I want to be able to split some text out of a txtfile:
For example:
Brackets#Release 1.11.6#Path-to-Brackets
Atom#v1.4#Path-to-Atom
I just want to have the "Release 1.11.6" part. I am doing a where-object starts with Brackets but I don't know the full syntax. Here is my code:
"Get-Content -Path thisfile.txt | Where-Object{$_ < IM STUCK HERE > !
You could do this:
((Get-Content thisfile.txt | Where-Object { $_ -match '^Brackets' }) -Split '#')[1]
This uses the -match operator to filter out any lines that don't start with Brackets (the ^ special regex character indicates that what follows must be at the beginning of the line). Then it uses the -Split operator to split those lines on # and then it uses the array index [1] to get the second element of the split (arrays start at 0).
Note that this will throw an error if the split on # doesn't return at least two elements and it assumes that the text you want is always the second of those elements.
$bracketsRelease = Get-Content -path thisfile.txt | foreach-object {
if ( $_ -match 'Brackets#(Release [^#]+)#' )
{
$Matches[1]
}
}
or
(select-string -Path file.txt -Pattern 'Brackets#(Release [^#]+)#').Matches[0].Groups[1].value
Related
Every night I got a text file that needs to be edited manually.
The file contains approximately 250 rows. Three example of a rows:
112;20-21;32;20-21;24;0;2;248;271;3;3;;
69;1;4;173390;5;0;0;5460;5464;3;3;;
24;7;4;173390;227;0;0;0;0;3;3;;
I need to replace the two last values in each row.
All rows ending with ;0;3;3;; should be replaced with ;0;17;18;; (the last one, solved)
The logic for the other two:
If the row contain a '-' it should replace the two last values from ;3;3;; to ;21;21;;
If it don´t have a '-' it should replace the two last values from ;3;3;; to ;22;22;;
This is my script
foreach ($file in Get-ChildItem *.*)
{
(Get-Content $file) -replace ';0;3;3;;',';;0;17;18;;' -replace ';3;3;;',';21;21;;' |Out-file -encoding ASCII $file-new}
If I could add a '-' in the end of each row continga a '-' I could solve the issue with a modified script:
(Get-Content $file) -replace ';0;3;3;;',';;0;17;18;;' -replace ';3;3;;-',';22;22;;' -replace ';3;3;;',';21;21;;'|Out-file -encoding ASCII $file-new}`
But how do I add a '-' in the end of a row, if the row contain a '-'?
Best Regards
Mr DXF
I tried with select-string, but I can´t figure it out...
if select-string -pattern '-' {append-text '-'|out-file -encoding ascii $file-new
else end
}
The following might do the trick, it uses a switch with the -Regex flag to read your files and match lines with regular expressions.
foreach ($file in Get-ChildItem *.* -File) {
& {
switch -Regex -File $file.FullName {
# if the line ends with `;3;3;;` but is not preceded by `;0`
'(?<!;0);3;3;;$' {
# if it contains a `-`
if($_.Contains('-')) {
$_ -replace ';3;3;;$', ';21;21;;'
continue
}
# if it doesn't contain a `-`
$_ -replace ';3;3;;$', ';22;22;;'
continue
}
# if the line ends with `';0;3;3;;`
';0;3;3;;$' {
$_ -replace ';0;3;3;;$', ';0;17;18;;'
continue
}
# if none of the above conditions are matched,
# output as is
Default { $_ }
}
} | Set-Content "$($file.BaseName)-new$($file.Extension)" -Encoding ascii
}
Using the content example in question the end result would become:
112;20-21;32;20-21;24;0;2;248;271;21;21;;
69;1;4;173390;5;0;0;5460;5464;22;22;;
24;7;4;173390;227;0;0;0;0;17;18;;
I have a text file that I would like to read and do some replacements using powershell only if the line starts with a specific character.
SAy i want to change all the dash (-) to an 'x' if and only if the line starts with a y.
I tried using the command
(Get-Content trial.log2) | Foreach-Object {$_ -replace "-", 'x'} | Set-Content trial.log2
However, it actually replaces all occurrences of the dash, not only for the line the starts with a y.
Can this be also done if I want to have multiple find replace and string manipulation using one get content command?
I have another string manipulation but only if it starts with an F
If line starts with an F, then get first 4 characters of the line, then append 'NEW' then get the next characters from character 20 to 30.
if line starts with a y, then do a replace of - with an X.
$F=(get-content $file) -like 'F*'
(Get-Content $file) | Foreach-Object {
$_ -replace "^F.+", -join("$F".Substring(0,4), "$NEW3",
} | Set-Content trial.log2
Get-Content trial.log2 | ForEach-Object {
if ( $_ -match '^y' ) {
$_ -replace '-', 'X'
}
else {
$_
}
} | Set-Content trial.log3
However, if i do this, texts are being written twice. I think there is something wrong with how I look for the line that starts with the F
Any help is appreciated. Thanks!
You can use a look-behind ((?<=pattern)) to assert that the preceding characters include a y following the start of the string:
(Get-Content trial.log2) | Foreach-Object {$_ -replace '(?<=^y.*)-','x'} | Set-Content trial.log2
How about something like:
Get-Content trial.log2 | ForEach-Object {
if ( $_ -match '^y' ) {
$_ -replace '-', 'x'
}
else {
$_
}
} | Out-File trial.log2.temp
I have a lot of .txt files where I need to lowercase content in between two characters - after "%" and before ";".
The code below makes all content in the files lowercase and I need it to only do it in all instances between the two characters as mentioned.
$path=".\*.txt"
Get-ChildItem $path -Recurse | foreach{
(Get-Content $_.FullName).ToLower() | Out-File $_.FullName
}
Here an example using regex replace with a callback function to perform the lowercase:
$path=".\*.txt"
$callback = { param($match) $match.Groups[1].Value.ToLower() }
$rex = [regex]'(?<=%)(.*)(?=;)'
Get-ChildItem $path -Recurse | ForEach-Object {
$rex.Replace((Get-Content $_ -raw), $callback) | Out-File $_.FullName
}
Explanation:
The regex uses a positive lookbehind to find the position of % and a lookahead for the position of ; and caputes everything between in a group:
The caputred group gets passed to the callbackfunction which invokes ToLower() on it.
I used the below steps to retrieve a string from file
$variable = 'abc#yahoo.com'
$test = $variable.split('#')[0];
$file = Get-Content C:\Temp\file1.txt | Where-Object { $_.Contains($test) }
$postPipePortion = $file | Foreach-Object {$_.Substring($_.IndexOf("|") + 1)}
This results in all lines that contain $test as a substring. I just want the result to contain only the lines that exactly matches $test.
For example, If a file contains
abc_def|hf#23$
abc|ohgvtre
I just want the text ohgvtre
If I understand the question correctly you probably want to use Import-Csv instead of Get-Content:
Import-Csv 'C:\Temp\file1.txt' -Delimiter '|' -Header 'foo', 'bar' |
Where-Object { $_.foo -eq $test } |
Select-Object -Expand bar
To address the exact matching, you should be testing for equality (-eq) rather than substring (.Contains()). Also, there is no need to parse the data multiple times. Here is your code, rewritten to to operate in one pass over the data using the -split operator.
$variable = 'abc#yahoo.com'
$test = $variable.split('#')[0];
$postPipePortion = (
# Iterate once over the lines in file1.txt
Get-Content C:\Temp\file1.txt | foreach {
# Split the string, keeping both parts in separate variables.
# Note the backslash - the argument to the -split operator is a regex
$first, $second = ($_ -split '\|')
# When the first half matches, output the second half.
if ($first -eq $test) {
$second
}
}
)
I'm trying to write a script to find all the periods in the first 11 characters or last 147 characters of each line (lines are fixed width of 193, so I'm attempting to ignore characters 12 through 45).
First I want a script that will just find all the periods from the first or last part of each line, but then if I find them I would like to replace all periods with 0's, but ignore periods on the 12th through 45th line and leaving those in place. It would scan all the *.dat files in the directory and create period free copies in a subfolder. So far I have:
$data = get-content "*.dat"
foreach($line in $data)
{
$line.substring(0,12)
$line.substring(46,147)
}
Then I run this with > Output.txt then do a select-string Output.txt -pattern ".". As you can see I'm a long ways from my goal as presently my program is mashing all the files together, and I haven't figured out how to do any replacement yet.
Get-Item *.dat |
ForEach-Object {
$file = $_
$_ |
Get-Content |
ForEach-Object {
$beginning = $_.Substring(0,12) -replace '\.','0'
$middle = $_.Substring(12,44)
$end = $_.Substring(45,147) -replace '\.','0'
'{0}{1}{2}' -f $beginning,$middle,$end
} |
Set-Content -Path (Join-Path $OutputDir $file.Name)
}
You can use the powershell -replace operator to replace the "." with "0". Then use substring as you do to build up the three portions of the string you're interested in to get the updated string. This will output an updated line for each line of your input.
$data = get-content "*.dat"
foreach($line in $data)
{
($line.SubString(0,12) -replace "\.","0") + $line.SubString(13,34) + ($line.substring(46,147) -replace "\.","0")
}
Note that the -replace operator performs a regular expression match and the "." is a special regular expression character so you need to escape it with a "\".