NSString to NSArray - iphone

Question

I want to split an NSString into an NSArray. For example, given:
NSString *myString=#"ABCDEF";
I want an NSArray like:
NSArray *myArray={A,B,C,D,E,F};
How to do this with Objective-C and Cocoa?

Answer 1

NSMutableArray *letterArray = [NSMutableArray array];
NSString *letters = #"ABCDEF𝍱क्";
[letters enumerateSubstringsInRange:NSMakeRange(0, [letters length])
options:(NSStringEnumerationByComposedCharacterSequences)
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
[letterArray addObject:substring];
}];
for (NSString *i in letterArray){
NSLog(#"%#",i);
}
results in
A
B
C
D
E
F
𝍱
क्
enumerateSubstringsInRange:options:usingBlock: available for iOS 4+ can enumerate a string with different styles. One is called NSStringEnumerationByComposedCharacterSequences, what will enumerate letter by letter but is sensitive to surrogate pairs, base characters plus combining marks, Hangul jamo, and Indic consonant clusters, all referred as Composed Character
Note, that the accepted answer "swallows" 𝍱and breaks क् into क and ्.

Answer 2

Conversion
NSString * string = #"A B C D E F";
NSArray * array = [string componentsSeparatedByString:#" "];
//Notice that in this case I separated the objects by a space because that's the way they are separated in the string
Logging
NSLog(#"%#", array);
This is what the console returned

Answer 3

NSMutableArray *chars = [[NSMutableArray alloc] initWithCapacity:[theString length]];
for (int i=0; i < [theString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%C", [theString characterAtIndex:i]];
[chars addObject:ichar];
}

Answer 4

This link contains examples to split a string into a array based on sub strings and also based on strings in a character set. I hope that post may help you.
here is the code snip
NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%c", [myString characterAtIndex:i]];
[characters addObject:ichar];
}

Answer 5

Without loop you can use this:
NSString *myString = #"ABCDEF";
NSMutableString *tempStr =[[NSMutableString alloc] initWithString:myString];
if([myString length] != 0)
{
NSError *error = NULL;
// declare regular expression object
NSRegularExpression *regex =[NSRegularExpression regularExpressionWithPattern:#"(.)" options:NSMatchingReportCompletion error:&error];
// replace each match with matches character + <space> e.g. 'A' with 'A '
[regex replaceMatchesInString:tempStr options:NSMatchingReportCompletion range:NSMakeRange(0,[myString length]) withTemplate:#"$0 "];
// trim last <space> character
[tempStr replaceCharactersInRange:NSMakeRange([tempStr length] - 1, 1) withString:#""];
// split into array
NSArray * arr = [tempStr componentsSeparatedByString:#" "];
// print
NSLog(#"%#",arr);
}
This solution append space in front of each character with the help of regular expression and uses componentsSeparatedByString with <space> to return an array

Answer 6

Swift 4.2:
String to Array
let list = "Karin, Carrie, David"
let listItems = list.components(separatedBy: ", ")
Output : ["Karin", "Carrie", "David"]
Array to String
let list = ["Karin", "Carrie", "David"]
let listStr = list.joined(separator: ", ")
Output : "Karin, Carrie, David"

Answer 7

In Swift, this becomes very simple.
Swift 3:
myString.characters.map { String($0) }
Swift 4:
myString.map { String($0) }