Build string with variable number of keys and formats - iphone

I have an NSDictionary object that contains my data. I am passing in an array of key names and a display format for a string representation of my data.
[self displayMyDataWithTheseKeys:myKeyArray inThisFormat:myFormat];
where, for example,
myKeyArray = [NSArray arrayWithObjects: #"Key1", #"Key2", nil];
myFormat = [NSString stringWithString: #"%# to the %# degree"];
However, myFormat may change and the number of keys in the array may vary as well.
If the number of elements in the array was always 2, this would be trivial. However, how can I handle a variable number of elements?

There isn't really a built-in method for this, but it's relatively easy to parse format strings with NSScanner. Here's a simple example, it only handles %# format specifiers, but as all elements in an NSArray are objects and not primitive types anyway, it shouldn't matter:
NSArray *myKeyArray = [NSArray arrayWithObjects: #"Key1", #"Key2", nil];
NSString *myFormat = [NSString stringWithString: #"%# to the %# degree"];
NSMutableString *result = [NSMutableString string];
NSScanner *scanner = [NSScanner scannerWithString:myFormat];
[scanner setCharactersToBeSkipped:[NSCharacterSet illegalCharacterSet]];
int i = 0;
while (![scanner isAtEnd]) {
BOOL scanned = [scanner scanString:#"%#" intoString:NULL];
if (scanned) {
if (i < [myKeyArray count]) {
[result appendString:[myKeyArray objectAtIndex:i]];
i++;
} else {
//Handle error: Number of format specifiers doesn't
//match number of keys in array...
}
}
NSString *chunk = nil;
[scanner scanUpToString:#"%#" intoString:&chunk];
if (chunk) {
[result appendString:chunk];
}
}

Use: stringByAppendingString
Here's an example on how to use it:
NSString *someString = #"String";
someString = [someString stringByAppendingString:[NSString stringWithFormat:#"%#",variable1]];
someString = [someString stringByAppendingString:[NSString stringWithFormat:#"%#",variable2]];
someString = [someString stringByAppendingString:[NSString stringWithFormat:#"%#",variable3]];
...and so on
If you have an array of keys which you want to put in a string:
NSString *string = #"And the keys are:\n";
for(int i = 0; i < [array count]; i++)
{
NSString *thisKey = (NSString *)[array objectAtIndex:i];
string = [string stringByAppendingString:[NSString stringWithFormat:#"Key number %d is %#",i,thisKey]];
}

Related

Convert String into special - splitting an NSString

I have a string like: "mocktail, wine, beer"
How can I convert this into: "mocktail", "wine", "beer"?
the following gives you the desired result:
NSString *_inputString = #"\"mocktail, wine, beer\"";
NSLog(#"input string : %#", _inputString);
NSLog(#"output string : %#", [_inputString stringByReplacingOccurrencesOfString:#", " withString:#"\", \""]);
the result is:
input string : "mocktail, wine, beer"
output string : "mocktail", "wine", "beer"
You need to use:
NSArray * components = [myString componentsSeparatedByString: #", "];
NSString *string = #"mocktail, wine, beer";
//remove whitespaces
NSString *trimmedString = [string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
//get array of string
NSArray *array = [trimmedString componentsSeparatedByString:#","];
NSMutableArray *newArray = [[NSMutableArray alloc] init];
for (NSString *trimmedString in array) {
NSString *newString = [NSMutableString stringWithFormat:#"'%#'", trimmedString];
[newArray addObject:newString];
}
//merge new strings
NSString *finalString = [NSString stringWithFormat:#"%#", [newArray objectAtIndex:0]];
for (NSInteger i = 1; i < [newArray count]; i++) {
finalString = [NSString stringWithFormat:#"%#, %#", finalString, [newArray objectAtIndex:i]];
}
Without knowing spesifically about iOS or objective-c, I assume you could use a split function.
In almost any higher level programming language there is such a function.
Try:
Objective-C split
This gets you an array of Strings. You can then practically do with those what you want to do, e.g. surrounding them with single quotes and appending them back together. :D

How to search in NSArray?

I am having an array like fallowing,
NSArray*array = [NSArray arrayWithObjects:#"1.1 something", #"1.2 something else", #"1.3 out of left field", #"1.4 yet another!", nil];
Now,i am having the string like fallowing,
NSString*str = #"1.3";
Now i will send the str .Then it needs to find that str in array and it need to return the index of object where that text found.Means i need index 2 has to come as output.Can anyone share the code please.Thanks in advance.
Here is an example using blocks, notice the method: hasPrefix:
NSArray *array = [NSArray arrayWithObjects:#"1.1 problem1", #"1.2 problem2", #"1.3 problem3", #"1.4 problem4", nil];
NSString *str = #"1.3";
NSUInteger index = [array indexOfObjectPassingTest:
^(id obj, NSUInteger idx, BOOL *stop) {
return [obj hasPrefix:str];
}];
NSLog(#"index: %lu", index);
NSLog output:
index: 2
First a comment,
NSString *str = 1.3;
does not create an NSString object. You should instead have
NSString *str = #"1.3";
To search the NSArray, you will either have to change the string to the exact string in the array or search the NSString as well. For the former, simply do
float num = 1.3;
NSString *str = [NSString stringWithFormat:#"%.1f problem%d",num,(num*10)%10];
[array indexOfObject:str];
You can get fancier using NSPredicates as well.
Try
NSString *searchString = [str stringByAppendingFormat: #" problem%#", [str substringFromIndex: 2]];
NSUInteger index = [array indexOfObject: searchString];
Or (because you somehow like oneliners):
[array indexOfObject: [[array filteredArrayUsingPredicate: [NSPredicate predicateWithFormat: #"SELF beginswith %#", str]] objectAtIndex: 0]];
The simplest way is to enumerate through values of array and check substrings:
NSArray *array = [NSArray arrayWithObjects: #"1.1 something", #"1.2 something else", #"1.3 out of left field", #"1.4 yet another!", nil];
NSString *str = #"1.33";
int i = -1;
int index = -1;
for (NSString *arrayString in array) {
i++;
if ([arrayString rangeOfString: str].location != NSNotFound) {
index = i;
break;
}
}
NSLog(#"Index: %d", index);
Not optimal but will work.

NSString to NSArray

I want to split an NSString into an NSArray. For example, given:
NSString *myString=#"ABCDEF";
I want an NSArray like:
NSArray *myArray={A,B,C,D,E,F};
How to do this with Objective-C and Cocoa?
NSMutableArray *letterArray = [NSMutableArray array];
NSString *letters = #"ABCDEF𝍱क्";
[letters enumerateSubstringsInRange:NSMakeRange(0, [letters length])
options:(NSStringEnumerationByComposedCharacterSequences)
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
[letterArray addObject:substring];
}];
for (NSString *i in letterArray){
NSLog(#"%#",i);
}
results in
A
B
C
D
E
F
𝍱
क्
enumerateSubstringsInRange:options:usingBlock: available for iOS 4+ can enumerate a string with different styles. One is called NSStringEnumerationByComposedCharacterSequences, what will enumerate letter by letter but is sensitive to surrogate pairs, base characters plus combining marks, Hangul jamo, and Indic consonant clusters, all referred as Composed Character
Note, that the accepted answer "swallows" 𝍱and breaks क् into क and ्.
Conversion
NSString * string = #"A B C D E F";
NSArray * array = [string componentsSeparatedByString:#" "];
//Notice that in this case I separated the objects by a space because that's the way they are separated in the string
Logging
NSLog(#"%#", array);
This is what the console returned
NSMutableArray *chars = [[NSMutableArray alloc] initWithCapacity:[theString length]];
for (int i=0; i < [theString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%C", [theString characterAtIndex:i]];
[chars addObject:ichar];
}
This link contains examples to split a string into a array based on sub strings and also based on strings in a character set. I hope that post may help you.
here is the code snip
NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%c", [myString characterAtIndex:i]];
[characters addObject:ichar];
}
Without loop you can use this:
NSString *myString = #"ABCDEF";
NSMutableString *tempStr =[[NSMutableString alloc] initWithString:myString];
if([myString length] != 0)
{
NSError *error = NULL;
// declare regular expression object
NSRegularExpression *regex =[NSRegularExpression regularExpressionWithPattern:#"(.)" options:NSMatchingReportCompletion error:&error];
// replace each match with matches character + <space> e.g. 'A' with 'A '
[regex replaceMatchesInString:tempStr options:NSMatchingReportCompletion range:NSMakeRange(0,[myString length]) withTemplate:#"$0 "];
// trim last <space> character
[tempStr replaceCharactersInRange:NSMakeRange([tempStr length] - 1, 1) withString:#""];
// split into array
NSArray * arr = [tempStr componentsSeparatedByString:#" "];
// print
NSLog(#"%#",arr);
}
This solution append space in front of each character with the help of regular expression and uses componentsSeparatedByString with <space> to return an array
Swift 4.2:
String to Array
let list = "Karin, Carrie, David"
let listItems = list.components(separatedBy: ", ")
Output : ["Karin", "Carrie", "David"]
Array to String
let list = ["Karin", "Carrie", "David"]
let listStr = list.joined(separator: ", ")
Output : "Karin, Carrie, David"
In Swift, this becomes very simple.
Swift 3:
myString.characters.map { String($0) }
Swift 4:
myString.map { String($0) }

convert a char to string

my code works great until know and, if I put a double digit number into the text field (like 12) nslog returns 2 single digit numbers (like 1 and 2). Now I need to put these 2 single digit numbers into 2 strings. can somebody help me. thanks in advance.
NSString *depositOverTotalRwy = [NSString stringWithFormat:#"%#", [deposit text]];
NSArray *components = [depositOverTotalRwy
componentsSeparatedByString:#"/"];
NSString *firstThird = [components objectAtIndex:0];
for(int i = 0; i < [firstThird length]; i++)
{
char extractedChar = [firstThird characterAtIndex:i];
NSLog(#"%c", extractedChar);
}
You should be able to use -stringWithFormat:.
NSString *s = [NSString stringWithFormat:#"%c", extractedChar];
EDIT:
You can store them in an array.
NSMutableArray *digits = [NSMutableArray array];
for ( int i = 0; i < [s length]; i++ ) {
char extractedChar = [s characterAtIndex:i];
[digits addObject:[NSString stringWithFormat:#"%c", extractedChar]];
}
Try to print the value of firstThird using NSLog(), see what it exactly hold, you code seem correct,
Use characterAtIndex function for NSString to extract a character at known location
- (unichar)characterAtIndex:(NSUInteger)index
Use as below
NSString *FirstDigit = [NSString stringWithFormat:#"%c", [myString characterAtIndex:0]];
NSString *SecondDigit = [NSString stringWithFormat:#"%c", [myString characterAtIndex:1]];

NSMutableArray of Objects

First off I am very new to Objective C and iPhone programming. Now that that is out of the way. I have read through most of the Apple documentation on this and some third party manuals.
I guess I just want to know if I'm going about this the correct way ...
- (NSMutableArray *)makeModel {
NSString *api = #"http://www.mycoolnewssite.com/api/v1";
NSArray *namesArray = [NSArray arrayWithObjects:#"News", #"Sports", #"Entertainment", #"Business", #"Features", nil];
NSArray *urlsArray = [NSArray arrayWithObjects:
[NSString stringWithFormat:#"%#/news/news/25/stories.json", api],
[NSString stringWithFormat:#"%#/news/sports/25/stories.json", api],
[NSString stringWithFormat:#"%#/news/entertainment/25/stories.json", api],
[NSString stringWithFormat:#"%#/news/business/25/stories.json", api],
[NSString stringWithFormat:#"%#/news/features/25/stories.json", api], nil];
NSMutableArray *result = [NSMutableArray array];
for (int i = 0; i < [namesArray count]; i++) {
NSMutableDictionary *objectDict = [NSMutableDictionary dictionary];
NSString *name = (NSString *)[namesArray objectAtIndex:i];
NSString *url = (NSString *)[urlsArray objectAtIndex:i];
[objectDict setObject:name forKey:#"NAME"];
[objectDict setObject:url forKey:#"URL"];
[objectDict setObject:#"NO" forKey:#"HASSTORIES"];
[result addObject:objectDict];
}
return result;
}
The output of the result is ...
(
{
HASSTORIES = NO;
NAME = News;
URL = "http://www.mycoolnewssite.com/api/v1/news/news/25/stories.json";
},
{
HASSTORIES = NO;
NAME = Sports;
URL = "http://www.mycoolnewssite.com/api/v1/news/sports/25/stories.json";
},
{
HASSTORIES = NO;
NAME = Entertainment;
URL = "http://www.mycoolnewssite.com/api/v1/news/entertainment/25/stories.json";
},
{
HASSTORIES = NO;
NAME = Business;
URL = "http://www.mycoolnewssite.com/api/v1/news/business/25/stories.json";
},
{
HASSTORIES = NO;
NAME = Features;
URL = "http://www.mycoolnewssite.com/api/v1/news/features/25/stories.json";
}
)
Any insight would be appreciated ;-)
It looks fine. There can be some minor improvements if you care.
1.
[NSString stringWithFormat:#"%#/news/news/25/stories.json", api]
can be replaced by
[api stringByAppendingString:#"/news/news/25/stories.json"]
if there's no chance the api appears in the middle or accepts other arguments.
2.
NSString *name = (NSString *)[namesArray objectAtIndex:i];
NSString *url = (NSString *)[urlsArray objectAtIndex:i];
The explicit cast is unnecessary. An id can be implicitly casted to and from other ObjC objects.
3.
You could use a convenient method -dictionaryWithObjectsAndKeys: to construct the dictionary in one-shot, so you don't need a temperary dictionary:
[result addObject:[NSMutableDictionary dictionaryWithObjectsAndKeys:
name, #"NAME",
url, #"URL",
#"NO", #"HASSTORIES", nil]];
4. (optional)
This transform is not useful if the function is not a hot spot.
Since the arrays are only used locally, it's more efficient to use a C array.
static const int arraySize = 5;
NSString* namesCArray[] = {#"News", #"Sports", #"Entertainment", #"Business", #"Features"};
NSString* urlsCArray[arraySize];
urlsArray[0] = [api stringByAppendingString:#"/news/news/25/stories.json"];
...
for (int i = 0; i < arraySize; ++ i) {
...
NSString* name = namesCArray[i];
NSString* url = urlsCArray[i];
...
}
this removes the repeated -count and -objectAtIndex: calls which is very slow compared with direct element access.
5. (optional)
This transform is not useful if the array is short.
You could use fast-enumeration to loop over an ObjC container:
int i = 0;
for (NSString* name in namesArray) {
NSString* url = [urlsArray objectAtIndex:i];
...
++ i;
}
6.
Usually we use [NSNumber numberWithBool:NO] to represent a boxed true/false value, instead of a string #"NO". NSNumber is also used a lot whenever a primitive number (int, float, etc.) cannot be used (e.g. to be stored in an NSArray). I don't know if your API explicitly requires a string NO, so it may not unsuitable for you.