I have a string that I need to seperate into values seperated by commas. I have achieved this part with the below REPLACE statement:
declare #mc varchar(200)
declare #mc1 varchar(200)
select #mc = 'FRED&#g4;g;MARY&#g4;g;BILL&#g4;g;TIMOTHY&#g4;g;JOHNATHAN'
select #mc1 = REPLACE(#mc, '&#g4;g;',', ')
The replace returns a string 'FRED, MARY, BILL, TIMOTHY, JOHNATHAN'
I then want to have another variable that will return the first 3 characters of each value before the commas, so the above string would be returned as:
'FRE, MAR, TIM, JOH'
Anyone know how I can achieve this?
Also happy for this to be done directly to the original #mc variable
ON SQL Server 2017+ you can make use of openJson to split the string into manageble segments and then string_agg to assemble the desired result:
declare #mc varchar(100)='FRED&#g4;g;MARY&#g4;g;BILL&#g4;g;TIMOTHY&#g4;g;JOHNATHAN'
select String_Agg(v, ', ')
from (select #mc)x(s)
cross apply (
select Left(j.[value],3) v, Convert(tinyint,j.[key]) Seq
from OpenJson(Concat('["',replace(s,';', '","'),'"]')) j
where Convert(tinyint,j.[key]) % 2 = 0
)j;
Demo Fiddle
Related
I have 2 varchar(64) values that are decimals in this case (say COLUMN1 and COLUMN2, both varchars, both decimal numbers(money)). I need to create a where clause where I say this:
COLUMN1 < COLUMN2
I believe I have to convert these 2 varchar columns to a different data types to compare them like that, but I'm not sure how to go about that. I tried a straight forward CAST:
CAST(COLUMN1 AS DECIMAL(9,2)) < CAST(COLUMN2 AS DECIMAL(9,2))
But I had to know that would be too easy. Any help is appreciated. Thanks!
You can create a UDF like this to check which values can't be cast to DECIMAL
CREATE OR REPLACE FUNCTION IS_DECIMAL(i VARCHAR(64)) RETURNS INTEGER
CONTAINS SQL
--ALLOW PARALLEL -- can use this on Db2 11.5 or above
NO EXTERNAL ACTION
DETERMINISTIC
BEGIN
DECLARE NOT_VALID CONDITION FOR SQLSTATE '22018';
DECLARE EXIT HANDLER FOR NOT_VALID RETURN 0;
RETURN CASE WHEN CAST(i AS DECIMAL(31,8)) IS NOT NULL THEN 1 END;
END
For example
CREATE TABLE S ( C VARCHAR(32) );
INSERT INTO S VALUES ( ' 123.45 '),('-00.12'),('£546'),('12,456.88');
SELECT C FROM S WHERE IS_DECIMAL(c) = 0;
would return
C
---------
£546
12,456.88
It really is that easy...this works fine...
select cast('10.15' as decimal(9,2)) - 1
from sysibm.sysdummy1;
You've got something besides a valid numerical character in your data..
And it's something besides leading or trailing whitespace...
Try the following...
select *
from table
where translate(column1, ' ','0123456789.')
<> ' '
or translate(column2, ' ','0123456789.')
<> ' '
That will show you the rows with alpha characters...
If the above does't return anything, then you've probably got a string with double decimal points or something...
You could use a regex to find those.
There is a built-in ability to do this without UDFs.
The xmlcast function below does "safe" casting between (var)char and decfloat (you may use as double or as decimal(X, Y) instead, if you want). It returns NULL if it's impossible to cast.
You may use such an expression twice in the WHERE clause.
SELECT
S
, xmlcast(xmlquery('if ($v castable as xs:decimal) then xs:decimal($v) else ()' passing S as "v") as decfloat) D
FROM (VALUES ( ' 123.45 '),('-00.12'),('£546'),('12,456.88')) T (S);
|S |D |
|---------|------------------------------------------|
| 123.45 |123.45 |
|-00.12 |-0.12 |
|£546 | |
|12,456.88| |
I find in my sql database string whit weird whitespace which cannot be replace like REPLACE(string, ' ', '') RTRIM and cant it even find with string = '% %'. This space is even transfered to new table when using SELECT string INTO
If i select this string in managment studio and copy that is seems is normal space and when everything is works but cant do nothing directly from database. What else can i do? Its some kind of error or can i try some special character for this?
First, you must identify the character.
You can do that by using a tally table (or a cte) and the Unicode function:
The following script will return a table with two columns: one contains a char and the other it's unicode value:
DECLARE #Str nvarchar(100) = N'This is a string containing 1 number and some words.';
with Tally(n) as
(
SELECT TOP(LEN(#str)) ROW_NUMBER() OVER(ORDER BY ##SPID)
FROM sys.objects a
--CROSS JOIN sys.objects b -- (unremark if there are not enough rows in the tally cte)
)
SELECT SUBSTRING(#str, n, 1) As TheChar,
UNICODE(SUBSTRING(#str, n, 1)) As TheCode
FROM Tally
WHERE n <= LEN(#str)
You can also add a condition to the where clause to only include "special" chars:
AND SUBSTRING(#str, n, 1) NOT LIKE '[a-zA-Z0-9]'
Then you can replace it using it's unicode value using nchar (I've used 32 in this example since it's unicode "regular" space:
SELECT REPLACE(#str, NCHAR(32), '|')
Result:
This|is|a|string|containing|1|number|and|some|words.
I need to build a SQL statement to be submitted on a linked server. The statement makes use of #parameters and case statements which contain quotation marks.
I found this Microsoft article 'How to pass a variable', which seemed ideal, however I am not able to get everything going. It seems that the linked server is not enabled for the final and neatest suggestion of calling Sp_executesql, so I have been trying the first two examples.
To start with, here is a cut down example of my SQL statement on its own:
SELECT *,
CASE WHEN FLDA = 'ABC' THEN 'DEF' ELSE 'ABC' END AS COL1
FROM MYTABLE
WHERE FLDB = #PARM
1, I can get the query to work when excluding the CASE statement:
DECLARE #TSQL NVARCHAR(4000), #PARM NVARCHAR(10)
SET #PARM = 'ABC'
SET #TSQL = 'SELECT * FROM OPENQUERY(MYLINKEDSERVER, ''
SELECT *
FROM MYTABLE
WHERE FLDA = '''''+#PARM+''''''')'
EXEC (#TSQL)
However I don't understand why I require 5 quotes before #PARM and then 7(!) after it? When coding SQL statements in a string in previous languages just 2 quotations together acted as a single. So why 5 and 7?
2, I can't get the SQL to work at all when attempting to add the CASE statement. I have tried all combinations of 2,3,4 quotations but to no avail: Do I again need a certain amount of opening quotes and then a different amount of closing quotes?
DECLARE #TSQL NVARCHAR(4000), #PARM NVARCHAR(10)
SET #PARM = 'ABC'
SET #TSQL = 'SELECT * FROM OPENQUERY(MYLINKEDSERVER, ''
SELECT *,
CASE WHEN FLDA = ''ABC'' THEN ''DEF'' ELSE ''ABC'' END AS COL1
FROM MYTABLE
WHERE FLDA = '''''+#PARM+''''''')'
EXEC (#TSQL)
Any help greatly appreciated!
Cheers
Mark
my first question was why do I need 5 and 7 quotes, so there was no error message there, but I get the point that I could have listed some of the errors seen when I was getting the incorrect number of quotes.
However the tip to use Print was very useful, so thank you all for that!
So it transpires that I do indeed require a pair of
quotes where a single quote is required. However, as I am creating a SQL string within a string, I need to double that again. So I first need to end my string with a single quote and then add 4 quotes to create the double quote required to proceed the variable - hence 5. And likewise, I need 4 quotes to get a pair of quotes following the variable, another pair of quotes for the quote to end the statement and then a final one to wrap around the end bracket of the OPENQUERY command....I hope that sort of reads correct!
So:
WHERE FLDA = '''''+#PARM+''''''')'
Printed as:
WHERE FLDA = ''ABC''')
And for my CASE statement, I required 4 set of quotes, to equate to 2. So:
CASE WHEN FLDA = ''''ABC'''' THEN ''''DEF'''' ELSE ''''ABC'''' END AS COL1
Printed as:
CASE WHEN FLDA = ''ABC'' THEN ''DEF'' ELSE ''ABC'' END AS COL1
I want to implement a stored procedure that extract letters from a varchar in firebird.
Example :
v_accountno' is of type varchar(50) and has the following values
accountno 1 - 000023208821
accountno 2 - 390026826850868140H
accountno 3 - 0700765001003267KAH
I want to extract the letters from v_accountno and output it in o_letter.
In my example: o_letter will store H for accountno 2 and KAH for accountno 3.
I tried the following stored procedure, which obviously won't work for accountno 3. (Please help).
CREATE OR ALTER PROCEDURE SP_EXTRACT_LETTER
returns (
o_letter varchar(50))
as
declare variable v_accountno varchar(50);
begin
v_accountno = '390026826850868140H';
if (not (:v_accountno similar to '[[:DIGIT:]]*')) then
begin
-- My SP won't work in for accountno 3 '0700765001003267KAH'
v_accountno = longsubstr(v_accountno, strlen(v_accountno), strlen(v_accountno));
o_letter = v_accountno;
end
suspend;
end
One solution would be to replace every digits with empty string like:
o_letter = REPLACE(v_accountno, '0', '')
o_letter = REPLACE(o_letter, '1', '')
o_letter = REPLACE(o_letter, '2', '')
...
Since Firebird 3, you can use substring for this, using its regex facility (using the similar clause):
substring(v_accountno similar '[[:digit:]]*#"[[:alpha:]]*#"' escape '#')
See also this dbfiddle.
I need to find and replace an expression within a dynamic query. I have a subset of a where condition in string type like
'fieldA=23 OR field_1=300 OR fieldB=4'
What I need is to find a way to detect expression field_1=300 within the string and replace it while retaining the expression field_1=300.
I can do the detection part using CHARINDEX or PATINDEX but I'm not able to figure out how to use the patterns in the REPLACE function and how to get the value of the field_1 parameter.
Thanks in advance.
I'm not entirely clear on what you're trying to acheieve (e.g. what are you wanting to replace "field_1=300" with, and is it the exact string "field_1=300" that you're looking for, or just the field name, i.e. "field_1"?).
Also, could you paste in the code you've written so far?
Here's a simple script which will extract the current value of a given field name:
DECLARE #str VARCHAR(100),
#str_tmp VARCHAR(100),
#field_pattern VARCHAR(10),
#field_val INT;
SET #str = 'fieldA=23 OR field_1=300 OR fieldB=4';
SET #field_pattern = 'field_1='
-- This part will extract the current value assigned to the "#field_pattern" field
IF CHARINDEX(#field_pattern, #str) > 0
BEGIN
SELECT #str_tmp = SUBSTRING(#str,
CHARINDEX(#field_pattern, #str) + LEN(#field_pattern),
LEN(#str)
);
SELECT #field_val = CAST(SUBSTRING(#str_tmp, 1, CHARINDEX(' ', #str_tmp)-1) AS INT);
END
PRINT #field_val
If you want to replace the value itself (e.g. replacing "300" in this case with "600"), then you could add something like this:
DECLARE #new_val INT;
SET #new_val = 600;
SET #str = REPLACE(#str, (#field_pattern+CAST(#field_val AS VARCHAR)), (#field_pattern+CAST(#new_val AS VARCHAR)));
PRINT #str;
Which would give you "fieldA=23 OR field_1=600 OR fieldB=4".
Cheers,
Dave