I am new to scripting but at my work place I see that they are storing warnings, errors and notes from logs of different programs under one file using the below command in a batch file:
check_log.bat > tlglogs
PS: If it matters the different logs and the output tlglogs are in the same Windows folder.
I would like to add a date time stamp to the tlglogs each time I run the batch file. Could you please let me know how to proceed as I am not familiar with scripting? I tried the below via Dr. Google's help but it did not help:
check_log.bat >tlglogs_%Date%
Thanks for your time and help. It is highly appreciated!
Cheers!
In Powershell you can get the current date like below:
Get-Date
You can save it to a variable and also define the format of the returned date.
$d = Get-Date -Format "ddMMyyyy"
So this will return a date in the format like 04082016 and save it in the variable $d which we can use for export.
check_log.bat > "tlglogs_$d"
That should do what you want.
Thanks Junaid, adding the below code in the batch file worked for me:
#echo off
set startDate=%date%
set startTime=%time%
set sdy=%startDate:~10%
set /a sdm=1%startDate:~4,2% - 100
set /a sdd=1%startDate:~7,2% - 100
set /a sth=%startTime:~0,2%
set /a stm=1%startTime:~3,2% - 100
set /a sts=1%startTime:~6,2% - 100
check_log.bat *.log > tlglogs%sdy%.%sdm%.%sdd%-%sth%.%stm%
If there is a much easier way please do let me know. Thanks again!
Related
I downloaded all the pictures from an old spanish social network and the Last modified date is the date that I downloaded the file instead of the real date. I would like to order all the pictures by Last modified date to upload to google photos using the correct date.
I know the real date because the image name has the date and time and I would make a script to change de last modified date using the name of the file. I don't care about the time.
Name of the file format: "yyyy-mm-dd hh-mm-ss.jpg"
I'm using windows, but is not a problem to install Unix to execute some bash script, because it may probabbly be easier.
Is there any way to do this?
Thanks in advance
You can use powershell $(Get-Item *Filename*).creationtime=$(Get-Date "mm/dd/yyyy hh:mm am/pm") in a batch file or command prompt to change the creation date of a file. for more information look at this. In your case you could do:
for %%i in (<folder with all the files path>) do (
set name=%%~i
set name=%name:~0,19%
powershell $(Get-Item %%~i).creationtime=$(Get-Date "%name:~5,2%/%name:~8,2%/%name:~0,4% %name:~11,2%:%name:~14,2%")
)
Note: I have not tested this since I do not have the data set for it.
i am running the following command in a cmd:
Prog.exe -time Components_2016_04_19_11.ss
I want to write a batch file that will be run hourly and i need the date in the command to change accordingly - the date needs to be in the format above, and the last part of the date is the current hour minus 7 hours
So if the time now is 1/1/2016 20:43 the command will look like this
Prog.exe -time Components_2016_01_01_13.ss
i need help creating the appropriate batch file
Thanks
For future reference, questions resembling "Write this for me. Here are my requirements." aren't well-received around here. But this time, just to prevent any more unhelpful answers from being posted, I'll help you out with a solution.
Pure batch is really cumbersome with date math. Compensating for midnight, month changes, leap years, etc. can be a nightmare. It's much easier to use a different language -- one which has a proper Date object that will handle calendar quirks without having to hack around them.
Here's a PowerShell solution to your problem:
Prog.exe -time ("Components_{0}.ss" -f (Get-Date).addHours(-7).toString("yyyy_MM_dd_HH"))
That's it, just a one-liner. If you require a batch script, you can employ the PowerShell helper to perform the date math heavy lifting.
#echo off & setlocal
for /f "delims=" %%I in (
'powershell -noprofile "(Get-Date).addHours(-7).toString('yyyy_MM_dd_HH')"'
) do (
Prog.exe -time Components_%%I.ss
)
goto :EOF
Get-Date
Get-Date | Get-Member
you can use this:
$GBL = 0
do{
Prog.exe
Get-Date
sleep 3600
}
while($GBL -lt 1)
$GBL it's a infinity variable for the loop. inside of the do execute the program and use the sleep for wait 3600 seconds or 1 hour for execute again. Get-Date it's for mark the date and time when the code it's executed.
I don't understand if you need this or something else.
You can modify the line of Prog.exe with the code you need.
If you answer me i can help you.
Have a good day (:
I have a script that needs to connect to an ftp server and download a file that is only created on Sunday and Sunday's yyyy-mm-dd-hh-mm-ss is appended to the file name. I need to find the last Sunday's date (based on today's date, I assume) and convert it to yyyy-mm-dd (I don't care about the time) so I can construct the filename in my ftp script. I have searched a lot of threads on this and other sites, but I'm kind of a novice at batch syntax. I cannot make assumptions about the date format on the machine that will run this script, but it will be in the same timezone as the ftp server and it will be running at least Windows 7. I thought about using the PowerShell solution in HOW to find last SUNDAY DATE through batch but I've read there are issues with PS script portability. Any help is greatly appreciated. Let me know if I need to provide more detail. Thanks!
(Get-Date).AddDays(-(get-date).dayofWeek.value__)
A couple years ago I wrote a batch script to find yesterday's date. I made it able to calculate 'yesterday' based on today's date. It takes into account months ending on the 30th or 31st, and even the next few leap years. The way I wrote it expects the date to be in the format 'Wed 02/24/2016' or 'ddd MM/DD/YYYY', so it may not be useful to you.
As I look at it now, it's probably more complicated than it needs to be and could probably use some cleanup, but it worked for my purposes. You might be able to modify it somehow to make it find last Sunday, instead of yesterday.
set yearCounter=0
set yyyy=%date:~10,4%
set mm=%date:~4,2%
set dd=%date:~7,2%
::use these to override the actual date values for testing
::set yyyy=xxxx
::set mm=xx
::set dd=xx
if %dd%==01 goto LDoM ::Last Day of Month
set DS=%yyyy%%mm%%dd%
set /A yesterday=%DS%-1
goto endyesterday
:LDoM
set /A lastyyyy=%yyyy%-%yearCounter%
if %yesterday:~4,2%==01 set lastmm=12& set lastdd=31& goto LDoY ::Last Day of Year
if %yesterday:~4,2%==02 set lastmm=01& set lastdd=31
if %yesterday:~4,2%==03 set lastmm=02& goto february
if %yesterday:~4,2%==04 set lastmm=03& set lastdd=31
if %yesterday:~4,2%==05 set lastmm=04& set lastdd=30
if %yesterday:~4,2%==06 set lastmm=05& set lastdd=31
if %yesterday:~4,2%==07 set lastmm=06& set lastdd=30
if %yesterday:~4,2%==08 set lastmm=07& set lastdd=31
if %yesterday:~4,2%==09 set lastmm=08& set lastdd=31
if %yesterday:~4,2%==10 set lastmm=09& set lastdd=30
if %yesterday:~4,2%==11 set lastmm=10& set lastdd=31
if %yesterday:~4,2%==12 set lastmm=11& set lastdd=30
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:february
set leapyear=n
set lastdd=28
if %yesterday:~0,4%==2016 set leapyear=y
if %yesterday:~0,4%==2020 set leapyear=y
if %yesterday:~0,4%==2024 set leapyear=y
if %yesterday:~0,4%==2028 set leapyear=y
if %leapyear%==y set lastdd=29
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:LDoY
set /A yearCounter=%yearCounter%+1
set /A lastyyyy=%yyyy%-%yearCounter%
set yesterday=%lastyyyy%%lastmm%%lastdd%
:endYesterday
#echo off
echo %yyyy% %lastyyyy%
echo %mm% %lastmm%
echo %dd% %lastdd%
echo.
echo today = %yyyy%%mm%%dd%
echo yesterday = %yesterday%
Working with date and time using pure batch can be done, but it is not very convenient.
The GetTimestamp.bat utility makes date/time computations and formatting simple within a batch context. It is pure script (hybrid JScript/batch) that runs natively on any Windows machine from XP onward. The previous link points to the most recent version. The utility was first introduced with a number of examples at http://www.dostips.com/forum/viewtopic.php?t=4847.
Full documentation is available from the command line via getTimestamp /?, or getTimestamp /?? for paged output.
With GetTimestamp, the solution can be as simple as:
#echo off
:: Get the current day of the week, with 0=Sunday, 6=Saturday
:: to be used as an offset from today to get the most recent Sunday
call getTimeStamp -f {w} -r offset
:: Use the offset to get the most recent Sunday in YYYY-MM-DD format
call getTimeStamp -od -%offset% -f {iso-dt} -r lastSunday
:: Show the result
echo lastSunday=%lastSunday%
Try the following from a batch file:
for /f "usebackq" %%d in (`powershell -noprofile -command "'{0:yyyy-MM-dd}' -f [DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek)"`) do set "lastSunday=%%d"
echo %lastSunday%
:: -> e.g., "2016-02-21", when run on 2016-02-25
To try this directly on the command prompt, replace %%d with %d.
The PowerShell expression at the heart of the command,
[DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek),
which calculates the date of the most recent Sunday, was gratefully borrowed from the answer that you link to in your question.
'{0:yyyy-MM-dd}' -f ... applies the desired yyyy-mm-dd formatting to the date.
powershell -noprofile command ... invokes the PowerShell expression and outputs its result to stdout.
for /f "usebackq" %%d in (`...`) do set lastSunday=%%d captures the output from the PowerShell command and assigns it to batch variable lastSunday.
While invoking PowerShell for just one command from a batch file will be slow, being able to calculate the desired date so conveniently probably outweighs performance concerns.
Hey guys, I'm looking for a batch file to tell me if certain folders have been modified today (I'll run it every morning). I'm happy to specify each of the folders to be to be queried, I just haven't been able to find anything that meets my requirements yet. If anyone knows off the top of their head what the code for the .bat would be, that would be awesome :) Thanks in advance.
Here's a batch file that should do the trick:
#echo off
setlocal ENABLEEXTENSIONS ENABLEDELAYEDEXPANSION
for /D %%Q IN (*.*) DO (
set FILETIME=%%~tQ
if "!FILETIME:~0,10!"=="%DATE:~4%" echo %%Q
)
This works by comparing the date-part of the file timestamp against the current date.
As written, it checks directories in the current directory, but you could replace *.* with whatever filespec you want to test (or pass it in as an argument).
I don't know if this will work on systems with anything other default English/US regional settings, but it could probably be tweaked to make it work, if it doesn't already. I also don't know what would happen if the system is shared between users in different time-zones.
you can use a vbscript
Set objFS = CreateObject( "Scripting.FileSystemObject" )
strFolder = WScript.Arguments(0)
Set objFolder = objFS.GetFolder(strFolder)
If DateDiff("d", Now, objFolder.DateLastModified ) = 0 Then
WScript.Echo "0"
End If
in your batch file (or command line)
C:\test>cscript //nologo test.vbs myFolderName
use a for loop to catch the output. (Or you can even do everything in vbscript )
Project moving forwards, I can see why creating .bat files to do things can become addictive!
I can now save somefile.txt at regular intervals, I then rename somefile.txt by adding the time and date to create a unique file name
ren somefile.txt somefile_%time:~0,2%%time:~3,2%-%date:~-10,2%%date:~3,2%%date:~-4,4%.txt
As an example, the code above has just renamed somefile.txt to somefile_1317_13022011.txt (1317hrs on 13th February 2011)
I ran
ren somefile.txt somefile_%time:~0,2%%time:~3,2%-%date:~-10,2%%date:~7,2%%date:~-4,4%.txt
yesterday, it ran successfully until midnight, and then it crashed (syntax error) although it was saving as 12012011 for the date (12th Jan 2011) instead of the correct date of 12022011.
Will the current version ran past midnight? Am I confusing myself with UK vs US date format?
Animuson gives a decent way to do it, but no help on understanding it. I kept looking and came across a forum thread with this commands:
Echo Off
IF Not EXIST n:\dbfs\doekasp.txt GOTO DoNothing
copy n:\dbfs\doekasp.txt n:\history\doekasp.txt
Rem rename command is done twice (2) to allow for 1 or 2 digit hour,
Rem If before 10am (1digit) hour Rename starting at location (0) for (2) chars,
Rem will error out, as location (0) will have a space
Rem and space is invalid character for file name,
Rem so second remame will be used.
Rem
Rem if equal 10am or later (2 digit hour) then first remame will work and second will not
Rem as doekasp.txt will not be found (remamed)
ren n:\history\doekasp.txt doekasp-%date:~4,2%-%date:~7,2%-%date:~10,4%_#_%time:~0,2%h%time:~3,2%m%time:~6,2%s%.txt
ren n:\history\doekasp.txt doekasp-%date:~4,2%-%date:~7,2%-%date:~10,4%_#_%time:~1,1%h%time:~3,2%m%time:~6,2%s%.txt
I always name year first YYYYMMDD, but wanted to add time. Here you will see that he has given a reason why 0,2 will not work and 1,1 will, because (space) is an invalid character. This opened my eyes to the issue. Also, by default you're in 24hr mode.
I ended up with:
ren Logs.txt Logs-%date:~10,4%%date:~7,2%%date:~4,2%_%time:~0,2%%time:~3,2%.txt
ren Logs.txt Logs-%date:~10,4%%date:~7,2%%date:~4,2%_%time:~1,1%%time:~3,2%.txt
Output:
Logs-20121707_1019
Digging up the old thread because all solutions have missed the simplest fix...
It is failing because the substitution of the time variable results in a space in the filename, meaning it treats the last part of the filename as a parameter into the command.
The simplest solution is to just surround the desired filename in quotes "filename".
Then you can have any date pattern you want (with the exception of those illegal characters such as /,\,...)
I would suggest reverse date order YYYYMMDD-HHMM:
ren "somefile.txt" "somefile-%date:~10,4%%date:~7,2%%date:~4,2%-%time:~0,2%%time:~3,2%.txt"
following should be your right solution
ren somefile.txt somefile_%time:~0,2%%time:~3,2%-%DATE:/=%.txt
I took the above but had to add one more piece because it was putting a space after the hour which gave a syntax error with the rename command.
I used:
set HR=%time:~0,2%
set HR=%Hr: =0%
set HR=%HR: =%
rename c:\ops\logs\copyinvoices.log copyinvoices_results_%date:~10,4%-%date:~4,2%-%date:~7,2%_%HR%%time:~3,2%.log
This gave me my format I needed:
copyinvoices_results_2013-09-13_0845.log
problem in %time:~0,2% can't set to 24 hrs format, ended with space(1-9), instead of 0(1-9)
go around with:
set HR=%time:~0,2%
set HR=%Hr: =0% (replace space with 0 if any <has a space in between : =0>)
then replace %time:~0,2% with %HR%
good luck
ls | xargs -I % mv % %_`date +%d%b%Y`
One line is enough.
ls all files/dirs under current dir and append date to each file.
I tried to do the same:
<fileName>.<ext> --> <fileName>_<date>_<time>.<ext>
I found that :
rename 's/(\w+)(\.\w+)/$1'$(date +"%Y%m%d_%H%M%S)'$2/' *