SQL Give me the name of all the people that I sent the same file - tsql

Question

I have a table that includes the userID that sent the file, the userID that the file was sent to, the filename and the date it was sent.
http://sqlfiddle.com/#!6/855cc6
I'm trying to get a statement that returns one row per filename sent with the list of records (one per file sent) with the names of the people I sent it to at the end of the row
Something like this:
01/08/2014 | "main doc" | "Jon P, Mike S, Ron W"
04/04/2014 | "other doc" | "Jon P, Mike S"
10/10/2014 | "last doc" | "Ron W"
(where the date is the oldest instance of the DateSent datetime field).
Sorry I don't know how to create functions in sqlfiddler so let's assume that there is a scalar function named "GetName(UserID)" that returns a name of the user passed as parameter. It returns one row only.

Answer 1

You can use FOR XML PATH to concatenate values like this:
SELECT DISTINCT
DateSent,
FileName,
SUBSTRING
(
(
SELECT CONCAT(',', t1.SentToUserID) --maybe GetName(t1.SentToUserID)
FROM FileSent t1
WHERE t1.FileName = t2.FileName AND t1.DateSent = t2.DateSent AND t1.UserID = t2.UserID
ORDER BY t1.FileName
FOR XML PATH ('')
), 2, 1000
) [SentFiles]
FROM FileSent t2
ORDER BY DateSent
Sample SQL Fiddle (two slightly different versions).
To get just the minimum date you can use MIN(DateSent) and GROUP BY on FileName and UserId
SELECT DISTINCT
MIN(DateSent) DateSent,
FileName,
STUFF ((SELECT CONCAT(',', t1.SentToUserID)
FROM FileSent T1
WHERE t1.FileName = t2.FileName AND t1.UserID = t2.UserID
FOR XML PATH('')
),1,1,'' ) [SentFiles]
FROM FileSent T2
GROUP BY FileName, UserID
SQL Fiddle for this.