the outer form. Or in the generalised case, like this:
Forms!Mainform!Subform1.Form!ControlName
However, the "Navigation Form" Wizard, when dragging subforms onto the Add New tab in Layout view doesn't name the subforms nicely. So I had to code it this way:
Forms![Navigation Form]!NavigationSubform.Form!ControlName
To my surprise this code continued to work when I added further forms within the Navigation Forms tabs and had controls named the same as one in question. I guess NavigationSubform automatically points to the tab with the current focus.
How can I change the positions of checkbox and label and how to implement a link into the label?
$acceptGTC = new Element\Checkbox('AGBs');
$acceptGTC->setLabel('I Accept the GTC (show it).');
$this->add($acceptGTC);
regards
n00n
meanwhile:
I tried to overwrite the view helper for checkboxes.
copied
*/vendor/zendframework/zend-form/src/View/Helper/FormCheckbox.php
to
*/module/Application/src/Application/View/Helper/FormCheckbox.php
added to module.config.php
'viewhelpers' => array('checkbox'=>'Application\View\Helper'),
But it still uses the original one...
Do I have to tell zend to use my FormCheckbox?
I don't exactly know the way you are rendering your Zend_Form_Element, but in order to enhance the rendering as you want you should build a custom decorator, and add it to this element.
You should read the Zend documentation on Zend_Form_Decorators, everything is quite well explained and should lead you to a fancy solution.
im trying to create customizable menu in umbraco. i.e. user should be able to add /remove / edit any menu item in menu. (User will not be a developer)
but i dont know how to do that..i've heard about Macros but dont know much about them so cant use it.
I think this has been done before also..
Thanks in advance
Generally, your menu will reflect your node structure within umbraco. This is the easiest way to allow your clients control of the site's navigation. If there are nodes that you would rather not have in the menu, that you could use the umbracoNaviHide property on the document type.
Try out some of the starter kits that are available. They will come with macros that build the navigation based on your nodes and will give you a good idea of how they work. You can even start by using a starterkit and then just modify it as you like. That's what I would recommend as you start out with umbraco. Umbraco has about 4 or so built in starterkits and Our Umbraco has several more that other users have contributed.
To use the default navigation template provided with Umbraco:
If you log into the Umbraco backoffice and head over to the Developer section, should should see Scripting Files. Right-click Scripting Files and choose Create. Choose a filename, like Nav and and from the "Choose a template" menu, select Site Map, then click Create. You should end up with the following razor code:
#*
SITEMAP
=================================
This snippet generates a complete sitemap of all pages that are published and visible (it'll filter out any
pages with a property named "umbracoNaviHide" that's set to 'true'). It's also a great example on how to make
helper methods in Razor and how to pass values to your '.Where' filters.
How to Customize for re-use (only applies to Macros, not if you insert this snippet directly in a template):
- If you add a Macro Parameter with the alias of "MaxLevelForSitemap" which specifies how deep in the hierarchy to traverse
How it works:
- The first line (var maxLevelForSitemap) assigns default values if none is specified via Macro Parameters
- Next is a helper method 'traverse' which uses recursion to keep making new lists for each level in the sitemap
- Inside the the 'traverse' method there's an example of using a 'Dictionary' to pass the 'maxLevelForSitemap' to
the .Where filter
- Finally the 'traverse' method is called taking the very top node of the website by calling AncesterOrSelf()
NOTE: It is safe to remove this comment (anything between # * * #), the code that generates the list is only the below!
*#
#inherits umbraco.MacroEngines.DynamicNodeContext
#helper traverse(dynamic node){
var maxLevelForSitemap = String.IsNullOrEmpty(Parameter.MaxLevelForSitemap) ? 4 : int.Parse(Parameter.MaxLevelForSitemap);
var values = new Dictionary<string,object>();
values.Add("maxLevelForSitemap", maxLevelForSitemap) ;
var items = node.Children.Where("Visible").Where("Level <= maxLevelForSitemap", values);
if (items.Count() > 0) {
<ul>
#foreach (var item in items) {
<li>
#item.Name
#traverse(item)
</li>
}
</ul>
}
}
<div class="sitemap">
#traverse(#Model.AncestorOrSelf())
</div>
This will produce a ul/li menu of the structure of your site. You plug this into your template by inserting the macro.
Take a look at the default Top Navigation template for XSLT or Razor. That should give you an idea of where to start and how navigation generally works in Umbraco. I second Douglas' answer that the Navigation usually mirrors the content structure in the Content section.
If you really want a setup where you add items to the nav independent of the Content tree structure, then use a Multinode Tree Picker on your Home Page and have that be the navigation in your Top Nav macro.
I have my Zend_Form, and sometimes, one of the fields should be hidden, and not seen by the user. Is there a way when I call the form in my controller, I could change one of the fields to be hidden?
Thanks
Kousha
You can remove the element using:
$form->removeElement('my-element-name');
in the controller.
You could also create two forms, one overriding the other, in which the child calls $this->remove('my-element-name').
Or, you could make the form constructor accept a boolean $flag that determines whether to add the field to the form.
So, as you can see, lots of different ways to structure it.
To change that field to one of type "hidden" (i.e. <input type="hidden">) is a different thing, but I'm not sure that's what you mean/need/want.
The best solution I have for this is to add a specific class to the element when it needs to be hidden. It may not be the perfect solution, but let me explain.
First, its very difficult to switch from one element type to another in Zend Form. Your elements are actually classes. So the text is Zend_Form_Element_Text - so its not just as easy as changing the 'type' attribute.
If the element must remain on the form (so, not removing it like the answer above suggests), your only other option would be hiding it with CSS.
Try the following code when it needs to be hidden:
$element = $form->getElement('MyElement');
$newClass = trim($element->getAttrib('class') . ' hidden');
$element->setAttrib('class', $newClass);
Then, of course, create CSS for the .hidden class.
Hope this helps!
I am extremely new to Zend Framework, In registration form, i need label text in two line. For Example:- In the case First name, I need to display like below:
First
Name:
How can i implement this? Please anyone help me!!!
By default, input fields labels are being escaped by Zend_View_Helper_FormLabel. However, you can easy switch this off:
$yourTextInputElement->getDecorator('label')->setOption('escape', false);
This way you can use labels as e.g. $yourTextInputElement->setLabel('First <br/> name');.
What about this nifty solution ?
http://jsfiddle.net/J67GD/
The best way is probably to use Description decorator, or subclass one of other standard ZF decorators.
Yanick's CSS solution might be a good choice too, depending what are you trying to do.