I have a long NSString in which I m trying to replace special characters. Part of my string looks like this:
"veau (c\u00f4telette)","veau (filet)","agneau (gigot)","agneau (c\u00f4telette)","b**\u0153**uf (hach\u00e9)","porc (hach\u00e9)"
I would like to replace all the \u0153 with "oe". I've tried:
[response stringByReplacingOccurrencesOfString:#"\u0153" withString:#"oe"];
but it doesn't work.... I don't understand why!
The backslash is an escape character, so if you want to specify the actual backslash character in a string literal, you need to use two backslashes.
NSString *new = [old stringByReplacingOccurrencesOfString: #"\\u0153" withString:#"oe"];
NSString is immutable, so the function generates a new string that you have to store:
NSString *new = [old stringByReplacingOccurrencesOfString:#"\u0153" withString:#"oe"];
Related
NSString *str = #"ABCDEFGHI";
I would like to get the characters into position.
For example, i would extract the first, third and fourth position character: "ACD"
Look up -substringWithRange:
NSString *trimmedString=[str substringFromIndex:[str length]1];
NSString *trimmedString1=[str substringFromIndex:[str length]3];
NSString *trimmedString2=[str substringFromIndex:[str length]4];
and append them to get desired result.
This should be simple but it's not working. I am trying to strip single quote marks from an NSString named parms using the following (stripped of non-relevant vars in the format string):
NSString *newVar =[[NSString alloc] initWithFormat:#"%#", [parms stringByReplacingOccurrencesOfString:#"'" withString:#""]];
So if parms contains "Mike's Hat" I would expect that newVar would contain "Mikes Hat". Instead it contains "Mike's Hat".
There must be more to your code than you are proving, but the following works perfectly:
NSString *parms = #"Mike's Hat";
NSString *newVar =[parms stringByReplacingOccurrencesOfString:#"’" withString:#""];
NSLog(#"%#",newVar);
Output: Mikes Hat
There could be a possibility that the character ' may not be the same character in your parms string if the above does not work for you.
Turns out, you are using the wrong character copy/paste this character into your string: ’
Just my two cents on this same problem I had in my code.... When I used the single quote on the keyboard to type ' into my code it didn't work. But I was printing string values to the console. When I copied and pasted the ' character from the console into my code it then worked. What is weird is that I'm using the same key on the keyboard to enter the string into a UITextField so I really don't know why the same key gets turned into something different but that's how I solved it.
In Xcode, if I have an NSString containing a number, ie #"12345", how do I split it into an array representing component parts, ie "1", "2", "3", "4", "5"... There is a componentsSeparatedByString on the NSString object, but in this case there is no delimiter...
There is a ready member function of NSString for doing that:
NSString* foo = #"safgafsfhsdhdfs/gfdgdsgsdg/gdfsgsdgsd";
NSArray* stringComponents = [foo componentsSeparatedByString:#"/"];
It may seem like characterAtIndex: would do the trick, but that returns a unichar, which isn't an NSObject-derived data type and so can't be put into an array directly. You'd need to construct a new string with each unichar.
A simpler solution is to use substringWithRange: with 1-character ranges. Run your string through a simple for (int i=0;i<[myString length];i++) loop to add each 1-character range to an NSMutableArray.
A NSString already is an array of it’s components, if by components you mean single characters. Use [string length] to get the length of the string and [string characterAtIndex:] to get the characters.
If you really need an array of string objects with only one character you will have to create that array yourself. Loop over the characters in the string with a for loop, create a new string with a single character using [NSString stringWithFormat:] and add that to your array. But this usually is not necessary.
In your case, since you have no delimiter, you have to get separate chars by
- (void)getCharacters:(unichar *)buffer range:(NSRange)aRange
or this one
- (unichar)characterAtIndex:(NSUInteger) index inside a loop.
That the only way I see, at the moment.
Don't know if this works for what you want to do but:
const char *foo = [myString UTF8String]
char third_character = foo[2];
Make sure to read the docs on UTF8String
I have:
NSString *promise = #"thereAreOtherWorldsThanThese";
which I'm trying to transform into the string:
#"There are other worlds than these"
I'm guessing this is a regex job, but I'm very new to Objective C, and have so far had no luck. I would greatly appreciate any help!
I'd use GTMRegex (http://code.google.com/p/google-toolbox-for-mac/), for example:
NSString *promise = #"thereAreOtherWorldsThanThese";
GTMRegex *regex = [GTMRegex regexWithPattern:#"([A-Z])"];
NSLog(#"%#", [[regex stringByReplacingMatchesInString:promise
withReplacement:#" \\1"] lowercaseString]);
As for removing the uppercase letters you can simply use lowercaseString on NSString.
But as for inserting spaces just before an uppercase letter, I would agree that it would be a job for a regex, and sadly, my regex fu is rubbish :)
Without using any libraries you can use this NSString category I posted. Just perform lowerCaseString on the string array.
How do I convert an NSString from CamelCase to TitleCase, 'playerName' into 'Player Name'?
I am having a lengthy string which contains alphabets and a special character like "|". i need to split this strings based on the "|" delimiter and store the individual string in to an array. Is there any string function which helps us to do the same.?
Thanks,
Shibin.
Sounds like you need componentsSeparatedByString:
NSString *string = #"hello|how|are|you";
NSArray *array = [string componentsSeparatedByString:#"|"];
NSLog(#"array: %#", array);
Output:
array: (
hello,
how,
are,
you
)