I have a quick question regarding handling of dates and times in 800xA.
What I´m trying to do is to take the current date, add/subtract days and save the result to a new variable.
I´m currently using "Date_and_timetocalendarstruct", to split the current date down to "current year", "current month", "current week" and so on.
I want to work it like this :
for example : take the current date and subtract it by one (or any other number) and thus, generating a new date to store away for future use.
This particular scenario is in ABB,s 800xA systems and its configured against a AC 800M controller.
I have tried a couple of things so for, regarding applying arithmetic operations to dates, but without success.
I hope someone here could point me in the right direction.
Thanks in advance
I think what you missed is the time data type.
date_and_time is used for a Calendar type of Data while time is a time span, e.g. a number of days.
What I understand you want to calculate is (in ST, but works in FBD as well):
OutDate := sub( InDate, Days);
Where OutDate and InDate are of Type date_and_time and Days is time.
If you specify Days with Value 5d, you will get OutDate as 5 days before InDate.
In a similar way, you will get a time span (type time) as output when subtracting two date_and_time values!
Related
I am working with overnight data (in particular I am concerned about the hours 6PM-6AM). I want this time frame to count as “day 1” for my study. My problem is that the date changes at midnight. Can anyone recommend code to reassign the time-frames that I am concerned about as “day1, day 2, etc.” instead of the Julian date. I am new to this so any suggestions would be very much appreciated!
*Update, here is a screenshot of the data I am working with. So, the column on the left is the julian date.. in this example I am looking at day 305 and 306 and the hours 18:20 (305) to 6:20 (306). I want these hours to be classified as day 1, instead of the date changing at midnight. Also, I need to get rid of the random date that is attached to my time column. I'm sure there is an easy way to do that, but if anyone knows off the top of your head I'd appreciate that!
Again, I'm very new to R and coding language, please be gentle!
Thanks a million.
You didn't mention what language you're using.
Given timespans 6pm to 6am, I believe the simplest solution would be to decrement 7 hours from any given date - then all of your timestamps would have the start day of the timespan as their day component.
Could someone please explain me creating BINS based on Weekdays in Tableau? I tried creating different Calculation Fields but it won't work
You're working too hard.
Tableau already knows how to bin values by dates at many levels of granualarity: such as year, month, day, weekday, hour etc. So you don't need to create a new field to bin dates by the day of the week. (creating bins is not difficult, it's just already available in this case)
Just put a discrete (blue) date or datetime field on a shelf. You'll see the date level of granularity displayed like, say, YEAR(MyDateField) with a leading plus sign.
You can either
click on the plus sign to drill down by adding a second level, say MONTH(MyDateField)
or
right click on the field to select the date level of granularity you want
Alex's Answer is exactly correct, Tableau will perform the operation automatically. What is great about is that you can select various formats (Full day name, number, 1 letter or 3 letter day etc.).
However if you absolutely need to you can used this formula:
datepart('weekday',[Date])
to give you the 1 (Sunday) to 7 (Saturday) value if you need it for something other reason, say another calculation.
I am having trouble grouping certain results in a work in progress report that arranges by start date, I have grouped using fixed values before but because the dates keep moving I am unsure what to do.
The start date is WIP_Schedule.Start_Date
the groups I am trying to create are:
[Group1] Overdue = the current date has passed the start date.
[Group2] (Yet to be named) = the current date 2 week period prior to the start date
[Group3] To Do = the current date after the two week period prior to the start date.
I am after a works instruction on how to achieve this.
I know this isn't a lot of information, if you require any more please ask.
Thanks,
Daniel
This is a pretty straightforward requirement, so you should be able to figure it out by searching the web. However, I'll give you part of the answer and hopefully you can figure it out.
Start by creating a formula to figure out the status of the date.
If {WIP_Schedule.Start_Date} > current date then "Overdue"
Else......
Then you can group based on that formula. All you have to do is figure out the rest of the formula.
I want to calculate the number of days passed between past date and a current date. My past date is in the format dd/mm/yyyy format. I have used below mentioned formulas but giving the proper output.
=DAYS360(A2,TODAY())
=MINUS(D2,TODAY())
In the above formula A2 = 4/12/2012 (dd/mm/yyyy) and I am not sure whether TODAY returns in dd/mm/yyyy format or not. I have tried using 123 button on the tool bar, but no luck.
The following seemed to work well for me:
=DATEDIF(B2, Today(), "D")
DAYS360 does not calculate what you want, i.e. the number of days passed between the two dates – see the end of this post for details.
MINUS() should work fine, just not how you tried but the other way round:
=MINUS(TODAY(),D2)
You may also use simple subtraction (-):
=TODAY()-D2
I made an updated copy of #DrCord’s sample spreadsheet to illustrate this.
Are you SURE you want DAYS360? That is a specialized function used in the
financial sector to simplify calculations for bonds. It assumes a 360 day
year, with 12 months of 30 days each. If you really want actual days, you'll
lose 6 days each year.
[source]
Since this is the top Google answer for this, and it was way easier than I expected, here is the simple answer. Just subtract date1 from date2.
If this is your spreadsheet dates
A B
1 10/11/2017 12/1/2017
=(B1)-(A1)
results in 51, which is the number of days between a past date and a current date in Google spreadsheet
As long as it is a date format Google Sheets recognizes, you can directly subtract them and it will be correct.
To do it for a current date, just use the =TODAY() function.
=TODAY()-A1
While today works great, you can't use a date directly in the formula, you should referencing a cell that contains a date.
=(12/1/2017)-(10/1/2017) results in 0.0009915716411, not 61.
I used your idea, and found the difference and then just divided by 365 days. Worked a treat.
=MINUS(F2,TODAY())/365
Then I shifted my cell properties to not display decimals.
If you are using the two formulas at the same time, it will not work...
Here is a simple spreadsheet with it working:
https://docs.google.com/spreadsheet/ccc?key=0AiOy0YDBXjt4dDJSQWg1Qlp6TEw5SzNqZENGOWgwbGc
If you are still getting problems I would need to know what type of erroneous result you are getting.
Today() returns a numeric integer value: Returns the current computer system date. The value is updated when your document recalculates. TODAY is a function without arguments.
The following worked for me. Kindly note that TODAY() must NOT be the first argument in the function otherwise it will not work.
=DATEDIF( W2, TODAY(), "d")
Today() does return value in DATE format.
Select your "Days left field" and paste this formula in the field
=DAYS360(today(),C2)
Go to Format > Number > More formats >Custom number format and select the number with no decimal numbers.
I tested, it works, at least in new version of Sheets, March 2015.
I am using Objective-C within X-code.
I am iterating through a dictionary which contains a date value as one of it's keys. All I want to do is get an array of all the distinct dates so I can use them in a table, as headers. I just plan on
iterating the dictionary and adding dates to a mutable array each time I encounter a new date.
I must set previous date to new date for comparisons to work and I am having a very difficult time figuring out how to set one date equal to another date.
This seems like it should be such a simple thing to do and I am trying to avoid converting the dates to strings first - but if that's what I have to do, then so be it.
Any help would be appreciated.
Thanks,
Gerry O.
If you know the time offset is same as GMT, you could do it by dividing the date's timestamp by 86400 seconds (or three more 0s in milliseconds) and comparing those. If a time offset is there, add or subtract by 3600 seconds per hour before you divide them. But then again, leap years and seconds would break that...
Most languages have libraries support extracting the year, date, month, etc. They take everything into account, usually.
In Objc, you can get a NSDateComponents from NSCalendar's components:fromDate: method. After this, you can call the components to see exactly what each component (I suggest year, month, day) is.
I think you want code to compare dates and You need two loops nested.... where in outer loops iterates with conditional inner loop... In inner loop you just check that previously you had the same date or not...
please go through the below post on same site...
How to compare two dates in Objective-C
hope you will get solution... else clarify your question....