Hey guys, I'm looking for a batch file to tell me if certain folders have been modified today (I'll run it every morning). I'm happy to specify each of the folders to be to be queried, I just haven't been able to find anything that meets my requirements yet. If anyone knows off the top of their head what the code for the .bat would be, that would be awesome :) Thanks in advance.
Here's a batch file that should do the trick:
#echo off
setlocal ENABLEEXTENSIONS ENABLEDELAYEDEXPANSION
for /D %%Q IN (*.*) DO (
set FILETIME=%%~tQ
if "!FILETIME:~0,10!"=="%DATE:~4%" echo %%Q
)
This works by comparing the date-part of the file timestamp against the current date.
As written, it checks directories in the current directory, but you could replace *.* with whatever filespec you want to test (or pass it in as an argument).
I don't know if this will work on systems with anything other default English/US regional settings, but it could probably be tweaked to make it work, if it doesn't already. I also don't know what would happen if the system is shared between users in different time-zones.
you can use a vbscript
Set objFS = CreateObject( "Scripting.FileSystemObject" )
strFolder = WScript.Arguments(0)
Set objFolder = objFS.GetFolder(strFolder)
If DateDiff("d", Now, objFolder.DateLastModified ) = 0 Then
WScript.Echo "0"
End If
in your batch file (or command line)
C:\test>cscript //nologo test.vbs myFolderName
use a for loop to catch the output. (Or you can even do everything in vbscript )
Related
I need a script that copies files that are newer than a specified time (read from a file) from a directory and subfolders to a mirroring folder structure (that needs to be created). However, this needs to take account of date and time, not just date.
I can't seem to find a way to do this using batch / robocopy or another approach. Any suggestions would be appreciated, ideally not using powershell (I realise it can probably do it, but I've never used it and the learning curve seems a bit steep for now).
I can adjust the date/time saved in the file to fit any format.
So, say date-time is 2016-08-17-18-00-00, then
Org\A\1.txt (2016-08-17-18-01-00) > Target\A\1.txt
Org\A\2.txt (2016-08-17-17-00-00) > (not copied, as too old)
Org\B\C\D\3.txt (2016-08-18-09-00-00) > Target\B\C\D\3.txt
I probably need to use a forfiles loop, but not sure how to take account of time as well as date.
#echo off
setlocal enabledelayedexpansion
set compare=201608171800
for /r %%F in (*) do (
set file=%%~fF
for /f "tokens=2 delims=.=" %%I in ('wmic datafile where name^="!file:\=\\!" get lastmodified /format:list') do (
if "%%I" geq "%compare%" for /f "tokens=2,* delims=\" %%A in ("%%~fF") do echo %%~fF -- N:\target\%%B
)
)
you may have to adapt the "2" in tokens=2,* to your needs.
Note: this is slow, because of wmic
because of string comparison this works with %compare% format of YYYYMMDDhhmmss or YYYYMMDDhhmm or even YYYY.
I am new to scripting but at my work place I see that they are storing warnings, errors and notes from logs of different programs under one file using the below command in a batch file:
check_log.bat > tlglogs
PS: If it matters the different logs and the output tlglogs are in the same Windows folder.
I would like to add a date time stamp to the tlglogs each time I run the batch file. Could you please let me know how to proceed as I am not familiar with scripting? I tried the below via Dr. Google's help but it did not help:
check_log.bat >tlglogs_%Date%
Thanks for your time and help. It is highly appreciated!
Cheers!
In Powershell you can get the current date like below:
Get-Date
You can save it to a variable and also define the format of the returned date.
$d = Get-Date -Format "ddMMyyyy"
So this will return a date in the format like 04082016 and save it in the variable $d which we can use for export.
check_log.bat > "tlglogs_$d"
That should do what you want.
Thanks Junaid, adding the below code in the batch file worked for me:
#echo off
set startDate=%date%
set startTime=%time%
set sdy=%startDate:~10%
set /a sdm=1%startDate:~4,2% - 100
set /a sdd=1%startDate:~7,2% - 100
set /a sth=%startTime:~0,2%
set /a stm=1%startTime:~3,2% - 100
set /a sts=1%startTime:~6,2% - 100
check_log.bat *.log > tlglogs%sdy%.%sdm%.%sdd%-%sth%.%stm%
If there is a much easier way please do let me know. Thanks again!
I have a script that needs to connect to an ftp server and download a file that is only created on Sunday and Sunday's yyyy-mm-dd-hh-mm-ss is appended to the file name. I need to find the last Sunday's date (based on today's date, I assume) and convert it to yyyy-mm-dd (I don't care about the time) so I can construct the filename in my ftp script. I have searched a lot of threads on this and other sites, but I'm kind of a novice at batch syntax. I cannot make assumptions about the date format on the machine that will run this script, but it will be in the same timezone as the ftp server and it will be running at least Windows 7. I thought about using the PowerShell solution in HOW to find last SUNDAY DATE through batch but I've read there are issues with PS script portability. Any help is greatly appreciated. Let me know if I need to provide more detail. Thanks!
(Get-Date).AddDays(-(get-date).dayofWeek.value__)
A couple years ago I wrote a batch script to find yesterday's date. I made it able to calculate 'yesterday' based on today's date. It takes into account months ending on the 30th or 31st, and even the next few leap years. The way I wrote it expects the date to be in the format 'Wed 02/24/2016' or 'ddd MM/DD/YYYY', so it may not be useful to you.
As I look at it now, it's probably more complicated than it needs to be and could probably use some cleanup, but it worked for my purposes. You might be able to modify it somehow to make it find last Sunday, instead of yesterday.
set yearCounter=0
set yyyy=%date:~10,4%
set mm=%date:~4,2%
set dd=%date:~7,2%
::use these to override the actual date values for testing
::set yyyy=xxxx
::set mm=xx
::set dd=xx
if %dd%==01 goto LDoM ::Last Day of Month
set DS=%yyyy%%mm%%dd%
set /A yesterday=%DS%-1
goto endyesterday
:LDoM
set /A lastyyyy=%yyyy%-%yearCounter%
if %yesterday:~4,2%==01 set lastmm=12& set lastdd=31& goto LDoY ::Last Day of Year
if %yesterday:~4,2%==02 set lastmm=01& set lastdd=31
if %yesterday:~4,2%==03 set lastmm=02& goto february
if %yesterday:~4,2%==04 set lastmm=03& set lastdd=31
if %yesterday:~4,2%==05 set lastmm=04& set lastdd=30
if %yesterday:~4,2%==06 set lastmm=05& set lastdd=31
if %yesterday:~4,2%==07 set lastmm=06& set lastdd=30
if %yesterday:~4,2%==08 set lastmm=07& set lastdd=31
if %yesterday:~4,2%==09 set lastmm=08& set lastdd=31
if %yesterday:~4,2%==10 set lastmm=09& set lastdd=30
if %yesterday:~4,2%==11 set lastmm=10& set lastdd=31
if %yesterday:~4,2%==12 set lastmm=11& set lastdd=30
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:february
set leapyear=n
set lastdd=28
if %yesterday:~0,4%==2016 set leapyear=y
if %yesterday:~0,4%==2020 set leapyear=y
if %yesterday:~0,4%==2024 set leapyear=y
if %yesterday:~0,4%==2028 set leapyear=y
if %leapyear%==y set lastdd=29
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:LDoY
set /A yearCounter=%yearCounter%+1
set /A lastyyyy=%yyyy%-%yearCounter%
set yesterday=%lastyyyy%%lastmm%%lastdd%
:endYesterday
#echo off
echo %yyyy% %lastyyyy%
echo %mm% %lastmm%
echo %dd% %lastdd%
echo.
echo today = %yyyy%%mm%%dd%
echo yesterday = %yesterday%
Working with date and time using pure batch can be done, but it is not very convenient.
The GetTimestamp.bat utility makes date/time computations and formatting simple within a batch context. It is pure script (hybrid JScript/batch) that runs natively on any Windows machine from XP onward. The previous link points to the most recent version. The utility was first introduced with a number of examples at http://www.dostips.com/forum/viewtopic.php?t=4847.
Full documentation is available from the command line via getTimestamp /?, or getTimestamp /?? for paged output.
With GetTimestamp, the solution can be as simple as:
#echo off
:: Get the current day of the week, with 0=Sunday, 6=Saturday
:: to be used as an offset from today to get the most recent Sunday
call getTimeStamp -f {w} -r offset
:: Use the offset to get the most recent Sunday in YYYY-MM-DD format
call getTimeStamp -od -%offset% -f {iso-dt} -r lastSunday
:: Show the result
echo lastSunday=%lastSunday%
Try the following from a batch file:
for /f "usebackq" %%d in (`powershell -noprofile -command "'{0:yyyy-MM-dd}' -f [DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek)"`) do set "lastSunday=%%d"
echo %lastSunday%
:: -> e.g., "2016-02-21", when run on 2016-02-25
To try this directly on the command prompt, replace %%d with %d.
The PowerShell expression at the heart of the command,
[DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek),
which calculates the date of the most recent Sunday, was gratefully borrowed from the answer that you link to in your question.
'{0:yyyy-MM-dd}' -f ... applies the desired yyyy-mm-dd formatting to the date.
powershell -noprofile command ... invokes the PowerShell expression and outputs its result to stdout.
for /f "usebackq" %%d in (`...`) do set lastSunday=%%d captures the output from the PowerShell command and assigns it to batch variable lastSunday.
While invoking PowerShell for just one command from a batch file will be slow, being able to calculate the desired date so conveniently probably outweighs performance concerns.
I have a series of files that have long filenames. For each filename that contains a hyphen I would like to keep the substring in position 6-8, append the _FM07_FY14.prn to the name and ignore the rest of the original filename. The new extension is now .prn. The two digits 07 stands for the month and 14 is the year. The month and year can be found from the "date created" property. Will appreciate it if you can show me how to automatically capture this mm and yy from the date created. Hardcoding this part is okay too since I can sort files by created dates and put them in separate folders.
For example
aaaaaD07.dfdd-1234.A.b.1233 new filename will be D07_FM01_FY14.prn
bbcbaA30dls-d343.a.123d new filename will be A30_FM01_FY14.prn
cdq0dG12ir3-438d.dfd.txt new filename will be G12_FM01_FY14.prn
This is the .bat file I come up with after reading many posts on here, and I don't know how to extract the mm and yy so I hard code it. I am not familiar with Powershell. I can only handle a .bat or .cmd file and run it at the command prompt. Any and all help will be highly appreciated. Thanks!
#ECHO OFF
SETLOCAL
for %%F in (*.*) do (
SET "name=%%a"
set "var=_FM01_FY14.prn"
ren *-* "%name:~6,8%var%"
)
*endlocal*
#ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
SET "sourcedir=U:\sourcedir\one"
PUSHD %sourcedir%
FOR /f "delims=" %%a IN (
'dir /b /a-d "*" '
) DO (
SET name=%%a
SET fdate=%%~ta
ECHO(REN "%%a" "!name:~5,3!_FM!fdate:~3,2!_FY!fdate:~8,2!.prn"
)
popd
GOTO :EOF
You would need to change the setting of sourcedir to suit your circumstances.
The format that I use for date is dd/mm/yyyy If yours is different, then you'll need to change the offset in the !fdate:~m,2! phrases. The value of m is the offset into the date string from the first character (the second parameter is the number of characters to select.)
The required REN commands are merely ECHOed for testing purposes. After you've verified that the commands are correct, change ECHO(REN to REN to actually rename the files.
The below commands (with debug lines added - indented) should only redirect the echo's output to a file, should it already exist, according to my understanding.
However, it would seem that if exist %test0% always fills the file (creating it if non-existant) with the echo's output.
Does anyone know what is wrong?
#echo off
type test.bat
set test0="e:\documents and settings\administrator\desktop\test.log"
echo.&echo.
if exist %test0% (echo !!Exists!!) else (echo !!Doesn't Exist!!)
(if exist %test0% echo.&echo.&echo -------------------------------------------------&echo.&echo.)>>%test0%
And the file gets created(!)
EDIT: This above was a simplified example, and unfortunately MSalters answer doesn't help me solve the full command (I had hoped it would). The full one line if statement is:
if exist %test0% (echo.&echo.&echo -------------------------------------------------&echo.&echo.) else (set /p .=<nul)>>%test0%&set errorlevel=0||set errorlevel=1
How would I have whichever condition of the if matched output to the file (Hopefully with only one reference to the file, i.e., not one in each if conditional), and have the errorlevel set based on the existance of the file?
Could anyone help with the actual full command issue?
You should never set ERRORLEVEL directly. That name is reserved for reporting on the results of the prior command. When you set the value directly, you override the intended functionality and it ceases to expand to the actual ERRORLEVEL, it expands to the value you set instead. That can break all kinds of code.
You can force the ERRORLEVEL to a value by running a command with known result, redirecting output to nul if necessary: ver >nul sets ERRORLEVEL to 0, set /p .=<nul sets ERRORLEVEL to 1.
You can force the ERRORLEVEL to any particular value of your choosing by using cmd /c exit /b N, where N is an integral value.
You also have faulty logic. Your IF command succeeds (has no error) regardless whether the condition evaluates to TRUE or FALSE. If you want to set the ERRORLEVEL, then you need to do it within your parenthesized blocks.
There is nothing wrong with putting everything on one line, but I find the code easier to read when using multiple lines for complex statements like yours. I believe the following is what you are looking for.
if exist %test0% (
echo.
echo.
echo -------------------------------------------------
echo.
echo.
ver >nul
) >>%test0% else (
set /p .=<nul
)
Edit in response to comments
Not much change needed.
if exist %test0% (
(
echo.
echo.
echo -------------------------------------------------
echo.
echo.
set ERR=0
) >>%test0%
) else (
copy nul %test0%
set ERR=1
)
Check your parentheses. (x) >> output.log redirects the output of x to output.log. That means the redirection happens regardless of what the output is, and in particular always creates the file.
Now if you'd write if Y (echo Text >> output.log) the redirection would be conditional on Y, and might not happen.
[edit]
With the question as it's worded now, the simple solution seems to be:
Set %ERRORLEVEL% based on exist %test0%. No redirection has happened at this point.
Use %ERRORLEVEL% to determine what to do. You can change %test0% without altering %ERRORLEVEL%.
BTW, ERRORLEVEL is not %ERRORLEVEL%