How do I find last Sunday's date and save it in a variable in a Windows batch file - date

I have a script that needs to connect to an ftp server and download a file that is only created on Sunday and Sunday's yyyy-mm-dd-hh-mm-ss is appended to the file name. I need to find the last Sunday's date (based on today's date, I assume) and convert it to yyyy-mm-dd (I don't care about the time) so I can construct the filename in my ftp script. I have searched a lot of threads on this and other sites, but I'm kind of a novice at batch syntax. I cannot make assumptions about the date format on the machine that will run this script, but it will be in the same timezone as the ftp server and it will be running at least Windows 7. I thought about using the PowerShell solution in HOW to find last SUNDAY DATE through batch but I've read there are issues with PS script portability. Any help is greatly appreciated. Let me know if I need to provide more detail. Thanks!

(Get-Date).AddDays(-(get-date).dayofWeek.value__)

A couple years ago I wrote a batch script to find yesterday's date. I made it able to calculate 'yesterday' based on today's date. It takes into account months ending on the 30th or 31st, and even the next few leap years. The way I wrote it expects the date to be in the format 'Wed 02/24/2016' or 'ddd MM/DD/YYYY', so it may not be useful to you.
As I look at it now, it's probably more complicated than it needs to be and could probably use some cleanup, but it worked for my purposes. You might be able to modify it somehow to make it find last Sunday, instead of yesterday.
set yearCounter=0
set yyyy=%date:~10,4%
set mm=%date:~4,2%
set dd=%date:~7,2%
::use these to override the actual date values for testing
::set yyyy=xxxx
::set mm=xx
::set dd=xx
if %dd%==01 goto LDoM ::Last Day of Month
set DS=%yyyy%%mm%%dd%
set /A yesterday=%DS%-1
goto endyesterday
:LDoM
set /A lastyyyy=%yyyy%-%yearCounter%
if %yesterday:~4,2%==01 set lastmm=12& set lastdd=31& goto LDoY ::Last Day of Year
if %yesterday:~4,2%==02 set lastmm=01& set lastdd=31
if %yesterday:~4,2%==03 set lastmm=02& goto february
if %yesterday:~4,2%==04 set lastmm=03& set lastdd=31
if %yesterday:~4,2%==05 set lastmm=04& set lastdd=30
if %yesterday:~4,2%==06 set lastmm=05& set lastdd=31
if %yesterday:~4,2%==07 set lastmm=06& set lastdd=30
if %yesterday:~4,2%==08 set lastmm=07& set lastdd=31
if %yesterday:~4,2%==09 set lastmm=08& set lastdd=31
if %yesterday:~4,2%==10 set lastmm=09& set lastdd=30
if %yesterday:~4,2%==11 set lastmm=10& set lastdd=31
if %yesterday:~4,2%==12 set lastmm=11& set lastdd=30
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:february
set leapyear=n
set lastdd=28
if %yesterday:~0,4%==2016 set leapyear=y
if %yesterday:~0,4%==2020 set leapyear=y
if %yesterday:~0,4%==2024 set leapyear=y
if %yesterday:~0,4%==2028 set leapyear=y
if %leapyear%==y set lastdd=29
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:LDoY
set /A yearCounter=%yearCounter%+1
set /A lastyyyy=%yyyy%-%yearCounter%
set yesterday=%lastyyyy%%lastmm%%lastdd%
:endYesterday
#echo off
echo %yyyy% %lastyyyy%
echo %mm% %lastmm%
echo %dd% %lastdd%
echo.
echo today = %yyyy%%mm%%dd%
echo yesterday = %yesterday%

Working with date and time using pure batch can be done, but it is not very convenient.
The GetTimestamp.bat utility makes date/time computations and formatting simple within a batch context. It is pure script (hybrid JScript/batch) that runs natively on any Windows machine from XP onward. The previous link points to the most recent version. The utility was first introduced with a number of examples at http://www.dostips.com/forum/viewtopic.php?t=4847.
Full documentation is available from the command line via getTimestamp /?, or getTimestamp /?? for paged output.
With GetTimestamp, the solution can be as simple as:
#echo off
:: Get the current day of the week, with 0=Sunday, 6=Saturday
:: to be used as an offset from today to get the most recent Sunday
call getTimeStamp -f {w} -r offset
:: Use the offset to get the most recent Sunday in YYYY-MM-DD format
call getTimeStamp -od -%offset% -f {iso-dt} -r lastSunday
:: Show the result
echo lastSunday=%lastSunday%

Try the following from a batch file:
for /f "usebackq" %%d in (`powershell -noprofile -command "'{0:yyyy-MM-dd}' -f [DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek)"`) do set "lastSunday=%%d"
echo %lastSunday%
:: -> e.g., "2016-02-21", when run on 2016-02-25
To try this directly on the command prompt, replace %%d with %d.
The PowerShell expression at the heart of the command,
[DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek),
which calculates the date of the most recent Sunday, was gratefully borrowed from the answer that you link to in your question.
'{0:yyyy-MM-dd}' -f ... applies the desired yyyy-mm-dd formatting to the date.
powershell -noprofile command ... invokes the PowerShell expression and outputs its result to stdout.
for /f "usebackq" %%d in (`...`) do set lastSunday=%%d captures the output from the PowerShell command and assigns it to batch variable lastSunday.
While invoking PowerShell for just one command from a batch file will be slow, being able to calculate the desired date so conveniently probably outweighs performance concerns.

Related

How do you define the first day of the month (without including week-ends) in a batch script?

I have created a scheduled task in Windows that consists of running a batch script.
The problem is that this task has to be scheduled every 1st day of the month except for weekends.
For example, for the month of May, this task should run on May 02nd.
As I can't do it via the task scheduler, my idea is to schedule the execution task every day and add a condition checking that the execution day is the 1st day of the month excluding weekends.
This script would be of the following form :
if today = firstday
C:/MyExec/popo.exe arg1 arg2
Can you help me to write this script please?
Thank you in advance.
There are loads of standard methods already created for this, so just for me to experiment a bit, here is an untested method (untested meaning I simply ensured there are no syntax errors, but I have not tested all dates scenarios etc:
#echo off
if not exist _mlock break>_mlock
for /f "tokens=1-3*delims=_" %%i in ('PowerShell -Command "& {Get-Date -format "dd_ddd_MM"}"') do (
if %%i lss 5 if /i not "%%j" == "Sat" if /i not "%%j" == "Sun" findstr "m%%k">nul _mlock || (
echo m%%k>"_mlock"
start "" "C:\MyExec\popo.exe" "arg1" "arg2"
)
)
The concept: Use powershell to get a non-locale dependent dd ddd mm (04 Wed 05). I check for the day number, if it is less than 5 (overkill in this scenario) and if the ddd is not Sat or Sun and if the month's lock file does not contain the current month number, it will launch the command. If however the lock file contains the month, it will skip it until the month is updated in the file.
You're welcome to test this, if you are not happy with the temp holding file method, you can also let it add the month as a lock to the batch-file itself instead.
Notes:
This does not cater for public holidays, only weekends as per your request.
The ddd day result is language dependent and will require you to amend Sat and Sun accordingly on non English Operating systems.
This version is language-independent, excepted for optional display, and doesn't require lock files.
I've put comments inside the batch itself, feel free to ask for precisions if needed. I've tested it for March and May 2022, it works and doesn't trigger the command more than one time per month.
#echo off
setlocal enableextensions enabledelayedexpansion
REM Get current date. Powershell is used to get values in a fixed order.
for /f "usebackq tokens=1-3 delims=/" %%A in (`PowerShell -Command "& {Get-Date -format "dd/MM/yyyy"}"`) do (
set DD=%%A
set MM=%%B
set YY=%%C
REM Scheduled day.
set EDD=01
)
REM Not during first 3 days after scheduled day? Skip.
set /A maxday=!EDD!+2
if !DD! LEQ !maxday! (
if !DD! GEQ !EDD! (
goto :can_test
)
)
echo !DD!/!MM!/!YY!: Not first days after scheduled day, no need to test.
goto :eof
:can_test
REM Compute day of week: 0=Monday, ... 5=Saturday, 6=Sunday.
set /A c=(14-!MM!)/12
set /A y=!YY!-!c!
set /A m=!MM!+(12*!c!)-2
set /A d=((!EDD!-1+!y!+(!y!/4)-(!y!/100)+(!y!/400)+((31*!m!)/12))) %% 7
REM Get human-readable day. Change according to your own language, if needed. Keep order, of course.
set DAYS=Monday Tuesday Wednesday Thursday Friday Saturday Sunday
set /A i=0
for %%A in (!DAYS!) do (
set DAY=%%A
if !i! EQU !d! goto :found_day
set /A i+=1
)
:found_day
echo Day of week for !EDD!/!MM!/!YY!: !d! ^(!DAY!^)
REM If EDD is during week-end, increase expected day (2 days for Saturday, 1 day for Sunday)..
if !d! GEQ 6 (
set /A EDD+=7-!d!
REM Handle non-significative zero.
if !EDD! LSS 10 (
set EDD=0!EDD!
)
echo On week-end, schedule it to !EDD!/!MM!/!YY! instead.
)
REM Are we on scheduled day EXACTLY?
if !DD! EQU !EDD! (
REM Executing command now.
echo Executing: C:\MyExec\popo.exe arg1 arg2
REM C:\MyExec\popo.exe arg1 arg2
goto :eof
)
REM We're before or after schedule, but still within the first three days in the month.
echo Unscheduled for today ^(!DD!/!MM!/!YY!^).
goto :eof
The "day of week" formula comes from here: Mathematical curiosities / Find the day of the week with a given date (in French).
I took also Gerhard's trick for obtaining a fixed date format quickly through Powershell. It could also have been done with an embedded VBS script, since this language natively have the Weekday function, but it may have been quite unreadable to add a temporary script generation within the batch itself.
Sorry for this answer but I've no reputation to add a comment below the answer I'm referring to, the one by Wisblade:
https://stackoverflow.com/a/72113645/16641207
And I think it is important to make some additions to his beautiful answer.
I'm answering just to point out that in the wonderful piece of batch posted by Wisblade, to avoid sundays and saturdays too, at line 38 instead of this:
if !d! GEQ 6 (
there should be:
if !d! GEQ 5 (
because numbering in the "array" begins with zero.
I would also underline that this conditional expression should be changed if weekend days are different in the country where the code is used: e.g. in Israel one should check if !d! is NOT 0 and NOT 6 (not a monday nor a sunday, but saturdays are workdays there, too).
Apart from that, I gave a big +1 to his question, works so beautifully.
I used in a scheduled task, combined with the ability of Windows Scheduled Tasks to be scheduled only on first mon/tue/wed/thu/fri of every month, and doing this I'm able to execute my instruction just on first working day of every month.
Simple and effective.

Is it possible to specifically compare two dates in batch?

I was wondering if it's possible to compare a specific date (in the MM/DD/YY format) to the current system date, and get the difference in minutes?
In my past questions, I've been able to grab the dates of processes and folders and create the conversion to minutes, but I'm stumped.
My project uses Batch/CMD and Powershell, so any of those formats would be more than acceptable.
Here's the code that I use for grabbing dates to minutes with processes:
if exist "C:\Windows\Prefetch\JAVAW*.*" (
for /f "usebackq" %%A in (`
powershell -NoP -C "[int]([datetime]::Now - (gci 'C:\Windows\Prefetch\JAVAW*.*' -Force).LastWriteTime).TotalMinutes"
`) do set "AgeMinutes=%%A"
)
if exist "C:\Windows\Prefetch\JAVAW*.*" echo JAVAW.pf was modified %AgeMinutes% minutes ago.
if not exist "C:\Windows\Prefetch\JAVAW*.*" echo Error: file not found.
Is a comparison to the current date (and outputting it into minutes) possible?

Dynamic date in batch file

i am running the following command in a cmd:
Prog.exe -time Components_2016_04_19_11.ss
I want to write a batch file that will be run hourly and i need the date in the command to change accordingly - the date needs to be in the format above, and the last part of the date is the current hour minus 7 hours
So if the time now is 1/1/2016 20:43 the command will look like this
Prog.exe -time Components_2016_01_01_13.ss
i need help creating the appropriate batch file
Thanks
For future reference, questions resembling "Write this for me. Here are my requirements." aren't well-received around here. But this time, just to prevent any more unhelpful answers from being posted, I'll help you out with a solution.
Pure batch is really cumbersome with date math. Compensating for midnight, month changes, leap years, etc. can be a nightmare. It's much easier to use a different language -- one which has a proper Date object that will handle calendar quirks without having to hack around them.
Here's a PowerShell solution to your problem:
Prog.exe -time ("Components_{0}.ss" -f (Get-Date).addHours(-7).toString("yyyy_MM_dd_HH"))
That's it, just a one-liner. If you require a batch script, you can employ the PowerShell helper to perform the date math heavy lifting.
#echo off & setlocal
for /f "delims=" %%I in (
'powershell -noprofile "(Get-Date).addHours(-7).toString('yyyy_MM_dd_HH')"'
) do (
Prog.exe -time Components_%%I.ss
)
goto :EOF
Get-Date
Get-Date | Get-Member
you can use this:
$GBL = 0
do{
Prog.exe
Get-Date
sleep 3600
}
while($GBL -lt 1)
$GBL it's a infinity variable for the loop. inside of the do execute the program and use the sleep for wait 3600 seconds or 1 hour for execute again. Get-Date it's for mark the date and time when the code it's executed.
I don't understand if you need this or something else.
You can modify the line of Prog.exe with the code you need.
If you answer me i can help you.
Have a good day (:

Batch Script For File Date/Time

I know there are similar questions but I have not been able to make any work. I need to check a particular file date and time against the current date and time.
So far I have
Set cdate=%date%
Set filename="c:\myfile"
If Not Exist %filename% GOTO CREATEFILE
For %%f In(%filename%) DoSet filedatetime=%%~tf
If %filedatetime:~0,-9%" == "%cdate% GOTO SHOFILE
My problem is that the cdate returned has the day of the week included in the date but the file date does not. Example cdate= Thur 1/01/2015. How can I get the cdate not to have the day of the week?
Thanks
For %%f In (%filename%) Do Set "filedatetime=%%~tf"
If "%filedatetime:~0,-9%"=="%cdate:~4%" GOTO SHOFILE
Note the required space after in and do
The set "var=value" syntax ensures that any trailing spaces on the batch line are not included in the value assigned to var.
if /i "%var%"=="value" performs a comparison on variables/values containing separators (eg spaces) The '/i' make the comparison case-insensitive if required.
Your cdate can be set like this:
SET cdate=%date:~4%
This has the following output:
echo %cdate%
01/01/2015

Printing current date and time in DOS script

I have a script that prints the date and time followed by a string in a log.
echo %DATE%_%TIME% Processing %%f >> process.log
The problem is that the date and time is always the date and time when the script is started. I've been running the script overnight, and still has the same date and time. Is there a way to update them so it shows the current date and time when the string is printed to the log file?
The fact that you have %%f indicates your echo command is in a FOR loop. The entire FOR loop is parsed at once, and %DATE% is expanded at parse time. The command is not re-parsed for each iteration, so that is why you get the same value for each iteration. You get the value that existed before the FOR statement is executed!
The solution is delayed expansion. Put setlocal enableDelayedExpansion near the top of your script. Then use !DATE!_!TIME! instead of %DATE%_%TIME%. Delayed expansion means the expansion occurs when the statement is executed, not when it is parsed. There is a good explanation in the HELP system. Type HELP SET or SET /? from a command prompt and look for the section that deals with delayed expansion.