I have a string which gives the Date (below)
NSString*str1=[objDict objectForKey:#"date"];
NSLog(#" str values2%#",str1); --> 04-Jan-13
Now Problem is I need to Trim the"-13" from here .I know about NSDateFormatter to format date.but I can't do that here.I need to trim that
For that I am using:-
NSCharacterSet *charc=[NSCharacterSet characterSetWithCharactersInString:#"-13"];
[str1 stringByTrimmingCharactersInSet:charc];
But this does not work.this does not trim...how to do that..help
Not sure why not use an NSDateFormatter but here's a very specific way to approach this (very bad coding practice in my opinion):
NSString *theDate = str1;
NSArray *components = [theDate componentsSeparatedByString:#"-"];
NSString *trimmedDate = [NSString stringWithFormat:#"%#-%#",[components objectAtIndex:0],[components objectAtIndex:1]];
But this does not work.this does not trim...
It does trim, but since NSString is immutable, the trimmed string is thrown away, because you do not assign it to anything.
This would work (but do not do it like that!)
str1 = [str1 stringByTrimmingCharactersInSet:charc];
What you do is not trimming, it's taking a substring. NSString provides a much better method for that:
str1 = [str1 substringToIndex:6]; // Take the initial 6 characters
Something like this:
NSString *trimmed = [textStr stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
or this:
NSString *trimmed = [textStr stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"-13"];
what you have done is correct. Only thing is stringByTrimmingCharactersInSet returns NSString. So you need to assign this value to NSString, like
str1 = [str1 stringByTrimmingCharactersInSet:charc];
if you're sure you have your string always formatted like "NN-CCC-NN" you can just trim the first 6 chars:
NSString* stringToTrim = #"04-Jan-13";
NSString* trimmedString = [stringToTrim substringToIndex:6];
NSLog(#"trimmedString: %#", trimmedString); // -> trimmedString: 04-Jan
Related
I want to replace a single character at a particular position in a string.
Example
String: 123-456-7890
Desired Output: 123-406-7890 (Replacing 5 at fifth position with 0)
https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/
visit here and read all about string
Use stringByReplacingCharactersInRange:withString:, forming the NSRange variable to indicate the 5th position.
NSString *phoneNumber = #"123-456-7890";
NSString *newString = [phoneNumber stringByReplacingCharactersInRange:NSMakeRange(5, 1) withString:#"0"];
NSLog(#"%#", newString);
Output: 123-406-7890
Read all about NSString.
for replacing string there are lots of way:
NSString *str = [yourString stringByReplacingOccuranceOfString:#"5" withString:#"0"];
second way first get range of string like:
NSRange range = [yourSting rangeOfString:#"5"];
NSString *first = [yourString substringToIndex:range.location];
NSString *second = [yourString substringFromIndex:range.location+range.length];
NSString *yourNewStr = [NSString stringWithFormat:#"%#0%#",first,second];
Tere are lots of other using string operation but First one is best in that.
Get the range (i.e. index) of first occurrence of the substring.
Then replace at that range with your desired replace value.
NSString *originalString = #"123 456 789";
NSRange r = [originalString rangeOfString:#"5"];
NSString *newString = [originalString stringByReplacingCharactersInRange:r withString:#"0"];
If you want to actually replace the 5th character rather than just any 5 you need to make a range first.
NSRange range = NSMakeRange(5, 1);
NSString *newString = [initialString stringByReplacingCharactersInRange:range withString:#"0"];
Edit: Corrected make range length
you can use :-
NSString *replacechar = #"0";
NSString *newString= [String stringByReplacingCharactersInRange:NSMakeRange(5,1) withString:replacechar];
NSString *col1 = [aBook.name stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#" \n\t"]];
NSLog(#"column1: %#", col1); //output:- ABC+Company
This is my xml data output.
It comes with '+' mark. How can i decode this?
Could you please help me?
You mean get the parts that are seperated by the '+' sign? You can do that with:
NSArray *stringArray = [col1 componentsSeparatedByString:#"+"];
[stringArray objectAtIndex:0]; //ABC
[stringArray objectAtIndex:1]; //Company
If you want to remove/replace the '+' sign you can do this:
NSString* string = [col1 stringByReplacingOccurrencesOfString:#"+" withString:#""]; //last string can be empty or have a string value
Hope this helped you!
You can also replace the plus signs with spaces, if that’s what you’re after:
NSString *name = [col1 stringByReplacingOccurrencesOfString:#"+" withString:#" "];
NSString * str=[zoneDict objectForKey:#"name"];
NSLog(#"==========string zone::==========%#",str);
// str="(GMT +3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
How can I get the 3:00 value from the above string?
NSString *str = #"(GMT -3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
NSRange endRange = [str rangeOfString:#")"];
NSString *timeString = [str substringWithRange:NSMakeRange(5, endRange.location-5)];
NSRange separatorRange = [timeString rangeOfString:#":"];
NSInteger hourInt = [[timeString substringWithRange:NSMakeRange(0, separatorRange.location)] intValue];
NSLog(#"Hour:%d",hourInt);
Rather than trying to extract the time offset from the string, is there any way you could store actual time zone data in your zoneDict? For example you could store NSTimeZone instances instead.
If all you have is the string, you could use an NSRegularExpression object and extract the relevant information using a regular expression instead.
If you could explain further what you're trying to do then there may be an alternative way to achieve what you want.
I like to use -[NSString componentsSeparatedByString]:
NSString *str = #"(GMT -3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
NSArray *myWords = [myString componentsSeparatedByString:#")"];
NSString *temp1 = [myWords objectAtIndex:0];
if ([temp1 rangeOfString:#"-"].location == NSNotFound) {
NSArray *temp2 = [temp1 componentsSeparatedByString:#"+"];
NSString *temp3 = [temp2 objectAtIndex:1];
NSLog(#"Your String - %#", temp3);
}
else {
NSArray *temp2 = [temp1 componentsSeparatedByString:#"-"];
NSString *temp3 = [temp2 objectAtIndex:1];
NSLog(#"Your String - %#", temp3);
}
Output:
Your String - 3:00
Using regular expressions is the better option in my view (if you are forced to extract the '3' only). The regular expression string would contain something like "\d?" but don't quote me on that, you'll have to look up the exact string. Perhaps someone on here could provide the exact string.
Consider this code:
NSString *aString = #"\tThis is a sample string";
NSString *trimmedString = [aString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSLog(#"The trimmed string: %#",trimmedString);
trimmedString = [aString stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"string"]];
NSLog(#"The trimmed string: %#",trimmedString);
Here if I use characterSetWithCharactersInString: on the same NSString object trimmedString, my previous whitespace trimming effect gets removed..
My question is,
Is there any possibility to use more than one NSCharacterSet object to the same NSString???
or Suggest me some other way to do this please, but the NSString object should be one and the same..
The problem is not because of character sets. Its because you are using aString while trimming the string second time. You should use trimmedString instead. Your code should look like,
trimmedString = [trimmedString stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"string"]];
What about this:
NSString *aString = #"\tThis is a sample string";
NSMutableCharacterSet *customSet = [[NSMutableCharacterSet alloc] init];
[customSet formUnionWithCharacterSet:[NSCharacterSet whitespaceCharacterSet]];
[customSet addCharactersInString:#"string"];
NSString *trimmedString = [aString stringByTrimmingCharactersInSet:customSet];
[customSet release];
Hi all i want extract the last part from string which is a four digit number '03276' i:e http://www.abc.com/news/read/welcome-new-gig/03276
how can i do that.
You can also use
NSString *sub = [#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent];
If you know how many characters you need, you can do something like this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [string substringFromIndex:[string length] - 5];
If you just know that it's the part after the last slash, you can do this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [[string componentsSeparatedByString:#"/"] lastObject];
Since *nix uses the same path separators as URL's this will be valid as well.
[#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent]
If you know the length of the number, and it's not gonna change, it can be as easy as:
NSString *result = [string substringFromIndex:[string length] - 4];
If the last part of the string is always the same length (5 characters) you could use this method to extract the last part:
- (NSString *)substringFromIndex:(NSUInteger)anIndex
Use the length of the string to determine the start index.
Something like this:
NSString *inputStr = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *newStr = [inputStr substringFromIndex:[inputStr length]-5];
NSLog(#"These are the last five characters of the string: %#", newStr);
(Code not tested)
NSString *str = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSArray *arr = [str componentSeparatedBy:#"gig/"];
NSString *strSubStringDigNum = [arr objectAtIndex:1];
strSubStringDigNum will have the value 03276
Try this:
NSString *myUrl = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *number = [[myUrl componentsSeparatedByString:#"/"] objectAtIndex: 5];