I'm trying to make an exercise from Udacity's Full Stack Foundations course. I have the do_POST method inside my subclass from BaseHTTPRequestHandler, basically I want to get a post value named message submitted with a multipart form, this is the code for the method:
def do_POST(self):
try:
if self.path.endswith("/Hello"):
self.send_response(200)
self.send_header('Content-type', 'text/html')
self.end_headers
ctype, pdict = cgi.parse_header(self.headers['content-type'])
if ctype == 'multipart/form-data':
fields = cgi.parse_multipart(self.rfile, pdict)
messagecontent = fields.get('message')
output = ""
output += "<html><body>"
output += "<h2>Ok, how about this?</h2>"
output += "<h1>{}</h1>".format(messagecontent)
output += "<form method='POST' enctype='multipart/form-data' action='/Hello'>"
output += "<h2>What would you like to say?</h2>"
output += "<input name='message' type='text'/><br/><input type='submit' value='Submit'/>"
output += "</form></body></html>"
self.wfile.write(output.encode('utf-8'))
print(output)
return
except:
self.send_error(404, "{}".format(sys.exc_info()[0]))
print(sys.exc_info() )
The problem is that the cgi.parse_multipart(self.rfile, pdict) is throwing an exception: TypeError: can't concat bytes to str, the implementation was provided in the videos for the course, but they're using Python 2.7 and I'm using python 3, I've looked for a solution all afternoon but I could not find anything useful, what would be the correct way to read data passed from a multipart form in python 3?
I've came across here to solve the same problem like you have.
I found a silly solution for that.
I just convert 'boundary' item in the dictionary from string to bytes with an encoding option.
ctype, pdict = cgi.parse_header(self.headers['content-type'])
pdict['boundary'] = bytes(pdict['boundary'], "utf-8")
if ctype == 'multipart/form-data':
fields = cgi.parse_multipart(self.rfile, pdict)
In my case, It seems work properly.
To change the tutor's code to work for Python 3 there are three error messages you'll have to combat:
If you get these error messages
c_type, p_dict = cgi.parse_header(self.headers.getheader('Content-Type'))
AttributeError: 'HTTPMessage' object has no attribute 'getheader'
or
boundary = pdict['boundary'].decode('ascii')
AttributeError: 'str' object has no attribute 'decode'
or
headers['Content-Length'] = pdict['CONTENT-LENGTH']
KeyError: 'CONTENT-LENGTH'
when running
c_type, p_dict = cgi.parse_header(self.headers.getheader('Content-Type'))
if c_type == 'multipart/form-data':
fields = cgi.parse_multipart(self.rfile, p_dict)
message_content = fields.get('message')
this applies to you.
Solution
First of all change the first line to accommodate Python 3:
- c_type, p_dict = cgi.parse_header(self.headers.getheader('Content-Type'))
+ c_type, p_dict = cgi.parse_header(self.headers.get('Content-Type'))
Secondly, to fix the error of 'str' object not having any attribute 'decode', it's because of the change of strings being turned into unicode strings as of Python 3, instead of being equivalent to byte strings as in Python 3, so add this line just under the above one:
p_dict['boundary'] = bytes(p_dict['boundary'], "utf-8")
Thirdly, to fix the error of not having 'CONTENT-LENGTH' in pdict just add these lines before the if statement:
content_len = int(self.headers.get('Content-length'))
p_dict['CONTENT-LENGTH'] = content_len
Full solution on my Github:
https://github.com/rSkogeby/web-server
I am doing the same course and was running into the same problem. Instead of getting it to work with cgi I am now using the parse library. This was shown in the same course just a few lessons earlier.
from urllib.parse import parse_qs
length = int(self.headers.get('Content-length', 0))
body = self.rfile.read(length).decode()
params = parse_qs(body)
messagecontent = params["message"][0]
And you have to get rid of the enctype='multipart/form-data' in your form.
In my case I used cgi.FieldStorage to extract file and name instead of cgi.parse_multipart
form = cgi.FieldStorage(
fp=self.rfile,
headers=self.headers,
environ={'REQUEST_METHOD':'POST',
'CONTENT_TYPE':self.headers['Content-Type'],
})
print('File', form['file'].file.read())
print('Name', form['name'].value)
Another hack solution is to edit the source of the cgi module.
At the very beginning of the parse_multipart (around the 226th line):
Change the usage of the boundary to str(boundary)
...
boundary = b""
if 'boundary' in pdict:
boundary = pdict['boundary']
if not valid_boundary(boundary):
raise ValueError('Invalid boundary in multipart form: %r'
% (boundary,))
nextpart = b"--" + str(boundary)
lastpart = b"--" + str(boundary) + b"--"
...
Related
I have this PowerShell code:
$AsyncTask = $BitmapDecoder.GetSoftwareBitmapAsync()
But discovered that some of the images coming in are rotated, so experimenting I came up with this:
$BmTf = [BitmapTransform]::new()
$BmTf.Rotation = [BitmapRotation]::None
# $BmTf.Rotation = [BitmapRotation]::Clockwise90Degrees
# $BmTf.Rotation = [BitmapRotation]::Clockwise180Degrees
# $BmTf.Rotation = [BitmapRotation]::Clockwise270Degrees
$AsyncTask = $BitmapDecoder.GetSoftwareBitmapAsync(
[BitmapPixelFormat]::Bgra8,
[BitmapAlphaMode]::Ignore,
$BmTf,
[ExifOrientationMode]::IgnoreExifOrientation,
[ColorManagementMode]::DoNotColorManage
)
While it does work, I'm not familiar BitmapPixelFormat, or the other parameters. The documentation for GetSoftwareBitmapAsync() doesn't appear to give any hints on what the default value it is using for BitmapPixelFormat.
Does anyone know the best values to pass to the version of GetSoftwareBitmapAsync() that takes 5 parameters to mimic the version of GetSoftwareBitmapAsync() that takes 0 parameters?
EDIT:
Just found out that trying [BitmapPixelFormat]::Unknown causes this error:
Exception calling "GetSoftwareBitmapAsync" with "5" argument(s): "The
parameter is incorrect. Windows.Graphics.Imaging: The bitmap pixel
format is unsupported."
But no errors with [BitmapPixelFormat]::Bgra8.
I don't know why GetSoftwareBitmapAsync doesn't like [BitmapPixelFormat]::Unknown, but here is the solution I found.
I need to first load the image to see if it needs rotating. That is done with the original command:
$AsyncTask = $BitmapDecoder.GetSoftwareBitmapAsync()
$SoftwareBitmap = GetAsync( $AsyncTask, ([SoftwareBitmap]) )
Then extract its BitmapPixelFormat:
$BitmapPixelFormat = $SoftwareBitmap.BitmapPixelFormat
And then use $BitmapPixelFormat for all calls to the 5 parameter version of GetSoftwareBitmapAsync().
I'm using the code below to try and strip the file extension off the incoming file and replace it with "ACK";
Can't use .lastIndexOf as it's not available in Rhino.
var _filename = String(sourceMap.get('originalFilename'));
pos = -1;
var search = ".";
for(var i = 0; i < _filename.length - search.length; i++) {
if (_filename.substr(i, search.length) == search) {
pos = i;
}
}
logger.info('_pos:' + _pos);
Every time I get a pos value of -1
i.e. Last full stop position not found.
BUT if I hardcode the filename in as "2020049.259317052.HC.P.F3M147-G" it works perfectly.
Is it something to do with the sourceMap.get('originalFilename') supplying a non-string or different
character set ?
This was tested on mirth 3.5. Rhino does, in fact, have String.prototype.lastIndexOf for all mirth versions going back to at least mirth 3.0. You were correctly converting the java string from the sourceMap to a javascript string, however, it is not necessary in this case.
Java strings share String.prototype methods as long as there is not a conflict in method name. Java strings themselves have a lastIndexOf method, so that is the one being called in my answer. The java string is able to then borrow the slice method from javascript seamlessly. The javascript method returns a javascript string.
If for some reason the filename starts with a . and doesn't contain any others, this won't leave you with a blank filename.
var filename = $('originalFilename');
var index = filename.lastIndexOf('.');
if (index > 0) filename = filename.slice(0, index);
logger.info('filename: ' + filename);
That being said, I'm not sure why your original code wasn't working. When I replaced the first line with
var originalFilename = new java.lang.String('2020049.259317052.HC.P.F3M147-G');
var _filename = String(originalFilename);
It gave me the correct pos value of 22.
New Answer
After reviewing and testing what agermano said he is correct.
In your sample code you are setting pos = i but logging _pos
New answer var newFilename = _filename.slice(0, _filename.lastIndexOf('.'))
Older Answer
First, you are mixing JavaScript types and Java types.
var _filename = String(sourceMap.get('originalFilename'));
Instead, do
var _filename = '' + sourceMap.get('originalFilename');
This will cause a type conversion from Java String to JS string.
Secondly, there is an easier way to do what you are trying to do.
var _filenameArr = ('' + sourceMap.get('originalFilename')).split('.');
_filenameArr.pop() // throw away last item
var _filename = _filenameArr.join('.') // rejoin the array with out the last item
logger.info('_filename:' + _filename)
My program stub looks like this:
import PySimpleGUI as sg
layout = [[sg.Text("Geheime Nachricht eintippen:")],
[sg.Multiline(size=(70,4),key="GEHEIM")],
[sg.Spin([i for i in range(1,26)], initial_value=12, key="SS"), sg.Text("Schlüssel zwischen 1 und 25 wählen")],
[sg.Radio("Codieren:", "RADIO1", key="XX" ,default=True),
sg.Radio("Decodieren:","RADIO1", key="YY")],
[sg.Text("ERGEBNIS:")],
[sg.Multiline(size=(70,4),key="AUSGABE")],
[sg.Button("Weiter"), sg.Button("Ende")]]
window = sg.Window("Geheimcode", layout)
while True: # Ereignisschleife
event, values = window.Read()
geheimertext = values("GEHEIM")
print(values("GEHEIM"))
schluessel = int(values["SS"])
print ("Schlüssel = ", schluessel)
if values["XX"] == True:
codedecode = "C"
print("wir codieren:",codedecode)
else:
codedecode = "D"
print("wir decodieren:",codedecode)
if event is None or event == "Ende":
break
window.Close()
The program-line geheimertext = values("GEHEIM") gives this error:
TypeError: 'dict' object is not callable
I quess that the multiline generates a dictonary in the dictionary values?
so my simple newbie-question is how to read the multiline of a gui made with pysimpleGUI
ok, one possible solution is to iterate over the elements of the multiline:
geheimertext=""
for zeichen in values["GEHEIM"]:
geheimertext = geheimertext +zeichen
print(geheimertext)
Is there a better solution? Please teach a newbie
print(values["GEHEIM"])
values is a dict, and not a callable, so you cannot use () brackets (callables are functions or objects that have a function property). You can access to values through [] brackets. values["GEHEIM"].
I have a create_user_profile signal and I'd like to use same signal to send a welcome email to the user.
This is what I wrote so far in my signals.py:
#receiver(post_save, sender=User)
def update_user_profile(sender, instance, created, **kwargs):
if created:
UserProfile.objects.create(user=instance)
instance.profile.save()
subject = 'Welcome to MyApp!'
from_email = 'no-reply#myapp.com'
to = instance.email
plaintext = get_template('email/welcome.txt')
html = get_template('email/welcome.html')
d = Context({'username': instance.username})
text_content = plaintext.render(d)
html_content = html.render(d)
try:
msg = EmailMultiAlternatives(subject, text_content, from_email, [to])
msg.attach_alternative(html_content, "text/html")
msg.send()
except BadHeaderError:
return HttpResponse('Invalid header found.')
This is failing with this error:
TypeError at /signup/
context must be a dict rather than Context.
pointing to the forms.save in my views.py file.
Can you help me to understand what's wrong here?
Just pass a dict to the render instead of a Context object
d = {'username': instance.username}
text_content = plaintext.render(d)
On django 1.11 the template context must be a dict:
https://docs.djangoproject.com/en/1.11/topics/templates/#django.template.backends.base.Template.render
Try to just remove the Context object creationg.
d = {'username': instance.username}
Hey there I am trying to make my first class my code is as follows:
class Twitt:
def __init__(self):
self.usernames = []
self.names = []
self.tweet = []
self.imageurl = []
def twitter_lookup(self, coordinents, radius):
twitter = Twitter(auth=auth)
coordinents = coordinents + "," + radius
print coordinents
query = twitter.search.tweets(q="", geocode='33.520661,-86.80249,50mi', rpp=10)
print query
for result in query["statuses"]:
self.usernames.append(result["user"]["screen_name"])
self.names.append(result['user']["name"])
self.tweet.append(h.unescape(result["text"]))
self.imageurl.append(result['user']["profile_image_url_https"])
What I am trying to be able to do is then use my class like so:
test = Twitt()
hello = test.twitter_lookup("38.5815720,-121.4944000","1m")
print hello.usernames
This does not work and I keep getting: "AttributeError: 'NoneType' object has no attribute 'usernames'"
Maybe I just misunderstood the tutorial or am trying to use this wrong. Any help would be appreciated thanks.
I see the error is test.twitter_lookup("38.5815720,-121.4944000","1m") return nothing. If you want the usernames, you need to do
test = Twitt()
test.twitter_lookup("38.5815720,-121.4944000","1m")
test.usernames
Your function twitter_lookup is modifying the Twitt object in-place. You didn't make it return any kind of value, so when you call hello = test.twitter_lookup(), there's no return value to assign to hello, and it ends up as None. Try test.usernames instead.
Alternatively, have the twitter_lookup function put its results in some new object (perhaps a dictionary?) and return it. This is probably the more sensible solution.
Also, the function accepts a coordinents (it's 'coordinates') argument, but then throws it away and uses a hard-coded value instead.