I have to tables : mutation and ann_commune. The colums code_postal and id_commune are in ann_commune, all the other ones in mutation.
I need to get together the average for the top 3 values of several departments
WITH six as (
SELECT commune as commune_six, AVG(valeur_fonciere) as moyenne_six
FROM mutation
LEFT JOIN ann_commune on mutation.id_commune = ann_commune.id_commune
WHERE code_postal LIKE '06%'
GROUP BY commune_six
ORDER BY moyenne_six DESC
LIMIT 3
),
treize as (
SELECT commune as commune_treize, AVG(valeur_fonciere) as moyenne_treize
FROM mutation
LEFT JOIN ann_commune on mutation.id_commune = ann_commune.id_commune
WHERE code_postal LIKE '13%'
GROUP BY commune_treize
ORDER BY moyenne_treize DESC
LIMIT 3
)
select AVG(moyenne_six)::NUMERIC(7,0) as Moyenne_top3_06,
AVG(moyenne_treize)::NUMERIC(7,0) as Moyenne_top3_13
from six, treize
I am sure there is a way to create a nicer quode, because I have to do the same with 10 averages. I did not find the solutions, but I am sure it exists.
Thank you in advance :).
I have a set of data like this
The Result should look Like this
My Query
SELECT max(pi.pi_serial) AS proforma_invoice_id,
max(mo.manufacturing_order_master_id) AS manufacturing_order_master_id,
max(pi.amount_in_local_currency) AS sales_value,
FROM proforma_invoice pi
JOIN schema_order_map som ON pi.pi_serial = som.pi_id
LEFT JOIN manufacturing_order_master mo ON som.mo_id = mo.manufacturing_order_master_id
WHERE to_date(pi.proforma_invoice_date, 'DD/MM/YYYY') BETWEEN to_date('01/03/2021', 'DD/MM/YYYY') AND to_date('19/04/2021', 'DD/MM/YYYY')
AND pi.pi_serial in (9221,
9299)
GROUP BY mo.manufacturing_order_master_id,
pi.pi_serial
ORDER BY pi.pi_serial
Option 1: Create a "Running Total" field in Crystal Reports to sum up only one "sales_value" per "proforma_invoice_id".
Option 2: Add a helper column to your Postgresql query like so:
case
when row_number()
over (partition by proforma_invoice_id
order by manufacturing_order_master_id)
= 1
then sales_value
else 0
end
as sales_value
I prepared this SQLFiddle with an example for you (and would of course like to encourage you to do the same for your next db query related question on SO, too :-)
I have two tables, EMPL which is a historical employee table to track changes in an employee's tax rate and PAYROLL which is also a historical table filled with employee pay over a number of periods.
FROM EMPL, based upon the EMPL.effect_pd <= PAYROLL.payroll_pd, only one record should be joined from EMPL to PAYROLL.
Below are the two tables, query and result set. However, I only want 1 record for each employee per pay period, which matches the relevant employee record based upon the payroll_pd and effect_pd.
(Click image to enlarge)
first of all - welcome!
You wrote "...FROM EMPL, based upon the EMPL.effect_pd <= PAYROLL.payroll_pd ..." but you start your SQL with PAYROLL and not with EMPL.
Pls test this statement first:
SELECT
E.rec_id
,E.empl_id
,E.empl_name
,E.tax_rate
,E.effect_pd
,P.rec_id
,P.payroll_pd
,P.empl_id
,P.pd_pay
FROM
empl AS E
LEFT OUTER JOIN
payroll AS P
ON E.empl_id = P.empl_id
AND E.effect_pd < P.payroll_pd
After that you get 7 records witch are uniqe.
i think, thats it.
Best regards
After 3 days of messing around with the code, I finally arrived at the solution which is:
SELECT * FROM PAYROLL p
LEFT JOIN EMPL e on p.empl_id = e.empl_id
WHERE e.rec_id = ( SELECT TOP 1 c.rec_id
FROM EMPL c
WHERE c.empl_id = p.empl_id
AND p.payroll_pd >= c.effect_pd
ORDER BY c.effect_pd DESC );
I have a 2 tables FIRST
id,rl_no,adm_date,fees
1,123456,14-11-10,100
2,987654,10-11-12,30
3,4343,14-11-17,20
and SECOND
id,rollno,fare,type
1,123456,20,bs
5,634452,1000,bs
3,123456,900,bs
4,123456,700,bs
My requirement is twofold,
1, i first need to get all columns from both tables with common rl_no. So i used:
SELECT a.ID,a.rl_no,a.adm_date,a.fees,b.rollno,b.fare,b.type FROM FIRST a
INNER JOIN
SECOND b ON a.rl_no = b.rollno
The output is like this:
id,rl_no,adm_date,fees,rollno,fare,type
1,123456,14-11-10,100,123456,20,bs
1,123456,10-11-12,100,123456,900,bs
1,123456,14-11-17,100,123456,700,bs
2,Next i wanted to get the sum(fare) of those rollno that were common between the 2 tables and also whose fare >= fees from FIRST table group by rollno and id.
My query is:
SELECT x.ID,x.rl_no,,x.adm_date,x.fees,x.rollno,x.type,sum(x.fare) as "fare" from (SELECT a.ID,a.rl_no,a.adm_date,a.fees,b.rollno,b.fare,b.type FROM FIRST a
INNER JOIN
SECOND b ON a.rl_no = b.rollno) x, FIRST y
WHERE x.rollno = y.rl_no AND x.fare >= y.fees AND x.type IS NOT NULL GROUP BY x.rollno,x.ID ;
But this is throwing in exceptions.
ORA-00979: not a GROUP BY expression
00979. 00000 - "not a GROUP BY expression"
The expected output will be like this:
id,rollno,adm_date,fare,type
1,123456,14-11-10,1620,bs
So could someone care to show an oracle newbie what i'm doing wrong here?
It looks like there's a couple different problems here;
Firstly, you're trying to group by an x.ID column which doesn't exist; it looks like you'll want to add ID to the selected columns in your sub-query.
Secondly, when aggregating with GROUP BY, all selected columns need to be either listed in the GROUP BY statement or aggregated. If you're grouping by rollno and ID, what do you want to have happen to all the extra values for adm_date, fees, and type? Are those always going to be the same for each distinct rollno and ID pair?
If so, simply add them to the GROUP BY statement, ie,
GROUP BY adm_date, fees, type, rollno, ID
If not, you'll need to work out exactly how you want to select which one to be output; If you've got output like your example (adding in an ID column here)
ID,adm_date,fees,rollno,fare,type
1,14-11-10,100,123456,20,bs
1,10-11-12,100,123456,900,bs
1,14-11-17,100,123456,700,bs
Call that result set 'a'. If I run;
SELECT a.ID, a.rollno, SUM(a.fare) as total_fare
FROM a
GROUP BY a.ID, a.rollno
Then the result will be a single row;
ID,rollno,total_fare
1,123456,1620
So, if you also select the adm_date, fees, and type columns, oracle has no idea what you mean to do with them. You're not using them for grouping, and you're not telling oracle how you want to pick which one to use.
You could do something like
SELECT a.ID,
FIRST(a.adm_date) as first_adm_date,
FIRST(a.fees) as first_fees,
a.rollno,
SUM(a.fare) as total_fare,
FIRST(a.type) as first_type
FROM a
GROUP BY a.ID, a.rollno
Which would give the result;
ID,first_adm_date,first_fees,rollno,total_fare,first_type
1,14-11-10,100,123456,1620,bs
I'm not sure if that's what you mean to do though.
I just created a temporary table as:
create temporary table userAndProductSales as
select p.p_name, u.u_name, u.s_price, u.quantity
from product p
join userAndStates u
on p.s_id = u.s_id
Now I want to select some columns with a particular order. For example, I want the select to give me an output of:
u_name1 p_name1
u_name1 p_name2
u_name1 p_name3
u_name1 p_name4
...
u_name2 p_name1
u_name2 p_name2
u_name2 p_name3
....
and so on and so forth. How do I get this ouput? I've tried something on the lines of:
select (select u_name from userandproductsales order by u_name), p_name from userandproductsales
but I'm getting an error
UPDATE: Figured out that the table I'm joining isn't giving me the correct data I want. Thanks for the help though.
Here is how to use ORDER BY :
SELECT * from userandstatesales
order by u_name , p_name
Unless there is a reason for creating a temporary table (like needing to access it later in the same session), you should avoid the expense and simply do a order by from your select. For example:
select p.p_name, u.u_name, u.s_price, u.quantity
from product p
join userAndStates u
on p.s_id = u.s_id
order by u.u_name, p.p_name;