Dose anyone know, how to retrieve kind of Google-talk user's id bellow of contact list?
xxxxx#public.talk.google.com
Talk between two users via hangouts (hangouts.google.com). This will "create" id#public.talk.google.com in roster's list of each user.
Then use Adium as Gtalk client, setup credentials for user which will be "sender" of your message.
Sign in via Adium and you will see in contact list id#public.talk.google.com of receiver.
Shortcut answer:
1) sender talks to receiver via hangouts
2) Use Adium for sender
3) read receiver id#public.talk.google.com in sender's contact list in Adium
Related
Well, how can I get all senders in user's mail using Google APIs? I need a list of emails (and other ex. information). They are not in user's contacts cause he need to add them before. So there can I find this list?
I need to get a full list of people which write messages to user's email.
In my app I've a button that allows users to send me an e-mail.
When users send me an e-mail I want to send to their a confirm e-mail.
But, from swift code, how can I get their email address in order to send to their the confirm mail?
Thank you
You will not be able to use Swift to grab a user's email address this way. This is intentional, to keep a user's information secure.
I would recommended either using an email service that will automatically respond to emails received, or allowing users to enter their email address elsewhere in the app.
I have a .NET console application that add a list of users in a selected Yammer group through [/group_memberships.json] endpoint and it works fine.
Anyway the customer wants to avoid the sending of a confirmation email to user that has been added. In fact, after my program runs, all users receive an email like "XXX has added you to the YYY group on Yammer. Go to group".
The only way that I found to avoid this email is disable email notification in user settings.
Is there another simple way? Through Rest API is possible tell to Yammer to do not send email or, otherwise, change the user settings? I'm asking it because there're some hidden Rest API not documented in the official Yammer site.
Thanks
Yammer doesn't have any API endpoint to achieve your objective. Your customer may consider adding a rule in exchange to block emails based on the "from" address and certain keywords in the "subject".
I have set up a basic install of XMPPHP and to test it I tried sending a message from one of my gtalk (GoogleTalk) accounts to another gTalk account. The receiving account did not show the message, or the normal "user * has sent you a message: accept/block"
I then sent my receiving account a chat message from within the Google interface, and it prompted me (as expected) to add my account to the list of approved chat people.
Once my sending account was on the "approved" list, i was able successfully to send messages with xmpphp with no problem.
My question: Using xmpphp, how do i send an INVITATION to chat? I can send messages fine once the recipient accepts my incoming chats, but the first message sent does not trigger the chat program to prompt me to accept the messages.
As a follow-up...is there a way to find out if the recipient has accepted the request? ANy way to know that the messages are being delivered (or not)?
I had the same problem and the solution is to send a "subscribe" request before the message.
So just call
$conn->subscribe('someguy#someserver.net');
before
$conn->message('someguy#someserver.net', 'This is a test message!');
In Google Talk, how to send a message to person that is not in my friend list?
I work on an application that notify customers of a bank about change of their accounts. When I send a message to a person not in my list, no error is created, but the message isn't delivered to the recipient.
Because of design issues it is not suitable to send an invitation to customers and store information about their responses to it.
You can message a user directly using XMPP without an active presence subscription (the requirement for an item to appear in your roster), but most clients (Google Talk clients included AFAIK) will discard the message upon reception, if the from header does not match a bare JID in their roster.