I want to replace a single character at a particular position in a string.
Example
String: 123-456-7890
Desired Output: 123-406-7890 (Replacing 5 at fifth position with 0)
https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/
visit here and read all about string
Use stringByReplacingCharactersInRange:withString:, forming the NSRange variable to indicate the 5th position.
NSString *phoneNumber = #"123-456-7890";
NSString *newString = [phoneNumber stringByReplacingCharactersInRange:NSMakeRange(5, 1) withString:#"0"];
NSLog(#"%#", newString);
Output: 123-406-7890
Read all about NSString.
for replacing string there are lots of way:
NSString *str = [yourString stringByReplacingOccuranceOfString:#"5" withString:#"0"];
second way first get range of string like:
NSRange range = [yourSting rangeOfString:#"5"];
NSString *first = [yourString substringToIndex:range.location];
NSString *second = [yourString substringFromIndex:range.location+range.length];
NSString *yourNewStr = [NSString stringWithFormat:#"%#0%#",first,second];
Tere are lots of other using string operation but First one is best in that.
Get the range (i.e. index) of first occurrence of the substring.
Then replace at that range with your desired replace value.
NSString *originalString = #"123 456 789";
NSRange r = [originalString rangeOfString:#"5"];
NSString *newString = [originalString stringByReplacingCharactersInRange:r withString:#"0"];
If you want to actually replace the 5th character rather than just any 5 you need to make a range first.
NSRange range = NSMakeRange(5, 1);
NSString *newString = [initialString stringByReplacingCharactersInRange:range withString:#"0"];
Edit: Corrected make range length
you can use :-
NSString *replacechar = #"0";
NSString *newString= [String stringByReplacingCharactersInRange:NSMakeRange(5,1) withString:replacechar];
Related
I need to extract string upto certain word
I have time like this :"2012-12-29T00:00:00" how can I extract the part upto TO.That is I dont need time.This string is not static .I mean it changes like "2013-01-21T00:00:00"
use like below
NSString *stingTime = #"2012-12-29T00:00:00";
if([stingTime rangeOfString:#"T"].location != NSNotFound)
stingTime = [stingTime substringToIndex:[stingTime rangeOfString:#"T"].location];
//output
2012-12-29
This should like this...
NSString *string = #"2012-12-29T00:00:00";
NSRange range = [string rangeOfString:#"T0"];
if (range.location != NSNotFound){
NSString *newString = [string substringToIndex:range.location];
NSLog(#"NewString = %#",newString);
}
You can use functions of NSString For e.g.:
NSString *string = #"2012-12-29T00:00:00";
NSString *newString = [string substringToIndex:10];
Your newString will contain 2012-12-29.
Hope this helps.
I have a string which gives the Date (below)
NSString*str1=[objDict objectForKey:#"date"];
NSLog(#" str values2%#",str1); --> 04-Jan-13
Now Problem is I need to Trim the"-13" from here .I know about NSDateFormatter to format date.but I can't do that here.I need to trim that
For that I am using:-
NSCharacterSet *charc=[NSCharacterSet characterSetWithCharactersInString:#"-13"];
[str1 stringByTrimmingCharactersInSet:charc];
But this does not work.this does not trim...how to do that..help
Not sure why not use an NSDateFormatter but here's a very specific way to approach this (very bad coding practice in my opinion):
NSString *theDate = str1;
NSArray *components = [theDate componentsSeparatedByString:#"-"];
NSString *trimmedDate = [NSString stringWithFormat:#"%#-%#",[components objectAtIndex:0],[components objectAtIndex:1]];
But this does not work.this does not trim...
It does trim, but since NSString is immutable, the trimmed string is thrown away, because you do not assign it to anything.
This would work (but do not do it like that!)
str1 = [str1 stringByTrimmingCharactersInSet:charc];
What you do is not trimming, it's taking a substring. NSString provides a much better method for that:
str1 = [str1 substringToIndex:6]; // Take the initial 6 characters
Something like this:
NSString *trimmed = [textStr stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
or this:
NSString *trimmed = [textStr stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"-13"];
what you have done is correct. Only thing is stringByTrimmingCharactersInSet returns NSString. So you need to assign this value to NSString, like
str1 = [str1 stringByTrimmingCharactersInSet:charc];
if you're sure you have your string always formatted like "NN-CCC-NN" you can just trim the first 6 chars:
NSString* stringToTrim = #"04-Jan-13";
NSString* trimmedString = [stringToTrim substringToIndex:6];
NSLog(#"trimmedString: %#", trimmedString); // -> trimmedString: 04-Jan
I have the following NSMutableString:
#"1*2*3*4*5"
I want to find the first * and remove everything after it, so my string = #"1"; How do I do this?
NSMutableString *string = [NSMutableString stringWithString:#"1*2*3*4*5"];
NSRange range = [string rangeOfString:#"*"];
if (range.location != NSNotFound)
{
[string deleteCharactersInRange:NSMakeRange(range.location, [string length] - range.location)];
}
You could try to divide this string by a separator and get the first object
NSString *result = [[MyString componentsSeparatedByString:#"*"]objectAtIndex:0];
After calling componentsSeparatedByString:#"*" you'll get the array of strings, separated by *,and the first object is right what you need.
Here's yet another strategy, using the very flexible NSScanner.
NSString* beginning;
NSScanner* scanner = [NSScanner scannerWithString:#"1*2*3*4*5"];
[scanner scanUpToString:#"*" intoString:&beginning];
You could use -rangeOfString: to find the index of the first asterisk and use that with -substringToIndex: to extract a substring from the original input. Something like this perhaps...
NSMutableString *input = #"1*2*3*4*5";
// Finds the range of the first instance. See NSString docs for more options.
NSRange firstAsteriskRange = [input rangeOfString:#"*"];
NSString *trimmedString = [input substringToIndex:firstAsteriskRange.location + 1];
Hi friends i want to display credit card number in table view cell,so i want to display only last four characters like XXXXXXXXXX1111 first charecters is replaced with x or some other character how can i do this can any one help me
i have tried like bellow
NSString *CardNumber = [CardNumberValues objectAtIndex:indexPath.row];
NSRange subStringRange = NSMakeRange(0,[CardNumber length]-4);
NSMutableCharacterSet *NumSet = [NSMutableCharacterSet characterSetWithRange:subStringRange];
CardNumber = [[CardNumber componentsSeparatedByCharactersInSet:NumSet] componentsJoinedByString:#"X"];
cell.CardNumber.text = CardNumber;
but its not working can u suggest any reference or code...
Use this
NSString *CardNumber = #"12345678901234";
NSString *str_padding=#"";
NSRange subStringRange = NSMakeRange(0,[CardNumber length]-4);
str_padding =[str_padding stringByPaddingToLength:subStringRange.length withString:#"X" startingAtIndex:0];
CardNumber = [CardNumber stringByReplacingOccurrencesOfString:[NSString stringWithFormat:#"%#",[CardNumber substringToIndex:subStringRange.length]] withString:str_padding];
NSLog(#"%#",CardNumber);
NSString *cardNumber = [NSString stringWithFormat: #"XXXX-XXXX-XXXX-%#", [[CardNumberValues objectAtIndex:indexPath.row] subStringWithIndex:12]];
cell.CardNumber.text = cardNumber;
I am assuming that card numbers are 16 digits.
Hi all i want extract the last part from string which is a four digit number '03276' i:e http://www.abc.com/news/read/welcome-new-gig/03276
how can i do that.
You can also use
NSString *sub = [#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent];
If you know how many characters you need, you can do something like this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [string substringFromIndex:[string length] - 5];
If you just know that it's the part after the last slash, you can do this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [[string componentsSeparatedByString:#"/"] lastObject];
Since *nix uses the same path separators as URL's this will be valid as well.
[#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent]
If you know the length of the number, and it's not gonna change, it can be as easy as:
NSString *result = [string substringFromIndex:[string length] - 4];
If the last part of the string is always the same length (5 characters) you could use this method to extract the last part:
- (NSString *)substringFromIndex:(NSUInteger)anIndex
Use the length of the string to determine the start index.
Something like this:
NSString *inputStr = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *newStr = [inputStr substringFromIndex:[inputStr length]-5];
NSLog(#"These are the last five characters of the string: %#", newStr);
(Code not tested)
NSString *str = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSArray *arr = [str componentSeparatedBy:#"gig/"];
NSString *strSubStringDigNum = [arr objectAtIndex:1];
strSubStringDigNum will have the value 03276
Try this:
NSString *myUrl = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *number = [[myUrl componentsSeparatedByString:#"/"] objectAtIndex: 5];