I am trying to a call a function using the following code:
{
fileName = strsplit(file,'.');
Process = strcat(fileName(1),'_config()')
}
The code works if I hard code: Process = EDA_config() but when I use the above to concatenate the string where fileName(1) = 'EDA', it results in an error. Any help would be appreciated.
Related
My program stub looks like this:
import PySimpleGUI as sg
layout = [[sg.Text("Geheime Nachricht eintippen:")],
[sg.Multiline(size=(70,4),key="GEHEIM")],
[sg.Spin([i for i in range(1,26)], initial_value=12, key="SS"), sg.Text("Schlüssel zwischen 1 und 25 wählen")],
[sg.Radio("Codieren:", "RADIO1", key="XX" ,default=True),
sg.Radio("Decodieren:","RADIO1", key="YY")],
[sg.Text("ERGEBNIS:")],
[sg.Multiline(size=(70,4),key="AUSGABE")],
[sg.Button("Weiter"), sg.Button("Ende")]]
window = sg.Window("Geheimcode", layout)
while True: # Ereignisschleife
event, values = window.Read()
geheimertext = values("GEHEIM")
print(values("GEHEIM"))
schluessel = int(values["SS"])
print ("Schlüssel = ", schluessel)
if values["XX"] == True:
codedecode = "C"
print("wir codieren:",codedecode)
else:
codedecode = "D"
print("wir decodieren:",codedecode)
if event is None or event == "Ende":
break
window.Close()
The program-line geheimertext = values("GEHEIM") gives this error:
TypeError: 'dict' object is not callable
I quess that the multiline generates a dictonary in the dictionary values?
so my simple newbie-question is how to read the multiline of a gui made with pysimpleGUI
ok, one possible solution is to iterate over the elements of the multiline:
geheimertext=""
for zeichen in values["GEHEIM"]:
geheimertext = geheimertext +zeichen
print(geheimertext)
Is there a better solution? Please teach a newbie
print(values["GEHEIM"])
values is a dict, and not a callable, so you cannot use () brackets (callables are functions or objects that have a function property). You can access to values through [] brackets. values["GEHEIM"].
I have been using urlread2 to read financial statements from marketwatch, and it was previously working. I am trying to run the same Matlab script I previously ran and cannot get it work. The html variable returned is an empty matrix.
Any ideas ?
Here is a link to the function: https://se.mathworks.com/matlabcentral/fileexchange/35693-urlread2
I know the function works, as I tried it running it on a different website.
Here is the Matlab script I am using.
url = ['http://www.marketwatch.com/investing/stock/AAPL/financials/'];
url = strrep(url,' ','');
query = 'urlread2';
params = {'term' query};
queryString = http_paramsToString(params,1);
url = [url '?' queryString];
[html,extras] = urlread2(url);
I know there are similar questions out there, but this one is a little different (I think).
I used the MATLAB Compiler to convert a .m to an Excel add-in. When I run the add-in on my machine, it works just fine. When I send it to a colleague, they get the "ActiveX component can't create object" error. They have added the add-in no problem.
Is there something going on here that's easily fixed?
MATLAB code:
function mess = createAndRouteOrderWithStyle()
c = startbbrg();
[num,text] = exportToM();
s = emsx('//blp/emapisvc_beta');
order.EMSX_ORDER_TYPE = text(1);
order.EMSX_SIDE = text(2);
order.EMSX_TICKER = text(3);
order.EMSX_AMOUNT = int32(num(1));
%order.EMSX_LIMIT_PRICE = num(2);
order.EMSX_BROKER = text(4);
order.EMSX_HAND_INSTRUCTION = text(5);
order.EMSX_TIF = text(6);
events = createOrderAndRoute(s,order);
mess = events.ERROR_MESSAGE;
close(s);
end
Excel VBA code:
Sub GO()
Cells(10,10).Formula = "=createAndRouteOrderWithStyle()"
End Sub
I'm trying to make an exercise from Udacity's Full Stack Foundations course. I have the do_POST method inside my subclass from BaseHTTPRequestHandler, basically I want to get a post value named message submitted with a multipart form, this is the code for the method:
def do_POST(self):
try:
if self.path.endswith("/Hello"):
self.send_response(200)
self.send_header('Content-type', 'text/html')
self.end_headers
ctype, pdict = cgi.parse_header(self.headers['content-type'])
if ctype == 'multipart/form-data':
fields = cgi.parse_multipart(self.rfile, pdict)
messagecontent = fields.get('message')
output = ""
output += "<html><body>"
output += "<h2>Ok, how about this?</h2>"
output += "<h1>{}</h1>".format(messagecontent)
output += "<form method='POST' enctype='multipart/form-data' action='/Hello'>"
output += "<h2>What would you like to say?</h2>"
output += "<input name='message' type='text'/><br/><input type='submit' value='Submit'/>"
output += "</form></body></html>"
self.wfile.write(output.encode('utf-8'))
print(output)
return
except:
self.send_error(404, "{}".format(sys.exc_info()[0]))
print(sys.exc_info() )
The problem is that the cgi.parse_multipart(self.rfile, pdict) is throwing an exception: TypeError: can't concat bytes to str, the implementation was provided in the videos for the course, but they're using Python 2.7 and I'm using python 3, I've looked for a solution all afternoon but I could not find anything useful, what would be the correct way to read data passed from a multipart form in python 3?
I've came across here to solve the same problem like you have.
I found a silly solution for that.
I just convert 'boundary' item in the dictionary from string to bytes with an encoding option.
ctype, pdict = cgi.parse_header(self.headers['content-type'])
pdict['boundary'] = bytes(pdict['boundary'], "utf-8")
if ctype == 'multipart/form-data':
fields = cgi.parse_multipart(self.rfile, pdict)
In my case, It seems work properly.
To change the tutor's code to work for Python 3 there are three error messages you'll have to combat:
If you get these error messages
c_type, p_dict = cgi.parse_header(self.headers.getheader('Content-Type'))
AttributeError: 'HTTPMessage' object has no attribute 'getheader'
or
boundary = pdict['boundary'].decode('ascii')
AttributeError: 'str' object has no attribute 'decode'
or
headers['Content-Length'] = pdict['CONTENT-LENGTH']
KeyError: 'CONTENT-LENGTH'
when running
c_type, p_dict = cgi.parse_header(self.headers.getheader('Content-Type'))
if c_type == 'multipart/form-data':
fields = cgi.parse_multipart(self.rfile, p_dict)
message_content = fields.get('message')
this applies to you.
Solution
First of all change the first line to accommodate Python 3:
- c_type, p_dict = cgi.parse_header(self.headers.getheader('Content-Type'))
+ c_type, p_dict = cgi.parse_header(self.headers.get('Content-Type'))
Secondly, to fix the error of 'str' object not having any attribute 'decode', it's because of the change of strings being turned into unicode strings as of Python 3, instead of being equivalent to byte strings as in Python 3, so add this line just under the above one:
p_dict['boundary'] = bytes(p_dict['boundary'], "utf-8")
Thirdly, to fix the error of not having 'CONTENT-LENGTH' in pdict just add these lines before the if statement:
content_len = int(self.headers.get('Content-length'))
p_dict['CONTENT-LENGTH'] = content_len
Full solution on my Github:
https://github.com/rSkogeby/web-server
I am doing the same course and was running into the same problem. Instead of getting it to work with cgi I am now using the parse library. This was shown in the same course just a few lessons earlier.
from urllib.parse import parse_qs
length = int(self.headers.get('Content-length', 0))
body = self.rfile.read(length).decode()
params = parse_qs(body)
messagecontent = params["message"][0]
And you have to get rid of the enctype='multipart/form-data' in your form.
In my case I used cgi.FieldStorage to extract file and name instead of cgi.parse_multipart
form = cgi.FieldStorage(
fp=self.rfile,
headers=self.headers,
environ={'REQUEST_METHOD':'POST',
'CONTENT_TYPE':self.headers['Content-Type'],
})
print('File', form['file'].file.read())
print('Name', form['name'].value)
Another hack solution is to edit the source of the cgi module.
At the very beginning of the parse_multipart (around the 226th line):
Change the usage of the boundary to str(boundary)
...
boundary = b""
if 'boundary' in pdict:
boundary = pdict['boundary']
if not valid_boundary(boundary):
raise ValueError('Invalid boundary in multipart form: %r'
% (boundary,))
nextpart = b"--" + str(boundary)
lastpart = b"--" + str(boundary) + b"--"
...
Hey there I am trying to make my first class my code is as follows:
class Twitt:
def __init__(self):
self.usernames = []
self.names = []
self.tweet = []
self.imageurl = []
def twitter_lookup(self, coordinents, radius):
twitter = Twitter(auth=auth)
coordinents = coordinents + "," + radius
print coordinents
query = twitter.search.tweets(q="", geocode='33.520661,-86.80249,50mi', rpp=10)
print query
for result in query["statuses"]:
self.usernames.append(result["user"]["screen_name"])
self.names.append(result['user']["name"])
self.tweet.append(h.unescape(result["text"]))
self.imageurl.append(result['user']["profile_image_url_https"])
What I am trying to be able to do is then use my class like so:
test = Twitt()
hello = test.twitter_lookup("38.5815720,-121.4944000","1m")
print hello.usernames
This does not work and I keep getting: "AttributeError: 'NoneType' object has no attribute 'usernames'"
Maybe I just misunderstood the tutorial or am trying to use this wrong. Any help would be appreciated thanks.
I see the error is test.twitter_lookup("38.5815720,-121.4944000","1m") return nothing. If you want the usernames, you need to do
test = Twitt()
test.twitter_lookup("38.5815720,-121.4944000","1m")
test.usernames
Your function twitter_lookup is modifying the Twitt object in-place. You didn't make it return any kind of value, so when you call hello = test.twitter_lookup(), there's no return value to assign to hello, and it ends up as None. Try test.usernames instead.
Alternatively, have the twitter_lookup function put its results in some new object (perhaps a dictionary?) and return it. This is probably the more sensible solution.
Also, the function accepts a coordinents (it's 'coordinates') argument, but then throws it away and uses a hard-coded value instead.