I have the following awk commmand..i want to make "issue-Fixed" as case-insensitive,can anyone provide inputs on how this can be done,i looked at http://www.unix.com/shell-programming-scripting/20196-case-insensitive-serach-awk.html but this doesnt seem to work for me
awk '/link|issue-Fixed:/{print $2}' foo.txt | sed 'N; y/\n/ /'
This might work for you:
awk '/link|[Ii][Ss][Ss][Uu][Ee]-[Ff][Ii][Xx][Ee][Dd]:/{print $2}' foo.txt | sed 'N; y/\n/ /'
Related
I need to modify the 5 to 9 column directly in each line from a file.
Currently i'm doing this in a while loop, getting each column by line.
For example a line looks like:
echo "m.mustermann#muster.com;surnanme;givenname;displayname;1111;2222;3333;44(#44;(5555"
line_9=$(echo $line | awk -F "[;]" '{print $9}' | sed 's/[^0-9+*,]*//g')
Is there a possibility to do that with "sed -i" instead of awk
Thanks for any help
I'm not sure it can be done generally in sed, but you could definitely do it in awk:
… | awk -F";" '{ gsub("[^0-9]*","",$9); print $9 }'
If you really want to do it with sed, the expression will look something like:
… | sed -e 's,\(^[^;]*;[^;]*;[^;]*;[^;]*;[^;]*;[^;]*;[^;]*;[^;]*;[0-9]*\)[^0-9]*\([0-9]*\)[^0-9]*\([0-9]*\)[^0-9]*\([0-9]*\)[^0-9]*\([0-9]*\)[^0-9]*\([0-9]*\)[^0-9]*\([0-9]*\)[^0-9]*\([0-9]*\)[^0-9]*\([0-9]*\)\(.*\),\1\2\3\4\5\6\7\8\9,'
For a version with sed (posix) only
line_9="$(echo $line | sed 'H;x;s/^\(.\)\(\([^;]*;\)\{8\}\)\([^;]*\)/\2\1\4\1/;h;s/\(\n\).*\1/\1/;x;s/.*\(\n\)\(.*\)\1.*/\2/;s/[^0-9+*,]*//g;G;s/\(.*\)\(\n\)\(.*\)\2/\3\1/;h;s/.*//;x' )"
This is probably a trivial one:
I have a file (my.file) with these lines:
>h1_c1
>h1_c2
>h1_c3
>h2_c1
>h2_c2
>h2_c3
and I want to change it in place to be:
>c1_h1
>c2_h1
>c3_h1
>c1_h2
>c2_h2
>c3_h3
I thought this ought to do it:
sed -i 's/\(\>\)\(h1\)\(\_\)\(.*\)/\1 \4 \3 \2/g' my.file
sed -i 's/\(\>\)\(h2\)\(\_\)\(.*\)/\1 \4 \3 \2/g' my.file
but it doesn't seem to work. How do I do it?
The obvious sed for your example is:
$ sed -i~ -e 's/^>\(h[0-9]\)_\(c[0-9]\)/>\2_\1/' *.foo
I tested this and it works for your example file.
Try this awk
awk -F">|_" '{print ">"$3"_"$2}' my.file > tmp && mv tmp my.file
awk -F">|_" '{print ">"$3"_"$2}' my.file
>c1_h1
>c2_h1
>c3_h1
>c1_h2
>c2_h2
>c3_h2
You can try this sed,
sed 's/>\(h[1-2]\)_\(.*\)/>\2_\1/' yourfile
(OR)
sed -r 's/>(h[1-2])_(.*)/>\2_\1/' yourfile
kent$ sed -r 's/>([^_]*)_(.*)/>\2_\1/' f
>c1_h1
>c2_h1
>c3_h1
>c1_h2
>c2_h2
>c3_h2
you add -i if you want it to happen "in-place"
I want to use sed to do this. I have 2 files:
keys.txt:
host1
host2
test.txt
host1 abc
host2 cdf
host3 abaasdf
I want to use sed to remove any lines in test.txt that contains the keyword in keys.txt. So the result of test.txt should be
host3 abaasdf
Can somebody show me how to do that with sed?
Thanks,
I'd recommend using grep for this (especially fgrep since there are no regexps involved), so
fgrep -v -f keys.txt test.txt
does it fine. With sed quickly this works:
sed -i.ORIGKEYS.txt ^-e 's_^_/_' -e 's_$_/d_' keys.txt
sed -f keys.txt test.txt
(This modifies the original keys.txt in place - with backup - to a sourceable sed script.)
fgrep -v -f is the best solution. Here are a couple of alternatives:
A combination of comm and join
comm -13 <(join keys.txt test.txt) test.txt
or awk
awk 'NR==FNR {key[$1]; next} $1 in key {next} 1' keys.txt test.txt
This might work for you (GNU sed):
sed 's|.*|/^&\\>/d|' keys.txt | sed -f - test.txt
I have a line:
<random junk>TYPE=snp;<more random junk>
and I need to return everything between the end of TYPE= and the ; (in this case snp but it could be any of a number of text strings.
I tried various sed / awk solutions but I can't seem to get it working. I have the feeling this is a simple problem so, sorry about that.
This seems to work:
sed 's/.*TYPE=\(.*\);.*/\1/'
EDIT:
Ah, so there can be semicolons in the random junk. Try this:
sed 's/.*TYPE=\([^;]*\);.*/\1/'
requires GNU grep:
grep -Po '(?<=TYPE=)[^;]+'
meaning: preceded by "TYPE=", find some non-semicolon characters
One way using GNU sed:
sed -r 's/.*TYPE=([^;]+).*/\1/' file.txt
Since you also tagged this awk:
$ text='<random junk>TYPE=snp;<more random junk>'
$ echo "$text" | awk -FTYPE= '{sub(/;.*/,"",$2); print $2}'
snp
$ text='foo=bar;baz=fnu;TYPE=snp;XAI=0;XAM=0'
$ echo "$text" | awk -FTYPE= '{sub(/;.*/,"",$2); print $2}'
snp
(Only using the variable to keep the lines from wrapping.)
Or, to parse this as set of variable=value pairs rather than just a string of text:
$ echo "$text" | awk -vRS=";" -F= '$1=="TYPE" {print $2}'
snp
You can also do this in pure bash, if you want:
$ t="red=blue;TYPE=snp;XAI=0.0037843;XAM=0.0170293;XAS=0.013245;XRI=0;XRM=0"
$ t=${t#*TYPE=}
$ t=${t%%;*}
$ echo $t
snp
How do I remove the greater than < sign from the beginning of the line ^
file.txt
> INSERT INTO
> INSERT INTO
Expected:
INSERT INTO
INSERT INTO
Give this a try:
sed 's/^> //' inputfile
awk
awk '{gsub(/^[ \t]*>[ \t]*/,"")}1' file
awk '{$1=""}1' file
sed
sed 's/^[ \t]*>[ \t]*//' file
cut
cut -d" " -f2- file
or using the shell
while read -r line; do echo ${line##>}; done < file
awk -F'>' '{print $2}' file.txt