I want to delete a particular line in each of 3000 text files.
I have tried using Notepad Plus but it creates a blank line for each matching line.
Sample File Content:
SAMPLE TXT FILE
---------------------
phone number
address
IAM A DEFAULT
city
state
pincode
----------------
Here IAM A DEFAULT is present in all 3000 files and it is present only once
You don't talk about identifying the files to be processed, but let's assume that you want to remove all IAM A DEFAULT lines from all *.txt files in the current directory
This Perl one-line command will doe that for you. It will also save each original file like abc.txt as abc.txt.bak
perl -i.bak -lne 'print unless $_ eq "IAM A DEFAULT"' *.txt
I hope that helps
With GNU sed and GNU bash 4:
shopt -s globstar nullglob
sed -i '/^IAM A DEFAULT/d' **/*.txt
Related
I need to replace "vi_chiron" with "vi_huracan" from all the files below. I am using the following command line and also have changed the permission to full access for all the underlying files:
grep -ri "vi_chiron" ./ | grep -v Header | xargs perl -e "s/vi_chiron/vi_huracan/" -pi
I am getting the error:
"Can't open ./build/drivers_file.min:#: No such file or directory.
" and many other similar errors. Any idea why ? Below is the permission for the file:
ll build/drivers_file.min
-rwxrwxrwx 1 ask vi 5860 Mar 13 12:07 build/drivers_file.min
You can change your command in the following ways:
grep -ril "vi_chiron" . | xargs grep -vl Header | xargs perl -e "s/vi_chiron/vi_huracan/" -pi
or
find . -type f -exec grep -ril "vi_chiron" | xargs grep -vl Header | xargs perl -e "s/vi_chiron/vi_huracan/" -pi
In order to manipulate all files that do not contain Header and change vi_chiron into vi_hurican.
If I were you, I would simplify the chain and do it the other way around:
grep -rvl Header . | xargs sed -i.bak 's/vi_chiron/vi_hurican/'
If you are confident enough change the -i.bak into -i in order to have sed not taking any backups.
Also note that your change and replace is not global, if you want to put it globally use: sed -i.bak 's/vi_chiron/vi_hurican/g' instead.
'-i[SUFFIX]' '--in-place[=SUFFIX]'
This option specifies that files are to be edited in-place. GNU
'sed' does this by creating a temporary file and sending output to
this file rather than to the standard output.(1).
This option implies '-s'.
When the end of the file is reached, the temporary file is renamed
to the output file's original name. The extension, if supplied, is
used to modify the name of the old file before renaming the
temporary file, thereby making a backup copy(2)).
This rule is followed: if the extension doesn't contain a '*', then
it is appended to the end of the current filename as a suffix; if
the extension does contain one or more '*' characters, then _each_
asterisk is replaced with the current filename. This allows you to
add a prefix to the backup file, instead of (or in addition to) a
suffix, or even to place backup copies of the original files into
another directory (provided the directory already exists).
If no extension is supplied, the original file is overwritten
without making a backup.
source: https://www.gnu.org/software/sed/manual/sed.txt
I'm trying to add the filename of a text file into the first line of a the same text file. for example if the file name is called test1.txt, then the first line when you open the file should be test1.
below is what I've done so for, the only problem i have is that the word "$file" is being written to the file not the file name. any help is appreciated.
for file in *.txt; do
sed -i '1 i\$file' $file;
awk 'sub("$", "\r")' "$file" > "$file"1;
mv "$file"1 "$file";
done
Without concise, testable sample input and expected output it's an untested guess but it SOUNDS like all you need is:
awk -i inplace -v ORS='\r\n' 'FNR==1{print FILENAME}1' *
No shell loop or multiple commands required.
The above uses GNU awk for inplace editing and I'm assuming the sub() in your code was intended to add a \r at the end of every line.
I've just started learning more about sed and awk and put this into a file called insert.sed and sourced it and passed it a file name:
sed -i '1s/^./'$1'\'$'\n/g' $1
In trying it, it seems to work okay:
rent$ cat x.txt
<<< Who are you?
rent$ source insert.sed x.txt
rent$ cat x.txt
x.txt
<< Who are you?
It is cutting off the first character of the first line so I'd have to fix that otherwise it does add the file name to first line.
I'm sure there's better ways of doing it.
If you want test1 on first line, with gnu sed
sed -i '1{x;s/.*/fich=$(ps -p $PPID -o args=);fich=${fich##*\\} };echo ${fich%%.*}/e;G}' test1.txt
I'd like to populate a shell variable with the file contents of the file that follow the # (but leave the file as-is) from beginning of one single-line file
I tried
file=$(head -n1 $another_filename | sed 's/^#//')
but output is the same. I don't want to delete the whole line, just hash.
Found it with your help of course.
file=$(head -n1 $filename |sed 's/^#//')
I have tried to scan through the other posts in stack overflow for this, but couldn't get my code work, hence I am posting a new question.
Below is the content of file temp.
<?xml version="1.0" encoding="UTF-8"?>
<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/<env:Body><dp:response xmlns:dp="http://www.datapower.com/schemas/management"><dp:timestamp>2015-01-
22T13:38:04Z</dp:timestamp><dp:file name="temporary://test.txt">XJzLXJlc3VsdHMtYWN0aW9uX18i</dp:file><dp:file name="temporary://test1.txt">lc3VsdHMtYWN0aW9uX18i</dp:file></dp:response></env:Body></env:Envelope>
This file contains the base64 encoded contents of two files names test.txt and test1.txt. I want to extract the base64 encoded content of each file to seperate files test.txt and text1.txt respectively.
To achieve this, I have to remove the xml tags around the base64 contents. I am trying below commands to achieve this. However, it is not working as expected.
sed -n '/test.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test.txt">##g'|perl -p -e 's#</dp:file>##g' > test.txt
sed -n '/test1.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test1.txt">##g'|perl -p -e 's#</dp:file></dp:response></env:Body></env:Envelope>##g' > test1.txt
Below command:
sed -n '/test.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test.txt">##g'|perl -p -e 's#</dp:file>##g'
produces output:
XJzLXJlc3VsdHMtYWN0aW9uX18i
<dp:file name="temporary://test1.txt">lc3VsdHMtYWN0aW9uX18i</dp:response> </env:Body></env:Envelope>`
Howeveer, in the output I am expecting only first line XJzLXJlc3VsdHMtYWN0aW9uX18i. Where I am commiting mistake?
When i run below command, I am getting expected output:
sed -n '/test1.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test1.txt">##g'|perl -p -e 's#</dp:file></dp:response></env:Body></env:Envelope>##g'
It produces below string
lc3VsdHMtYWN0aW9uX18i
I can then easily route this to test1.txt file.
UPDATE
I have edited the question by updating the source file content. The source file doesn't contain any newline character. The current solution will not work in that case, I have tried it and failed. wc -l temp must output to 1.
OS: solaris 10
Shell: bash
sed -n 's_<dp:file name="\([^"]*\)">\([^<]*\).*_\1 -> \2_p' temp
I add \1 -> to show link from file name to content but for content only, just remove this part
posix version so on GNU sed use --posix
assuming that base64 encoded contents is on the same line as the tag around (and not spread on several lines, that need some modification in this case)
Thanks to JID for full explaination below
How it works
sed -n
The -n means no printing so unless explicitly told to print, then there will be no output from sed
's_
This is to substitute the following regex using _ to separate regex from the replacement.
<dp:file name=
Regular text
"\([^"]*\)"
The brackets are a capture group and must be escaped unless the -r option is used( -r is not available on posix). Everything inside the brackets is captured. [^"]* means 0 or more occurrences of any character that is not a quote. So really this just captures anything between the two quotes.
>\([^<]*\)<
Again uses the capture group this time to capture everything between the > and <
.*
Everything else on the line
_\1 -> \2
This is the replacement, so replace everything in the regex before with the first capture group then a -> and then the second capture group.
_p
Means print the line
Resources
http://unixhelp.ed.ac.uk/CGI/man-cgi?sed
http://www.grymoire.com/Unix/Sed.html
/usr/xpg4/bin/sed works well here.
/usr/bin/sed is not working as expected in case if the file contains just 1 line.
below command works for a file containing only single line.
/usr/xpg4/bin/sed -n 's_<env:Envelope\(.*\)<dp:file name="temporary://BackUpDir/backupmanifest.xml">\([^>]*\)</dp:file>\(.*\)_\2_p' securebackup.xml 2>/dev/null
Without 2>/dev/null this sed command outputs the warning sed: Missing newline at end of file.
This because of the below reason:
Solaris default sed ignores the last line not to break existing scripts because a line was required to be terminated by a new line in the original Unix implementation.
GNU sed has a more relaxed behavior and the POSIX implementation accept the fact but outputs a warning.
i have several files in which i want to replace a certain word with the name of the file itself..
for example i have 2 files named test1.txt and test2.txt
both files are equal and look like
bla1,bla2,temp
bla2,bla3,temp
with the sed i want to replace the word temp with the name of the file itself
so after the sed operation i have 2 different files
test1.txt , which looks like :
bla1,bla2,test1
bla2,bla3,test1
test2.txt, which looks like :
bla1,bla2,test2
bla2,bla3,test2
so my question ... how do i use the actual name of the input file itself as part of the replace command?
sed "s/temp/ ??filename??/ ??? " *.txt
thanks for your suggestions
I'm not sure you can reference the filename using sed although I could be wrong. You would probably use a shell hack. A better aproach to substitute all occurrences of temp with the filename would be the following awk script:
$ awk '{gsub(/temp/,FILENAME)}1' file
use awk, awk has FILENAME variable:
awk '{sub(/temp/,FILENAME)}7' yourfile
awk 'BEGIN{FS=OFS=","} {$NF=FILENAME}1' file
The difference between this and the sub() solutions is that this will work even if the word "temp" exists elsewhere in your file, e.g. if "bla1" contains the word "temperature".
If you need to strip ".txt" from the file name as it appears from your posted desired output, tweak it to:
awk 'BEGIN{FS=OFS=","} {t=FILENAME; sub(/\.txt$/,"",t); $NF=t}1' file
You can probably edit FILENAME itself but I find it best not to mess with the builtin variables if you don't have to.
You could do it with a little bit of bash to help you out, if that's available.
find . -name "test*.txt" -type f | awk -F '/' '{print $2;}' | while read file; do sed -i "s|temp|$file|" ./$file; done
That's a kind of hacky adaptation of a script I have to do something similar. It can undoubtedly be shortened.
no sed internal variable for the file name so you need some previous batch command for a generic process
for FileName in MyFileShellFilter
do
cat <> ${FileName} | sed "s|,temp$|,${FileName}|"
done
just be carrefull with file name used, they normaly don't have \ but could have & that are s// special meaning. I use | as separator to allow / in file name but for this reason, no unescaped | are allowed in file name (normaly not)
with xargs:
printf "%s\n" *.txt | xargs -I FILE -L 1 sed 's/temp/FILE/' FILE
The filename cannot have: newlines, slashes, ampersand, single quote.