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I have an image (620x1024), that I want to turn into a same sized image of equally luminous red. What do?
Is this the type of thing you're looking for?
function h = redifyImage(fname, luminosity)
img = imread(fname);
img(:,:,2:3) = 0;
img(:,:,1) = luminosity;
h = image(img);
end
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i want to display some data into a label but it is not showing the full text. How can i fix this behaviour ? I set the lines to 0, but is still not working.
Set horizontal compression resistance to 1000 (Required).
You can do it in the storyboard or programmatically.
label.setContentCompressionResistancePriority(.required, for: .horizontal)
Don't set a guaranteed height like equal 50 set a minimum height like >= 50 that ways it will keep on expanding as required.
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I have Two Offset to draw Line using Custom Painter, i need to check these offsets are in straight line (horizontally). how do i check? If not it is not in a straight line, how to change offset.
Two lines are horizontally straight if they share the same dy property.
To check if they are the same you can do:
Offset o1 = ...;
Offset o2 = ...;
if(o1.dy == o2.dy) {
// horizontal line
}
else {
// not horizontal
}
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I have an image which I have converted to a binary mask.
My regions of interest are those with 1 in the mask.
I want to find the coordinates of these regions,
and go to the original image (same dimensions) so I can crop the unprocessed part of the image.
You can use this answer to get a bounding box from your binary mask.
Once you have the bounding box (rect variable in the aforementioned answer) you can use imcrop to crop the original image around it
cIm = imcrop( origImg, rect );
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I am doing an image processing project. In my project there is an GUI file that reads an image and processing it for segmentation. while reading an image file, initially it is checking the size of that image... However, I don't understand what the function I=[m x n x 4] really means. Could someone explain this to me?
Your image I is of size m pixels high by n pixels wide and has 4 channels: Red, Green, Blue and an alpha channel.
Matlab stores I as a 3D array, you can access the x-y-th pixel by I(y,x,:) returning the four-vector representing the RGBA value of the x-y-th pixel.
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I want to get lat long of rectangle in format "[51.49, -0.1], [51.48, -0.06]" means only diagonal lat long.
I am using getLatLngs(). It gives all four co-ordinates of rectangle.
if (type === 'rectangle') {
pt = layer.getLatLngs();
}
You can use getLatLngs():
var latLngs = rect.getLatLngs();
var diagonal = [latLngs[1], latLngs[3]];
or you can use getBounds():
var bounds = rect.getBounds();
var diagonal = [bounds.getNorthWest(), bounds.getSouthEast()];