How can i display the full text on a label? [closed] - swift

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i want to display some data into a label but it is not showing the full text. How can i fix this behaviour ? I set the lines to 0, but is still not working.

Set horizontal compression resistance to 1000 (Required).
You can do it in the storyboard or programmatically.
label.setContentCompressionResistancePriority(.required, for: .horizontal)

Don't set a guaranteed height like equal 50 set a minimum height like >= 50 that ways it will keep on expanding as required.

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Draw stright line using customPainter in flutter [closed]

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I have Two Offset to draw Line using Custom Painter, i need to check these offsets are in straight line (horizontally). how do i check? If not it is not in a straight line, how to change offset.
Two lines are horizontally straight if they share the same dy property.
To check if they are the same you can do:
Offset o1 = ...;
Offset o2 = ...;
if(o1.dy == o2.dy) {
// horizontal line
}
else {
// not horizontal
}

What type of color is this 0xfffbb448? [closed]

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I am learning flutter in most of my UI tutorial they are using this type of color code
0xfffbb448
I need to know what type is it? Where I can find these color codes? Try to find on google but not able to find which type of color code is this.
The color code 0xFFfbb448 is how you define a hexadecimal color in flutter. It starts with 0x, then 2 digits that represents the opacity/transparency, and then the last 6 digits is the color code Hex #.
You can get the 6 digit color code # from many sources such as https://htmlcolorcodes.com/ or https://www.w3schools.com/colors/colors_picker.asp
You may also find the 2 digits transparency code from sources such as https://gist.github.com/lopspower/03fb1cc0ac9f32ef38f4
An example:
Colors.blue.withopacity(0.5) would be the same as Color(0x800000FF)
where 80 means 50% opacity, and #0000FF is Hex color code for blue
There are many sources out there and similar questions like the below link to find out more.
How do I use hexadecimal color strings in Flutter?

Determination of area of circular object in image [closed]

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I want to determine area of circular object in image below using MATLAB. Can someone explain codes for doing that? I got thresholded image but I did not proceed more.
If the binary image is img, and it contains only values 0 (background) and 1 (object), or it is a logical array containing true and false, and all the object pixels are considered part of the object, then sum(img(:)) is the area of the object in pixels.
If the segmented image contains multiple objects, or noise, it will have to be filtered first to leave only the pixels that belong to the one object.
To convert the area in pixels to an area in physical units you need to know the size of a pixel. This is often obtained by adding a ruler to the image.

LaTeX: Put a dot next to a page number [closed]

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I'm currently working on my thesis, and one of the requirements is to put a dot just next to the page number (which is at the top right corner).
This is the code that I am using for the moment. It does everything that I want except for the dot...
\usepackage{fancyhdr}
\pagestyle{fancy}
\fancyhf{} % sets both header and footer to nothing
\renewcommand{\headrulewidth}{0pt} %Deletes the horizontal bar
\fancyhead[R]{\thepage} %puts the page number to the right
Could someone help me with my problem ?
Thank you in advance.
Use something like \hspace to \thepage:
\fancyhead[R]{\thepage \hspace{1 mm} . } %adjust 1 mm to any value as needed
Just put the dot after the \thepage;
\documentclass{article}
\usepackage{fancyhdr}
\pagestyle{fancy}
\fancyhf{}
\renewcommand{\headrulewidth}{0pt}
\fancyhead[R]{\thepage.}
\begin{document}
See the page number in the top-right corner.
\end{document}
The result:

Issue with red hues in image processing with image [closed]

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I have an image (620x1024), that I want to turn into a same sized image of equally luminous red. What do?
Is this the type of thing you're looking for?
function h = redifyImage(fname, luminosity)
img = imread(fname);
img(:,:,2:3) = 0;
img(:,:,1) = luminosity;
h = image(img);
end