IPhone Development - sqlite3_bind_int not working - iphone

Question

i'm trying to insert some data on a database using this code:
-(void)insertLocationOnDatabase:(LocationType *)aLocation {
sqlite3_stmt *stmt;
int location = [aLocation.locationID intValue];
NSLog(#"Location ID: %i", location);
const char *sql = "insert into tbl_location values (?,?,?,?)";
if (sqlite3_prepare_v2(database, sql, -1, &stmt, NULL) == SQLITE_OK) {
sqlite3_bind_int(stmt, 0, location);
sqlite3_bind_text(stmt, 1, [aLocation.Description UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(stmt, 2, [aLocation.isActive UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(stmt, 3, [aLocation.sequenceOrder UTF8String], -1, SQLITE_TRANSIENT);
if (sqlite3_step(stmt) == SQLITE_DONE) {
NSLog(#"Location %# inserted on database",aLocation.Description);
}
else {
NSLog(#"Error on step: %i",sqlite3_errcode(database));
}
}
else {
NSLog(#"Error on prepare: %i",sqlite3_errcode(database));
}
}
the problem is on line:
sqlite3_bind_int(stmt, 0, location);
without this line and changing the sql, the code works fine, but when i put this line back, i get this error:
2010-09-17 10:24:01.032 StockControl[944:207] Error on step: 20
From sqlite3.h:
#define SQLITE_MISMATCH 20 /* Data type mismatch */
Somebody knows where is my mistake?
Regards,
Claudio

Answer 1

According to the docs for the binding methods in SQLite, the bindings count from one, not zero:
The second argument is the index of
the SQL parameter to be set. The
leftmost SQL parameter has an index of
1.
That might well lead to a type mismatch.

Answer 2

Why not use following methods?
NSString *sqlCmd = [NSString stringWithFormat:
#"insert into tbl_location values (%d,'%#','%#','%#')",
location,
aLocation.Description,
aLocation.isActive,
aLocation.sequenceOrder];
const char *sql = [sqlCmd UTF8String];
// ...
I use bind only for large data, for example an image file.