i have a problem with this particular NSString B and Ｂ . As you can see the encoding is different. So I am wondering if there is any way to convert Ｂ to B so that the computer can standardize the character.
Does this work?
NSString *newString = [oldString stringByReplacingOccurrencesOfString:#"Ｂ" withString: #"B"];
Related
Say I have a string like "123alpha". I can use NSNumber to get the 123 out, but how can I determine the part of the string that NSNumber didn't use?
You can use NSScanner to both get the value and the rest of the string.
NSString *input = #"123alpha";
NSScanner *scanner = [NSScanner scannerWithString:input];
float number;
[scanner scanFloat:&number];
NSString *rest = [input substringFromIndex:[scanner scanLocation]];
If it is important to know exactly what is left after parsing the value this is a better approach than trying to trim characters. While I can't think of any particular bad input at the moment that would fail the solution suggested by the OP in the comment to this answer, it looks like a bug waiting to happen.
if your numbers are always at the beginning or end of a string and you want only the remaining characters, you could trim with a character set.
NSString *alpha = #"123alpha";
NSString *stripped = [alpha stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"0123456789"]];
If its starts out as a char * (as opposed to an NSString *), you can use strtol() to get the number and discover where the number ends in a single call.
when i use this code for generate an hash256 in my iPhone app:
unsigned char hashedChars[32];
NSString *inputString;
inputString = [NSString stringWithFormat:#"hello"];
CC_SHA256([inputString UTF8String],
[inputString lengthOfBytesUsingEncoding:NSASCIIStringEncoding ],
hashedChars);
NSData * hashedData = [NSData dataWithBytes:hashedChars length:32];
The hash256 of inputString, is created correctly, but if i use a string like this #"\x00\x25\x53\b4", the hash256 is different from the real string with "\x" characters.
I think that the problem is in encoding "UTF8" instead of ascii.
Thanks!
I would be suspicious of the first character, "\x00" - thats going to terminate anything that thinks its dealing with "regular C strings".
Not sure whether lengthOfBytesUsingEncoding: takes that stuff into account, but its something I'd experiment with.
You're getting the bytes with [inputString UTF8String] but the length with [inputString lengthOfBytesUsingEncoding:NSASCIIStringEncoding]. This is obviously wrong. Moreover (assuming you mean "\xB4" and that it turns into something not in ASCII), "\xB4" is not likely to be in ASCII. The docs for NSString say
Returns 0 if the specified encoding cannot be used to convert the receiver
So you're calculating the hash of the empty string. Of course it's wrong.
You're less likely to have problems if you only generate the data once:
NSData * inputData = [inputString dataUsingEncoding:NSUTF8StringEncoding];
CC_SHA256(inputData.bytes, inputData.length, hashedChars);
I am trying to format a URL but am getting a bug out of it. My code is below.
NSString *twitterURL = [NSString stringWithFormat:#"http://twitter.com/?status=My%20score%20is:%i%20and%20CharsPerMin%20is:%#", currentScore, charPerMin.text];
When calling the method it doesn't do a thing. I think the issue is with %20. %20 is being used to space each word in the URL.
You need to escape your % signs by doubling them:
NSString *twitterURL = [NSString stringWithFormat:#"http://twitter.com/?status=My%%20PracticeTyper%%20score%%20is:%i%%20and%%20CharsPerMin%%20is:%#", currentScore, charPerMin.text];
I have:
NSString *promise = #"thereAreOtherWorldsThanThese";
which I'm trying to transform into the string:
#"There are other worlds than these"
I'm guessing this is a regex job, but I'm very new to Objective C, and have so far had no luck. I would greatly appreciate any help!
I'd use GTMRegex (http://code.google.com/p/google-toolbox-for-mac/), for example:
NSString *promise = #"thereAreOtherWorldsThanThese";
GTMRegex *regex = [GTMRegex regexWithPattern:#"([A-Z])"];
NSLog(#"%#", [[regex stringByReplacingMatchesInString:promise
withReplacement:#" \\1"] lowercaseString]);
As for removing the uppercase letters you can simply use lowercaseString on NSString.
But as for inserting spaces just before an uppercase letter, I would agree that it would be a job for a regex, and sadly, my regex fu is rubbish :)
Without using any libraries you can use this NSString category I posted. Just perform lowerCaseString on the string array.
How do I convert an NSString from CamelCase to TitleCase, 'playerName' into 'Player Name'?
I have a long NSString in which I m trying to replace special characters. Part of my string looks like this:
"veau (c\u00f4telette)","veau (filet)","agneau (gigot)","agneau (c\u00f4telette)","b**\u0153**uf (hach\u00e9)","porc (hach\u00e9)"
I would like to replace all the \u0153 with "oe". I've tried:
[response stringByReplacingOccurrencesOfString:#"\u0153" withString:#"oe"];
but it doesn't work.... I don't understand why!
The backslash is an escape character, so if you want to specify the actual backslash character in a string literal, you need to use two backslashes.
NSString *new = [old stringByReplacingOccurrencesOfString: #"\\u0153" withString:#"oe"];
NSString is immutable, so the function generates a new string that you have to store:
NSString *new = [old stringByReplacingOccurrencesOfString:#"\u0153" withString:#"oe"];