Weird problem with a sqlite3-database (Can only write once) - iphone

Question

i have a huge problem with my sqlite3 database on the iphone sdk 4. I can only write/read the database once! With the iphone sdk 3.2 everything had just worked fine.
After the first try i get the errormessage "SQLITE_BUSY".
Here's a snippet of my code i use:
-(void) addFavoriteOdv:(Odv*)odv name:(NSString*)name;
{
#synchronized(self)
{
if(name == nil)
name = odv.name;
NSString* rowId = [self addOdv:odv];
int existing = [self numberOfFavoriteOdvs:rowId];
if(existing == 0)
{
sqlite3 *database = [self getOpenDatabase];
const char *insertStatement = [#"insert into favoriteodvs(odv, name) values (?, ?)" UTF8String];
int retCode = 0;
sqlite3_stmt *statement;
retCode = sqlite3_prepare_v2(database, insertStatement, -1, &statement, NULL);
if(retCode == SQLITE_OK)
{
sqlite3_bind_text(statement, 1, [rowId UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 2, [name UTF8String], -1, SQLITE_TRANSIENT);
if(sqlite3_step(statement)!= SQLITE_DONE)
{
NSLog(#"SQL Error: %s", sqlite3_errmsg(database));
NSLog(#"Inserting FavoriteOdv failed");
}
}
sqlite3_finalize(statement);
sqlite3_close(database);
}
}
}
Has anybody an idea? I use the libsqlite3.dylib.
Thanks,
Sebastian

Answer 1

to reuse your prepared statement - you must call
sqlite3_reset(statement);
right after you're received "SQLITE_DONE" from sqlite3_step. After that you can bind another data and run your query again.
p.s. wrong:
const char *insertStatement = [#"insert into favoriteodvs(odv, name) values (?, ?)" UTF8String];
correct:
const char *insertStatement = "insert into favoriteodvs(odv, name) values (?, ?)";