I'm trying to use Exiftool to write metadata for my tif type file. Everything was fine until I try to write value for Keyword in metadata. I found that Keyword only accepts 64 characters at one time. I also found that by using + symbol we managed to write more than 64 characters in Keyword, but it was separated by ; for each keyword I wrote. For an example, if I write Keyword 3 times using the + it added ; 3 times. Is there anyway I can write the Keyword without the ;. Please advice. Thanks
Have you tried using the "-sep" option before writing the tags
-sep", "
See 17. "List-type tags do not behave as expected"
Related
I am having some difficulty getting linebreaks to work for my Unity UI elements. (Unity 2019.2.17f1 Personal)
What I'm doing is:
string twoLinesOfText = LanguagePack.getTextByID(ID);
result:
twoLinesOfText = "Text line 1\nText line 2"
Expected output:
Text line 1
Text line 2
Reality:
Text line 1\nText line 2
I have tried using "\n", "\\n" and "\r\n". None of these give the intended result.
I assign the text to the component using
UITextComponent.GetComponent<Text>().text = twoLinesOfText;
Can this direct assignment be a problem? Do i need to push my string through a toString() or parse it somehow for the \n to be recognised?
Workaround:
I have a workaround. By using an XML file for my LanguagePack, and inserting (enter) linebreaks in the base file, I feed the linebreaks into my Unity UI elements. Obviously this is not ideal.
Reading back the strings in Debug.Log does not show which linebreak code was ultimately used: it just breaks the string according to the (enter) linebreaks in the XML file.
You can't import it trought Language Package. What you should do is :
string line1 = LanguagePackage.getTextByID(ID1);
string line2 = LanguagePackage.getTextByID(ID2);
string twoLinesOfText = line1 + "\n" + line2;
UITextComponent.GetComponent<Text>().text = twoLinesOfText;
Run into this problem myself, a little investigation showed that what I thought was \n in the string had been converted to \\n so it showed in the text box as \n.
Converting it during debugging to just \n got me the multiline text I wanted.
Now to investigate where in my data chain it got converted :-)
Ok, investigation complete. A file was saved, on my PC from a program in Visual Basic using the File.WriteAllLines function, one of those lines had a couple of instances of \n. A look at that file in notepad shows it had correctly written that line. The problem came when I used File.ReadAllLines in my unity program as it converted those \n instances to \\n. As far as I can tell this is not a documented action, in fact it's possible, on reading the MS docs, to think that it would have split that line into multiple lines, which it doesn't do.
I checked in my VB program and File.ReadAllLines does not behave in this way there. It's probably something to do with the environment, VB does not use \n, C# does. I fixed the problem by tagging a replace onto the string e.g. string.Replace("\\n", "\n"). It's entirely possible that attempting to write a string from C# with File.WriteAllLines could also mess with \n.
Geez, this was hard to write as the Editor here messes with \\n and convert it to \n and I end up having to use \\\n
For people who encounter this issue. You Could try to use some HTML similar syntax and see whether it works or not.
Eg:
Using for newline instead of \n
I am building some tables in org-mode and I need to enter "||" into the table (for the logical OR command) and nothing I try turns the two characters off as table constructors.
I've tried single quotes, double quotes, backticks and prefacing them with '\'. I've also tried every permutation of using ':=' to get a literal string and they don't work.
// Tony Williams
Depending on what you want to do with the output of the table, you could use alternative unicode characters that look like vertical pipes (or double vertical pipes). Examples:
This is the pipe character written twice (as for logical OR):
||
Those are similar (or not too different) looking unicode characters
‖ - ¦¦ - ❘❘
Of course, this won't work for you if you are not just interested in the looks (but escaping pipes would not work either).
See here more unicode characters you might like better than those 3 above
It turns out that you can use HTML entities in org-mode tables for output via pandoc.
\vert{} doesn't work but I went to the table pointed to by MrSpock and tried the HTML entity and the output when run through pandoc was perfect. || gives me '||'. I also tested a few other HTML entities and they also worked fine.
Well, if the goal is to export your notes, then
$\lvert\mathbb{N}\rvert$
would be an equivalent of
$|\mathbb{N}|$
Character is: \vert
Example: a \vert\ b -> a | b
I'm converting a rather large old fix-format code written in Fortran 77 to free-format. Within the code I frequently encounter read statements like
DOUBLE PRECISION :: VARIABLE
read(1,10) VARIABLE
10 format(2A10)
However, what it reads from input file is in fact a line of string. The code runs perfectly fine, but it crashes when one tries to read VARIABLE from a namelist instead of a fixed format input file.
How is this possible in Fortran? Is there any reference where I can find more information about?
Any help is greatly appreciated.
This comes from the days before F77 when doubles and integers were used for storing characters. From the format statement, this is probably from a CDC which could store 10 six bit characters in each word. Double precision was two words so it was two lots of 10 characters. If you change the code to
CHARACTER(LEN=20) VARIABLE
READ(1,10) VARIABLE
10 FORMAT(A20)
It should work. There isn't a lot of information about on CDC compilers. I've never tried using a namelist with one so I can't really comment about it. Try http://bitsavers.trailing-edge.com/pdf/cdc/cyber/cyber_70/chippewa/Chippewa_Fortran-Run_Apr66.pdf
I've prepared a macro in Notepad++ to transform a ldif file in a csv file with a few fields. Everything is OK but I have a final problem: I have to have 2 fields with a specific length and in this moment I cannot ensure that length because in the source file they are not coming so
For instance, I generate this line:
12345,namenamename,123456
And I have to ensure that the 2nd and 3rd fields have 30 (filling with spaces at right side) and 9 (filling with zeros at left) characters, so in this case I should generate:
12345,namenamename ,000123456
I haven't found how Notepad++ could match a pattern in order to add spaces/zeros, so I have though in to add 1 space/zero to the proper field and repeat this step so many times as needed to ensure the lengths (this is, 29 and 8, because they cannot come empty) and search with the length in the regex (for instance: \d{1,8} for the third field)
My question is: can I repeat only one step of the macro several times (and the rest of the macro only 1 repetition)?
I've read the wiki related to this point (http://sourceforge.net/apps/mediawiki/notepad-plus/index.php?title=Editing_Configuration_Files#.3CMacros.3E) and I don't found anything neither
If not possible, how could be a good solution? Create another 2 different macros and after execute the main one, execute this new 2 macros several times?
Thanks in advance!
A two pass solution with Notepad++ is possible. Find a pair of characters or two short sequence of characters that never occurs in your data file. I will use =#<= and =>#= here.
First pass, generate or convert the input text into the form 12345,=#<=namenamename______________________________,000000000123456=>#=. Ie add 30 spaces after the name and nine zeroes before the number (underscores used here just to make things clearer).
Second pass, do a regular expression search for =#<=(.{30})_*,0*(\d{9})=>#= and replace with \1,\2.
I have just suggested a similar solution in special timestamp format of csv
I have an NSArray of lines (objective-c iphone), and I'm trying to find the line which starts with a number, followed by a dot and a space, but can have any number of spaces (including none) before it, and have any text following it eg:
1. random text
2. text random
3.
what regular expression would I use to get this? (I'm trying to learn it, and I needed the above expression anyway, so I thought I'd use it as an example)
With C#:
#"^ *[0-9]+\. "
It doesn't check for the presence of something after the ., so this is legal:
1.(space)
If you delete the # and escape the \ it should work with other languages (it is pretty "down-to-earth" as RegExpes go)
I may suggest (Perl-compatible regexp):
^\s*\d+\.\s
At the beginning of a line:
Any number (0-n) of spaces
One or more digits
A dot
A space
Something like
^\s*\d+\.
But it depends on the language.
/^\s*[0-9]+\.\s+/
would be my guess providing you don't have any space before the number