my code works great until know and, if I put a double digit number into the text field (like 12) nslog returns 2 single digit numbers (like 1 and 2). Now I need to put these 2 single digit numbers into 2 strings. can somebody help me. thanks in advance.
NSString *depositOverTotalRwy = [NSString stringWithFormat:#"%#", [deposit text]];
NSArray *components = [depositOverTotalRwy
componentsSeparatedByString:#"/"];
NSString *firstThird = [components objectAtIndex:0];
for(int i = 0; i < [firstThird length]; i++)
{
char extractedChar = [firstThird characterAtIndex:i];
NSLog(#"%c", extractedChar);
}
You should be able to use -stringWithFormat:.
NSString *s = [NSString stringWithFormat:#"%c", extractedChar];
EDIT:
You can store them in an array.
NSMutableArray *digits = [NSMutableArray array];
for ( int i = 0; i < [s length]; i++ ) {
char extractedChar = [s characterAtIndex:i];
[digits addObject:[NSString stringWithFormat:#"%c", extractedChar]];
}
Try to print the value of firstThird using NSLog(), see what it exactly hold, you code seem correct,
Use characterAtIndex function for NSString to extract a character at known location
- (unichar)characterAtIndex:(NSUInteger)index
Use as below
NSString *FirstDigit = [NSString stringWithFormat:#"%c", [myString characterAtIndex:0]];
NSString *SecondDigit = [NSString stringWithFormat:#"%c", [myString characterAtIndex:1]];
Related
I'm new to iPhone development, I want to convert a string to hex format.
For example 00A400024F01 to 0x00,0xA4,0x00,0x02,0x4F,0x01 I guess I should start by dividing the string and then convert the grouped value. I don't know how to do that.
u just found answer from this stackoverflow question:-
How to convert an NSString to hex values
+ (NSString *) stringToHex:(NSString *)str
{
NSUInteger len = [str length];
unichar *chars = malloc(len * sizeof(unichar));
[str getCharacters:chars];
NSMutableString *hexString = [[NSMutableString alloc] init];
for(NSUInteger i = 0; i < len; i++ )
{
// [hexString [NSString stringWithFormat:#"%02x", chars[i]]]; /*previous input*/
[hexString appendFormat:#"%02x", chars[i]]; /*EDITED PER COMMENT BELOW*/
}
free(chars);
return [hexString autorelease];
}
UPDATE
You can divide one sting on to two string using below method:-
NSString * mystring = #"Hello,How are you";// suppos your string like that
NSArray * array = [mystring componentsSeparatedByString:#","];
NSString * str1 = [array objectAtIndex:0]; //Hello
NSString * str2 = [array objectAtIndex:1]; //How are you
and if you want to murge two string in to one string like :-
NSString *str1=#"hi Sweet Lady";
NSString *str2=#"How are you";
NSString *mainstr=[NSString stringWithFormat:#"%# %#",str1,str2];
Output is ==== hi Sweet Lady How are you
how can I display 5 raise to 1/3 in iphone i.e I want 1/3 written above 5 can anyone help please
I Found this solution, hope so it would be helpful for you.
x to the power of y in a UILabel could be easy. Just replace your indices with unicode superscript characters... I use the following method to turn an integer into a string with superscript characters.
+(NSString *)convertIntToSuperscript:(int)i
{
NSArray *array = [[NSArray alloc] initWithObjects:#"⁰", #"¹", #"²", #"³", #"⁴", #"⁵", #"⁶", #"⁷", #"⁸", #"⁹", nil];
if (i >= 0 && i <= 9) {
NSString *myString = [NSString stringWithFormat:#"%#", [array objectAtIndex:i]];
[array release];
return myString;
}
else {
NSString *base = [NSString stringWithFormat:#"%i", i];
NSMutableString *newString = [[NSMutableString alloc] init];
for (int b = 0; b<[base length]; b++) {
int temp = [[base substringWithRange:NSMakeRange(b, 1)] intValue];
[newString appendString:[array objectAtIndex:temp]];
}
[array release];
NSString *returnString = [NSString stringWithString:newString];
[newString release];
return returnString;
}
}
Try this NSString *cmsquare=#"cm\u00B2";
It will display cm².
Yes you can do that but you need custom UILabel, either Make it by yourself or Get it Open Source..
I got some weird issue here. The code is as below
NSMutableString *unicodeString = [NSMutableString string];
for (NSUInteger i = 0; i < [data length]; i++) {
unsigned char byte;
[data getBytes:&byte range:NSMakeRange(i, 1)];
unichar unicodeChar = byte;
NSString *appendString = [NSString stringWithFormat:#"%C",[_toUnicode unicharFromCIDString:unicodeChar]];
[unicodeString appendFormat:#"%#",appendString];
NSLog(#"%#",appendString); //1
}
NSLog(#"%#",unicodeString)//2
the appendString print, but unicodeString never print. Is this because of bytes issue?? I have tried retain appendString but it still won't print
*UPDATED found the answer
An other way :
NSString *appendString = [NSString stringWithCharacters:&unicodeChar length:1];
[unicodeString appendFormat:#"%#", appendString];
I have found that the problem is %C is for 16bit unichar so If I want to append to NSString I have to use %c which is 8bit. This works perfectly.
NSString *appendString = [NSString stringWithFormat:#"%c",[_toUnicode unicharFromCIDString:unicodeChar]];
[unicodeString appendFormat:#"%#",appendString];
I need to convert a hex string to binary form in objective-c, Could someone please guide me?
For example if i have a hex string 7fefff78, i want to convert it to 1111111111011111111111101111000?
BR,
Suppi
Nice recursive solution...
NSString *hex = #"49cf3e";
NSUInteger hexAsInt;
[[NSScanner scannerWithString:hex] scanHexInt:&hexAsInt];
NSString *binary = [NSString stringWithFormat:#"%#", [self toBinary:hexAsInt]];
-(NSString *)toBinary:(NSUInteger)input
{
if (input == 1 || input == 0)
return [NSString stringWithFormat:#"%u", input];
return [NSString stringWithFormat:#"%#%u", [self toBinary:input / 2], input % 2];
}
Simply convert each digit one by one: 0 -> 0000, 7 -> 0111, F -> 1111, etc. A little lookup table could make this very concise.
The beauty of number bases that are powers of another base :-)
In case you need leading zeros, for example 18 returns 00011000 instead of 11000
-(NSString *)toBinary:(NSUInteger)input strLength:(int)length{
if (input == 1 || input == 0){
NSString *str=[NSString stringWithFormat:#"%u", input];
return str;
}
else {
NSString *str=[NSString stringWithFormat:#"%#%u", [self toBinary:input / 2 strLength:0], input % 2];
if(length>0){
int reqInt = length * 4;
for(int i= [str length];i < reqInt;i++){
str=[NSString stringWithFormat:#"%#%#",#"0",str];
}
}
return str;
}
}
NSString *hex = #"58";
NSUInteger hexAsInt;
[[NSScanner scannerWithString:hex] scanHexInt:&hexAsInt];
NSString *binary = [NSString stringWithFormat:#"%#", [self toBinary:hexAsInt strLength:[hex length]]];
NSLog(#"binario %#",binary);
I agree with kerrek SB's answer and tried this.
Its work for me.
+(NSString *)convertBinaryToHex:(NSString *) strBinary
{
NSString *strResult = #"";
NSDictionary *dictBinToHax = [[NSDictionary alloc] initWithObjectsAndKeys:
#"0",#"0000",
#"1",#"0001",
#"2",#"0010",
#"3",#"0011",
#"4",#"0100",
#"5",#"0101",
#"6",#"0110",
#"7",#"0111",
#"8",#"1000",
#"9",#"1001",
#"A",#"1010",
#"B",#"1011",
#"C",#"1100",
#"D",#"1101",
#"E",#"1110",
#"F",#"1111", nil];
for (int i = 0;i < [strBinary length]; i+=4)
{
NSString *strBinaryKey = [strBinary substringWithRange: NSMakeRange(i, 4)];
strResult = [NSString stringWithFormat:#"%#%#",strResult,[dictBinToHax valueForKey:strBinaryKey]];
}
return strResult;
}
i have for exemple "My String" i want to extract the first character .
String *_initialeStr = self.carte.Titre ;
originalCarte.Init = memmove(_initialeStr , _initialeStr+1,length(_initialeStr));
NSString has characterAtIndex: method where you can pass 0 as index...
Use characterAtIndex: from NSString class.
- (unichar)characterAtIndex:(NSUInteger)index
Use as below .
NSString *temp = #"Hello world";
unichar myCharacter = [temp characterAtIndex:0];
That doesn't even look like Objective-C.
Having a property named Init is quite confusing and what is String?
Perhaps this is what you want:
NSString *initialString = self.carte.titre;
originalCarte.initialLetter = [initialString characterAtIndex:0];
This outputs the first character of myString:
NSString *myString = #"The text I want to access.";
NSMutableArray *myArray = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for ( i = 0; i < [myString length]; i++ )
[myArray addObject:[NSNumber numberWithChar:[myString characterAtIndex:i]]];
NSLog( #"First character: %c", [[myArray objectAtIndex:0] charValue] );