Google Sheets - IF Statement - Null date (1/1/2500) workaround - date

I am working on a large nested IF statement that checks several validation points for each row of my sheet. There are several date validations, including chronological order and certain fields not being future dates. However, our system requires that if we must null any dates for processing, that date becomes 1/1/2500, and no matter what I do I cannot seem to get the formula to ignore this date when accounting for future dates or chronology.
//The date cannot be later than the current date - I want this to ignore 1/1/2500
IF(K1<>1/1/2500,"",IF(AND(K1>TODAY()),"Date A cannot be future date",""))
//The two dates must be in chronological order, also ignoring 1/1/2500
IF(U1<>1/1/2500,"",IF(AND(U1>AA1,AA1),"Date A, Date B should be in chronological order",""))
The above approach does not seem to recognize 1/1/2500, even though I got it to work with other dates.
I also tried going with >12/31/2099 (ignore any date greater than 12/31/2099) but it just ignores every date.
Any help would be appreciated.

It looks as though it is failing because K1 is compared to 12/31/2099.
If you use an expression like this in a formula, it will interpret it as an arithmetic expression 12 divided by 31 divided by 2099, which is a very small number, so the greater than test will always be true.
Try starting the formula with Date to convert a year, month, and day into a date.
If(K1>date(2099,12,31)
and you should get the right answer.
See my previous answer for Excel.

Related

Why does RANDARRAY in Excel's "integer" parameter include dates that are outside of the directed min/max values?

In Excel, I am trying to create random dates based on three cell values:
Start Date
End Date
Size
Random Dates
2/1/2022
1/31/2023
10
Where "Random Dates" is populated with:
D1: =WORKDAY(RANDARRAY(10,1,A2,B2),1)
Using this formula returns dates within the range, as expected. However, when setting the Integer (I've also seen this called "whole_number") parameter of RANDARRAY to TRUE, it will sometimes select a date outside of the range (i.e., the next business date above the range). See:
D1: =WORKDAY(RANDARRAY(10,1,A2,B2,TRUE),1) Can (and sometimes does) return "2/1/2023" in the spill.
I've tried to look up why this may be for dates, because it doesn't react the same way with numbers. One thought is it has something to do with when it converts the dates selected to integers when INTEGER=TRUE, which may be because it's including time serials in the function somewhere? I'm not sure.
NOTE: "End Date" is not a weekend date and no holidays are used.
I also tried taking WORKDAY away, which doesn't add a date outside of the max value, with either TRUE or FALSE for INTEGER.
I then added type-casted the RANDARRAY as INT:
D1: =INT(RANDARRAY(10,1,A2,B2,TRUE)) which didn't seem to replicate the issue.
But when I added a 5th column with a WORKDAY function in each cell, it then added an additional day again:
E1: =WORKDAY(D1,1) filled down for each of the results.
As soon as I take the TRUE parameter out of cell D1, it goes back to even the values in column E calculating only within the range. This strikes me as Dates passed to RANDARRAY are potentially being calculated with MAX-1 instead of just the MAX provided when INTEGER=FALSE. Which seems like it would be strange behavior.

How to count number of days between two dates in SQL Developer?

I tried this way
select tv.reg_number, tv.make, tv.model, tev.date_taken,tev.date_return, count(tev.date_taken, tev.date_return) as day_difference
from table_vehicle tv, table_evehicle tev
where tv.reg_number=tev.reg_number
and tev.date_return is not null
group by tv.reg_number, tv.make, tv.model, tev.date_taken, tev.date_return;
Is anyone able to help me on this one?
Subtracting one date from another will yield the number of days between the two dates, so assuming both tev.date_taken and tev.date_return of the DATE data type, you can use tev.date_return - tev.date_taken as day_difference to get the number of days between the two dates. If tev.date_taken and/or tev.date_return contain a time components the returned number may include a fractional portion. If you don't want the fractional day, you can TRUNCate, ROUND or take the CEILing of the resulting value.
However, if either value is a TIMESTAMP the resulting value will be an INTERVAL data type. If this is the case, then you can either cast the TIMESTAMP values to DATE values, or EXTRACT(DAY FROM (tev.date_return - tev.date_taken)) as day_difference to get just the truncated numeric number of days between the two dates.

Number of days between past date and current date in Google spreadsheet

I want to calculate the number of days passed between past date and a current date. My past date is in the format dd/mm/yyyy format. I have used below mentioned formulas but giving the proper output.
=DAYS360(A2,TODAY())
=MINUS(D2,TODAY())
In the above formula A2 = 4/12/2012 (dd/mm/yyyy) and I am not sure whether TODAY returns in dd/mm/yyyy format or not. I have tried using 123 button on the tool bar, but no luck.
The following seemed to work well for me:
=DATEDIF(B2, Today(), "D")
DAYS360 does not calculate what you want, i.e. the number of days passed between the two dates – see the end of this post for details.
MINUS() should work fine, just not how you tried but the other way round:
=MINUS(TODAY(),D2)
You may also use simple subtraction (-):
=TODAY()-D2
I made an updated copy of #DrCord’s sample spreadsheet to illustrate this.
Are you SURE you want DAYS360? That is a specialized function used in the
financial sector to simplify calculations for bonds. It assumes a 360 day
year, with 12 months of 30 days each. If you really want actual days, you'll
lose 6 days each year.
[source]
Since this is the top Google answer for this, and it was way easier than I expected, here is the simple answer. Just subtract date1 from date2.
If this is your spreadsheet dates
A B
1 10/11/2017 12/1/2017
=(B1)-(A1)
results in 51, which is the number of days between a past date and a current date in Google spreadsheet
As long as it is a date format Google Sheets recognizes, you can directly subtract them and it will be correct.
To do it for a current date, just use the =TODAY() function.
=TODAY()-A1
While today works great, you can't use a date directly in the formula, you should referencing a cell that contains a date.
=(12/1/2017)-(10/1/2017) results in 0.0009915716411, not 61.
I used your idea, and found the difference and then just divided by 365 days. Worked a treat.
=MINUS(F2,TODAY())/365
Then I shifted my cell properties to not display decimals.
If you are using the two formulas at the same time, it will not work...
Here is a simple spreadsheet with it working:
https://docs.google.com/spreadsheet/ccc?key=0AiOy0YDBXjt4dDJSQWg1Qlp6TEw5SzNqZENGOWgwbGc
If you are still getting problems I would need to know what type of erroneous result you are getting.
Today() returns a numeric integer value: Returns the current computer system date. The value is updated when your document recalculates. TODAY is a function without arguments.
The following worked for me. Kindly note that TODAY() must NOT be the first argument in the function otherwise it will not work.
=DATEDIF( W2, TODAY(), "d")
Today() does return value in DATE format.
Select your "Days left field" and paste this formula in the field
=DAYS360(today(),C2)
Go to Format > Number > More formats >Custom number format and select the number with no decimal numbers.
I tested, it works, at least in new version of Sheets, March 2015.

Filter data by different time intervals

I need to filter my query with different time intervals like that:
...
where
date >= '2011-07-01' and date <='2011-09-30'
and date >='2012-07-01' and date >='2012-09-30'
I suppose such code is not good, because these dates conflicts with each other. But how to filter only these two intervals, skipping everything else? Is it even possible? Because if I query like this, I don't get any results.I tried to use BETWEEN, but it does same thing.
I bypassed this by extracting quarters from years and calculating only third quarter. But then other quarters sum is showed as zero and I can't ignore these rows that have sum column with zero value. I tried to filter where price > 0 (column where sum goes), but it says that column do not exist. So I put it whole FROM under '('')' brackets to make it calculate sum before where clause, but it still does give me error that such column do not exist.
Also if you need to see query I have now, I can post it, just tell me if it is needed.
I want to do this, because I need to compare third quarter of two different years (maybe I should use another approach).
You're not going to get any results because you can't have a date that's both within 7/1/2011 through 9/30/11 and after 7/1/2012 and after 9/30/12.
You can have a date that is either between 7/1/20122 and 9/30/2011 or between 7/1/2012 and 9/30/2012.
SELECT col1 FROM table1
WHERE date BETWEEN '7/1/2011' AND '9/30/2011' OR date BETWEEN '7/1/2012' AND '9/30/2012';

Set one date from another date

I am using Objective-C within X-code.
I am iterating through a dictionary which contains a date value as one of it's keys. All I want to do is get an array of all the distinct dates so I can use them in a table, as headers. I just plan on
iterating the dictionary and adding dates to a mutable array each time I encounter a new date.
I must set previous date to new date for comparisons to work and I am having a very difficult time figuring out how to set one date equal to another date.
This seems like it should be such a simple thing to do and I am trying to avoid converting the dates to strings first - but if that's what I have to do, then so be it.
Any help would be appreciated.
Thanks,
Gerry O.
If you know the time offset is same as GMT, you could do it by dividing the date's timestamp by 86400 seconds (or three more 0s in milliseconds) and comparing those. If a time offset is there, add or subtract by 3600 seconds per hour before you divide them. But then again, leap years and seconds would break that...
Most languages have libraries support extracting the year, date, month, etc. They take everything into account, usually.
In Objc, you can get a NSDateComponents from NSCalendar's components:fromDate: method. After this, you can call the components to see exactly what each component (I suggest year, month, day) is.
I think you want code to compare dates and You need two loops nested.... where in outer loops iterates with conditional inner loop... In inner loop you just check that previously you had the same date or not...
please go through the below post on same site...
How to compare two dates in Objective-C
hope you will get solution... else clarify your question....