I have an one hexa decimal number
535443326663315634524877795678586b536854535530342f44526a795744716133353942704359697a6b736e446953677171555473
I want to convert this number to ASCII format which will look like this
STC2fc1V4RHwyVxXkShTSU04/DRjyWDqa359BpCYizksnDiSgqqUTsYUOcHKHNMJOdqR1/TQywpD9a9xhri
i have seen solutions here but none of them is useful to me
NSString containing hex convert to ascii equivalent
i checked here but they give different result. Any help
This works perfectly
- (NSString *)stringFromHexString:(NSString *)hexString {
// The hex codes should all be two characters.
if (([hexString length] % 2) != 0)
return nil;
NSMutableString *string = [NSMutableString string];
for (NSInteger i = 0; i < [hexString length]; i += 2) {
NSString *hex = [hexString substringWithRange:NSMakeRange(i, 2)];
NSInteger decimalValue = 0;
sscanf([hex UTF8String], "%x", &decimalValue);
[string appendFormat:#"%c", decimalValue];
NSLog(#"string--%#",string);
}
_hexString1=string;
NSLog(#"string ---%#",_hexString1);
return string;
}
If you're starting with NSData * you could get the ASCII string this way:
NSData *someData = [NSData dataWithHexString:#"ABC123"];
NSString *asciiString = [[NSString alloc] initWithData: someData encoding:NSASCIIStringEncoding];
I have an int value which I obtained from the character 爸, which is 29240. I can convert this number to hex, but I have no clue how to write the chinese character out in an NSString with only the int 29240.
Basically, what I did was:
NSString * s = #"爸";
int a = [s characterAtIndex:0];
NSLog(#"%d", a);
What it gave as output was 29240.
However, I don't know how to create an NSString that just contains 爸 from only the int 29240.
I converted 29240 into binary which gave me 7238, but I can't seem to create a method which allows me to input any integer and NSLog the corresponding character.
I can hard code it in, so that I have
char cString[] = "\u7238";
NSData *data = [NSData dataWithBytes:cString length:strlen(cString)];
NSString *string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"result string: %#", string);
But I'm not sure how to do it with any int.
Thanks to anyone who can help me!
To create a string from one (or more) Unicode characters use initWithCharacters:
unichar c = 29240;
NSString *string = [[NSString alloc] initWithCharacters:&c length:1];
NSString uses UTF-16 characters internally, so
this works for all characters in the "Basic Multilingual Plane", i.e. all characters up to U+FFFF. The following code works for arbitrary characters:
uint32_t ch = 0x1F60E;
ch = OSSwapHostToLittleInt32(ch); // To make it byte-order safe
NSString *s1 = [[NSString alloc] initWithBytes:&ch length:4 encoding:NSUTF32LittleEndianStringEncoding];
NSLog(#"%#", s1);
// Output: 😎
Try out this code snippet to get you started in the right direction:
NSString *s = #"0123456789";
for (int i = 0; i < [s length]; i++) {
NSLog(#"Value: %d", [s characterAtIndex:i]);
}
Just pass in the character as an integer:
unichar decimal = 12298;
NSString *charStr = [NSString stringWithFormat:#"%C", decimal];
I'm new to iPhone development, I want to convert a string to hex format.
For example 00A400024F01 to 0x00,0xA4,0x00,0x02,0x4F,0x01 I guess I should start by dividing the string and then convert the grouped value. I don't know how to do that.
u just found answer from this stackoverflow question:-
How to convert an NSString to hex values
+ (NSString *) stringToHex:(NSString *)str
{
NSUInteger len = [str length];
unichar *chars = malloc(len * sizeof(unichar));
[str getCharacters:chars];
NSMutableString *hexString = [[NSMutableString alloc] init];
for(NSUInteger i = 0; i < len; i++ )
{
// [hexString [NSString stringWithFormat:#"%02x", chars[i]]]; /*previous input*/
[hexString appendFormat:#"%02x", chars[i]]; /*EDITED PER COMMENT BELOW*/
}
free(chars);
return [hexString autorelease];
}
UPDATE
You can divide one sting on to two string using below method:-
NSString * mystring = #"Hello,How are you";// suppos your string like that
NSArray * array = [mystring componentsSeparatedByString:#","];
NSString * str1 = [array objectAtIndex:0]; //Hello
NSString * str2 = [array objectAtIndex:1]; //How are you
and if you want to murge two string in to one string like :-
NSString *str1=#"hi Sweet Lady";
NSString *str2=#"How are you";
NSString *mainstr=[NSString stringWithFormat:#"%# %#",str1,str2];
Output is ==== hi Sweet Lady How are you
example: NSString *day = [[NSString stringWithFormat:#"السبت"];and i think the
representation of this string in hex is this :%C7%E1%D3%C8%CA (windows-1256 encoding)
what i want is how to convert arabic string to hex like this.
A possible solution:
NSString *day =#"السبت";
NSData *strData = [day dataUsingEncoding:NSWindowsCP1254StringEncoding];
NSMutableString *mut = [NSMutableString string];
int i;
for (i = 0; i < [strData length]; i++)
{
[mut appendFormat:#"%%%02X", ((char *)[strData bytes])[i]];
}
mut will contain the hexadecimal encoded representation of day.
Something like [day stringByAddingPercentEscapesUsingEncoding:#"whatever"] ?
I'd like to convert a regular NSString into an NSString with the (what I assume are) ASCII hex values and back.
I need to produce the same output that the Java methods below do, but I can't seem to find a way to do it in Objective-C. I've found some examples in C and C++ but I've had a hard time working them into my code.
Here are the Java methods I'm trying to reproduce:
/**
* Encodes the given string by using the hexadecimal representation of its UTF-8 bytes.
*
* #param s The string to encode.
* #return The encoded string.
*/
public static String utf8HexEncode(String s) {
if (s == null) {
return null;
}
byte[] utf8;
try {
utf8 = s.getBytes(ENCODING_UTF8);
} catch (UnsupportedEncodingException x) {
throw new RuntimeException(x);
}
return String.valueOf(Hex.encodeHex(utf8));
}
/**
* Decodes the given string by using the hexadecimal representation of its UTF-8 bytes.
*
* #param s The string to decode.
* #return The decoded string.
* #throws Exception If an error occurs.
*/
public static String utf8HexDecode(String s) throws Exception {
if (s == null) {
return null;
}
return new String(Hex.decodeHex(s.toCharArray()), ENCODING_UTF8);
}
Update: Thanks to drawnonward's answer here's the method I wrote to create the hex NSStrings. It gives me an "Initialization discards qualifiers from pointer target type" warning on the char declaration line, but it works.
- (NSString *)stringToHex:(NSString *)string
{
char *utf8 = [string UTF8String];
NSMutableString *hex = [NSMutableString string];
while ( *utf8 ) [hex appendFormat:#"%02X" , *utf8++ & 0x00FF];
return [NSString stringWithFormat:#"%#", hex];
}
Haven't had time to write the decoding method yet. When I do, I'll edit this to post it for anyone else interested.
Update2: So the method I posted above actually doesn't output what I'm looking for. Instead of outputting hex values in 0-f format, it was instead outputting all numbers. I finally got back to working on this problem and was able to write a category for NSString that exactly duplicates the Java methods I posted. Here it is:
//
// NSString+hex.h
// Created by Ben Baron on 10/20/10.
//
#interface NSString (hex)
+ (NSString *) stringFromHex:(NSString *)str;
+ (NSString *) stringToHex:(NSString *)str;
#end
//
// NSString+hex.m
// Created by Ben Baron on 10/20/10.
//
#import "NSString+hex.h"
#implementation NSString (hex)
+ (NSString *) stringFromHex:(NSString *)str
{
NSMutableData *stringData = [[[NSMutableData alloc] init] autorelease];
unsigned char whole_byte;
char byte_chars[3] = {'\0','\0','\0'};
int i;
for (i=0; i < [str length] / 2; i++) {
byte_chars[0] = [str characterAtIndex:i*2];
byte_chars[1] = [str characterAtIndex:i*2+1];
whole_byte = strtol(byte_chars, NULL, 16);
[stringData appendBytes:&whole_byte length:1];
}
return [[[NSString alloc] initWithData:stringData encoding:NSASCIIStringEncoding] autorelease];
}
+ (NSString *) stringToHex:(NSString *)str
{
NSUInteger len = [str length];
unichar *chars = malloc(len * sizeof(unichar));
[str getCharacters:chars];
NSMutableString *hexString = [[NSMutableString alloc] init];
for(NSUInteger i = 0; i < len; i++ )
{
[hexString appendString:[NSString stringWithFormat:#"%x", chars[i]]];
}
free(chars);
return [hexString autorelease];
}
#end
The perfect and short way to convert nsstring to hexadecimal values
NSMutableString *tempHex=[[NSMutableString alloc] init];
[tempHex appendString:#"0xD2D2D2"];
unsigned colorInt = 0;
[[NSScanner scannerWithString:tempHex] scanHexInt:&colorInt];
lblAttString.backgroundColor=UIColorFromRGB(colorInt);
The macro used for this code is----
#define UIColorFromRGB(rgbValue)
[UIColor \colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 \
green:((float)((rgbValue & 0xFF00) >> 8))/255.0 \
blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0]
For these lines of Java
utf8 = s.getBytes(ENCODING_UTF8);
new String(decodedHexString, ENCODING_UTF8);
Objective-C equivalents would be
utf8 = [s UTF8String];
[NSString initWithUTF8String:decodedHexString];
To make an NSString with the hexadecimal representation of a character string:
NSMutableString *hex = [NSMutableString string];
while ( *utf8 ) [hex appendFormat:#"%02X" , *utf8++ & 0x00FF];
You will have to make your own decodeHex function. Just pull two characters out of the string and, if they are valid, add a byte to the result.
There is a problem with your stringToHex method - it drops leading 0s, and ignores 00s. Just as a quick fix, I made the below:
+ (NSString *) stringToHex:(NSString *)str
{
NSUInteger len = [str length];
unichar *chars = malloc(len * sizeof(unichar));
[str getCharacters:chars];
NSMutableString *hexString = [[NSMutableString alloc] init];
for(NSUInteger i = 0; i < len; i++ )
{
// [hexString [NSString stringWithFormat:#"%02x", chars[i]]]; /*previous input*/
[hexString appendFormat:#"%02x", chars[i]]; /*EDITED PER COMMENT BELOW*/
}
free(chars);
return [hexString autorelease];
}
Thanks to all who contributed on this thread. It was a great help to me. Since things have moved on a little since the original post, here's my updated implementation for iOS 6. I went with the categories approach, but chose to split the load between NSData and NSString. Comments welcomed.
First, the NSString half, which handles decoding a hex encoded string into an NSData object.
#implementation NSString (StringToHexData)
//
// Decodes an NSString containing hex encoded bytes into an NSData object
//
- (NSData *) stringToHexData
{
int len = [self length] / 2; // Target length
unsigned char *buf = malloc(len)
unsigned char *whole_byte = buf;
char byte_chars[3] = {'\0','\0','\0'};
int i;
for (i=0; i < [self length] / 2; i++) {
byte_chars[0] = [self characterAtIndex:i*2];
byte_chars[1] = [self characterAtIndex:i*2+1];
*whole_byte = strtol(byte_chars, NULL, 16);
whole_byte++;
}
NSData *data = [NSData dataWithBytes:buf length:len];
free( buf );
return data;
}
#end
The changes were mostly for efficiency's sake: some simple old-fashioned pointer arithmetic means I could allocate the whole buffer in one go, and populate it byte by byte. Then the whole thing is passed to NSData in one go.
The encoding part, in NSData, looks like this:
#implementation NSData (DataToHexString)
- (NSString *) dataToHexString
{
NSUInteger len = [self length];
char * chars = (char *)[self bytes];
NSMutableString * hexString = [[NSMutableString alloc] init];
for(NSUInteger i = 0; i < len; i++ )
[hexString appendString:[NSString stringWithFormat:#"%0.2hhx", chars[i]]];
return hexString;
}
#end
Again, some minor changes, though I suspect no efficiency gains here. The use of "%0.2hhx" solved all the problems of missing leading zero's and ensures that only a single-byte is output at a time.
Hope this helps the next person taking this on!
One possible solution:
+(NSString*)hexFromStr:(NSString*)str
{
NSData* nsData = [str dataUsingEncoding:NSUTF8StringEncoding];
const char* data = [nsData bytes];
NSUInteger len = nsData.length;
NSMutableString* hex = [NSMutableString string];
for(int i = 0; i < len; ++i)[hex appendFormat:#"%02X", data[i]];
return hex;
}
So, first off, I would like to thank drawnonward for his answer. This gave me the first function, mean and clean. In the same spirit, I wrote the other one. Hope you like it.
#synthesize unsigned char* value= _value;
- (NSString*) hexString
{
_value[CONSTANT]= '\0';
unsigned char* ptr= _value;
NSMutableString* hex = [[NSMutableString alloc] init];
while ( *ptr ) [hex appendFormat:#"%02x", *ptr++ & 0x00FF];
return [hex autorelease];
}
- (void) setHexString:(NSString*)hexString
{
_value[CONSTANT]= '\0';
unsigned char* ptr= _value;
for (const char* src= [hexString cStringUsingEncoding:NSASCIIStringEncoding];
*src;
src+=2)
{
unsigned int hexByte;
/*int res=*/ sscanf(src,"%02x",&hexByte);
*ptr++= (unsigned char)(hexByte & 0x00FF);
}
*ptr= '\0';
}
My input was an digit base10 string, and the output should be the hex representation in string format. Examples:
#"10" -> #"A"
#"1128" -> #"468"
#"1833828235" -> #"6D4DFF8B"
Implementation:
+ (NSString *) stringToHex:(NSString *)str{
NSInteger result = [str integerValue];
NSString *hexStr = (result)?#"":#"0";
while (result!=0) {
NSInteger reminder = result % 16;
if(reminder>=0 && reminder<=9){
hexStr = [[NSString stringWithFormat:#"%ld",(long)reminder] stringByAppendingString:hexStr];
}else if(reminder==10){
hexStr = [#"A" stringByAppendingString:hexStr];
}else if(reminder==11){
hexStr = [#"B" stringByAppendingString:hexStr];
}else if(reminder==12){
hexStr = [#"C" stringByAppendingString:hexStr];
}else if(reminder==13){
hexStr = [#"D" stringByAppendingString:hexStr];
}else if(reminder==14){
hexStr = [#"E" stringByAppendingString:hexStr];
}else{
hexStr = [#"F" stringByAppendingString:hexStr];
}
result /=16;
}
return hexStr;
}
Perhaps you should use NSString dataUsingEncoding: to encode and initWithData:length:encoding: to decode. Depends on where you are getting the data from.