How to create a specific date in Google Script - date

I have a spreadsheet that asks people to enter in a day of the month when we need to send out a bill. What I want to do is create a calendar event based on that. So, essentially what I need is an event that starts at the current month, day from the spreadsheet, and continues to a specified point in time.
var monthlyDate = row[6]; // Seventh column, monthly date of payment
var curDate = new Date();
var curMonth = curDate.getMonth();
var curYear = curDate.getYear();
curDate.setDate(curMonth, monthlyDate, curYear);
Logger.log("Day of month: %s", monthlyDate);
Logger.log("Current Date: %s", curDate);
Logger.log("Current Date: %s", Date());
What I'm seeing is that the monthly date is coming in as a float "6.0" for example, and no matter what I enter in for monthlyDate in the setDate line, it keeps setting the date to 10/9/15 (Today is 10/15/15). I've hard-coded that value to many different numbers, but for some reason it's just not working.
How can I create a date (in any format) that follows the scheme "Current Month / Day from Speadsheet / Current Year" ?

The getMonth() method returns a "zero-indexed" number. So, it returns the number 9 for the 10th month. setDate() doesn't set the date, it sets the "Day of the Month". The name of that method is misleading.
Documentation - setDate()
So, the last two parameters that you are using in setDate() are doing nothing. You are setting the day of the month to 9.
If you want to set multiple date parameters at the same time, you need to use the new Date() method:
var d = new Date(year, month, day, hours, minutes, seconds, milliseconds);
The month parameter accept values from 0 to 11, 0 is Jan and 11 is Dec
Date Reference

Related

Create agent and give its population different id/names and stop each id delay on different time

I have an agent and set its parameter Name and give 3 different names
What I want to do is stop the delay of each name on a different calendar date. How I can achieve that?
You can get the current year, month and day with the following functions:
int getYear(Date date) — returns the year of the current date.
int getMonth(Date date) — returns the month of the current date: one of the constants JANUARY, FEBRUARY, etc.
int getDayOfMonth(Date date)— returns the day of the month of the current date: 1, 2, …
Based on these, you can get the first agent in the delay block with delay.get(0) and use if function.
Pseudo-code like this;
if (date==x){
if (delay.get(0)==myAgents.get(0)){
stopDelay(delay.get(0));
}
}
or
if (date==x){
if (delay.get(0).Name=="yyy"){
stopDelay(delay.get(0));
}
}

Calculate a Reference Date in DAX

Trying to nail down the syntax for a pretty straightforward problem.
I have a table called Events and a full-feature DATES table with a relationship between the Dates[Date] field.
Using the event name as a slicer, I trying to create a [First Monday] measure that will return the date of the first Monday of the month.
So for example, if my event date was 2/14/19, [First Monday] would return 2/4/19.
Your Date table needs to contain 2 columns:
Year-Month: for example, "2018-01"
Weekday Number: for example, 1 (for Monday); or Weekday Name (i.e, "Monday")
Then:
First Monday =
CALCULATE( MIN('Date'[Date]),
ALL('Date'),
VALUES('Date'[Year-Month]),
'Date'[Weekday Name] = "Monday")
How it works:
First, we need to access all dates in the Date table, so we use ALL()
Second, we need to see only dates for the current context year and month, for which we can use VALUES()
Third, for each month we only want Mondays, hence Date[Weekday] = "Monday"
All this unfiltering/filtering generates a set of Mondays for the Year-Month visible in the current filter context. All we need to do now is to find the earliest of the Mondays using Min(Date).

Calculate next pay day in Swift

I am trying to do some math calculations in Swift and getting a bit stuck.
Essentially we get paid every 4th Friday, and I want to do a calculation that based on today's date, works out how many days until our next Pay Day.
I've got a reference day of "28/03/2008",
In order to calculate the next 4th Friday of the month, you need a combination of the right DateComponents and Calendar.
// The 4th Friday at noon
let payDayComps = DateComponents(hour: 12, weekday: 6, weekdayOrdinal: 4)
// Given the current date, calculate the next 4th Friday at noon
let nextPayDay = Calendar.current.nextDate(after: Date(), matching: payDayComps, matchingPolicy: .nextTime)
You don't need a past reference date for this if your goal is to get the next 4th Friday based on today's date. Change the value of the after parameter if you need to calculate the 4th Friday based on some other specific date.
If this is run on the 4th Friday of a month then it will return today's date if run before noon and it will return the 4th Friday of the next month if run after noon. Change the hour value in payDayComps if you want different results (such as 0 for midnight).
To calculate the number of days until that next pay day you can do:
let daysToPayDay = Calendar.current.dateComponents([.day], from: Date(), to: nextPayDay).day!

MS Access 2010 (Design View): return Monday of the current week with Monday as 1st day of the week

I need to make my Access query always return the Monday of the current week. I have seen a few solutions on Google/StackOverflow but they are written in SQL and I am a beginner in creating Access queries (I am using the Design view to make them).
Goal: The week should be considered as M T W T F S S. Then, the query should always return the Monday of the current week. Therefore, if it is Sunday, it should still return the Monday before, NOT the next week's Monday. Can anyone explain how to do this using the Design View in Access 2010?
Keep in mind that in this context we are working with dates, so if we do Date() - 1, we will get 1 day prior to today.
Date() ~ Today's date
DatePart(
"w" - Weekday
Date() - Today's date
2 - vBMonday (Access assumes Sunday is the first day of the week, which is why this is necessary.)
1 - vbFirstJan1 - This gets into using the first week of the year. We could have omitted this, as 1 is the default.
)
-1 - Subtract 1 from the DatePart value.
Values
Date() = 4/27/2015 (at time of this writing)
DatePart("w",Date(),2,1) = 1
DatePart("w",Date(),2,1)-1 = 0
So we have Date()-0... Okay, what's so great about that? Well, let's look at a more useful scenario where today's date is a day other than Monday.
Let's act like today is 4/28/2015 (Tuesday)
Date() = 4/28/2015
DatePart("w",Date(),2,1) = 2
DatePart("w",Date(),2,1)-1 = 1
So, from the outside, in; give me the current weekday value. (1 = Monday, 2 = Tuesday, etc.), and subtract 1 from that -> that's how many days we need to subtract from the current date to get back to the weekday value of 1 (Monday).
Here's a function that will do this:
Public Function DatePrevWeekday( _
ByVal datDate As Date, _
Optional ByVal bytWeekday As VbDayOfWeek = vbMonday) _
As Date
' Returns the date of the previous weekday, as spelled in vbXxxxday, prior to datDate.
' 2000-09-06. Cactus Data ApS.
' No special error handling.
On Error Resume Next
DatePrevWeekday = DateAdd("d", 1 - Weekday(datDate, bytWeekday), datDate)
End Function
As vbMonday is 2 and your date is today, you can use the core expression in a query:
PreviousMonday: DateAdd("d",1-Weekday(Date(),2),Date())

Modifying date in ColdFusion

How can I adjust a date in coldfusion to get the next day at 1AM?
the date is taken from a database, and stored as a string. I'm thinking the way to do it is through CreateDateTime and filling it with the time and date using year,month,day + 1 etc.
I'm just worried that it won't work when the next day falls on the next month
Using DateAdd() you can always be sure that it will take the context of the current date into account. So if it is August 31 and you add one day it will correctly make the date Sept 1st. It will also properly switch the year if you did the same on Dec 31st.
<cfset nextDate = dateAdd("d", 1, now()) />
<cfset nextDateWithTime = createDateTime(year(nextDate), month(nextDate), day(nextDate), 1, 0, 0) />
<cfoutput>#nextDateWithTime#</cfoutput>
Assuming the date is something which CF recognizes as a date, and contains date only, without time, you could do something like:
<cfscript>
function tomorrowOneAM(date) {
var resultValue = DateAdd("d",1,date);
resultValue = DateAdd("h",1,resultValue);
return resultValue;
}
</cfscript>