Breaking when a method returns null in the Eclipse debugger - eclipse

I'm working on an expression evaluator. There is an evaluate() function which is called many times depending on the complexity of the expression processed.
I need to break and investigate when this method returns null. There are many paths and return statements.
It is possible to break on exit method event but I can't find how to put a condition about the value returned.

I got stuck in that frustration too. One can inspect (and write conditions) on named variables, but not on something unnamed like a return value. Here are some ideas (for whoever might be interested):
One could include something like evaluate() == null in the breakpoint's condition. Tests performed (Eclipse 4.4) show that in such a case, the function will be performed again for the breakpoint purposes, but this time with the breakpoint disabled. So you will avoid a stack overflow situation, at least. Whether this would be useful, depends on the nature of the function under consideration - will it return the same value at breakpoint time as at run time? (Some s[a|i]mple code to test:)
class TestBreakpoint {
int counter = 0;
boolean eval() { /* <== breakpoint here, [x]on exit, [x]condition: eval()==false */
System.out.println("Iteration " + ++counter);
return true;
}
public static void main(String[] args) {
TestBreakpoint app = new TestBreakpoint();
System.out.println("STARTED");
app.eval();
System.out.println("STOPPED");
}
}
// RESULTS:
// Normal run: shows 1 iteration of eval()
// Debug run: shows 2 iterations of eval(), no stack overflow, no stop on breakpoint
Another way to make it easier (to potentially do debugging in future) would be to have coding conventions (or personal coding style) that require one to declare a local variable that is set inside the function, and returned only once at the end. E.g.:
public MyType evaluate() {
MyType result = null;
if (conditionA) result = new MyType('A');
else if (conditionB) result = new MyType ('B');
return result;
}
Then you can at least do an exit breakpoint with a condition like result == null. However, I agree that this is unnecessarily verbose for simple functions, is a bit contrary to flow that the language allows, and can only be enforced manually. (Personally, I do use this convention sometimes for more complex functions (the name result 'reserved' just for this use), where it may make things clearer, but not for simple functions. But it's difficult to draw the line; just this morning had to step through a simple function to see which of 3 possible cases was the one fired. For today's complex systems, one wants to avoid stepping.)
Barring the above, you would need to modify your code on a case by case basis as in the previous point for the single function to assign your return value to some variable, which you can test. If some work policy disallows you to make such non-functional changes, one is quite stuck... It is of course also possible that such a rewrite could result in a bug inadvertently being resolved, if the original code was a bit convoluted, so beware of reverting to the original after debugging, only to find that the bug is now back.

You didn't say what language you were working in. If it's Java or C++ you can set a condition on a Method (or Function) breakpoint using the breakpoint properties. Here are images showing both cases.
In the Java example you would unclik Entry and put a check in Exit.
Java Method Breakpoint Properties Dialog
!
C++ Function Breakpoint Properties Dialog

This is not yet supported by the Eclipse debugger and added as an enhancement request. I'd appreciate if you vote for it.
https://bugs.eclipse.org/bugs/show_bug.cgi?id=425744

Related

Swift - understanding return types in recursion: when should return the function vs. just return on its own

This may be a little too general for this forum, but hoping someone can explain this in a way that makes sense to my brain. I've tried reading and researching and have found lots of examples - but I still don't understand the "why" which means that I am not understanding exactly how a program comes back from a function return.
Here is a very simple function I wrote that solves a puzzle using backwards recursion. It works well.
func solver(grid: [[Int]])->[[Int]] {
var returnGrid = constraintPropogation(grid: grid)
if contradictionCheck(grid: returnGrid) == false {
return returnGrid
} else {
if returnGrid.flatMap({$0}).filter({$0 == 3}).count == 0 {
print("SOLVED**********")
gridPrint(grid: returnGrid)
print()
stopFlag = true
stopAnswer = returnGrid
return returnGrid
} else {
let randStart = getRandomStart(grid: returnGrid)
returnGrid[randStart.x][randStart.y] = 0
solver(grid: returnGrid)
returnGrid[randStart.x][randStart.y] = 1
solver(grid: returnGrid)
}
}
if stopFlag == true {return stopAnswer}
return solver(grid: returnGrid)
}
My issue is understanding the returns. In the third line of the function if a contradiction check fails this means that we've gone down a path that would not be possible. Therefore we return. That makes sense. The second return in the middle of the function occurs when the puzzle is solved, so it makes sense to return there. But the last one at the end "return solver(grid: returnGrid)" is challenging to my understanding. Here we are returning but also calling this same function again. This is not going deeper into the potential solution path (that happens in the "else" section where the function is called). Why do we need to call the function again rather than just returning? What is happening under the hood? Does the return happen first where we "pop back up a level" and then we are calling the function again effectively one rung higher on the stack? When I write these words I realize that I have a vague understanding - but somehow it is not all clicking together for me.
Am at the point now that when I'm writing functions that involve recursion I just try both returning on own or returning and calling function again to see which one achieves what I want. But I'd really like to understand it rather than just guessing. If anyone had a simple explanation I would appreciate it.
Your function solver takes an array of arrays, and returns an array of arrays. Any call to return(something) returns that something to the caller.
Saying return(someArrayOfArrays) means you are done, and have a result.
Saying return(solver(someArrayOfArrays)) says "call this function again, passing in a new value. Return whatever the result is as the function result." The current call to solver() is done doing work, and passes its intermediate results to another call to the function. That's the recursion. You can think of this as nesting a function call inside a function call inside a function call, or stacking function calls on top of each other.
The call to solver(grid: returnGrid) does not make any sense. That is a recursive call, but you ignore the result. Thus, that call does nothing useful. If your remove that line, it won't make any difference to the outcome. That line is saying "Go do a bunch of work and find an answer for me, but I will throw away your answer". The compiler should give you a "function result ignored" warning at that line.
Beyond that, I can't tell what your code is doing. It appears to be modifying at least one global variable, "stopAnswer". That suggests it's not a pure recursive function.

Understanding the continuation theorem in Scala

So, I was trying to learn about Continuation. I came across with the following saying (link):
Say you're in the kitchen in front of the refrigerator, thinking about a sandwich. You take a continuation right there and stick it in your pocket. Then you get some turkey and bread out of the refrigerator and make yourself a sandwich, which is now sitting on the counter. You invoke the continuation in your pocket, and you find yourself standing in front of the refrigerator again, thinking about a sandwich. But fortunately, there's a sandwich on the counter, and all the materials used to make it are gone. So you eat it. :-) — Luke Palmer
Also, I saw a program in Scala:
var k1 : (Unit => Sandwich) = null
reset {
shift { k : Unit => Sandwich) => k1 = k }
makeSandwich
}
val x = k1()
I don't really know the syntax of Scala (looks similar to Java and C mixed together) but I would like to understand the concept of Continuation.
Firstly, I tried to run this program (by adding it into main). But it fails, I think that it has a syntax error due to the ) near Sandwich but I'm not sure. I removed it but it still does not compile.
How to create a fully compiled example that shows the concept of the story above?
How this example shows the concept of Continuation.
In the link above there was the following saying: "Not a perfect analogy in Scala because makeSandwich is not executed the first time through (unlike in Scheme)". What does it mean?
Since you seem to be more interested in the concept of the "continuation" rather than specific code, let's forget about that code for a moment (especially because it is quite old and I don't really like those examples because IMHO you can't understand them correctly unless you already know what a continuation is).
Note: this is a very long answer with some attempts to describe what a continuations is and why it is useful. There are some examples in Scala-like pseudo-code none of which can actually be compiled and run (there is just one compilable example at the very end and it references another example from the middle of the answer). Expect to spend a significant amount of time just reading this answer.
Intro to continuations
Probably the first thing you should do to understand a continuation is to forget about how modern compilers for most of the imperative languages work and how most of the modern CPUs work and particularly the idea of the call stack. This is actually implementation details (although quite popular and quite useful in practice).
Assume you have a CPU that can execute some sequence of instructions. Now you want to have a high level languages that support the idea of methods that can call each other. The obvious problem you face is that the CPU needs some "forward only" sequence of commands but you want some way to "return" results from a sub-program to the caller. Conceptually it means that you need to have some way to store somewhere before the call all the state of the caller method that is required for it to continue to run after the result of the sub-program is computed, pass it to the sub-program and then ask the sub-program at the end to continue execution from that stored state. This stored state is exactly a continuation. In most of the modern environments those continuations are stored on the call stack and often there are some assembly instructions specifically designed to help handling it (like call and return). But again this is just implementation details. Potentially they might be stored in an arbitrary way and it will still work.
So now let's re-iterate this idea: a continuation is a state of the program at some point that is enough to continue its execution from that point, typically with no additional input or some small known input (like a return value of the called method). Running a continuation is different from a method call in that usually continuation never explicitly returns execution control back to the caller, it can only pass it to another continuation. Potentially you can create such a state yourself, but in practice for the feature to be useful you need some support from the compiler to build continuations automatically or emulate it in some other way (this is why the Scala code you see requires a compiler plugin).
Asynchronous calls
Now there is an obvious question: why continuations are useful at all? Actually there are a few more scenarios besides the simple "return" case. One such scenario is asynchronous programming. Actually if you do some asynchronous call and provide a callback to handle the result, this can be seen as passing a continuation. Unfortunately most of the modern languages do not support automatic continuations so you have to grab all the relevant state yourself. Another problem appears if you have some logic that needs a sequence of many async calls. And if some of the calls are conditional, you easily get to the callbacks hell. The way continuations help you avoid it is by allowing you build a method with effectively inverted control flow. With typical call it is the caller that knows the callee and expects to get a result back in a synchronous way. With continuations you can write a method with several "entry points" (or "return to points") for different stages of the processing logic that you can just pass to some other method and that method can still return to exactly that position.
Consider following example (in pseudo-code that is Scala-like but is actually far from the real Scala in many details):
def someBusinessLogic() = {
val userInput = getIntFromUser()
val firstServiceRes = requestService1(userInput)
val secondServiceRes = if (firstServiceRes % 2 == 0) requestService2v1(userInput) else requestService2v2(userInput)
showToUser(combineUserInputAndResults(userInput,secondServiceRes))
}
If all those calls a synchronous blocking calls, this code is easy. But assume all those get and request calls are asynchronous. How to re-write the code? The moment you put the logic in callbacks you loose the clarity of the sequential code. And here is where continuations might help you:
def someBusinessLogicCont() = {
// the method entry point
val userInput
getIntFromUserAsync(cont1, captureContinuationExpecting(entry1, userInput))
// entry/return point after user input
entry1:
val firstServiceRes
requestService1Async(userInput, captureContinuationExpecting(entry2, firstServiceRes))
// entry/return point after the first request to the service
entry2:
val secondServiceRes
if (firstServiceRes % 2 == 0) {
requestService2v1Async(userInput, captureContinuationExpecting(entry3, secondServiceRes))
// entry/return point after the second request to the service v1
entry3:
} else {
requestService2v2Async(userInput, captureContinuationExpecting(entry4, secondServiceRes))
// entry/return point after the second request to the service v2
entry4:
}
showToUser(combineUserInputAndResults(userInput, secondServiceRes))
}
It is hard to capture the idea in a pseudo-code. What I mean is that all those Async method never return. The only way to continue execution of the someBusinessLogicCont is to call the continuation passed into the "async" method. The captureContinuationExpecting(label, variable) call is supposed to create a continuation of the current method at the label with the input (return) value bound to the variable. With such a re-write you still has a sequential-looking business logic even with all those asynchronous calls. So now for a getIntFromUserAsync the second argument looks like just another asynchronous (i.e. never-returning) method that just requires one integer argument. Let's call this type Continuation[T]
trait Continuation[T] {
def continue(value: T):Nothing
}
Logically Continuation[T] looks like a function T => Unit or rather T => Nothing where Nothing as the return type signifies that the call actually never returns (note, in actual Scala implementation such calls do return, so no Nothing there, but I think conceptually it is easy to think about no-return continuations).
Internal vs external iteration
Another example is a problem of iteration. Iteration can be internal or external. Internal iteration API looks like this:
trait CollectionI[T] {
def forEachInternal(handler: T => Unit): Unit
}
External iteration looks like this:
trait Iterator[T] {
def nextValue(): Option[T]
}
trait CollectionE[T] {
def forEachExternal(): Iterator[T]
}
Note: often Iterator has two method like hasNext and nextValue returning T but it will just make the story a bit more complicated. Here I use a merged nextValue returning Option[T] where the value None means the end of the iteration and Some(value) means the next value.
Assuming the Collection is implemented by something more complicated than an array or a simple list, for example some kind of a tree, there is a conflict here between the implementer of the API and the API user if you use typical imperative language. And the conflict is over the simple question: who controls the stack (i.e. the easy to use state of the program)? The internal iteration is easier for the implementer because he controls the stack and can easily store whatever state is needed to move to the next item but for the API user the things become tricky if she wants to do some aggregation of the stored data because now she has to save the state between the calls to the handler somewhere. Also you need some additional tricks to let the user stop the iteration at some arbitrary place before the end of the data (consider you are trying to implement find via forEach). Conversely the external iteration is easy for the user: she can store all the state necessary to process data in any way in local variables but the API implementer now has to store his state between calls to the nextValue somewhere else. So fundamentally the problem arises because there is only one place to easily store the state of "your" part of the program (the call stack) and two conflicting users for that place. It would be nice if you could just have two different independent places for the state: one for the implementer and another for the user. And continuations provide exactly that. The idea is that we can pass execution control between two methods back and forth using two continuations (one for each part of the program). Let's change the signatures to:
// internal iteration
// continuation of the iterator
type ContIterI[T] = Continuation[(ContCallerI[T], ContCallerLastI)]
// continuation of the caller
type ContCallerI[T] = Continuation[(T, ContIterI[T])]
// last continuation of the caller
type ContCallerLastI = Continuation[Unit]
// external iteration
// continuation of the iterator
type ContIterE[T] = Continuation[ContCallerE[T]]
// continuation of the caller
type ContCallerE[T] = Continuation[(Option[T], ContIterE[T])]
trait Iterator[T] {
def nextValue(cont : ContCallerE[T]): Nothing
}
trait CollectionE[T] {
def forEachExternal(): Iterator[T]
}
trait CollectionI[T] {
def forEachInternal(cont : ContCallerI[T]): Nothing
}
Here ContCallerI[T] type, for example, means that this is a continuation (i.e. a state of the program) the expects two input parameters to continue running: one of type T (the next element) and another of type ContIterI[T] (the continuation to switch back). Now you can see that the new forEachInternal and the new forEachExternal+Iterator have almost the same signatures. The only difference in how the end of the iteration is signaled: in one case it is done by returning None and in other by passing and calling another continuation (ContCallerLastI).
Here is a naive pseudo-code implementation of a sum of elements in an array of Int using these signatures (an array is used instead of something more complicated to simplify the example):
class ArrayCollection[T](val data:T[]) : CollectionI[T] {
def forEachInternal(cont0 : ContCallerI[T], lastCont: ContCallerLastI): Nothing = {
var contCaller = cont0
for(i <- 0 to data.length) {
val contIter = captureContinuationExpecting(label, contCaller)
contCaller.continue(data(i), contIter)
label:
}
}
}
def sum(arr: ArrayCollection[Int]): Int = {
var sum = 0
val elem:Int
val iterCont:ContIterI[Int]
val contAdd0 = captureContinuationExpecting(labelAdd, elem, iterCont)
val contLast = captureContinuation(labelReturn)
arr.forEachInternal(contAdd0, contLast)
labelAdd:
sum += elem
val contAdd = captureContinuationExpecting(labelAdd, elem, iterCont)
iterCont.continue(contAdd)
// note that the code never execute this line, the only way to jump out of labelAdd is to call contLast
labelReturn:
return sum
}
Note how both implementations of the forEachInternal and of the sum methods look fairly sequential.
Multi-tasking
Cooperative multitasking also known as coroutines is actually very similar to the iterations example. Cooperative multitasking is an idea that the program can voluntarily give up ("yield") its execution control either to the global scheduler or to another known coroutine. Actually the last (re-written) example of sum can be seen as two coroutines working together: one doing iteration and another doing summation. But more generally your code might yield its execution to some scheduler that then will select which other coroutine to run next. And what the scheduler does is manages a bunch of continuations deciding which to continue next.
Preemptive multitasking can be seen as a similar thing but the scheduler is run by some hardware interruption and then the scheduler needs a way to create a continuation of the program being executed just before the interruption from the outside of that program rather than from the inside.
Scala examples
What you see is a really old article that is referring to Scala 2.8 (while current versions are 2.11, 2.12, and soon 2.13). As #igorpcholkin correctly pointed out, you need to use a Scala continuations compiler plugin and library. The sbt compiler plugin page has an example how to enable exactly that plugin (for Scala 2.12 and #igorpcholkin's answer has the magic strings for Scala 2.11):
val continuationsVersion = "1.0.3"
autoCompilerPlugins := true
addCompilerPlugin("org.scala-lang.plugins" % "scala-continuations-plugin_2.12.2" % continuationsVersion)
libraryDependencies += "org.scala-lang.plugins" %% "scala-continuations-library" % continuationsVersion
scalacOptions += "-P:continuations:enable"
The problem is that plugin is semi-abandoned and is not widely used in practice. Also the syntax has changed since the Scala 2.8 times so it is hard to get those examples running even if you fix the obvious syntax bugs like missing ( here and there. The reason of that state is stated on the GitHub as:
You may also be interested in https://github.com/scala/async, which covers the most common use case for the continuations plugin.
What that plugin does is emulates continuations using code-rewriting (I suppose it is really hard to implement true continuations over the JVM execution model). And under such re-writings a natural thing to represent a continuation is some function (typically called k and k1 in those examples).
So now if you managed to read the wall of text above, you can probably interpret the sandwich example correctly. AFAIU that example is an example of using continuation as means to emulate "return". If we re-sate it with more details, it could go like this:
You (your brain) are inside some function that at some points decides that it wants a sandwich. Luckily you have a sub-routine that knows how to make a sandwich. You store your current brain state as a continuation into the pocket and call the sub-routine saying to it that when the job is done, it should continue the continuation from the pocket. Then you make a sandwich according to that sub-routine messing up with your previous brain state. At the end of the sub-routine it runs the continuation from the pocket and you return to the state just before the call of the sub-routine, forget all your state during that sub-routine (i.e. how you made the sandwich) but you can see the changes in the outside world i.e. that the sandwich is made now.
To provide at least one compilable example with the current version of the scala-continuations, here is a simplified version of my asynchronous example:
case class RemoteService(private val readData: Array[Int]) {
private var readPos = -1
def asyncRead(callback: Int => Unit): Unit = {
readPos += 1
callback(readData(readPos))
}
}
def readAsyncUsage(rs1: RemoteService, rs2: RemoteService): Unit = {
import scala.util.continuations._
reset {
val read1 = shift(rs1.asyncRead)
val read2 = if (read1 % 2 == 0) shift(rs1.asyncRead) else shift(rs2.asyncRead)
println(s"read1 = $read1, read2 = $read2")
}
}
def readExample(): Unit = {
// this prints 1-42
readAsyncUsage(RemoteService(Array(1, 2)), RemoteService(Array(42)))
// this prints 2-1
readAsyncUsage(RemoteService(Array(2, 1)), RemoteService(Array(42)))
}
Here remote calls are emulated (mocked) with a fixed data provided in arrays. Note how readAsyncUsage looks like a totally sequential code despite the non-trivial logic of which remote service to call in the second read depending on the result of the first read.
For full example you need prepare Scala compiler to use continuations and also use a special compiler plugin and library.
The simplest way is a create a new sbt.project in IntellijIDEA with the following files: build.sbt - in the root of the project, CTest.scala - inside main/src.
Here is contents of both files:
build.sbt:
name := "ContinuationSandwich"
version := "0.1"
scalaVersion := "2.11.6"
autoCompilerPlugins := true
addCompilerPlugin(
"org.scala-lang.plugins" % "scala-continuations-plugin_2.11.6" % "1.0.2")
libraryDependencies +=
"org.scala-lang.plugins" %% "scala-continuations-library" % "1.0.2"
scalacOptions += "-P:continuations:enable"
CTest.scala:
import scala.util.continuations._
object CTest extends App {
case class Sandwich()
def makeSandwich = {
println("Making sandwich")
new Sandwich
}
var k1 : (Unit => Sandwich) = null
reset {
shift { k : (Unit => Sandwich) => k1 = k }
makeSandwich
}
val x = k1()
}
What the code above essentially does is calling makeSandwich function (in a convoluted manner). So execution result would be just printing "Making sandwich" into console. The same result would be achieved without continuations:
object CTest extends App {
case class Sandwich()
def makeSandwich = {
println("Making sandwich")
new Sandwich
}
val x = makeSandwich
}
So what's the point? My understanding is that we want to "prepare a sandwich", ignoring the fact that we may be not ready for that. We mark a point of time where we want to return to after all necessary conditions are met (i.e. we have all necessary ingredients ready). After we fetch all ingredients we can return to the mark and "prepare a sandwich", "forgetting that we were unable to do that in past". Continuations allow us to "mark point of time in past" and return to that point.
Now step by step. k1 is a variable to hold a pointer to a function which should allow to "create sandwich". We know it because k1 is declared so: (Unit => Sandwich).
However initially the variable is not initialized (k1 = null, "there are no ingredients to make a sandwich yet"). So we can't call the function preparing sandwich using that variable yet.
So we mark a point of execution where we want to return to (or point of time in past we want to return to) using "reset" statement.
makeSandwich is another pointer to a function which actually allows to make a sandwich. It's the last statement of "reset block" and hence it is passed to "shift" (function) as argument (shift { k : (Unit => Sandwich).... Inside shift we assign that argument to k1 variable k1 = k thus making k1 ready to be called as a function. After that we return to execution point marked by reset. The next statement is execution of function pointed to by k1 variable which is now properly initialized so finally we call makeSandwich which prints "Making sandwich" to a console. It also returns an instance of sandwich class which is assigned to x variable.
Not sure, probably it means that makeSandwich is not called inside reset block but just afterwards when we call it as k1().

return inside a switch block yields "unreachable code" warning

I'm writing UnityScript code and at one point in my program, I want to terminate a function from within a switch block. This is a boiled down version of my code:
function Move(target: int) {
var targetTransform : Transform;
switch (target) {
case 0:
// do something including assigning targetTransform
break;
case 1:
// do something including actually moving my object
return; // since I moved already, I want the function to terminate here
default:
// do something including assigning targetTransform
}
object.Move(targetTransform); // object is locally available
}
Now for whatever reason, the Compiler gives me a
Assets/Scripts/GameMaster.js(490,9): BCW0015: WARNING: Unreachable code detected.
The line is the one containing the switch.
From my previous research, I found many similar problems, but all of them had actually unreachable code, like for example break statements after the returns or a return at the end even though each and every case returned at some point. This is not the case here, I just want one of my cases to return out of the function altogether, while the others shall break out of the switch and go on from there.
Is there a way to get rid of this warning? What is causing it in the first place, is this just a bug?
If at all possible, I'd prefer not to use a boolean and check for it after the switch block... This just seems like overkill only to terminate one case early.
This bug exists at least since 2010. Although it's perfectly legal to use a return statement instead of a break, the compiler will complain about unreachable code.
You have basically two options
ignore the warning and keep your code nice and clean
work around the warning by replacing the return with a boolean + break and check for the boolean after the switch block
As far as I know you can't even disable or suppress the warning. It's possible in C# but UnityScript seems to lack this feature. So this would result in a third possible solution: convert your code to C# :-)

Using LuaJ with Scala

I am attempting to use LuaJ with Scala. Most things work (actually all things work if you do them correctly!) but the simple task of setting object values has become incredibly complicated thanks to Scala's setter implementation.
Scala:
class TestObject {
var x: Int = 0
}
Lua:
function myTestFunction(testObject)
testObject.x = 3
end
If I execute the script or line containing this Lua function and pass a coerced instance of TestObject to myTestFunction this causes an error in LuaJ. LuaJ is trying to direct-write the value, and Scala requires you to go through the implicitly-defined setter (with the horrible name x_=, which is not valid Lua so even attempting to call that as a function makes your Lua not parse).
As I said, there are workarounds for this, such as defining your own setter or using the #BeanProperty markup. They just make code that should be easy to write much more complicated:
Lua:
function myTestFunction(testObject)
testObject.setX(testObject, 3)
end
Does anybody know of a way to get luaj to implicitly call the setter for such assignments? Or where I might look in the luaj source code to perhaps implement such a thing?
Thanks!
I must admit that I'm not too familiar with LuaJ, but the first thing that comes to my mind regarding your issue is to wrap the objects within proxy tables to ease interaction with the API. Depending upon what sort of needs you have, this solution may or may not be the best, but it could be a good temporary fix.
local mt = {}
function mt:__index(k)
return self.o[k] -- Define how your getters work here.
end
function mt:__newindex(k, v)
return self.o[k .. '_='](v) -- "object.k_=(v)"
end
local function proxy(o)
return setmetatable({o = o}, mt)
end
-- ...
function myTestFunction(testObject)
testObject = proxy(testObject)
testObject.x = 3
end
I believe this may be the least invasive way to solve your problem. As for modifying LuaJ's source code to better suit your needs, I had a quick look through the documentation and source code and found this, this, and this. My best guess says that line 71 of JavaInstance.java is where you'll find what you need to change, if Scala requires a different way of setting values.
f.set(m_instance, CoerceLuaToJava.coerce(value, f.getType()));
Perhaps you should use the method syntax:
testObject:setX(3)
Note the colon ':' instead of the dot '.' which can be hard to distinguish in some editors.
This has the same effect as the function call:
testObject.setX(testObject, 3)
but is more readable.
It can also be used to call static methods on classes:
luajava.bindClass("java.net.InetAddress"):getLocalHost():getHostName()
The part to the left of the ':' is evaluated once, so a statement such as
x = abc[d+e+f]:foo()
will be evaluated as if it were
local tmp = abc[d+e+f]
x = tmp.foo(tmp)

Eclipse JUNIT: Why is it possible to sometimes do a compare on a failed assertequals(String,String) but not always

I thought at first the compare option only appears for a test if the assertequals is between 2 strings, which makes sense. I believe i have also fired a failNotEquals(String1,String2) and the compare option comes up as well. I have done this when the object does not implement equals or perhaps i wish to compare for equality using my own rules and failing if that fails. However i have noticed a few times here and there sometimes failNotequals(String,String) does not enable the "compare" option. Am i missing something ???
CLARIFICATION of COMPARE option
The >compare< option is a menu option that is available when one right clicks on a failed junit item from the gui where it creates a tree with items for each "test". Often theres also a >print stack trace< option.
You get the "compare" option, when the end result of the test is a junit.framework.ComparisonFailure object. In that case you can see a visual comparison of the two objects (Strings for example) and check how they differ from each other.
Other types of results, such as a java.lang.IllegalAccessError, aren't parsed to that effect, as Eclipse doesn't know (and cannot deduce) that you were comparing two objects that lead to such a result, so it doesn't offer you the same visual boons.
I am not entirely sure what you mean by
failNotEquals does not enable the "compare" option
Here are a couple of thoughts.
failNotEquals takes three arguments, not two:
failNotEquals(message, expected, actual);
Even if strings would print out the same, they are NOT the same object. You need to tell JUnit how to compare them.
Consider this small, working test case.
import junit.framework.TestCase;
public class DemoTest extends TestCase {
public void testSomething() {
String a = "Hello";
assertTrue("Strings should be the same", "Hello".equals(a));
failNotEquals("Strings should be the same", "Hello", a);
}
}
The assertTrue works, but the failNotEquals does not.
The assertTrue is probably what you want. The "Hello".equals(a) will compare the strings properly. You can also use a equalsIgnoreCase here.
I'm guessing that the failNotEquals is probably close to what you are using. It fails with a java.lang.IllegalAccessError.