I have an agent and set its parameter Name and give 3 different names
What I want to do is stop the delay of each name on a different calendar date. How I can achieve that?
You can get the current year, month and day with the following functions:
int getYear(Date date) — returns the year of the current date.
int getMonth(Date date) — returns the month of the current date: one of the constants JANUARY, FEBRUARY, etc.
int getDayOfMonth(Date date)— returns the day of the month of the current date: 1, 2, …
Based on these, you can get the first agent in the delay block with delay.get(0) and use if function.
Pseudo-code like this;
if (date==x){
if (delay.get(0)==myAgents.get(0)){
stopDelay(delay.get(0));
}
}
or
if (date==x){
if (delay.get(0).Name=="yyy"){
stopDelay(delay.get(0));
}
}
Related
Trying to nail down the syntax for a pretty straightforward problem.
I have a table called Events and a full-feature DATES table with a relationship between the Dates[Date] field.
Using the event name as a slicer, I trying to create a [First Monday] measure that will return the date of the first Monday of the month.
So for example, if my event date was 2/14/19, [First Monday] would return 2/4/19.
Your Date table needs to contain 2 columns:
Year-Month: for example, "2018-01"
Weekday Number: for example, 1 (for Monday); or Weekday Name (i.e, "Monday")
Then:
First Monday =
CALCULATE( MIN('Date'[Date]),
ALL('Date'),
VALUES('Date'[Year-Month]),
'Date'[Weekday Name] = "Monday")
How it works:
First, we need to access all dates in the Date table, so we use ALL()
Second, we need to see only dates for the current context year and month, for which we can use VALUES()
Third, for each month we only want Mondays, hence Date[Weekday] = "Monday"
All this unfiltering/filtering generates a set of Mondays for the Year-Month visible in the current filter context. All we need to do now is to find the earliest of the Mondays using Min(Date).
Given this domain:
class Burger{
String description
Date dateCreated
}
Currently, I have this namedQuery
queryOnDateCreated {Date dateArgument ->
eq 'dateCreated', dateArgument
}
I need a query that allows me find all the objects in the domain Burger with a specific dateCreated only taking into accountYear, Month and day (of month), while ignoring hours, minutes, seconds, miliseconds.
After some additional research, I found a solution which I'm going to share in case it helps someone else:
The named query needs to be as follows:
queryOnDateCreated {Date dateArgument ->
def dateArgumentIntervalEnd = DateUtils.addMilliseconds(dateArgument + 1, - 1)
between 'dateCreated', dateArgument, dateArgumentIntervalEnd
}
Explanation:
The "between" criteria returns every object in the domain whose date is between the interval given.
Since dateArgument is a Date created only with Year, Month and Day, it's time should be 00:00:00:000 (the first moment of the day).
Furthermore, "dateArgument + 1" holds the value of the next day (at the same time), which is why the substraction of 1 millisecond is required, that way "dateArgumentIntervalEnd" will hold the value of the same Year, Month and Day of "dateArgument" but the time will be 23:59:59:999 holding an interval of the whole day.
I have a timestamp field which has this definition:
Time interval: the beginning of the time interval expressed as the
number of millisecond elapsed from the Unix Epoch on January 1st, 1970
at UTC. The end of the time interval can be obtained by adding 600000
milliseconds (10 minutes) to this value. TYPE: numeric
I would like to split this field into Year, Month, Day of Month, Day of Week, Week Number.
It appears that I would need to use a Derive field with a Formula. But as a user new to the SPSS world, it isn't clear to me how I would use the derive field to do this.
The equivalent in pandas is:
df['Datetime'] = pd.to_datetime(df['Time interval'].astype(int))
df['Year'] = df['Datetime'].dt.year
df['Month'] = df['Datetime'].dt.month
df['Day'] = df['Datetime'].dt.day
df['DayOfWeek'] = df['Datetime'].dt.dayofweek
Do you want to create the 5 variables in separate, right?
For create:
**1) Year - Use a derive node and call the new variable as 'Year' with the syntax: "datetime_year(field)" -> will extract the year in numbers (2012)
2) Month- Use a derive node and call the new variable as 'Month' with the syntax: "datetime_month(field)" -> will extract the month in numbers (1 to 12)
3) Day of Month- Use a derive node and call the new variable as 'DayMonth' with the syntax: "datetime_day(field)" -> will extract the date of the month in numbers (1 to 31)
4) Day of Week - Use a derive node and call the new variable as 'DayWeek' with the syntax: "datetime_weekday(field)" -> will extract the weekday in numbers (1 to 7)
5) Week Number - Use a derive node and call the new variable as 'WeekNumb' with the syntax: "date_iso_week(field)" -> ISO 8601 (it's the only function that I never used in your list).**
Also, you can check others expressions inside the derive node tab, just select all functions and make some tests.
IBM Ref
I hope to have been helpful.
I have a spreadsheet that asks people to enter in a day of the month when we need to send out a bill. What I want to do is create a calendar event based on that. So, essentially what I need is an event that starts at the current month, day from the spreadsheet, and continues to a specified point in time.
var monthlyDate = row[6]; // Seventh column, monthly date of payment
var curDate = new Date();
var curMonth = curDate.getMonth();
var curYear = curDate.getYear();
curDate.setDate(curMonth, monthlyDate, curYear);
Logger.log("Day of month: %s", monthlyDate);
Logger.log("Current Date: %s", curDate);
Logger.log("Current Date: %s", Date());
What I'm seeing is that the monthly date is coming in as a float "6.0" for example, and no matter what I enter in for monthlyDate in the setDate line, it keeps setting the date to 10/9/15 (Today is 10/15/15). I've hard-coded that value to many different numbers, but for some reason it's just not working.
How can I create a date (in any format) that follows the scheme "Current Month / Day from Speadsheet / Current Year" ?
The getMonth() method returns a "zero-indexed" number. So, it returns the number 9 for the 10th month. setDate() doesn't set the date, it sets the "Day of the Month". The name of that method is misleading.
Documentation - setDate()
So, the last two parameters that you are using in setDate() are doing nothing. You are setting the day of the month to 9.
If you want to set multiple date parameters at the same time, you need to use the new Date() method:
var d = new Date(year, month, day, hours, minutes, seconds, milliseconds);
The month parameter accept values from 0 to 11, 0 is Jan and 11 is Dec
Date Reference
I need to make my Access query always return the Monday of the current week. I have seen a few solutions on Google/StackOverflow but they are written in SQL and I am a beginner in creating Access queries (I am using the Design view to make them).
Goal: The week should be considered as M T W T F S S. Then, the query should always return the Monday of the current week. Therefore, if it is Sunday, it should still return the Monday before, NOT the next week's Monday. Can anyone explain how to do this using the Design View in Access 2010?
Keep in mind that in this context we are working with dates, so if we do Date() - 1, we will get 1 day prior to today.
Date() ~ Today's date
DatePart(
"w" - Weekday
Date() - Today's date
2 - vBMonday (Access assumes Sunday is the first day of the week, which is why this is necessary.)
1 - vbFirstJan1 - This gets into using the first week of the year. We could have omitted this, as 1 is the default.
)
-1 - Subtract 1 from the DatePart value.
Values
Date() = 4/27/2015 (at time of this writing)
DatePart("w",Date(),2,1) = 1
DatePart("w",Date(),2,1)-1 = 0
So we have Date()-0... Okay, what's so great about that? Well, let's look at a more useful scenario where today's date is a day other than Monday.
Let's act like today is 4/28/2015 (Tuesday)
Date() = 4/28/2015
DatePart("w",Date(),2,1) = 2
DatePart("w",Date(),2,1)-1 = 1
So, from the outside, in; give me the current weekday value. (1 = Monday, 2 = Tuesday, etc.), and subtract 1 from that -> that's how many days we need to subtract from the current date to get back to the weekday value of 1 (Monday).
Here's a function that will do this:
Public Function DatePrevWeekday( _
ByVal datDate As Date, _
Optional ByVal bytWeekday As VbDayOfWeek = vbMonday) _
As Date
' Returns the date of the previous weekday, as spelled in vbXxxxday, prior to datDate.
' 2000-09-06. Cactus Data ApS.
' No special error handling.
On Error Resume Next
DatePrevWeekday = DateAdd("d", 1 - Weekday(datDate, bytWeekday), datDate)
End Function
As vbMonday is 2 and your date is today, you can use the core expression in a query:
PreviousMonday: DateAdd("d",1-Weekday(Date(),2),Date())