I got some weird issue here. The code is as below
NSMutableString *unicodeString = [NSMutableString string];
for (NSUInteger i = 0; i < [data length]; i++) {
unsigned char byte;
[data getBytes:&byte range:NSMakeRange(i, 1)];
unichar unicodeChar = byte;
NSString *appendString = [NSString stringWithFormat:#"%C",[_toUnicode unicharFromCIDString:unicodeChar]];
[unicodeString appendFormat:#"%#",appendString];
NSLog(#"%#",appendString); //1
}
NSLog(#"%#",unicodeString)//2
the appendString print, but unicodeString never print. Is this because of bytes issue?? I have tried retain appendString but it still won't print
*UPDATED found the answer
An other way :
NSString *appendString = [NSString stringWithCharacters:&unicodeChar length:1];
[unicodeString appendFormat:#"%#", appendString];
I have found that the problem is %C is for 16bit unichar so If I want to append to NSString I have to use %c which is 8bit. This works perfectly.
NSString *appendString = [NSString stringWithFormat:#"%c",[_toUnicode unicharFromCIDString:unicodeChar]];
[unicodeString appendFormat:#"%#",appendString];
Related
I have an one hexa decimal number
535443326663315634524877795678586b536854535530342f44526a795744716133353942704359697a6b736e446953677171555473
I want to convert this number to ASCII format which will look like this
STC2fc1V4RHwyVxXkShTSU04/DRjyWDqa359BpCYizksnDiSgqqUTsYUOcHKHNMJOdqR1/TQywpD9a9xhri
i have seen solutions here but none of them is useful to me
NSString containing hex convert to ascii equivalent
i checked here but they give different result. Any help
This works perfectly
- (NSString *)stringFromHexString:(NSString *)hexString {
// The hex codes should all be two characters.
if (([hexString length] % 2) != 0)
return nil;
NSMutableString *string = [NSMutableString string];
for (NSInteger i = 0; i < [hexString length]; i += 2) {
NSString *hex = [hexString substringWithRange:NSMakeRange(i, 2)];
NSInteger decimalValue = 0;
sscanf([hex UTF8String], "%x", &decimalValue);
[string appendFormat:#"%c", decimalValue];
NSLog(#"string--%#",string);
}
_hexString1=string;
NSLog(#"string ---%#",_hexString1);
return string;
}
If you're starting with NSData * you could get the ASCII string this way:
NSData *someData = [NSData dataWithHexString:#"ABC123"];
NSString *asciiString = [[NSString alloc] initWithData: someData encoding:NSASCIIStringEncoding];
I have an int value which I obtained from the character 爸, which is 29240. I can convert this number to hex, but I have no clue how to write the chinese character out in an NSString with only the int 29240.
Basically, what I did was:
NSString * s = #"爸";
int a = [s characterAtIndex:0];
NSLog(#"%d", a);
What it gave as output was 29240.
However, I don't know how to create an NSString that just contains 爸 from only the int 29240.
I converted 29240 into binary which gave me 7238, but I can't seem to create a method which allows me to input any integer and NSLog the corresponding character.
I can hard code it in, so that I have
char cString[] = "\u7238";
NSData *data = [NSData dataWithBytes:cString length:strlen(cString)];
NSString *string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"result string: %#", string);
But I'm not sure how to do it with any int.
Thanks to anyone who can help me!
To create a string from one (or more) Unicode characters use initWithCharacters:
unichar c = 29240;
NSString *string = [[NSString alloc] initWithCharacters:&c length:1];
NSString uses UTF-16 characters internally, so
this works for all characters in the "Basic Multilingual Plane", i.e. all characters up to U+FFFF. The following code works for arbitrary characters:
uint32_t ch = 0x1F60E;
ch = OSSwapHostToLittleInt32(ch); // To make it byte-order safe
NSString *s1 = [[NSString alloc] initWithBytes:&ch length:4 encoding:NSUTF32LittleEndianStringEncoding];
NSLog(#"%#", s1);
// Output: 😎
Try out this code snippet to get you started in the right direction:
NSString *s = #"0123456789";
for (int i = 0; i < [s length]; i++) {
NSLog(#"Value: %d", [s characterAtIndex:i]);
}
Just pass in the character as an integer:
unichar decimal = 12298;
NSString *charStr = [NSString stringWithFormat:#"%C", decimal];
I'm new to iPhone development, I want to convert a string to hex format.
For example 00A400024F01 to 0x00,0xA4,0x00,0x02,0x4F,0x01 I guess I should start by dividing the string and then convert the grouped value. I don't know how to do that.
u just found answer from this stackoverflow question:-
How to convert an NSString to hex values
+ (NSString *) stringToHex:(NSString *)str
{
NSUInteger len = [str length];
unichar *chars = malloc(len * sizeof(unichar));
[str getCharacters:chars];
NSMutableString *hexString = [[NSMutableString alloc] init];
for(NSUInteger i = 0; i < len; i++ )
{
// [hexString [NSString stringWithFormat:#"%02x", chars[i]]]; /*previous input*/
[hexString appendFormat:#"%02x", chars[i]]; /*EDITED PER COMMENT BELOW*/
}
free(chars);
return [hexString autorelease];
}
UPDATE
You can divide one sting on to two string using below method:-
NSString * mystring = #"Hello,How are you";// suppos your string like that
NSArray * array = [mystring componentsSeparatedByString:#","];
NSString * str1 = [array objectAtIndex:0]; //Hello
NSString * str2 = [array objectAtIndex:1]; //How are you
and if you want to murge two string in to one string like :-
NSString *str1=#"hi Sweet Lady";
NSString *str2=#"How are you";
NSString *mainstr=[NSString stringWithFormat:#"%# %#",str1,str2];
Output is ==== hi Sweet Lady How are you
In my application I am converting a NSString to HexString. But I always require a fixed size(16 bytes) hex string e.g. if the length of my hex string is 15 bytes, I want it to be 16 bytes. I know that I can add zeros at the beginning of the hex string, but how to add that because simply adding a "0" is not working while I am converting it back into NSString.
You can try this code....
+ (NSString *) stringToHex:(NSString *)str
{
NSUInteger len = [str length];
unichar *chars = malloc(len * sizeof(unichar));
[str getCharacters:chars];
NSMutableString *hexString = [[NSMutableString alloc] init];
for(NSUInteger i = 0; i < len; i++ )
{
// [hexString [NSString stringWithFormat:#"%02x", chars[i]]]; //previous input
[hexString appendFormat:#"%02x", chars[i]]; //EDITED PER COMMENT BELOW
}
free(chars);
return [hexString autorelease];
}
I hope this will help you.
happy coding.
my code works great until know and, if I put a double digit number into the text field (like 12) nslog returns 2 single digit numbers (like 1 and 2). Now I need to put these 2 single digit numbers into 2 strings. can somebody help me. thanks in advance.
NSString *depositOverTotalRwy = [NSString stringWithFormat:#"%#", [deposit text]];
NSArray *components = [depositOverTotalRwy
componentsSeparatedByString:#"/"];
NSString *firstThird = [components objectAtIndex:0];
for(int i = 0; i < [firstThird length]; i++)
{
char extractedChar = [firstThird characterAtIndex:i];
NSLog(#"%c", extractedChar);
}
You should be able to use -stringWithFormat:.
NSString *s = [NSString stringWithFormat:#"%c", extractedChar];
EDIT:
You can store them in an array.
NSMutableArray *digits = [NSMutableArray array];
for ( int i = 0; i < [s length]; i++ ) {
char extractedChar = [s characterAtIndex:i];
[digits addObject:[NSString stringWithFormat:#"%c", extractedChar]];
}
Try to print the value of firstThird using NSLog(), see what it exactly hold, you code seem correct,
Use characterAtIndex function for NSString to extract a character at known location
- (unichar)characterAtIndex:(NSUInteger)index
Use as below
NSString *FirstDigit = [NSString stringWithFormat:#"%c", [myString characterAtIndex:0]];
NSString *SecondDigit = [NSString stringWithFormat:#"%c", [myString characterAtIndex:1]];