Sorry about quite silly question but after several days of searching I still don't have the answer and I'm realy stackoverfloved about it.
I have refinerycms extension. Like this:
$ rails generate refinery:engine shop name:string logo:image
I want it to be controlled from both backend and frontend of my application.
Have no problems with backend. (Thank you for refinerycms team.)
Have no problems with frontend when the form contains only "name". (Or any other attribute that doesn't have image type).
Have problems with image type attributes.
I don't want frontend user to have the same image editing form as backend users does.
I want the form to be smth like this:
<div class='field'>
<%= f.label :logo , "Logo"%>
<%= f.file_field :logo %>
</div>
And I want images loaded by frontend user to be saved with Refinery::Image.
I bet the problem is only in my frontend controller create action for shops, but I have no clue how it should be overwritten.
Thanks a lot for any suggestion.
In the controller, you will have to pass the 'logo' param to the model as a Refinery::Image instance. To do so, you create an instance of Refinery::Image and merge it to the model.
Example:
logo = Refinery::Image.create(image: params[:shop][:logo])
#shop = Refinery::Shops::Shop.create(params[:shop].merge({logo: logo}))
I have FE form with file_field (:logo) on FE and in my normal controller (not the admin one) I have this method to handle params from request:
def model_params
permitted = params.require(:model).permit!
permitted[:logo] = Refinery::Image.create(image: permitted[:logo])
return permitted
end
to permits params and create image form file.
And then in my create method:
def create
if (#new_beer = ::Refinery::Models::Model.create(model_params))
#do some stuff when it succeeds to create it
redirect_to SOMEWHERE
else
redirect_to SOMEWHERE, notice: "Something went wrong!"
end
end
Hope it can help! :)
Related
I have a Rails model called request_form. In the form I have multiple boxes that can be selected, similar to the "What can we craft for you section" in the following site http://mostlyserious.io/get-started/
I have a field called number_of_guests that can be a handful of values depending on which section is clicked. I plan on using javascript to grab the value of the clicked element and assigning it to the request_no_of_guest param. However, in the form I have that same field rendered 5 times to allow for each selection. What is the best way about this? Is there a better way to handle this? I thought about creating a controller method that loops through each instance of that request_no_of_guests param and determining which instance is populated and then sending that up.
Is this the best way to handle this case?
Well as you did not provide any useful detail I will answer as I understood the question.
Let’s have a quick look at what this might look like. To do so, we’ll imagine a demo app into which you can enter the name of a professor and select their various areas of expertise.
Professor has a field expertise which is String.
The form can be as follows:
<%= label_tag 'expertise_physics', 'Physics' %>
<%= check_box_tag 'professor[expertise][]', 'Physics', checked('Physics'), id: 'expertise_physics' %>
<%= label_tag 'expertise_maths', 'Maths' %>
<%= check_box_tag 'professor[expertise][]', 'Maths', checked('Maths'), id: 'expertise_maths' %>
alter app/controllers/professors_controller.rb
from
params.require(:professor).permit(:name, :expertise)
to
params.require(:professor).permit(:name, expertise:[])
Then in app/models/professor.rb
before_save do
self.expertise.gsub!(/[\[\]\"]/, "") if attribute_present?("expertise")
end
and in /app/helpers/professors_helper.rb
def checked(area)
#professor.expertise.nil? ? false : #professor.expertise.match(area)
end
This way you can grab the different values selected in the form into the expertise attribute, however this is not recommended if you are planning to query the selected options. The right way would be create a new model called Expertise and then create the relationship professor has_many expertises.
But if you are looking for something simple, then use the above code.
I have a basic front-end form within a component that I created using ComponentCreator.
How and where do I direct the form "action"? Where can I handle this so that I am following the MVC design pattern? My form is within a view (default.php)
The form should simply insert to the database upon submission. I don't want to use a form building extension, I have tried these and they don't meet my requirements.
What version of Joomla? Assuming your not using AJAX then just direct to your controller.
<form id='MyForm' method='post' action='index.php?option=com_mycomponent&task=myoperation'>
<input type='text' name='myname'/>
...</form>
Then you will have a function in your controller (controller.php) called myoperation that will process all the things in your form (not forgetting the token of course)
JSession::checkToken('request') or jexit( JText::_( 'JINVALID_TOKEN' ) );
$jinput = JFactory::getApplication()->input;
$add_name = $jinput->get('myname', '', 'STRING');
//whatever you need to do...
//add to model if you wanted to add name to DB
$model = &$this->getModel();
$model->updateDB(...);
Then create function updateDB in model.
This is a rough example with Joomla 2.5 but should work with 3.x. Hope this helps.
I have a simple search form I want to reuse across multiple pages in my codeigniter application. For example, right now I have a search form in the sidebar and I'm planning on displaying that sidebar on the index, about, and other pages.
I want to have the form validation display errors on the same page the users submits the form from.
For example:
User is on About page.
User submits form with invalid data
User sees error in the sidebar on the About page
and
User is on Index page.
User submits form with invalid data
User sees error in the sidebar on the Index page
But I'd like to reuse that form validation logic. I just want it to display the error on whichever page the user posted from.
Any ideas how to do that? Sorry for the noob question, I'm pretty new to CI.
Here you have to think globally.
Step.1 : Make one view file : display.php
which contains :
<div id = "main">
<div id = "header">
[load header file here]
</div>
<?php
if(validation_errors() != '') {
?>
<div id = "error">
<?=validation_errors()?>
</div>
<?php
}
?>
<div id = "content">
<?=$page?>
</div>
<div id = "footer">
[load footer file here]
</div>
</div>
Step.2 : About us Page.(controlller)
.... Your data ....
at end of controller function
$data['page'] = 'aboutus';
$this->load->view('display',$data);
With regards to your comment on the above question you could use Flash data
With the assumption that you have the session library loaded, here is a helper function.
function last_page($page = null){
$ci = get_instance();
if($page === null)
return $ci->session->flashdata('last_page');
$ci->session->set_flashdata('last_page', $page);
}
then you can call last_page('about'); at the top of the about page, and then when you want to find out what the last page you were on was you can just call last_page(); with no params.
In the User Guide, there's different ways to configure sets/groups of rules. Then you can simply have something like:
if ($this->form_validation->run('signup') == FALSE)
{
$this->load->view('myform');
}
else
{
$this->load->view('formsuccess');
}
Which will run your "signup" group of validations. To me, this is the cleanest way to achieve reusable validation rules.
This is a perfectly valid question.
I'm not a PHP expert, nor a CI expert, but the fact is sometimes you want to post to a controller that didn't create the view from which you're posting. Which means posting back to itself is not going to work.
I came across this post on the Ellislab forum:
http://ellislab.com/forums/viewthread/217176/
On this page, There are 2 methods of going about it. Both of which use flashdata and both of which are totally valid, IMHO.
The first: create a helper function
http://ellislab.com/forums/viewreply/1003010/
The second: extend the CI_Form_Validation Class.
http://ellislab.com/forums/viewreply/1047536/
The second is the way I went as it seems cleanest although some may argue whether the form validation class should know anything about flash data.
I am using an application (a blog) written using the CodeIgniter framework and would like to search my blog from my browsers location bar by adding a string to the end of my blogs url like this:
http://mysite.com/blog/index.php/search...
As you can see in the example above I am not really sure how to format the rest of the url after the search part so I am hoping someone here might be able to point me in the right direction.
This is what the form looks like for the search box if that helps at all.
form class="searchform" action="http://mysite.com/blog/index.php/search" method="post">
<input id="searchtext" class="search_input" type="text" value="" name="searchtext">
<input type="submit" value="Search" name="Search">
</form>
Thx,
Mark
Since your form is posting to http://mysite.com/blog/index.php/search, I'm assuming this 'search' controller's default function is the one your are attempting to submit your data to. I think that the easiest way to do this would be to just grab the post data inside of the controller method you're posting to. Example:
function search()
{
$search_params = $this->input->post('search_text');
}
Then you would have whatever the user input stored as $search_params, and you can take actions from there. Am I misunderstanding what you're asking?
It seems like you're kind of discussing two different approaches. If you wanted to make a request to
mysite.com/blog/index.php/search&q=what_I_am_looking_for
This is going to call the search controllers default method (which is index by default). If you wanted to use the URL to pass parameters like that you would go to your function in the search controller and do:
print_r($this->input->get('q'));
This will print out "what_am_I_looking_for".
An easier approach in my opinion would be to:
1. Create a view called "search_view" with the HTML content you pasted above, and have the form "action" http://www.mysite.com/blog/index.php/test/search
Create a controller called "Test" that looks like the following:
class Test extends CI_Controller {
function search()
{
$search = $this->input->post('searchtext');
print_r($search);
}
public function display_search()
{
$this->load->view('search_view');
}
}
Visit http://www.mysite.com/blog/index.php/test/display_search in your browser. This should present you with the form you placed in search_view.php. Once the form is submitted, you should be sent to the search function and print out the variable $search, which will have whatever text you submitted on that form.
If this isn't what you were looking for then I am afraid I do not understand your question.
I am rather new to MVC applications, and one thing I am trying to accomplish is enabling or disabling stylesheets based on a Session value.
I have stylesheets referenced in my Site.Master page in this manner:
<%=Html.Stylesheet("~/styles/main.css", "string")%>
<%=Html.Stylesheet("~/styles/additions.css", "string")%>
Right now, for testing, I have been putting an if statement around the Html.Stylesheet tags saying:
<% if (Session["cssRule"] = "enableCss") { %>
<%=Html.Stylesheet("~/styles/main.css", "screen")%>
<%=Html.Stylesheet("~/styles/additions.css", "screen")%>
<%} %>
So if the 'cssRule' Session value is null, no CSS loads. Currently this is working fine, but it is not exactly what I am looking for. Right now I set the Session value in the Controller when the user logs in, but ultimately I need to set the value of the Session variable depending on if a user clicks the enable or disable button. Since I have been primarily using webforms for the past year and a half, I just want to drop a hyperlink and set an event for it, but alas, this is the future of MVC so I need to figure out how I can do something like this..
So my real question is how can I set the Session of the "cssRule" value by clicking a link using MVC?
I'll assume you want to use a standard link (not ajax) and that your main view is Index
Just add a method in your controller (pseudocode)
public ActionResult ToggleCSS()
{
if (Session["cssRule"] != null && Session["cssRule"] == "enableCSS")
{
Session["cssRule"] = "disableCSS";
}
else
{
Session["cssRule"] = "enableCSS";
}
return View("Index");
}
Then in your view, use
<%= Html.ActionLink("ToggleCSS", "ControllerName") %>
You can use lots of fancy different methods to obtain the same result; use ajax and relaod the page, or not, or redirect to a page listing css files to apply, etc... but this one should work :)