question about CodeIgniter urls - forms

I am using an application (a blog) written using the CodeIgniter framework and would like to search my blog from my browsers location bar by adding a string to the end of my blogs url like this:
http://mysite.com/blog/index.php/search...
As you can see in the example above I am not really sure how to format the rest of the url after the search part so I am hoping someone here might be able to point me in the right direction.
This is what the form looks like for the search box if that helps at all.
form class="searchform" action="http://mysite.com/blog/index.php/search" method="post">
<input id="searchtext" class="search_input" type="text" value="" name="searchtext">
<input type="submit" value="Search" name="Search">
</form>
Thx,
Mark

Since your form is posting to http://mysite.com/blog/index.php/search, I'm assuming this 'search' controller's default function is the one your are attempting to submit your data to. I think that the easiest way to do this would be to just grab the post data inside of the controller method you're posting to. Example:
function search()
{
$search_params = $this->input->post('search_text');
}
Then you would have whatever the user input stored as $search_params, and you can take actions from there. Am I misunderstanding what you're asking?

It seems like you're kind of discussing two different approaches. If you wanted to make a request to
mysite.com/blog/index.php/search&q=what_I_am_looking_for
This is going to call the search controllers default method (which is index by default). If you wanted to use the URL to pass parameters like that you would go to your function in the search controller and do:
print_r($this->input->get('q'));
This will print out "what_am_I_looking_for".
An easier approach in my opinion would be to:
1. Create a view called "search_view" with the HTML content you pasted above, and have the form "action" http://www.mysite.com/blog/index.php/test/search
Create a controller called "Test" that looks like the following:
class Test extends CI_Controller {
function search()
{
$search = $this->input->post('searchtext');
print_r($search);
}
public function display_search()
{
$this->load->view('search_view');
}
}
Visit http://www.mysite.com/blog/index.php/test/display_search in your browser. This should present you with the form you placed in search_view.php. Once the form is submitted, you should be sent to the search function and print out the variable $search, which will have whatever text you submitted on that form.
If this isn't what you were looking for then I am afraid I do not understand your question.

Related

Prestashop module development - why is this template redirecting not working

On user-registration confirmation I want to show a simple popup. For the moment, in order to simplify I'm happy to show an "Hello World".
This is the template file, views/templates/hook/registrationConfirm.tpl
<div id="idname" class="block">
<h1 class="title_block">HelloWorld</h1>
</div>
In my custom module I have this hook (which I know is being triggered doing debug):
public function hookActionCustomerAccountAdd($params) {
return $this->display(__FILE__, 'registrationConfirm.tpl');
}
It doesn't show anything (I also tried inspect the source code of the rendered page, but I dind't find the "HelloWorld")
Hooks starting by "Action" react to an action but do not display anything, but those starting with "Display" do.
You should also react to the hook displayCustomerAccount
public function hookActionCustomerAccountAdd() {
$this->is_new_account = true;
}
public function hookDisplayCustomerAccount()
{
if ($this->is_new_account) {
return $this->display(__FILE__, 'registrationConfirm.tpl');
}
}
I tried the solution posted by #shagshag but for some reason it doesn't work for me. So I share my solution (it's not pretty, nor efficient I think, but it seem to work for me): in the hookActionCustomerAccountAdd I save on a custom table (newCustomersTmp) email and customer id, because these are the data I need after, in the display Hook. Then in the hookDisplayCustomerAccount I check if an user with the current email ($this->context->customer->email) already exists in my table: if so I retrieve the data, do the actions I need with them and delete the row in the table.

Set class or ID on <h:inputHidden> in JSF

I'm trying to set a class or id parameter on a <h:inputHidden> in JSF. The code looks like this:
<h:inputHidden value="#{getData.name}" class="targ" />
But in the browser, the class isn't set:
<input type="hidden" name="j_idt6" value="j_idt6">
I need to set a class to this parameter, because I have a JavaScript autocomplete function for a <h:inputText> that sets a value in the hidden input, which needs to be passed in the next page.
Any ideas? Thanks!
I know it's a little bit late, but it can help someone in the future.
As inputHidden shows nothing in the browser there's no sense to allow it to have a class.
You can use the Id but as the Id could change as you change the component parents using it would bring some headache.
I'd suggest as a workaround, you can give it a parent so you can manipulate it by javascript.
Exemple:
JSF
<h:panelGroup styleClass="someCssClass">
<h:inputHidden id="someId" value="someValue" />
</h:panelGroup>
Javascript (using jQuery, you could use pure javascript also)
$('.someCssClass input[type=hidden]').val('yourNewValue');
None of these answers here satisfied my needs (need the PrimeFaces component, need class not ID, wrapping is too much work), so here's what I came up with:
Use pass-through attributes: https://www.primefaces.org/jsf-2-2-pass-through-attributes
Use pass:hidden-class="blah" (in my case, it's xmlns:pass up top)
Use [attribute=value] selector:
https://www.w3schools.com/cssref/sel_attribute_value.asp
document.querySelector multiple data-attributes in one element
That basically boils down to using something like this (because h:inputHidden becomes a regular input): document.querySelector("input[hidden-class=" + blah + "]")
Please, see similar question - How can I know the id of a JSF component so I can use in Javascript
You can sed "id" property, but in final html code it can be not the same, but composite: for example, if your input with id="myhidden" is inside form with id="myform", final input will have id="myform:myhidden".
In the end, I used a standard HTML <input type="hidden"> tag, as I had no advantages for using the JSF one. If you're trying to set a value in a hidden input with JavaScript, I recommend using this workaround.

Zend creating forms based on requests within one controller/action

I don't really know how to word the title well, but here's my issue. I decided instead of having 25 controllers to handle pages, I have one PageController with a viewAction that takes in a :page parameter - for example, http://localhost/website/page/about-us would direct to PageController::viewAction() with a parameter of page = about-us. All of the pages are stored in a templates folder, so the viewrenderer is set to render application\templates\default\about-us.phtml.
I did this so I can consolidate and it seemed like a better approach. My question is the following: lets say when the page request is contact-us, I would need a Zend_Form to be used within the contact page. So, I would need a way within PageController::viewAction() to recognize that the page needs to have a form built, build the form, and also upon submission the need to process it (maybe this should be handled in an abstract process method - not sure).
I have no idea how to implement this. I thought maybe I can store a column with the name of a form and a connecting page identifier. Even better, create a one-to-many page to forms, and then in the submission loop through the forms and check if submitted and if so then process it (maybe there is a isSubmitted() method within zend_form. I really don't know how to handle this, and am looking for any help i can get.
Thanks!
Here is something that came to mind that may work or help point you in a direction that works for you.
This may only work well assuming you were to have no more than one form per page, if you need more than one form on a page, you would have to do something beyond this automatic form handling.
Create a standard location for forms that are attached to pages (e.g. application/forms/page). This is where the automatic forms associated with pages will be kept.
In your viewAction, you could take advantage of the autoloader to see if a form for that page exists. For example:
$page = $this->getParam('page');
$page = ucfirst(preg_replace('/-(\w)/ie', "strtoupper('$1')", $page)); // contact-us -> ContactUs
$class = 'Application_Form_Page_' . $page;
// class_exists will invoke the autoloader to map a class to a file
if (class_exists($class)) {
// a form is defined for this page
$form = new $class();
// check if form was posted
if ($this->getRequest()->isPost()) {
if ($form->isValid($this->getRequest()->getPost()) {
// form is valid - determine how to process it
}
}
// assign the form to the view
$this->view->pageForm = $form;
}
All this really leaves out is the action you take to process a specific form. Since the contact form will likely generate an email, and another form may insert data into a database, you will need some sort of callback system or perhaps another class that can be mapped automatically which contains the form processor code.
Anyway something along those lines is what came to mind first, I hope that helps give you some more ideas.

How to reuse codeigniter form on multiple pages

I have a simple search form I want to reuse across multiple pages in my codeigniter application. For example, right now I have a search form in the sidebar and I'm planning on displaying that sidebar on the index, about, and other pages.
I want to have the form validation display errors on the same page the users submits the form from.
For example:
User is on About page.
User submits form with invalid data
User sees error in the sidebar on the About page
and
User is on Index page.
User submits form with invalid data
User sees error in the sidebar on the Index page
But I'd like to reuse that form validation logic. I just want it to display the error on whichever page the user posted from.
Any ideas how to do that? Sorry for the noob question, I'm pretty new to CI.
Here you have to think globally.
Step.1 : Make one view file : display.php
which contains :
<div id = "main">
<div id = "header">
[load header file here]
</div>
<?php
if(validation_errors() != '') {
?>
<div id = "error">
<?=validation_errors()?>
</div>
<?php
}
?>
<div id = "content">
<?=$page?>
</div>
<div id = "footer">
[load footer file here]
</div>
</div>
Step.2 : About us Page.(controlller)
.... Your data ....
at end of controller function
$data['page'] = 'aboutus';
$this->load->view('display',$data);
With regards to your comment on the above question you could use Flash data
With the assumption that you have the session library loaded, here is a helper function.
function last_page($page = null){
$ci = get_instance();
if($page === null)
return $ci->session->flashdata('last_page');
$ci->session->set_flashdata('last_page', $page);
}
then you can call last_page('about'); at the top of the about page, and then when you want to find out what the last page you were on was you can just call last_page(); with no params.
In the User Guide, there's different ways to configure sets/groups of rules. Then you can simply have something like:
if ($this->form_validation->run('signup') == FALSE)
{
$this->load->view('myform');
}
else
{
$this->load->view('formsuccess');
}
Which will run your "signup" group of validations. To me, this is the cleanest way to achieve reusable validation rules.
This is a perfectly valid question.
I'm not a PHP expert, nor a CI expert, but the fact is sometimes you want to post to a controller that didn't create the view from which you're posting. Which means posting back to itself is not going to work.
I came across this post on the Ellislab forum:
http://ellislab.com/forums/viewthread/217176/
On this page, There are 2 methods of going about it. Both of which use flashdata and both of which are totally valid, IMHO.
The first: create a helper function
http://ellislab.com/forums/viewreply/1003010/
The second: extend the CI_Form_Validation Class.
http://ellislab.com/forums/viewreply/1047536/
The second is the way I went as it seems cleanest although some may argue whether the form validation class should know anything about flash data.

Programmatically submitting a form while using AjaxForm

I wanted to find a way to upload a single file*, in the background, have it start automatically after file selection, and not require a flash uploader, so I am trying to use two great mechanisms (jQuery.Form and JQuery MultiFile) together. I haven't succeeded, but I'm pretty sure it's because I'm missing something fundamental.
Just using MultiFile, I define the form as follows...
<form id="photoForm" action="image.php" method="post" enctype="multipart/form-data">
The file input button is defined as...
<input id="photoButton" "name="sourceFile" class="photoButton max-1 accept-jpg" type="file">
And the Javascript is...
$('#photoButton').MultiFile({
afterFileSelect: function(){
document.getElementById("photoForm").submit();
}
});
This works perfectly. As soon as the user selects a single file, MultiFile submits the form to the server.
If instead of using MultiFile, as shown above, let's say I include a Submit button along with the JQuery Form plugin defined as follows...
var options = {
success: respondToUpload
};
$('#photoForm').ajaxForm(options);
... this also works perfectly. When the Submit button is clicked, the form is uploaded in the background.
What I don't know how to do is get these two to work together. If I use Javascript to submit the form (as shown in the MultiFile example above), the form is submitted but the JQuery.Form function is not called, so the form does not get submitted in the background.
I thought that maybe I needed to change the form registration as follows...
$('#photoForm').submit(function() {
$('#photoForm').ajaxForm(options);
});
...but that didn't solve the problem. The same is true when I tried .ajaxSubmit instead of .ajaxForm.
What am I missing?
BTW: I know it might sound strange to use MultiFile for single-file uploads, but the idea is that the number of files will be dynamic based on the user's account. So, I'm starting with one but the number changes depending on conditions.
The answer turns out to be embarrassingly simple.
Instead of programmatically submitting using...
document.getElementById("photoForm").submit();
... I used...
$("#photoForm").submit();
Also, since I only need to upload multiple files on occasion, I used a simpler technique...
1) The form is the same as my original...
<form id="photoForm" action="image.php" method="post" enctype="multipart/form-data">
2) The file input field is basically the same...
<input id="photoFile" "name="sourceFile" style="cursor:pointer;" type="file">
3) If the file input field changes, submit is executed...
$("#photoFile").change(function() {
$("#photoForm").submit();
});
4) The AjaxForm listener does its thing...
var options = {
success: respondToUpload
};
$('#photoForm').ajaxForm(options);