I am using Objective-C within X-code.
I am iterating through a dictionary which contains a date value as one of it's keys. All I want to do is get an array of all the distinct dates so I can use them in a table, as headers. I just plan on
iterating the dictionary and adding dates to a mutable array each time I encounter a new date.
I must set previous date to new date for comparisons to work and I am having a very difficult time figuring out how to set one date equal to another date.
This seems like it should be such a simple thing to do and I am trying to avoid converting the dates to strings first - but if that's what I have to do, then so be it.
Any help would be appreciated.
Thanks,
Gerry O.
If you know the time offset is same as GMT, you could do it by dividing the date's timestamp by 86400 seconds (or three more 0s in milliseconds) and comparing those. If a time offset is there, add or subtract by 3600 seconds per hour before you divide them. But then again, leap years and seconds would break that...
Most languages have libraries support extracting the year, date, month, etc. They take everything into account, usually.
In Objc, you can get a NSDateComponents from NSCalendar's components:fromDate: method. After this, you can call the components to see exactly what each component (I suggest year, month, day) is.
I think you want code to compare dates and You need two loops nested.... where in outer loops iterates with conditional inner loop... In inner loop you just check that previously you had the same date or not...
please go through the below post on same site...
How to compare two dates in Objective-C
hope you will get solution... else clarify your question....
Related
I am working on a large nested IF statement that checks several validation points for each row of my sheet. There are several date validations, including chronological order and certain fields not being future dates. However, our system requires that if we must null any dates for processing, that date becomes 1/1/2500, and no matter what I do I cannot seem to get the formula to ignore this date when accounting for future dates or chronology.
//The date cannot be later than the current date - I want this to ignore 1/1/2500
IF(K1<>1/1/2500,"",IF(AND(K1>TODAY()),"Date A cannot be future date",""))
//The two dates must be in chronological order, also ignoring 1/1/2500
IF(U1<>1/1/2500,"",IF(AND(U1>AA1,AA1),"Date A, Date B should be in chronological order",""))
The above approach does not seem to recognize 1/1/2500, even though I got it to work with other dates.
I also tried going with >12/31/2099 (ignore any date greater than 12/31/2099) but it just ignores every date.
Any help would be appreciated.
It looks as though it is failing because K1 is compared to 12/31/2099.
If you use an expression like this in a formula, it will interpret it as an arithmetic expression 12 divided by 31 divided by 2099, which is a very small number, so the greater than test will always be true.
Try starting the formula with Date to convert a year, month, and day into a date.
If(K1>date(2099,12,31)
and you should get the right answer.
See my previous answer for Excel.
Here I'm saving the date range using golang. Suppose we have to save the all monday comes between the range of the 1-may-2018 to 14-july-2018.
How we will find all the monday between these range using golang and on the other hand we have set the start_time (8:00 A.M.) and the end_time (6:00 P.M.) of the first two coming monday in the database but on the third monday we have a change in the schedule that there is a time change like start_time (9:00 A.M.) and end_time (5:00 P.M.). Then how I will make my database to make this situation in practically using the golang.
Can Anybody help me for this to solve this solution. I made a database for and I do ppr work on it and make some fields shown below:-
Fields for Schedule //Schedule is a collection name
Id (int)
Day (string)
Start_hours (int)
Start_minutes (int)
End_hours (int)
End_minutes (int)
Start_date (timestamp)
End_date (timestamp)
How I will select monday between the selected range and how will I do the situation I explained above can anybody give guidance to me to make this situation easier. Thank you if this is a basic question then I'm really sorry.
I'd make something like this.
Find the first Monday date from the date range (see for example How do I get the first Monday of a given month in Go?
Mondays happen every week, so you can easily find the rest of dates by adding 7 days till the end date
Store all the Monday dates you found with the start and end times
I wouldn't bother with hours and minutes as you can easily get them from the timestamps in Go. Here is the simplified DB structure I would make
Fields for Schedule //Schedule is a collection name
Id (int)
Day (string)
Date (timestamp) // the actual date
Start (timestamp)
End (timestamp)
You don't need any more fields. You can get the day of the week (Day (string) in your structure, e.g. Monday) from the Date field too, but I believe if you want to query the collection by different days, this might speed things up, but be careful if you need to adjust for time zones. If you work with more than one, then store everything in UTC and you may have an extra filed Timezone, cos a date could be Monday for one zone and Sunday for another.
So, the Schedule will hold weekdays and start and end times for each of them. I'm not sure if you need to store initial date ranges, the Schedule collection will hold that range as well, form the first record to the last one. In my mind, I'd initially populate the collection with a given date range, then later on, I can modify it by adding new days, or deleting them.
When you query this collection with some start and end date range for the Date field, if your first result comes newer than 7 days from the start, this means you miss 1 or more entries from the start. If the last result comes older than 7 days from the range end, this means you miss some entries prior to the range end.
There is nothing specific to Go, in my opinion, Go works well with dates and you don't need any special date structures in your DB.
I have a quick question regarding handling of dates and times in 800xA.
What I´m trying to do is to take the current date, add/subtract days and save the result to a new variable.
I´m currently using "Date_and_timetocalendarstruct", to split the current date down to "current year", "current month", "current week" and so on.
I want to work it like this :
for example : take the current date and subtract it by one (or any other number) and thus, generating a new date to store away for future use.
This particular scenario is in ABB,s 800xA systems and its configured against a AC 800M controller.
I have tried a couple of things so for, regarding applying arithmetic operations to dates, but without success.
I hope someone here could point me in the right direction.
Thanks in advance
I think what you missed is the time data type.
date_and_time is used for a Calendar type of Data while time is a time span, e.g. a number of days.
What I understand you want to calculate is (in ST, but works in FBD as well):
OutDate := sub( InDate, Days);
Where OutDate and InDate are of Type date_and_time and Days is time.
If you specify Days with Value 5d, you will get OutDate as 5 days before InDate.
In a similar way, you will get a time span (type time) as output when subtracting two date_and_time values!
I have found similar help, but the issue was more complex, I am only good with the basics of SQL and am striking out here. I get a handful of columns a,b,c,startdate,enddate and i need to parse that data out into multiple rows depending on how many months are within the range.
Eg: a,b,c,1/1/2015, 3/15,2015 would become:
a,b,c,1/1/2015,value_here_doesnt_matter
a,b,c,2/1/2015,value_here_doesnt_matter
a,b,c,3/1/2015,value_here_doesnt_matter
Does not matter if the start date or end date is on a specific day, the only thing that matters is month and year. So if the range included any day in a given month, I'd want to output start days for each month in the range, with the 1st as a default day.
Could I have any advice on which direction to begin? I'm attempting generate_series, but am unsure if this is the right approach or how to make it work with keeping the data in the first few arbitrary columns consistent.
I think generate_series is the way to go. Without knowing what the rest of your data looks like, I would start with something like this:
select
a, b, c, generate_series(startdate, enddate, interval '1 month')::date
from
my_table
I want to calculate the number of days passed between past date and a current date. My past date is in the format dd/mm/yyyy format. I have used below mentioned formulas but giving the proper output.
=DAYS360(A2,TODAY())
=MINUS(D2,TODAY())
In the above formula A2 = 4/12/2012 (dd/mm/yyyy) and I am not sure whether TODAY returns in dd/mm/yyyy format or not. I have tried using 123 button on the tool bar, but no luck.
The following seemed to work well for me:
=DATEDIF(B2, Today(), "D")
DAYS360 does not calculate what you want, i.e. the number of days passed between the two dates – see the end of this post for details.
MINUS() should work fine, just not how you tried but the other way round:
=MINUS(TODAY(),D2)
You may also use simple subtraction (-):
=TODAY()-D2
I made an updated copy of #DrCord’s sample spreadsheet to illustrate this.
Are you SURE you want DAYS360? That is a specialized function used in the
financial sector to simplify calculations for bonds. It assumes a 360 day
year, with 12 months of 30 days each. If you really want actual days, you'll
lose 6 days each year.
[source]
Since this is the top Google answer for this, and it was way easier than I expected, here is the simple answer. Just subtract date1 from date2.
If this is your spreadsheet dates
A B
1 10/11/2017 12/1/2017
=(B1)-(A1)
results in 51, which is the number of days between a past date and a current date in Google spreadsheet
As long as it is a date format Google Sheets recognizes, you can directly subtract them and it will be correct.
To do it for a current date, just use the =TODAY() function.
=TODAY()-A1
While today works great, you can't use a date directly in the formula, you should referencing a cell that contains a date.
=(12/1/2017)-(10/1/2017) results in 0.0009915716411, not 61.
I used your idea, and found the difference and then just divided by 365 days. Worked a treat.
=MINUS(F2,TODAY())/365
Then I shifted my cell properties to not display decimals.
If you are using the two formulas at the same time, it will not work...
Here is a simple spreadsheet with it working:
https://docs.google.com/spreadsheet/ccc?key=0AiOy0YDBXjt4dDJSQWg1Qlp6TEw5SzNqZENGOWgwbGc
If you are still getting problems I would need to know what type of erroneous result you are getting.
Today() returns a numeric integer value: Returns the current computer system date. The value is updated when your document recalculates. TODAY is a function without arguments.
The following worked for me. Kindly note that TODAY() must NOT be the first argument in the function otherwise it will not work.
=DATEDIF( W2, TODAY(), "d")
Today() does return value in DATE format.
Select your "Days left field" and paste this formula in the field
=DAYS360(today(),C2)
Go to Format > Number > More formats >Custom number format and select the number with no decimal numbers.
I tested, it works, at least in new version of Sheets, March 2015.