I'm trying to write a script to find all the periods in the first 11 characters or last 147 characters of each line (lines are fixed width of 193, so I'm attempting to ignore characters 12 through 45).
First I want a script that will just find all the periods from the first or last part of each line, but then if I find them I would like to replace all periods with 0's, but ignore periods on the 12th through 45th line and leaving those in place. It would scan all the *.dat files in the directory and create period free copies in a subfolder. So far I have:
$data = get-content "*.dat"
foreach($line in $data)
{
$line.substring(0,12)
$line.substring(46,147)
}
Then I run this with > Output.txt then do a select-string Output.txt -pattern ".". As you can see I'm a long ways from my goal as presently my program is mashing all the files together, and I haven't figured out how to do any replacement yet.
Get-Item *.dat |
ForEach-Object {
$file = $_
$_ |
Get-Content |
ForEach-Object {
$beginning = $_.Substring(0,12) -replace '\.','0'
$middle = $_.Substring(12,44)
$end = $_.Substring(45,147) -replace '\.','0'
'{0}{1}{2}' -f $beginning,$middle,$end
} |
Set-Content -Path (Join-Path $OutputDir $file.Name)
}
You can use the powershell -replace operator to replace the "." with "0". Then use substring as you do to build up the three portions of the string you're interested in to get the updated string. This will output an updated line for each line of your input.
$data = get-content "*.dat"
foreach($line in $data)
{
($line.SubString(0,12) -replace "\.","0") + $line.SubString(13,34) + ($line.substring(46,147) -replace "\.","0")
}
Note that the -replace operator performs a regular expression match and the "." is a special regular expression character so you need to escape it with a "\".
Related
Every night I got a text file that needs to be edited manually.
The file contains approximately 250 rows. Three example of a rows:
112;20-21;32;20-21;24;0;2;248;271;3;3;;
69;1;4;173390;5;0;0;5460;5464;3;3;;
24;7;4;173390;227;0;0;0;0;3;3;;
I need to replace the two last values in each row.
All rows ending with ;0;3;3;; should be replaced with ;0;17;18;; (the last one, solved)
The logic for the other two:
If the row contain a '-' it should replace the two last values from ;3;3;; to ;21;21;;
If it don´t have a '-' it should replace the two last values from ;3;3;; to ;22;22;;
This is my script
foreach ($file in Get-ChildItem *.*)
{
(Get-Content $file) -replace ';0;3;3;;',';;0;17;18;;' -replace ';3;3;;',';21;21;;' |Out-file -encoding ASCII $file-new}
If I could add a '-' in the end of each row continga a '-' I could solve the issue with a modified script:
(Get-Content $file) -replace ';0;3;3;;',';;0;17;18;;' -replace ';3;3;;-',';22;22;;' -replace ';3;3;;',';21;21;;'|Out-file -encoding ASCII $file-new}`
But how do I add a '-' in the end of a row, if the row contain a '-'?
Best Regards
Mr DXF
I tried with select-string, but I can´t figure it out...
if select-string -pattern '-' {append-text '-'|out-file -encoding ascii $file-new
else end
}
The following might do the trick, it uses a switch with the -Regex flag to read your files and match lines with regular expressions.
foreach ($file in Get-ChildItem *.* -File) {
& {
switch -Regex -File $file.FullName {
# if the line ends with `;3;3;;` but is not preceded by `;0`
'(?<!;0);3;3;;$' {
# if it contains a `-`
if($_.Contains('-')) {
$_ -replace ';3;3;;$', ';21;21;;'
continue
}
# if it doesn't contain a `-`
$_ -replace ';3;3;;$', ';22;22;;'
continue
}
# if the line ends with `';0;3;3;;`
';0;3;3;;$' {
$_ -replace ';0;3;3;;$', ';0;17;18;;'
continue
}
# if none of the above conditions are matched,
# output as is
Default { $_ }
}
} | Set-Content "$($file.BaseName)-new$($file.Extension)" -Encoding ascii
}
Using the content example in question the end result would become:
112;20-21;32;20-21;24;0;2;248;271;21;21;;
69;1;4;173390;5;0;0;5460;5464;22;22;;
24;7;4;173390;227;0;0;0;0;17;18;;
I need to loop through multiple text files and check for a $ value in position 7 on each line of text and replace it with an * when found. But ONLY when it is in position 7. I do not want to change it if it is found in other positions. This is as far as I have gotten. Any help would be greatly appreciated.
Get-ChildItem 'C:\*.txt' -Recurse |
foreach $line in Get-Content $_ {
$linePosition1to5 = $line.Substring(0,6)
$linePosition7 = $line.Substring(6,1)
$linePositionRest = $line.Substring(8)
if($linePosition7 = "$"){
$linePosition7 = "*"
}
$linePosition1to5 + $linePosition7 + $linePositionRest |
Set-Content $_
}
Is there something that doesn't work in your example, or just that all the nested substrings are annoying to work with?
I'd use regex for this one. e.g.
$Lines = Get-Content -Path "C:\examplefile.txt" -raw
$Lines -replace '(?m)(^.{6})\$', '$1*'
To explain the regex:
?m indicates that it's multiline, required because I used raw get-content rather than pulling an array. Array would work too, just needs a loop like you did.
^.{6} line start plus any 6 characters (capture group 1)
$ escaped dollar character
$1* Capture group 1 left as is, dollar replaced with *, anything else not captured and therefore left untouched.
Thanks for code and the explanation. I realized that I left out the -raw option and it did work. Putting it back in it seems to add a line to the end of each file. Unless you can think of reason why I shouldn't I was going to leave it out.
Get-ChildItem 'C:\TEST\*.txt' -Recurse | ForEach {
(Get-Content $_ | ForEach { $_ -replace '(?m)(^.{6})\$', '$1*'}) |
Set-Content $_
}
Can this be done in easily or at all in powershell?
How would one remove all lines from "test.txt" that do not contain exactly 24 words
This is not too hard in PowerShell.
Something like below should do it:
# read the file and use Where-Object to capture only those lines that have 24 words exactly.
# the regex -split uses '\W+', meaning to split each line on (at least one) Non-Word character.
$result = Get-Content -Path 'D:\test.txt' | Where-Object { ($_ -split '\W+').Count -eq 24 }
# output on screen
$result
# write output to new file
$result | Out-File -FilePath 'D:\test24.txt' -Force
I have the following txt file.
[AppRemover]
Enable=0
[CleanWipe]
Enable=0
[RerunSetup]
Enable=0
How do I change the Enable=0 to Enable=1 under [CleanWipe] only?
Below is how I plan on using the code with my file.
$Path = C:\temp\file.txt
$File = Get-Content -Path $Path
# Code to update file
$File | Out-File $Path
You can use -replace to update the value if it is 0.
$Path = C:\temp\file.txt
(Get-Content $Path -Raw) -replace "(?<text>\[CleanWipe\]\r?\nEnable=)0",'${text}1' |
Set-Content $Path
Using a module that parses INI files will be the best solution though. I'd recommend trying PsIni.
Explanation:
The -Raw switch reads the file contents as a single string. This makes it easier to work with newline characters.
-replace performs a regex match and then replace. Below is the regex match breakdown.
(?<text>) is a named capture group. Anything matched within that capture group can be recalled in the replace string as '${text}'.
\[CleanWipe\] is a literal match of [CleanWipe] while escaping the [] characters with \.
\r? is optional carriage return
\n is the newline character
Enable= is a literal match
0 is a literal match
The replace string is the capture group contents and 1 when a match exists. Technically, a capture group is not needed if you want to use a positive lookbehind instead. The positive lookbehind assertion is (?<=). That solution would look like the following:
$Path = C:\temp\file.txt
(Get-Content $Path -Raw) -replace "(?<=\[CleanWipe\]\r?\nEnable=)0",'1' |
Set-Content $Path
The problem with the -replace solutions as they written is they will update the file regardless of a change actually being made to the contents. You would need to add an extra comparison to prevent that. Other issues could be extra white space on any of these lines. You can account for that by adding \s* where you think those possibilities may exist.
Alternative With More Steps:
$file = Get-Content $Path
$TargetIndex = $file.IndexOf('[CleanWipe]') + 1
if ($file[$TargetIndex] -match 'Enable=0') {
$file[$TargetIndex] = 'Enable=1'
$file | Set-Content $Path
}
This solution will only update the file if it meets the match condition. It uses the array method IndexOf() to determine where [CleanWipe] is. Then assumes the line you want to change is in the next index.
IndexOf() is not the only way to find an index. The method requires that your line match the string exactly. You can use Select-String (case-insensitive by default) to return a line number. Since it will be a line number and not an index (indexes start at 0 while line numbers start at 1), it will invariably be the index number you want.
$file = Get-Content $Path
$TargetIndex = ($file | Select-String -Pattern '[CleanWipe]' -SimpleMatch).LineNumber
if ($file[$TargetIndex] -match 'Enable=0') {
$file[$TargetIndex] = 'Enable=1'
$file | Set-Content $Path
}
I want to be able to split some text out of a txtfile:
For example:
Brackets#Release 1.11.6#Path-to-Brackets
Atom#v1.4#Path-to-Atom
I just want to have the "Release 1.11.6" part. I am doing a where-object starts with Brackets but I don't know the full syntax. Here is my code:
"Get-Content -Path thisfile.txt | Where-Object{$_ < IM STUCK HERE > !
You could do this:
((Get-Content thisfile.txt | Where-Object { $_ -match '^Brackets' }) -Split '#')[1]
This uses the -match operator to filter out any lines that don't start with Brackets (the ^ special regex character indicates that what follows must be at the beginning of the line). Then it uses the -Split operator to split those lines on # and then it uses the array index [1] to get the second element of the split (arrays start at 0).
Note that this will throw an error if the split on # doesn't return at least two elements and it assumes that the text you want is always the second of those elements.
$bracketsRelease = Get-Content -path thisfile.txt | foreach-object {
if ( $_ -match 'Brackets#(Release [^#]+)#' )
{
$Matches[1]
}
}
or
(select-string -Path file.txt -Pattern 'Brackets#(Release [^#]+)#').Matches[0].Groups[1].value