I have the following NSMutableString:
#"1*2*3*4*5"
I want to find the first * and remove everything after it, so my string = #"1"; How do I do this?
NSMutableString *string = [NSMutableString stringWithString:#"1*2*3*4*5"];
NSRange range = [string rangeOfString:#"*"];
if (range.location != NSNotFound)
{
[string deleteCharactersInRange:NSMakeRange(range.location, [string length] - range.location)];
}
You could try to divide this string by a separator and get the first object
NSString *result = [[MyString componentsSeparatedByString:#"*"]objectAtIndex:0];
After calling componentsSeparatedByString:#"*" you'll get the array of strings, separated by *,and the first object is right what you need.
Here's yet another strategy, using the very flexible NSScanner.
NSString* beginning;
NSScanner* scanner = [NSScanner scannerWithString:#"1*2*3*4*5"];
[scanner scanUpToString:#"*" intoString:&beginning];
You could use -rangeOfString: to find the index of the first asterisk and use that with -substringToIndex: to extract a substring from the original input. Something like this perhaps...
NSMutableString *input = #"1*2*3*4*5";
// Finds the range of the first instance. See NSString docs for more options.
NSRange firstAsteriskRange = [input rangeOfString:#"*"];
NSString *trimmedString = [input substringToIndex:firstAsteriskRange.location + 1];
Related
I need to extract string upto certain word
I have time like this :"2012-12-29T00:00:00" how can I extract the part upto TO.That is I dont need time.This string is not static .I mean it changes like "2013-01-21T00:00:00"
use like below
NSString *stingTime = #"2012-12-29T00:00:00";
if([stingTime rangeOfString:#"T"].location != NSNotFound)
stingTime = [stingTime substringToIndex:[stingTime rangeOfString:#"T"].location];
//output
2012-12-29
This should like this...
NSString *string = #"2012-12-29T00:00:00";
NSRange range = [string rangeOfString:#"T0"];
if (range.location != NSNotFound){
NSString *newString = [string substringToIndex:range.location];
NSLog(#"NewString = %#",newString);
}
You can use functions of NSString For e.g.:
NSString *string = #"2012-12-29T00:00:00";
NSString *newString = [string substringToIndex:10];
Your newString will contain 2012-12-29.
Hope this helps.
I am trying to get the first sentence of a text view. I have the following code but am getting an out of bounds error. Thank You. Or are there any ways that aren't really complex.
-(IBAction)next:(id)sender
{
NSRange ran = [[tv.text substringFromIndex:lastLocation] rangeOfString:#". "];
if(ran.location != NSNotFound)
{
NSString * getRidOfFirstHalfString = [[tv.text substringFromIndex:lastLocation] substringToIndex:ran.location];
NSLog(#"%#",getRidOfFirstHalfString);
lastLocation+=getRidOfFirstHalfString.length;
}
How about:
NSString *finalString = [[tv.text componentsSeparatedByString:#"."] objectAtIndex:0] // Get the 1st part (left part) of the separated string
Go through the textview's text and divide the text into separate components where you find a period by calling componentsSeperatedByString on tv.text. You want the first sentence, which would be the 0th object in the array.
I know you've already accepted an answer to this question, but you might want to consider using the text view's tokenizer instead of just searching for the string ". " The tokenizer will automatically handle punctuation like !, ?, and closing quotes. You can use it like this:
id<UITextInputTokenizer> tokenizer = textView.tokenizer;
UITextRange *range = [tokenizer rangeEnclosingPosition:textView.beginningOfDocument
withGranularity:UITextGranularitySentence
inDirection:UITextStorageDirectionForward];
NSString *firstSentence = [textView textInRange:range];
If you want to enumerate all of the sentences, you can do it like this:
id<UITextInputTokenizer> tokenizer = textView.tokenizer;
UITextPosition *start = textView.beginningOfDocument;
while (![start isEqual:textView.endOfDocument]) {
UITextPosition *end = [tokenizer positionFromPosition:start toBoundary:UITextGranularitySentence inDirection:UITextStorageDirectionForward];
NSString *sentence = [textView textInRange:[textView textRangeFromPosition:start toPosition:end]];
NSLog(#"sentence=%#", sentence);
start = end;
}
Try checking that the substring was actually found.
NSRange ran = [tv.text rangeOfString:#". "];
if(ran.location != NSNotFound)
{
NSString * selectedString = [tv.text substringToIndex:ran.location];
NSLog(#"%#",selectedString);
}
You could alternatively try using NSScanner like this:
NSString *firstSentence = [[NSString alloc] init];
NSScanner *scanner = [NSScanner scannerWithString:tv.text];
NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:#"."];
[scanner scanUpToCharactersFromSet:set intoString:&firstSentence];
I'm not sure if you want this, but since you want the first sentence, you could append a period (you probably know how to do this, but it doesn't hurt to show it anyway):
firstSentence = [firstSentence stringByAppendingFormat:#"."];
Hope this helps!
PS: If it didn't work for you, maybe the text view doesn't actually contain any text.
I want to replace a single character at a particular position in a string.
Example
String: 123-456-7890
Desired Output: 123-406-7890 (Replacing 5 at fifth position with 0)
https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/
visit here and read all about string
Use stringByReplacingCharactersInRange:withString:, forming the NSRange variable to indicate the 5th position.
NSString *phoneNumber = #"123-456-7890";
NSString *newString = [phoneNumber stringByReplacingCharactersInRange:NSMakeRange(5, 1) withString:#"0"];
NSLog(#"%#", newString);
Output: 123-406-7890
Read all about NSString.
for replacing string there are lots of way:
NSString *str = [yourString stringByReplacingOccuranceOfString:#"5" withString:#"0"];
second way first get range of string like:
NSRange range = [yourSting rangeOfString:#"5"];
NSString *first = [yourString substringToIndex:range.location];
NSString *second = [yourString substringFromIndex:range.location+range.length];
NSString *yourNewStr = [NSString stringWithFormat:#"%#0%#",first,second];
Tere are lots of other using string operation but First one is best in that.
Get the range (i.e. index) of first occurrence of the substring.
Then replace at that range with your desired replace value.
NSString *originalString = #"123 456 789";
NSRange r = [originalString rangeOfString:#"5"];
NSString *newString = [originalString stringByReplacingCharactersInRange:r withString:#"0"];
If you want to actually replace the 5th character rather than just any 5 you need to make a range first.
NSRange range = NSMakeRange(5, 1);
NSString *newString = [initialString stringByReplacingCharactersInRange:range withString:#"0"];
Edit: Corrected make range length
you can use :-
NSString *replacechar = #"0";
NSString *newString= [String stringByReplacingCharactersInRange:NSMakeRange(5,1) withString:replacechar];
I have a string that contains words with consonants and vowels. How can I extract only consonants from the string?
NSString *str = #"consonants.";
Result must be:
cnsnnts
You could make a character set with all the vowels (#"aeiouy")
+ (id)characterSetWithCharactersInString:(NSString *)aString
then use the
- (NSString *)stringByTrimmingCharactersInSet:(NSCharacterSet *)set
method.
EDIT: This will only remove vowels at the beginning and end of the string as pointed out in the other post, what you could do instead is use
- (NSArray *)componentsSeparatedByCharactersInSet:(NSCharacterSet *)separator
then stick the components back together. You may also need to include capitalized versions of the vowels in the set, and if you want to also deal with accents (à á è è ê ì etc...) you'll probably have to include that also.
Unfortunately stringByTrimmingCharactersInSet wont work as it only trim leading and ending characters, but you could try using a regular expression and substitution like this:
[[NSRegularExpression
regularExpressionWithPattern:#"[^bcdefghjklmnpqrstvwx]"
options:NSRegularExpressionCaseInsensitive
error:NULL]
stringByReplacingMatchesInString:str
options:0
range:NSMakeRange(0, [str length])
withTemplate:#""]
You probably want to tune the regex and options for your needs.
Possible, for sure not-optimal, solution. I'm printing intermediate results for your learning. Take care of memory allocation (I didn't care). Hopefully someone will send you a better solution, but you can copy and paste this for the moment.
NSString *test = #"Try to get all consonants";
NSMutableString *found = [[NSMutableString alloc] init];
NSInteger loc = 0;
NSCharacterSet *consonants = [NSCharacterSet characterSetWithCharactersInString:#"bcdfghjklmnpqrstvwxyz"];
while(loc!=NSNotFound && loc<[test length]) {
NSRange r = [[test lowercaseString] rangeOfCharacterFromSet:consonants options:0 range:NSMakeRange(loc, [test length]-loc)];
if(r.location!=NSNotFound) {
NSString *temp = [test substringWithRange:r];
NSLog(#"Range: %# Temp: %#",NSStringFromRange(r), temp);
[found appendString:temp];
loc=r.location+r.length;
} else {
loc=NSNotFound;
}
}
NSLog(#"Found: %#",found);
Here is a NSString category that does the job:
- (NSString *)consonants
{
NSString *result = [NSString stringWithString:self];
NSCharacterSet *characterSet = [NSCharacterSet characterSetWithCharactersInString:#"aeiou"];
while(1)
{
NSRange range = [result rangeOfCharacterFromSet:characterSet options:NSCaseInsensitiveSearch];
if(range.location == NSNotFound)
break;
result = [result stringByReplacingCharactersInRange:range withString:#""];
}
return result;
}
Hi all i want extract the last part from string which is a four digit number '03276' i:e http://www.abc.com/news/read/welcome-new-gig/03276
how can i do that.
You can also use
NSString *sub = [#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent];
If you know how many characters you need, you can do something like this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [string substringFromIndex:[string length] - 5];
If you just know that it's the part after the last slash, you can do this:
NSString *string = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *subString = [[string componentsSeparatedByString:#"/"] lastObject];
Since *nix uses the same path separators as URL's this will be valid as well.
[#"http://www.abc.com/news/read/welcome-new-gig/03276" lastPathComponent]
If you know the length of the number, and it's not gonna change, it can be as easy as:
NSString *result = [string substringFromIndex:[string length] - 4];
If the last part of the string is always the same length (5 characters) you could use this method to extract the last part:
- (NSString *)substringFromIndex:(NSUInteger)anIndex
Use the length of the string to determine the start index.
Something like this:
NSString *inputStr = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *newStr = [inputStr substringFromIndex:[inputStr length]-5];
NSLog(#"These are the last five characters of the string: %#", newStr);
(Code not tested)
NSString *str = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSArray *arr = [str componentSeparatedBy:#"gig/"];
NSString *strSubStringDigNum = [arr objectAtIndex:1];
strSubStringDigNum will have the value 03276
Try this:
NSString *myUrl = #"http://www.abc.com/news/read/welcome-new-gig/03276";
NSString *number = [[myUrl componentsSeparatedByString:#"/"] objectAtIndex: 5];