Specifice order to tables in postgres - postgresql

I just created a temporary table as:
create temporary table userAndProductSales as
select p.p_name, u.u_name, u.s_price, u.quantity
from product p
join userAndStates u
on p.s_id = u.s_id
Now I want to select some columns with a particular order. For example, I want the select to give me an output of:
u_name1 p_name1
u_name1 p_name2
u_name1 p_name3
u_name1 p_name4
...
u_name2 p_name1
u_name2 p_name2
u_name2 p_name3
....
and so on and so forth. How do I get this ouput? I've tried something on the lines of:
select (select u_name from userandproductsales order by u_name), p_name from userandproductsales
but I'm getting an error
UPDATE: Figured out that the table I'm joining isn't giving me the correct data I want. Thanks for the help though.

Here is how to use ORDER BY :
SELECT * from userandstatesales
order by u_name , p_name

Unless there is a reason for creating a temporary table (like needing to access it later in the same session), you should avoid the expense and simply do a order by from your select. For example:
select p.p_name, u.u_name, u.s_price, u.quantity
from product p
join userAndStates u
on p.s_id = u.s_id
order by u.u_name, p.p_name;

Related

Use postgresql query results to form another query

I am trying to select from one table using the select result from another table. I can run this in two queries but would like to optimize it into just one.
First query.. Select ids where matching other id
select id from lookuptable where paid = '547'
This results in something like this
6316352
6316353
6318409
6318410
6320468
6320469
6320470
6322526
6322527
6324586
6324587
6326648
I would like to then use this result to make another selection. I can do it manually like below. Note, there could be many rows with these values so I've been using a IN statement
select * from "othertable" where id in (6316352,6316353,6318409,6318410,6320468,6320469,6320470,6322526,6322527,6324586,6324587,6326648);
select
ot.*
from
"othertable" as ot
join
lookuptable as lt
on
ot.id = lt.id
where
lt.paid = '547'
The IN operator supports not just value lists but also subqueries, so you can literally write
select * from "othertable" where id in (select id from lookuptable where paid = '547');

Issue using INNER JOIN on multiple tables in Postgres

I am trying to create a new table by using inner join to combine multiple tables. All, the tables have a primary key/column called reach_id. I have a primary table called q3_studies. I want all of the columns from this table. I then have multiple other tables that have reach_id + another column. I want to JOIN this table ON reach_id that matches q3_studies but only include the other columns (so I don't have redundant reach_id columns). My first attempt seems to work if I run it from SELECT * ... using a LIMIT 1000; at the end, but adds redundant reach_ids.
SELECT * FROM second_schema.q3_studies s
INNER JOIN second_schema.bs_trigger_q3 b ON s.reach_id = b.reach_id
INNER JOIN second_schema.mod_unmod_q3 m ON s.reach_id = m.reach_id LIMIT 1000;
How can I amend this to add only the additional columns (ex: bs_trigger_q3 has an additional columns called bs_trigger, mod_unmod_q3 has an additional column called mod_unmod)?
Secondly, if I try to create a new table, I get an error: column reach_id specified more than one. What am I doing wrong here?
CREATE TABLE first_schema.report_q3 AS
SELECT * FROM second_schema.q3_studies s
INNER JOIN second_schema.bs_trigger_q3 b ON s.reach_id = b.reach_id
INNER JOIN second_schema.mod_unmod_q3 m ON s.reach_id = m.reach_id;
Instead of select * you need to list the columns you want explicitly. This is good practice in any case. It also allows you to rename columns e.g. s.column_A as "foo_column"
In the future the schema may change.
CREATE TABLE first_schema.report_q3 AS
SELECT
s.reach_id,
s.column_A, s.column_B,
b.column_C, b.column_D,
m.column_E, m.column_F
FROM second_schema.q2_studies s
INNER JOIN second_schema.bs_trigger_q3 b ON s.reach_id = b.reach_id
INNER JOIN second_schema.mod_unmod_q3 m ON s.reach_id = m.reach_id
;
If your editor does not help you with column names consider a different editor.

How to give alias for columns with same name after joining two tables in Postgres

Hi Guys I'm doing inner join for two tables and selecting all the columns from both tables. But I'm getting three cols with same name like id, created_at and updated_at.
Query:
SELECT addresses.* , facilities.* FROM facilities
INNER JOIN addresses
ON facilities.main_address_id = addresses.id
Is there any possible way that I can mention alias for above cols having same name while selecting all cols with * ?
Help of any kind would be appreciated! Thanks!
No you can't do this other than aliasing each column separately.
But if your query will be repetitive you could create VIEW:
CREATE OR REPLACE VIEW facilities_addresses AS
SELECT
addresses.column AS "addresses_column",
facilities.column AS "facilities_column"
FROM facilities
INNER JOIN addresses ON (facilities.main_address_id = addresses.id)
and then you can query:
SELECT * FROM facilities_addresses
yes you can
SELECT
addr.id as addressesId ,
addr.created_at as addresses_created_at,
addr.updated_at as addresses_update_at,
fac.id as facilitiesId,
fac.created_at as facilities_created_at,
fac.updated_at as facilities_updated_at FROM facilities as fac
INNER JOIN addresses as addr
ON facilities.main_address_id = addresses.id

oracle: grouping on merged columns

I have a 2 tables FIRST
id,rl_no,adm_date,fees
1,123456,14-11-10,100
2,987654,10-11-12,30
3,4343,14-11-17,20
and SECOND
id,rollno,fare,type
1,123456,20,bs
5,634452,1000,bs
3,123456,900,bs
4,123456,700,bs
My requirement is twofold,
1, i first need to get all columns from both tables with common rl_no. So i used:
SELECT a.ID,a.rl_no,a.adm_date,a.fees,b.rollno,b.fare,b.type FROM FIRST a
INNER JOIN
SECOND b ON a.rl_no = b.rollno
The output is like this:
id,rl_no,adm_date,fees,rollno,fare,type
1,123456,14-11-10,100,123456,20,bs
1,123456,10-11-12,100,123456,900,bs
1,123456,14-11-17,100,123456,700,bs
2,Next i wanted to get the sum(fare) of those rollno that were common between the 2 tables and also whose fare >= fees from FIRST table group by rollno and id.
My query is:
SELECT x.ID,x.rl_no,,x.adm_date,x.fees,x.rollno,x.type,sum(x.fare) as "fare" from (SELECT a.ID,a.rl_no,a.adm_date,a.fees,b.rollno,b.fare,b.type FROM FIRST a
INNER JOIN
SECOND b ON a.rl_no = b.rollno) x, FIRST y
WHERE x.rollno = y.rl_no AND x.fare >= y.fees AND x.type IS NOT NULL GROUP BY x.rollno,x.ID ;
But this is throwing in exceptions.
ORA-00979: not a GROUP BY expression
00979. 00000 - "not a GROUP BY expression"
The expected output will be like this:
id,rollno,adm_date,fare,type
1,123456,14-11-10,1620,bs
So could someone care to show an oracle newbie what i'm doing wrong here?
It looks like there's a couple different problems here;
Firstly, you're trying to group by an x.ID column which doesn't exist; it looks like you'll want to add ID to the selected columns in your sub-query.
Secondly, when aggregating with GROUP BY, all selected columns need to be either listed in the GROUP BY statement or aggregated. If you're grouping by rollno and ID, what do you want to have happen to all the extra values for adm_date, fees, and type? Are those always going to be the same for each distinct rollno and ID pair?
If so, simply add them to the GROUP BY statement, ie,
GROUP BY adm_date, fees, type, rollno, ID
If not, you'll need to work out exactly how you want to select which one to be output; If you've got output like your example (adding in an ID column here)
ID,adm_date,fees,rollno,fare,type
1,14-11-10,100,123456,20,bs
1,10-11-12,100,123456,900,bs
1,14-11-17,100,123456,700,bs
Call that result set 'a'. If I run;
SELECT a.ID, a.rollno, SUM(a.fare) as total_fare
FROM a
GROUP BY a.ID, a.rollno
Then the result will be a single row;
ID,rollno,total_fare
1,123456,1620
So, if you also select the adm_date, fees, and type columns, oracle has no idea what you mean to do with them. You're not using them for grouping, and you're not telling oracle how you want to pick which one to use.
You could do something like
SELECT a.ID,
FIRST(a.adm_date) as first_adm_date,
FIRST(a.fees) as first_fees,
a.rollno,
SUM(a.fare) as total_fare,
FIRST(a.type) as first_type
FROM a
GROUP BY a.ID, a.rollno
Which would give the result;
ID,first_adm_date,first_fees,rollno,total_fare,first_type
1,14-11-10,100,123456,1620,bs
I'm not sure if that's what you mean to do though.

How to use GROUP BY with Firebird?

I'm trying create a SELECT with GROUP BY in Firebird but I can't have any success. How could I do this ?
Exception
Can't format message 13:896 -- message file C:\firebird.msg not found.
Dynamic SQL Error.
SQL error code = -104.
Invalid expression in the select list (not contained in either an aggregate function or the GROUP BY clause).
(49,765 sec)
trying
SELECT FA_DATA, FA_CODALUNO, FA_MATERIA, FA_TURMA, FA_QTDFALTA,
ALU_CODIGO, ALU_NOME,
M_CODIGO, M_DESCRICAO,
FT_CODIGO, FT_ANOLETIVO, FT_TURMA
FROM FALTAS Falta
INNER JOIN ALUNOS Aluno ON (Falta.FA_CODALUNO = Aluno.ALU_CODIGO)
INNER JOIN MATERIAS Materia ON (Falta.FA_MATERIA = Materia.M_CODIGO)
INNER JOIN FORMACAOTURMAS Turma ON (Falta.FA_TURMA = Turma.FT_CODIGO)
WHERE (Falta.FA_CODALUNO = 238) AND (Turma.FT_ANOLETIVO = 2015)
GROUP BY Materia.M_CODIGO
Simple use of group by in firebird,group by all columns
select * from T1 t
where t.id in
(SELECT t.id FROM T1 t
INNER JOIN T2 j ON j.id = t.jid
WHERE t.id = 1
GROUP BY t.id)
Using GROUP BY doesn't make sense in your example code. It is only useful when using aggregate functions (+ some other minor uses). In any case, Firebird requires you to specify all columns from the SELECT column list except those with aggregate functions in the GROUP BY clause.
Note that this is more restrictive than the SQL standard, which allows you to leave out functionally dependent columns (ie if you specify a primary key or unique key, you don't need to specify the other columns of that table).
You don't specify why you want to group (because it doesn't make much sense to do it with this query). Maybe instead you want to ORDER BY, or you want the first row for each M_CODIGO.