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I have Two Offset to draw Line using Custom Painter, i need to check these offsets are in straight line (horizontally). how do i check? If not it is not in a straight line, how to change offset.
Two lines are horizontally straight if they share the same dy property.
To check if they are the same you can do:
Offset o1 = ...;
Offset o2 = ...;
if(o1.dy == o2.dy) {
// horizontal line
}
else {
// not horizontal
}
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i want to display some data into a label but it is not showing the full text. How can i fix this behaviour ? I set the lines to 0, but is still not working.
Set horizontal compression resistance to 1000 (Required).
You can do it in the storyboard or programmatically.
label.setContentCompressionResistancePriority(.required, for: .horizontal)
Don't set a guaranteed height like equal 50 set a minimum height like >= 50 that ways it will keep on expanding as required.
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I want to determine area of circular object in image below using MATLAB. Can someone explain codes for doing that? I got thresholded image but I did not proceed more.
If the binary image is img, and it contains only values 0 (background) and 1 (object), or it is a logical array containing true and false, and all the object pixels are considered part of the object, then sum(img(:)) is the area of the object in pixels.
If the segmented image contains multiple objects, or noise, it will have to be filtered first to leave only the pixels that belong to the one object.
To convert the area in pixels to an area in physical units you need to know the size of a pixel. This is often obtained by adding a ruler to the image.
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I have an image which I have converted to a binary mask.
My regions of interest are those with 1 in the mask.
I want to find the coordinates of these regions,
and go to the original image (same dimensions) so I can crop the unprocessed part of the image.
You can use this answer to get a bounding box from your binary mask.
Once you have the bounding box (rect variable in the aforementioned answer) you can use imcrop to crop the original image around it
cIm = imcrop( origImg, rect );
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I have an image (620x1024), that I want to turn into a same sized image of equally luminous red. What do?
Is this the type of thing you're looking for?
function h = redifyImage(fname, luminosity)
img = imread(fname);
img(:,:,2:3) = 0;
img(:,:,1) = luminosity;
h = image(img);
end
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I want to get lat long of rectangle in format "[51.49, -0.1], [51.48, -0.06]" means only diagonal lat long.
I am using getLatLngs(). It gives all four co-ordinates of rectangle.
if (type === 'rectangle') {
pt = layer.getLatLngs();
}
You can use getLatLngs():
var latLngs = rect.getLatLngs();
var diagonal = [latLngs[1], latLngs[3]];
or you can use getBounds():
var bounds = rect.getBounds();
var diagonal = [bounds.getNorthWest(), bounds.getSouthEast()];