I have a production environment that consists of several (persistent and ad-hoc) EMR Spark clusters.
I would like to use one instance of spark-jobserver to manage the job JARs for this environment in general, and be able to specify the intended master right when I POST /jobs, and not permanently in the config file (using master = "local[4]" configuration key).
Obviously I would prefer to have spark-jobserver running on a standalone machine, and not on any of the masters.
Is this somehow possible?
You can write a SparkMasterProvider
https://github.com/spark-jobserver/spark-jobserver/blob/master/job-server/src/spark.jobserver/util/SparkMasterProvider.scala
A complex example is here https://github.com/spark-jobserver/jobserver-cassandra/blob/master/src/main/scala/spark.jobserver/masterLocators/dse/DseSparkMasterProvider.scala
I think all you have to do is write one that will return the config input as spark master, that way you can pass it as part of job config.
Related
I want to get the cluster link (or the cluster ID to manually compose the link) inside a running Spark job.
This will be used to print the link in an alerting message, making it easier for engineers to reach the logs.
Is it possible to achieve that in a Spark job running in Databricks?
When Databricks cluster starts, there is a number of Spark configuration properties added. Most of them are having name starting with spark.databricks. - you can find all of the in the Environment tab of the Spark UI.
Cluster ID is available as spark.databricks.clusterUsageTags.clusterId property and you can get it as:
spark.conf.get("spark.databricks.clusterUsageTags.clusterId")
You can get workspace host name via dbutils.notebook.getContext().apiUrl.get call (for Scala), or dbutils.notebook.entry_point.getDbutils().notebook().getContext().apiUrl().get() (for Python)
I have an Apache spark standalone set up.
I wish to start 3 workers to run in parallel:
I use the commands below.
./start-master.sh
SPARK_WORKER_INSTANCES=3 SPARK_WORKER_CORES=2 ./start-slaves.sh
I tried to run a few jobs and below are the apache UI results:
Ignore the last three applications that failed: Below are my questions:
Why do I have just one worker displayed in the UI despite asking spark to start 3 each with 2 cores?
I want to partition my input RDD for better performance. So for the first two jobs with no partions, I had a time of 2.7 mins. Here my Scala source code had the following.
val tweets = sc.textFile("/Users/soft/Downloads/tweets").map(parseTweet).persist()
In my third job (4.3 min) I had the below:
val tweets = sc.textFile("/Users/soft/Downloads/tweets",8).map(parseTweet).persist()
I expected a shorter time with more partitions(8). Why was this the opposite of what was expected?
Apparently you have only one active worker, which you need to investigate why other workers are not reported by checking the spark logs.
More partitions doesn't always mean that the application runs faster, you need to check how you are creating partitions from source data, the amount of data parition'd and how much data is being shuffled, etc.
In case you are running on a local machine it is quite normal to just start a single worker with several CPU's as shown in the output. It will still split you task of the available CPU's in the machine.
Partitioning your file will happen automatically depending on the amount of available resources, it works quite well most of the time. Spark (and partitioning the files) comes with some overhead, so often, especially on a single machine Spark adds so much overhead it will slowdown you process. The added values comes with large amounts of data on a cluster of machines.
Assuming that you are starting a stand-alone cluster, I would suggest using the configuration files to setup a the cluster and use start-all.sh to start a cluster.
first in your spark/conf/slaves (copied from spark/conf/slaves.template add the IP's (or server names) of you worker nodes.
configure the spark/conf/spark-defaults.conf (copied from spark/conf/spark-defaults.conf.template Set at least the master node to the server that runs your master.
Use the spark-env.sh (copied from spark-env.sh.template) to configure the cores per worker, memory etc:
export SPARK_WORKER_CORES="2"
export SPARK_WORKER_MEMORY="6g"
export SPARK_DRIVER_MEMORY="4g"
export SPARK_REPL_MEM="4g"
Since it is standalone (and not hosted on a Hadoop environment) you need to share (or copy) the configuration (or rather the complete spark directory) to all nodes in your cluster. Also the data you are processing needs to be available on all nodes e.g. directly from a bucket or a shared drive.
As suggested by the #skjagini checkout the various log files in spark/logs/ to see what's going on. Each node will write their own log files.
See https://spark.apache.org/docs/latest/spark-standalone.html for all options.
(we have a setup like this running for several years and it works great!)
okay i have a EMR cluster which writes to HDFS and I am able to view the directory and see the files
via
hadoop fs -ls /user/hadoop/jobs - i am not seeing /user/hive or jobs directory in hadoop, but its supposed to be there.
I need to get in to the spark shell and perform sparql, so i created identical cluster with same vpc,security groups, and subnet id.
What i am supposed to see
Why this is happending i am not sure but i think this might be it? Or any suggestions
Could this be something to with a stale rule?
I am running into the same issue as in this thread with my Scala Spark Streaming application: Why does Spark job fail with "too many open files"?
But given that I am using Azure HDInsights to deploy my YARN cluster, and I don't think I can log into that machine and update the ulimit in all machines.
Is there any other way to solve this problem? I cannot reduce the number of reducers by too much either, or my job will become much slower.
You can ssh into all nodes from the head node (ambari ui show fqdn of all nodes).
ssh sshuser#nameofthecluster.azurehdinsight.net
You can the write a custom action that alters the settings on the necessary nodes if you want to automate this action.
I'm using Amazon Web Services to create an autoscaling group of application instances behind an Elastic Load Balancer. I'm using a CloudFormation template to create the autoscaling group + load balancer and have been using Ansible to configure other instances.
I'm having trouble wrapping my head around how to design things such that when new autoscaling instances come up, they can automatically be provisioned by Ansible (that is, without me needing to find out the new instance's hostname and run Ansible for it). I've looked into Ansible's ansible-pull feature but I'm not quite sure I understand how to use it. It requires a central git repository which it pulls from, but how do you deal with sensitive information which you wouldn't want to commit?
Also, the current way I'm using Ansible with AWS is to create the stack using a CloudFormation template, then I get the hostnames as output from the stack, and then generate a hosts file for Ansible to use. This doesn't feel quite right – is there "best practice" for this?
Yes, another way is just to simply run your playbooks locally once the instance starts. For example you can create an EC2 AMI for your deployment that in the rc.local file (Linux) calls ansible-playbook -i <inventory-only-with-localhost-file> <your-playbook>.yml. rc.local is almost the last script run at startup.
You could just store that sensitive information in your EC2 AMI, but this is a very wide topic and really depends on what kind of sensitive information it is. (You can also use private git repositories to store sensitive data).
If for example your playbooks get updated regularly you can create a cron entry in your AMI that runs every so often and that actually runs your playbook to make sure your instance configuration is always up to date. Thus avoiding having "push" from a remote workstation.
This is just one approach there could be many others and it depends on what kind of service you are running, what kind data you are using, etc.
I don't think you should use Ansible to configure new auto-scaled instances. Instead use Ansible to configure a new image, of which you will create an AMI (Amazon Machine Image), and order AWS autoscaling to launch from that instead.
On top of this, you should also use Ansible to easily update your existing running instances whenever you change your playbook.
Alternatives
There are a few ways to do this. First, I wanted to cover some alternative ways.
One option is to use Ansible Tower. This creates a dependency though: your Ansible Tower server needs to be up and running at the time autoscaling or similar happens.
The other option is to use something like packer.io and build fully-functioning server AMIs. You can install all your code into these using Ansible. This doesn't have any non-AWS dependencies, and has the advantage that it means servers start up fast. Generally speaking building AMIs is the recommended approach for autoscaling.
Ansible Config in S3 Buckets
The alternative route is a bit more complex, but has worked well for us when running a large site (millions of users). It's "serverless" and only depends on AWS services. It also supports multiple Availability Zones well, and doesn't depend on running any central server.
I've put together a GitHub repo that contains a fully-working example with Cloudformation. I also put together a presentation for the London Ansible meetup.
Overall, it works as follows:
Create S3 buckets for storing the pieces that you're going to need to bootstrap your servers.
Save your Ansible playbook and roles etc in one of those S3 buckets.
Have your Autoscaling process run a small shell script. This script fetches things from your S3 buckets and uses it to "bootstrap" Ansible.
Ansible then does everything else.
All secret values such as Database passwords are stored in CloudFormation Parameter values. The 'bootstrap' shell script copies these into an Ansible fact file.
So that you're not dependent on external services being up you also need to save any build dependencies (eg: any .deb files, package install files or similar) in an S3 bucket. You want this because you don't want to require ansible.com or similar to be up and running for your Autoscale bootstrap script to be able to run. Generally speaking I've tried to only depend on Amazon services like S3.
In our case, we then also use AWS CodeDeploy to actually install the Rails application itself.
The key bits of the config relating to the above are:
S3 Bucket Creation
Script that copies things to S3
Script to copy Bootstrap Ansible. This is the core of the process. This also writes the Ansible fact files based on the CloudFormation parameters.
Use the Facts in the template.