T-SQL XML to retrieve attribute value and the respective element value - tsql

Question

I have an XML column in a table. This column is called UserDef. The Xml looks like this:
<UserDefs>
<UserDef id="EmpNum">002</UserDef>
<UserDef id="EmpDept">AUT</UserDef>
<UserDef id="EmpName">XYZ ABC</UserDef>
<UserDef id="EmpHireDate">2009-11-01T23:59:00-06:00</UserDef>
</UserDefs>
What should the query look like to return a result like this:
Column1 Column2
--------------------
EmpNum 002
EmpDept AUT
EmpName XYZ ABC
EmpHireDate 2009-11-01 23:59:00
Thank you.

Answer 1

declare #xml xml
set #xml = '<UserDefs>
<UserDef id="EmpNum">002</UserDef>
<UserDef id="EmpDept">AUT</UserDef>
<UserDef id="EmpName">XYZ ABC</UserDef>
<UserDef id="EmpHireDate">2009-11-01T23:59:00-06:00</UserDef>
</UserDefs>'
select R.nref.value('./#id[1]','nvarchar(200)') as Column1,
R.nref.value('./text()[1]','nvarchar(200)') as Column2
from #xml.nodes('/UserDefs/*') R(nref);
consider to use proper length for varchar/nvarchar type for your real data
and also you will need to convert date value properly
if we need to select from table:
declare #xml xml
set #xml = '<UserDefs>
<UserDef id="EmpNum">002</UserDef>
<UserDef id="EmpDept">AUT</UserDef>
<UserDef id="EmpName">XYZ ABC</UserDef>
<UserDef id="EmpHireDate">2009-11-01T23:59:00-06:00</UserDef>
</UserDefs>'
declare #txml table(UserDef xml)
insert into #txml values (#xml);
select
a.value('./#id[1]','nvarchar(200)') as Column1,
a.value('./text()[1]','nvarchar(200)') as Column2
from #txml
CROSS APPLY UserDef.nodes('/UserDefs/*') AS tbl(a)