I have to calculate the difference in days between two dates and I figured out that
there is no such thing as a DATEDIFF() function in DB2.
I tried doing it like that:
(DAYOFYEAR(date1)-DAYOFYEAR(date2)+(YEAR(date1)-YEAR(date2))*365)
This is obviously not working for leap years, but I do not have to deal with that.
I know that date1 is always later than date2.
Do I have any flaws in my logic? It is not working (it's an exercise and I have a function to test my results). Is there an easier way to do that?
Thank you.
It would possibly help if we knew what version of DB2 you were using and what platform it was running on. But it seems likely that you can do something like this:
select
days(my1stdate) - days(my2nddate) as myDuration
from mySchema.myTable
The DAYS() function converts a DATE value into the number of days between Jan 1, 0001, and the supplied DATE value. Once both DATEs are converted, the subtraction (difference) is straightforward.
Related
I have created a simple generic inquiry that shows some data after joining two tables. I am now struggling to implement a condition that should make the result only contain rows where a date field is equal to yesterday date.
I am a bit annoyed as Acumatica has created the method `today()` neatly, but not a `yesterday()` or `tomorrow()`.
Does anyone have a good solution that they care to share?
Help is much appreciated,
Cheers.
P.s
I have made this very hackish solution that somewhat works, but breaks between change in month or year.
=CStr(Year(Today()))+CStr(Month( Today() ))+CStr( Day(Today())-1)
Okay, so I found the solution to my problem!
I read that Acumatica is coded C# and.NET which made me think of how adding dates is done there. You utilise the DateAdd(date, interval, number) under the time tab to create relative changes to date.
In this case, the date is the time source from where you want to change, interval is in which interval/dimension you wanna move, for example, 'd' is for days. You can find more prefixes here: crosspost. Lastly, number is how much you want to change in the interval, in my case -1.
TLDR; Use DateAdd(Today(), 'd', -1) to get the previous date in relation to the current date.
You can simply write Equals to #Today-1 for Yesterday like below:
I am trying to find a date difference In Impala. I have tried a few options. my most recent is below
ABS(dayofyear(CAST(firstdate AS TIMESTAMP)-dayofyear(CAST(seconddate AS TIMESTAMP)
an example of data looks like:
firstDate:
2017-11-25
secondDate: 2017-11-30
The solution that I am looking for in the above scenario would be five. The provided code would give me this answer, but the trouble comes in when the first date is in december and the second one ends in January.
Firstdate: 2016-12-30 seconddate:2017-12-30
with the above code this gives me an output of 358 days,the outcome that I would want to see is 8 days. This code is only looking at what day of the year this falls on, and is not able to consider moving from year to year. I know that there is no datediff function on Impala and I've also tried using just subtraction on the two timestamps but that didn't work either. I have scoured google and have come back empty any suggestions would be greatly appreciated
SQL
SELECT DATEDIFF(TO_DATE(firstdate), TO_DATE(seconddate));
Is this what you are looking for?
I have found similar help, but the issue was more complex, I am only good with the basics of SQL and am striking out here. I get a handful of columns a,b,c,startdate,enddate and i need to parse that data out into multiple rows depending on how many months are within the range.
Eg: a,b,c,1/1/2015, 3/15,2015 would become:
a,b,c,1/1/2015,value_here_doesnt_matter
a,b,c,2/1/2015,value_here_doesnt_matter
a,b,c,3/1/2015,value_here_doesnt_matter
Does not matter if the start date or end date is on a specific day, the only thing that matters is month and year. So if the range included any day in a given month, I'd want to output start days for each month in the range, with the 1st as a default day.
Could I have any advice on which direction to begin? I'm attempting generate_series, but am unsure if this is the right approach or how to make it work with keeping the data in the first few arbitrary columns consistent.
I think generate_series is the way to go. Without knowing what the rest of your data looks like, I would start with something like this:
select
a, b, c, generate_series(startdate, enddate, interval '1 month')::date
from
my_table
I want to calculate the number of days passed between past date and a current date. My past date is in the format dd/mm/yyyy format. I have used below mentioned formulas but giving the proper output.
=DAYS360(A2,TODAY())
=MINUS(D2,TODAY())
In the above formula A2 = 4/12/2012 (dd/mm/yyyy) and I am not sure whether TODAY returns in dd/mm/yyyy format or not. I have tried using 123 button on the tool bar, but no luck.
The following seemed to work well for me:
=DATEDIF(B2, Today(), "D")
DAYS360 does not calculate what you want, i.e. the number of days passed between the two dates – see the end of this post for details.
MINUS() should work fine, just not how you tried but the other way round:
=MINUS(TODAY(),D2)
You may also use simple subtraction (-):
=TODAY()-D2
I made an updated copy of #DrCord’s sample spreadsheet to illustrate this.
Are you SURE you want DAYS360? That is a specialized function used in the
financial sector to simplify calculations for bonds. It assumes a 360 day
year, with 12 months of 30 days each. If you really want actual days, you'll
lose 6 days each year.
[source]
Since this is the top Google answer for this, and it was way easier than I expected, here is the simple answer. Just subtract date1 from date2.
If this is your spreadsheet dates
A B
1 10/11/2017 12/1/2017
=(B1)-(A1)
results in 51, which is the number of days between a past date and a current date in Google spreadsheet
As long as it is a date format Google Sheets recognizes, you can directly subtract them and it will be correct.
To do it for a current date, just use the =TODAY() function.
=TODAY()-A1
While today works great, you can't use a date directly in the formula, you should referencing a cell that contains a date.
=(12/1/2017)-(10/1/2017) results in 0.0009915716411, not 61.
I used your idea, and found the difference and then just divided by 365 days. Worked a treat.
=MINUS(F2,TODAY())/365
Then I shifted my cell properties to not display decimals.
If you are using the two formulas at the same time, it will not work...
Here is a simple spreadsheet with it working:
https://docs.google.com/spreadsheet/ccc?key=0AiOy0YDBXjt4dDJSQWg1Qlp6TEw5SzNqZENGOWgwbGc
If you are still getting problems I would need to know what type of erroneous result you are getting.
Today() returns a numeric integer value: Returns the current computer system date. The value is updated when your document recalculates. TODAY is a function without arguments.
The following worked for me. Kindly note that TODAY() must NOT be the first argument in the function otherwise it will not work.
=DATEDIF( W2, TODAY(), "d")
Today() does return value in DATE format.
Select your "Days left field" and paste this formula in the field
=DAYS360(today(),C2)
Go to Format > Number > More formats >Custom number format and select the number with no decimal numbers.
I tested, it works, at least in new version of Sheets, March 2015.
I am using Objective-C within X-code.
I am iterating through a dictionary which contains a date value as one of it's keys. All I want to do is get an array of all the distinct dates so I can use them in a table, as headers. I just plan on
iterating the dictionary and adding dates to a mutable array each time I encounter a new date.
I must set previous date to new date for comparisons to work and I am having a very difficult time figuring out how to set one date equal to another date.
This seems like it should be such a simple thing to do and I am trying to avoid converting the dates to strings first - but if that's what I have to do, then so be it.
Any help would be appreciated.
Thanks,
Gerry O.
If you know the time offset is same as GMT, you could do it by dividing the date's timestamp by 86400 seconds (or three more 0s in milliseconds) and comparing those. If a time offset is there, add or subtract by 3600 seconds per hour before you divide them. But then again, leap years and seconds would break that...
Most languages have libraries support extracting the year, date, month, etc. They take everything into account, usually.
In Objc, you can get a NSDateComponents from NSCalendar's components:fromDate: method. After this, you can call the components to see exactly what each component (I suggest year, month, day) is.
I think you want code to compare dates and You need two loops nested.... where in outer loops iterates with conditional inner loop... In inner loop you just check that previously you had the same date or not...
please go through the below post on same site...
How to compare two dates in Objective-C
hope you will get solution... else clarify your question....