I am having a lengthy string which contains alphabets and a special character like "|". i need to split this strings based on the "|" delimiter and store the individual string in to an array. Is there any string function which helps us to do the same.?
Thanks,
Shibin.
Sounds like you need componentsSeparatedByString:
NSString *string = #"hello|how|are|you";
NSArray *array = [string componentsSeparatedByString:#"|"];
NSLog(#"array: %#", array);
Output:
array: (
hello,
how,
are,
you
)
Related
I have to read .csv file which has three columns. While parsing the .csv file, I get the string in this format Christopher Bass,\"Cry the Beloved Country Final Essay\",cbass#cgs.k12.va.us. I want to store the values of three columns in an Array, so I used componentSeparatedByString:#"," method! It is successfully returning me the array with three components:
Christopher Bass
Cry the Beloved Country Final Essay
cbass#cgs.k12.va.us
but when there is already a comma in the column value, like this
Christopher Bass,\"Cry, the Beloved Country Final Essay\",cbass#cgs.k12.va.us
it separates the string in four components because there is a ,(comma) after the Cry:
Christopher Bass
Cry
the Beloved Country Final Essay
cbass#cgs.k12.va.us
so, How can I handle this by using regular expression. I have "RegexKitLite" classes but which regular expression should I use. Please help!
Thanks-
Any regular expression would probably turn out with the same problem, what you need is to sanitize your entries or strings, either by escaping your commas or by highlighting strings this way: "My string". Otherwise you will have the same problem. Good luck.
For your example you would probably need to do something like:
\"Christopher Bass\",\"Cry\, the Beloved Country Final Essay\",\"cbass#cgs.k12.va.us\"
That way you could use a regexp or even the same method from the NSString class.
Not related at all, but the importance of sanitizing strings: http://xkcd.com/327/ hehehe.
How about this:
componentsSeparatedByRegex:#",\\\"|\\\","
This should split your string whereever " and , appear together in either order, resulting in a three-member array. This of course assumes that the second element in the string is always enclosed in parentheses, and the characters " and , never appear consecutively within the three components.
If either of these assumptions is incorrect, other methods to identify string components may be used, but it should be made clear that no generic solution exists. If the three component strings can contain " and , anywhere, not even a limited solution is possible in such cases:
Doe, John,\"\"Why Unescaped Strings Suck\", And Other Development Horror Stories\",Doe, John <john.doe#dev.null>
Hopefully there is nothing like the above in your CSV data. If there is, the data is basically unusable, and you should look into a better CSV exporter.
The regex you're searching for is: \\"(.*)\\"[ ^,]*|([^,]*),
in ObjC: (('\"' && string_1 && '\"' && 0-n spaces) || string_2 except comma) && comma
NSString *str = #"Christopher Bass,\"Cry, the Beloved Country ,Final Essay\",cbass#cgs.k12.va.us,som";
NSString *regEx = #"\\\"(.*)\\\"[ ^,]*|([^,]*),";
NSMutableArray *split = [[str componentsSeparatedByRegex:regEx] mutableCopy];
[split removeObject:#""]; // because it will print always both groups even if the other is empty
NSLog(#"%#", split);
// OUTPUT:
2012-02-07 17:42:18.778 tmpapp[92170:c03] (
"Christopher Bass",
"Cry, the Beloved Country ,Final Essay",
"cbass#cgs.k12.va.us",
som
)
RegexKitLite will add both strings to the array, therefore you will end up with empty objects for your array. removeObject:#"" will delete those but if you need to maintain true empty values (eg. your source has val,,ue) you have to modify the code to the following:
str = [str stringByReplacingOccurrencesOfRegex:regEx withString:#"$1$2∏"];
NSArray *split = [str componentsSeparatedByString:#"∏"];
$1 and $2 are those two strings mentioned above, ∏ is in this case a character which will most likely never appear in normal text (and is easy to remember: option-shift-p).
The last part looks like it will never contain a comma. Neither will the first one as far as I can see...
What about splitting the string like this:
NSArray *splitArr = [str componentsSeparatedByString:#","];
NSString *nameStr = [splitArr objectAtIndex:0];
NSString *emailStr = [splitArr lastObject];
NSString *contentStr = #"";
for(int i=1; i<[splitArr count]-1; ++i) {
contentStr = [contentStr stringByAppendingString:[splitArr objectAtIndex:i]];
}
This will use the first and last string as is, and combine the rest into the content.
Kind of a hack, but a name and an email address will never contain a comma, right?
Is the title guarantied to have the quotation marks? And is it the only component that can have them? Because then componentSeparatedByString:#"\"" should get you this:
Christopher Bass,
Cry, the Beloved Country Final Essay
,cbass#cgs.k12.va.us
Then use componentSeparatedByString:#"," or substringFrom/ToIndex: to get rid of the two commas in the first and last component.
Here's a solution using substring:
NSString* input = #"Christopher Bass,\"Cry, the Beloved Country Final Essay\",cbass#cgs.k12.va.us";
NSArray* split = [input componentsSeparatedByString:#"\""];
NSString* part1 = [split objectAtIndex:0];
NSString* part2 = [split objectAtIndex:1];
NSString* part3 = [split objectAtIndex:2];
part1 = [part1 substringToIndex:[part1 length] - 1];
part3 = [part3 substringFromIndex:1];
NSLog(part1);
NSLog(part2);
NSLog(part3);
I am copying an NSMutableArray to a string. When I am displaying the string I am getting a "(" sign before the array items and the array entries are separated by a comma in between. I want to display the array entries line by line, and not by comma separated. How can I do this
There are a number of ways to do this. If you just want to join the array with a new-line character, the easiest is to use NSArray's -componentsJoinedByString: method. For example, to do exactly what you asked:
NSArray* myArray = // assume this exists
NSString* stringJoinedByNewLines = [myArray componentsJoinedByString:#"\n"];
// This should show each of the elements separated by a new-line (and they are now in a single string)
NSLog(#"the string: %#", stringJoinedByNewLines);
NSMutableArray * items = someArray;
NSMutableString * bulletList = [NSMutableString stringWithCapacity:items.count*10];
for (NSString * s in items)
{
[bulletList appendFormat:#"%#\n", s];
}
yourTextView.text = bulletList;
You can try
NSString*str=[str1 stringByReplacingOccurrencesOfString:#"(" withString:#"\n"];
This will replace all the opening braces with a new line character.Do the same for closing brace.
For example, I read a data like this
a\tbcd\tttte\tjjjd\tnjnjnjd\tss\tee
and I want to make a array like this:
{ #"a", #"bcd", #"ttte", #"jjjd", #"njnjnjd", #"ss", #"ee" }
How can I do so? Thank you.
You can use -componentsSeparatedByString:, as in
NSArray *ary = [mystring componentsSeparatedByString:#"\t"];
- (NSArray *)componentsSeparatedByString:(NSString *)separator
componentsSeparatedByString: Returns
an array containing substrings from
the receiver that have been divided by
a given separator.
(NSArray *)componentsSeparatedByString:(NSString
*)separator Parameters separator The separator string. Return Value An
NSArray object containing substrings
from the receiver that have been
divided by separator.
Discussion The substrings in the array
appear in the order they did in the
receiver. Adjacent occurrences of the
separator string produce empty strings
in the result. Similarly, if the
string begins or ends with the
separator, the first or last
substring, respectively, is empty. For
example, this code fragment:
NSString *list = #"Norman, Stanley, Fletcher";
NSArray *listItems = [list componentsSeparatedByString:#", "];
produces an array { #"Norman",#"Stanley", #"Fletcher" }.
If list begins with a comma and
space—for example, ", Norman, Stanley,
Fletcher"—the array has these
contents: { #"", #"Norman",
#"Stanley", #"Fletcher" }
If list has no separators—for example,
"Norman"—the array contains the string
itself, in this case { #"Norman" }.
Availability Available in Mac OS X v10.0 and later.
See Also:
componentsJoinedByString: (NSArray)
– pathComponents
Related Sample Code:
ColorMatching
CoreRecipes
iSpend
iSpendPlugin
QTKitMovieShuffler
Declared In NSString.h
From NSString docs
In Xcode, if I have an NSString containing a number, ie #"12345", how do I split it into an array representing component parts, ie "1", "2", "3", "4", "5"... There is a componentsSeparatedByString on the NSString object, but in this case there is no delimiter...
There is a ready member function of NSString for doing that:
NSString* foo = #"safgafsfhsdhdfs/gfdgdsgsdg/gdfsgsdgsd";
NSArray* stringComponents = [foo componentsSeparatedByString:#"/"];
It may seem like characterAtIndex: would do the trick, but that returns a unichar, which isn't an NSObject-derived data type and so can't be put into an array directly. You'd need to construct a new string with each unichar.
A simpler solution is to use substringWithRange: with 1-character ranges. Run your string through a simple for (int i=0;i<[myString length];i++) loop to add each 1-character range to an NSMutableArray.
A NSString already is an array of it’s components, if by components you mean single characters. Use [string length] to get the length of the string and [string characterAtIndex:] to get the characters.
If you really need an array of string objects with only one character you will have to create that array yourself. Loop over the characters in the string with a for loop, create a new string with a single character using [NSString stringWithFormat:] and add that to your array. But this usually is not necessary.
In your case, since you have no delimiter, you have to get separate chars by
- (void)getCharacters:(unichar *)buffer range:(NSRange)aRange
or this one
- (unichar)characterAtIndex:(NSUInteger) index inside a loop.
That the only way I see, at the moment.
Don't know if this works for what you want to do but:
const char *foo = [myString UTF8String]
char third_character = foo[2];
Make sure to read the docs on UTF8String
I have a long NSString in which I m trying to replace special characters. Part of my string looks like this:
"veau (c\u00f4telette)","veau (filet)","agneau (gigot)","agneau (c\u00f4telette)","b**\u0153**uf (hach\u00e9)","porc (hach\u00e9)"
I would like to replace all the \u0153 with "oe". I've tried:
[response stringByReplacingOccurrencesOfString:#"\u0153" withString:#"oe"];
but it doesn't work.... I don't understand why!
The backslash is an escape character, so if you want to specify the actual backslash character in a string literal, you need to use two backslashes.
NSString *new = [old stringByReplacingOccurrencesOfString: #"\\u0153" withString:#"oe"];
NSString is immutable, so the function generates a new string that you have to store:
NSString *new = [old stringByReplacingOccurrencesOfString:#"\u0153" withString:#"oe"];