NSString * str=[zoneDict objectForKey:#"name"];
NSLog(#"==========string zone::==========%#",str);
// str="(GMT +3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
How can I get the 3:00 value from the above string?
NSString *str = #"(GMT -3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
NSRange endRange = [str rangeOfString:#")"];
NSString *timeString = [str substringWithRange:NSMakeRange(5, endRange.location-5)];
NSRange separatorRange = [timeString rangeOfString:#":"];
NSInteger hourInt = [[timeString substringWithRange:NSMakeRange(0, separatorRange.location)] intValue];
NSLog(#"Hour:%d",hourInt);
Rather than trying to extract the time offset from the string, is there any way you could store actual time zone data in your zoneDict? For example you could store NSTimeZone instances instead.
If all you have is the string, you could use an NSRegularExpression object and extract the relevant information using a regular expression instead.
If you could explain further what you're trying to do then there may be an alternative way to achieve what you want.
I like to use -[NSString componentsSeparatedByString]:
NSString *str = #"(GMT -3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
NSArray *myWords = [myString componentsSeparatedByString:#")"];
NSString *temp1 = [myWords objectAtIndex:0];
if ([temp1 rangeOfString:#"-"].location == NSNotFound) {
NSArray *temp2 = [temp1 componentsSeparatedByString:#"+"];
NSString *temp3 = [temp2 objectAtIndex:1];
NSLog(#"Your String - %#", temp3);
}
else {
NSArray *temp2 = [temp1 componentsSeparatedByString:#"-"];
NSString *temp3 = [temp2 objectAtIndex:1];
NSLog(#"Your String - %#", temp3);
}
Output:
Your String - 3:00
Using regular expressions is the better option in my view (if you are forced to extract the '3' only). The regular expression string would contain something like "\d?" but don't quote me on that, you'll have to look up the exact string. Perhaps someone on here could provide the exact string.
Related
I have a string which gives the Date (below)
NSString*str1=[objDict objectForKey:#"date"];
NSLog(#" str values2%#",str1); --> 04-Jan-13
Now Problem is I need to Trim the"-13" from here .I know about NSDateFormatter to format date.but I can't do that here.I need to trim that
For that I am using:-
NSCharacterSet *charc=[NSCharacterSet characterSetWithCharactersInString:#"-13"];
[str1 stringByTrimmingCharactersInSet:charc];
But this does not work.this does not trim...how to do that..help
Not sure why not use an NSDateFormatter but here's a very specific way to approach this (very bad coding practice in my opinion):
NSString *theDate = str1;
NSArray *components = [theDate componentsSeparatedByString:#"-"];
NSString *trimmedDate = [NSString stringWithFormat:#"%#-%#",[components objectAtIndex:0],[components objectAtIndex:1]];
But this does not work.this does not trim...
It does trim, but since NSString is immutable, the trimmed string is thrown away, because you do not assign it to anything.
This would work (but do not do it like that!)
str1 = [str1 stringByTrimmingCharactersInSet:charc];
What you do is not trimming, it's taking a substring. NSString provides a much better method for that:
str1 = [str1 substringToIndex:6]; // Take the initial 6 characters
Something like this:
NSString *trimmed = [textStr stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
or this:
NSString *trimmed = [textStr stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"-13"];
what you have done is correct. Only thing is stringByTrimmingCharactersInSet returns NSString. So you need to assign this value to NSString, like
str1 = [str1 stringByTrimmingCharactersInSet:charc];
if you're sure you have your string always formatted like "NN-CCC-NN" you can just trim the first 6 chars:
NSString* stringToTrim = #"04-Jan-13";
NSString* trimmedString = [stringToTrim substringToIndex:6];
NSLog(#"trimmedString: %#", trimmedString); // -> trimmedString: 04-Jan
I have a string like: "mocktail, wine, beer"
How can I convert this into: "mocktail", "wine", "beer"?
the following gives you the desired result:
NSString *_inputString = #"\"mocktail, wine, beer\"";
NSLog(#"input string : %#", _inputString);
NSLog(#"output string : %#", [_inputString stringByReplacingOccurrencesOfString:#", " withString:#"\", \""]);
the result is:
input string : "mocktail, wine, beer"
output string : "mocktail", "wine", "beer"
You need to use:
NSArray * components = [myString componentsSeparatedByString: #", "];
NSString *string = #"mocktail, wine, beer";
//remove whitespaces
NSString *trimmedString = [string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
//get array of string
NSArray *array = [trimmedString componentsSeparatedByString:#","];
NSMutableArray *newArray = [[NSMutableArray alloc] init];
for (NSString *trimmedString in array) {
NSString *newString = [NSMutableString stringWithFormat:#"'%#'", trimmedString];
[newArray addObject:newString];
}
//merge new strings
NSString *finalString = [NSString stringWithFormat:#"%#", [newArray objectAtIndex:0]];
for (NSInteger i = 1; i < [newArray count]; i++) {
finalString = [NSString stringWithFormat:#"%#, %#", finalString, [newArray objectAtIndex:i]];
}
Without knowing spesifically about iOS or objective-c, I assume you could use a split function.
In almost any higher level programming language there is such a function.
Try:
Objective-C split
This gets you an array of Strings. You can then practically do with those what you want to do, e.g. surrounding them with single quotes and appending them back together. :D
I have NSString like this #"0,0,0,0,0,0,1,2012-03-08,2012-03-17". I want values separated by comma. I want values before comma and neglect comma.
I am new in iPhone, I know how to do in Java but not getting how to do in Objective-C.
NSString *string = #"0,0,0,0,0,0,1,2012-03-08,2012-03-17";
NSArray *componentArray = [string componentSeperatedByString:#","];
Use the componentsSeparatedByString: method of NSString.
NSString *str = #"0,0,0,0,0,0,1,2012-03-08,2012-03-17";
NSArray *components = [str componentsSeparatedByString:#","];
for (NSString *comp in components)
{
NSLog(#"%#", comp);
}
for (NSString *s in [yourstring componentsSeparatedByString:#","])
{
int thisval = [s intValue];
}
All,
I have a dictionary with two keys and values. I need to extract bits and pieces from them and place them into seperate strings.
{
IP = "192.168.17.1";
desc = "VUWI-VUWI-ABC_Dry_Cleaning-R12-01";
}
That is what the dictionary looks like when I call description.
I want the new output to be like this:
NSString *IP = #"192.168.17.1";
NSString *desc = #"ABC Dry Cleaning"; //note: I need to get rid of the underscores
NSString *type = #"R";
NSString *num = #"12";
NSString *ident = #"01";
How would I achieve this?
I've read through the Apple developer docs on NSRegularExpression but I find it hard to understand. I'm sure once I get some help once here I can figure it out in the future, I just need to get started.
Thanks in advance.
Okay, so first, you have to get the object associated with each key:
NSString *ip = [dic objectForKey:#"IP"]; //Btw, you shouldn't start a variable's name with a capital letter.
NSString *tempDesc = [dic objectForKey:#"desc"];
Then, what I would do is split the string in tempDesc, based on the character -.
NSArray *tmpArray = [tempDesc componentsSeparatedByString:#"-"];
Then you just have to get the strings or substrings you're interested in, and reformat them as needed:
NSString *desc = [[tmpArray objectAtIndex:2] stringByReplacingOccurrencesOfString:#"_" withString:#" "];
NSString *type = [[tmpArray objectAtIndex:3] substringToIndex:1];
NSString *num = [[tmpArray objectAtIndex:3] substringFromIndex:1];
NSString *ident = [tmpArray objectAtIndex:4];
As you can see, this works perfectly without using NSRegularExpression.
Hi all i want extract the last part from string which is a four digit number '03276' i:e http://www.abc.com/news/read/welcome-new-gig/03276
how can i do that.
You can also use
NSString *sub = [#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent];
If you know how many characters you need, you can do something like this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [string substringFromIndex:[string length] - 5];
If you just know that it's the part after the last slash, you can do this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [[string componentsSeparatedByString:#"/"] lastObject];
Since *nix uses the same path separators as URL's this will be valid as well.
[#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent]
If you know the length of the number, and it's not gonna change, it can be as easy as:
NSString *result = [string substringFromIndex:[string length] - 4];
If the last part of the string is always the same length (5 characters) you could use this method to extract the last part:
- (NSString *)substringFromIndex:(NSUInteger)anIndex
Use the length of the string to determine the start index.
Something like this:
NSString *inputStr = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *newStr = [inputStr substringFromIndex:[inputStr length]-5];
NSLog(#"These are the last five characters of the string: %#", newStr);
(Code not tested)
NSString *str = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSArray *arr = [str componentSeparatedBy:#"gig/"];
NSString *strSubStringDigNum = [arr objectAtIndex:1];
strSubStringDigNum will have the value 03276
Try this:
NSString *myUrl = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *number = [[myUrl componentsSeparatedByString:#"/"] objectAtIndex: 5];