I am trying to sort using Sphinx (PHP) to show in order of price but when I do it will show £10 before £1.75 so I need to use ABS like in mySQL.
I have tried this:
$s->SetSortMode (SPH_SORT_EXPR, "ABS(display_price) ASC" );
It doesnt seem to work though.
Can anybody help?
Check, if display_price attribute treated as a decimal in search index
Probably you have
sql_attr_string = display_price
instead of
sql_attr_float = display_price
or
sql_attr_bigint = display_price
updated
SPH_SORT_EXPR is ALWAYS descending order. the ASC/DESC are for use with EXTENDED mode only.
To 'invert' it to become acsending, can build it into the expression.
$s->SetSortMode (SPH_SORT_EXPR, "1000000-CEIL(ABS(display_price*100.0))" );
Related
Basically what I am trying to do is say to my query that I want all of the users that have isBoosted = True to be first and after that, all others.
Thank You!
you can use the method sort to order descending because true=1 and false=0 like this:
db.users.find().sort("isBoosted", -1)
Or
db.users.find([your filter criteria]).sort("isBoosted", -1)
I want to get result matches with all nodes contains property 'abc' value as 'xyz' or 'pqr'.
I am trying in below ways:
http://localhost:4502/bin/querybuilder.json?path=/content/campaigns/asd&property=abc&property.1_value=/%xyz/%&property.2_value=/%pqr/%property.operation=like&p.limit=-1&orderby:path
http://localhost:4502/bin/querybuilder.json?path=/content/campaigns/asd&property=abc&property.1_value=/%xyz/%&property.2_value=/%pqr/%&property.1_operation=like&property.2_operation=like&p.limit=-1&orderby:path
http://localhost:4502/bin/querybuilder.json?path=/content/campaigns/asd&1_property=abc&1_property.1_value=/%xyz/%&1_property.1_operation=like&2_property=abc&1_property.1_value=/%xyz/%&2_property.1_operation=like&p.limit=-1&orderby:path
But none of them served my purpose. Any thing that I am missing in this?
The query looks right and as such should work. However if it is just xyz or pqr you would like to match in the query, you may not need the / in the values.
For eg.
path=/content/campaigns/asd
path.self=true //In order to include the current path as well for searching
property=abc
property.1_value=%xyz%
property.2_value=%abc%
property.operation=like
p.limit=-1
Possible things which you can check
Check if the path that you are trying to search contains the desired nodes/properties.
Check if the property name that you are using is right.
If you want to match exact values, you can avoid using the like operator and remove the wild cards from the values.
You can actually use the 'OR' operator in your query to combine two or more values of a property.
For example in the query debug interface : http:///libs/cq/search/content/querydebug.html
path=/content/campaigns/asd
property=PROPERTY1
property.1_value=VALUE1
property.2_value=VALUE2
property.operation=OR
p.limit=-1
It worked with below query:
http://localhost:4502/bin/querybuilder.json?orderby=path
&p.limit=-1
&path=/content/campaigns
&property=jcr:content/par/nodeName/xyz
&property.1_value=pqr
&property.2_value=%abc%
&property.operation=like
&type=cq:Page
Note: property name should be fully specified form the type of node we are expecting.
Ex: jcr:content/par/nodeName/xyz above instead of just xyz
I want to display the number of images uploaded to an imagefield, in a views field or views tpl.php. How can I do this? My imagefield is called boatimages. I tried this but it comes out as 0, not the correct number: < ? php print count($fields->field_boatimages) ?>
Ack. I do not think count() works like that.
Why not just do this using Views? Take a look at Arguments > Settings and you'll see 'display record count' which seems like all you would need for this.
My suggestion is install the devel module and use the function dpm to print the variable if you wanna know the structure (print_r() may work too). If count isn't working it's because, you are probably using it with the wrong data.
OR, you could just query the database for the field. I'm gonna provide you instructions for drupal 7 but drupal 6 should be similar.
Check the table field_data_field_boatimages. See how there's a list of your images related with a single entity_id
Then execute this query
SELECT COUNT(*) FROM `field_data_field_boatimages` WHERE entity_id = ###
Where ### is the entity_id you want to know. You can get it by looking for arg(1) if arg(0) == node in your page.
Now you just have to use php power to print thar result
$query = SELECT COUNT(*) FROM `field_data_field_boatimages` WHERE entity_id = :eid
$result = db_query($query, array(':eid', $nid))->fetchField();
echo $result;
Drupal 6 would be very similar. Just a little difference in the table names and the query syntax. For example using db_result instead of fetchField()
Anyway good luck!
I tried to grab the latest N records with a unique value (first_name).
So far:
#users = User.all(:limit => 5, :sort => [:created_at, :desc]).distinct(:first_name)
almost works..But ignores the limit and sort order
Also:
#users = User.limit(5).desc(:created_at).distinct(:first_name)
Ignores both 'limit' and 'desc'
#users = User.limit(5)
Works..
What am I doing wrong?
Any help would be greatly appreciated!
I played with this for a little while and this is the best I could come up with.
Good luck.
#users = User.desc(:created_at).reduce([]) do |arr, user|
unless arr.length == 5 || arr.detect{ |u| u.first_name == user.first_name }
arr << user
end
arr
end
Have you tried using a pagination gem such as amatsuda / kaminari and limiting the results using page().per()?
Both distinct and count ignore the limit command in Mongoid. With count you can pass true (i.e. User.limit(5).count(true)) to force it to pay attention to the scope. Unfortunately there is no such trick for distinct as far as I'm aware (see docs/source here).
If you want to just grab the first 5 first_name's you can do this (not distinct):
User.desc(:created_at).limit(5).map(&:first_name)
This will respect the limit, but still load 5 full objects from the database (then discard the rest of the object to give you full name). If you actually need to run distinct, you're better off heading toward an aggregation framework solution.
I haven't tested, but this seems to be what you're looking for: https://stackoverflow.com/a/17568267/127311
I played with some result I found this.
User.limit(2).count => 10 #but in array I found only two results
User.limit(2).to_a.count => 2
May be limit gives the correct result, but count query gives wrong result.
so in my query i have select columnx from tblz
it returns 001.255556.84546
I want to be able to split this via '.' and put it into three columns.
column1 = 001
column2 = 255556
column3 = 84576
is this possible?
For info, in 2008 these dont work, you have to do the following:
=Split(Fields!returnedValue.Value, ".").GetValue(0)
Create three calculated fields with the following expressions:
=(Split(Fields!columnx.Value, ".")).GetValue(0)
=(Split(Fields!columnx.Value, ".")).GetValue(1)
=(Split(Fields!columnx.Value, ".")).GetValue(2)
I'm not sure it works or not, maybe give it a try. You might need to use IIF() statement to check values before getting them.
In SSRS you reference the field name, tell it the delimiter to use. Since you are not assigning to a variable, per se, you then need to tell it which part of the split string to use. In your example
=Split(Fields!returnedValue.Value,".")(0)
=Split(Fields!returnedValue.Value,".")(1)
=Split(Fields!returnedValue.Value,".")(2)
You would replace returnedValue with whatever the actual field name is, and place each one of those into your columns 1 - 3, respectively.
This answer was originally posted in the question instead of being posted as an answer:
=(Split(Fields!columnx.Value,".")).GetValue(0)
=(Split(Fields!columnx.Value,".")).GetValue(1)
=(Split(Fields!columnx.Value,".")).GetValue(2)