How can I view index of particular table in AS400? In which table index description of table is stored?
If your "index" is really a logical file, you can see a list of these using:
select * from qsys2.systables
where table_schema = 'YOURLIBNAME' and table_type = 'L'
To complete the previous answers: if your AS400/IBMi's files are "IBM's old style" Physical and Logical files, the qsys2.syskeys and qsys2.sysindexes are empty.
==> you retrieve index infos in QADBKFLD (for "indexes" info) and QADBXREF(for fields list) tables
select * from QSYS.QADBXREF where DBXFIL = 'YOUR_LOGICAL_FILE_NAME' and DBXLIB = 'YOUR_LIBRARY'
select * from QSYS.QADBKFLD where DBKFIL = 'YOUR_LOGICAL_FILE_NAME' and DBKLB2 = 'YOUR_LIBRARY'
WARNING: YOUR_LOGICAL_FILE_NAME is not your "table name", but the name of the file ! You have to join another table QSYS.QADBFDEP to match LOGICAL_FILE_NAME / TABLE_NAME :
To found indexes from your table's name:
Select r.*
from QSYS.QADBXREF r, QSYS.QADBFDEP d
where d.DBFFDP = r.DBXFIL and d.DBFLIB=r.DBXLIB
and d.DBFFIL = 'YOUR_TABLE_NAME' and d.DBFLIB = 'YOUR_LIBRARY'
To found all indexes' fields from your table:
Select DBXFIL , f.DBKFLD, DBKPOS , t.DBXUNQ
from QSYS.QADBXREF t
INNER JOIN QSYS.QADBKFLD f on DBXFIL = DBKFIL and DBXLIB = DBKLIB
INNER JOIN QSYS.QADBFDEP d on d.DBFFDP = t.DBXFIL and d.DBFLIB=t.DBXLIB
where d.DBFFIL = 'YOUR_TABLE_NAME' and d.DBFLIB = 'YOUR_LIBRARY'
order by DBXFIL, DBKPOS
if your indexes is create with SQL you can see liste of index in sysindexes system view
SELECT * FROM qsys2.sysindexes WHERE TABLE_SCHEMA='YOURLIBNAME' and
TABLE_NAME = 'YOURTABLENAME'
if you want detail columns for index you can join syskeys tables
SELECT KEYS.INDEX_NAME, KEYS.COLUMN_NAME
FROM qsys2.syskeys KEYS
JOIN qsys2.sysindexes IX ON KEYS.ixname = IX.name
WHERE TABLE_SCHEMA='YOURLIBNAME' and TABLE_NAME = 'YOURTABLENAME'
order by INDEX_NAME
You could also use commands to get the information. Command DSPDBR FILE(LIBNAME/FILENAME) will show a list of the objects dependent on a physical file. The objects that show a data dependency can then be further explored by running DSPFD FILE(LIBNAME/FILENAME). This will show the access paths of the logical file.
Related
I've set up PostgreSQL Anonymizer on my database with security labels and everything works fine.
I'm trying to regularly ceck if there is missing security labels on the columns of my database to telle the developers to add them in the next release but I can't fin a way to read the security labels.
Can anyone know how to do this ?
EDIT on 10/11/2022
Thanks to #Shiva, I've end up doing this query :
select cl."oid", col.ordinal_position, col.table_schema, col.table_name, col.column_name
FROM information_schema.columns col
join pg_catalog.pg_class cl on cl.relname = col.table_name
WHERE col.table_schema = 'XXXX'
and not exists (select objoid FROM pg_seclabel where provider = 'anon' and objsubid = col.ordinal_position and objoid = cl."oid");
You have to query pg_seclabel catalog to get list of security labels.
SELECT objsubid, provider, label FROM pg_seclabel WHERE objoid::regclass = 'mytable'::regclass
objsubid is the column number whose corresponding column name can be found by querying information_schema.columns catalog.
SELECT column_name FROM information_schema.columns WHERE table_name = 'mytable' AND ordinal_position = <column_number>
You can combine the above two queries to find columns that do not have the required security labels.
I have one column , and i want to find in How many table that column used as foreign and also name of the table in which that column is used. I have PostgreSQL database . and i am using PG admin tool
select R.TABLE_NAME from INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE u
inner join INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS FK
on U.CONSTRAINT_CATALOG = FK.UNIQUE_CONSTRAINT_CATALOG
and U.CONSTRAINT_SCHEMA = FK.UNIQUE_CONSTRAINT_SCHEMA
and U.CONSTRAINT_NAME = FK.UNIQUE_CONSTRAINT_NAME inner join INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE R
ON R.CONSTRAINT_CATALOG = FK.CONSTRAINT_CATALOG
AND R.CONSTRAINT_SCHEMA = FK.CONSTRAINT_SCHEMA
AND R.CONSTRAINT_NAME = FK.CONSTRAINT_NAME WHERE U.COLUMN_NAME='M_InLine_ID'
AND U.TABLE_NAME = 'M_InLine'
I tried above query but it snot given any output
Please help me out
I have History table and transaction table.....and reference table...
If status in reference table is CLOSE then take those record verify in History table if not there insert from transaction table..... wiring query like this .... checking better one... please advice.. this query can be used for huge data ?
INSERT INTO LIB1.HIST_TBL
( SELECT R.ACCT, R.STATUS, R.DATE FROM
LIB2.HIST_TBL R JOIN LIB1.REF_TBL C
ON R.ACCT = C.ACCT WHERE C.STATUS = '5'
AND R.ACCT NOT IN
(SELECT ACTNO FROM LIB1.HIST_TBL)) ;
If you're on a current release of DB2 for i, take a look at the MERGE statement
MERGE INTO hist_tbl H
USING (SELECT * FROM ref_tbl R
WHERE r.status = 'S')
ON h.actno = r.actno
WHEN NOT MATCHED THEN
INSERT (actno,histcol2, histcol3) VALUES (r.actno,r.refcol2,r.refcol3)
--if needed
WHEN MATCHED
UPDATE SET (actno,histcol2, histcol3) = (r.actno,r.refcol2,r.refcol3)
Hi i am new to oracle_sqldeveloper can you please give me the answer how to know the table structure and relationships of a database.
You can try
DESC <table_name>
Try this:
select table_name, column_name, data_type
from all_tab_columns
where table_name = <TABLE_NAME_HERE>
and owner = '<YOUR_USER_HERE_IN_CAPITAL_LETTERS>'
If you have comments on your table then to get columns' comments:
select tc.table_name, tc.column_name, tc.data_type, cc.comments
from all_col_comments cc, all_tab_columns tc
where tc.table_name = <TABLE_NAME_HERE>
and tc.owner = <OWNER_OF_TABLE_HERE>
and tc.table_name = cc.table_name
and tc.column_name = cc.column_name
and tc.owner = cc.owner
If you are logged in under owner of the table you can write this:
select table_name, column_name, data_type
from user_tab_columns
where table_name = <TABLE_NAME_HERE>
or to get columns with comments
select tc.table_name, tc.column_name, tc.data_type, cc.comments
from user_col_comments cc, user_tab_columns tc
where tc.table_name = '<TABLE_NAME_HERE>'
and tc.owner = '<YOUR_USER_HERE_IN_CAPITAL_LETTERS>'
and tc.table_name = cc.table_name
and tc.column_name = cc.column_name
To get relationships between tables user this query:
select uc1.table_name
, uc1.constraint_name
, cc1.column_name
, uc2.table_name r_table_name
, uc2.constraint_name r_constraint_name
, cc2.column_name r_column_name
from all_constraints uc1
, all_constraints uc2
, all_cons_columns cc1
, all_cons_columns cc2
where 1 = 1
and uc2.constraint_type = 'R'
and uc1.constraint_name = uc2.r_constraint_name
and cc1.table_name = uc1.table_name
and cc1.constraint_name = uc1.constraint_name
and cc2.table_name = uc1.table_name
and cc2.constraint_name = uc1.constraint_name
and uc1.owner = '<YOUR_USER_HERE_IN_CAPITAL_LETTERS>'
and uc2.owner = uc1.owner
and cc1.owner = uc1.owner
and cc2.owner = uc1.owner
order by 1
/
Columns with the "R_" prefix mean that they are foreign data (they represent foreign keys). As you can see, I used the tables with the "ALL_" prefix, to use similar tables with the "USER_" prefix, get rid of the "OWNER" section.
To know more about oracle data dictionary read this
1) type your table name.
2) right click on table name & click Open Declaration.
I have a SQL 2008 R2 database with some tables on it having some of those tables a Full-Text Index defined. I'd like to know how to determine the size of the index of a specific table, in order to control and predict it's growth.
Is there a way of doing this?
The catalog view sys.fulltext_index_fragments keeps track of the size of each fragment, regardless of catalog, so you can take the SUM this way. This assumes the limitation of one full-text index per table is going to remain the case. The following query will get you the size of each full-text index in the database, again regardless of catalog, but you could use the WHERE clause if you only care about a specific table.
SELECT
[table] = OBJECT_SCHEMA_NAME(table_id) + '.' + OBJECT_NAME(table_id),
size_in_KB = CONVERT(DECIMAL(12,2), SUM(data_size/1024.0))
FROM sys.fulltext_index_fragments
-- WHERE table_id = OBJECT_ID('dbo.specific_table_name')
GROUP BY table_id;
Also note that if the count of fragments is high you might consider a reorganize.
If you are after a specific Catalogue
Use SSMS
- Clik on [Database] and expand the objects
- Click on [Storage]
- Right Click on {Specific Catalogue}
- Choose Propertie and click.
IN General TAB.. You will find the Catalogue Size = 'nn'
I use something similar to this (which will also calculate the size of XML-indexes, ... if present)
SELECT S.name,
SO.name,
SIT.internal_type_desc,
rows = CASE WHEN GROUPING(SIT.internal_type_desc) = 0 THEN SUM(SP.rows)
END,
TotalSpaceGB = SUM(SAU.total_pages) * 8 / 1048576.0,
UsedSpaceGB = SUM(SAU.used_pages) * 8 / 1048576.0,
UnusedSpaceGB = SUM(SAU.total_pages - SAU.used_pages) * 8 / 1048576.0,
TotalSpaceKB = SUM(SAU.total_pages) * 8,
UsedSpaceKB = SUM(SAU.used_pages) * 8,
UnusedSpaceKB = SUM(SAU.total_pages - SAU.used_pages) * 8
FROM sys.objects SO
INNER JOIN sys.schemas S ON S.schema_id = SO.schema_id
INNER JOIN sys.internal_tables SIT ON SIT.parent_object_id = SO.object_id
INNER JOIN sys.partitions SP ON SP.object_id = SIT.object_id
INNER JOIN sys.allocation_units SAU ON (SAU.type IN (1, 3)
AND SAU.container_id = SP.hobt_id)
OR (SAU.type = 2
AND SAU.container_id = SP.partition_id)
WHERE S.name = 'schema'
--AND SO.name IN ('TableName')
GROUP BY GROUPING SETS(
(S.name,
SO.name,
SIT.internal_type_desc),
(S.name, SO.name), (S.name), ())
ORDER BY S.name,
SO.name,
SIT.internal_type_desc;
This will generally give numbers higher than sys.fulltext_index_fragments, but when combined with the sys.partitions of the table, it will add up to the numbers returned from EXEC sys.sp_spaceused #objname = N'schema.TableName';.
Tested with SQL Server 2016, but documentation says it should be present since 2008.