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Look at this:
glueContext.getSinkWithFormat(connectionType = "s3",
options = JsonOptions(
Map("path" -> outputLgSingleDir,
"partitionKeys" -> List("org_name"))),
format = "parquet", transformationContext = "")
.writeDynamicFrame(lHistory)
What possible values for JsonOptions are?
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I have a List(List(15,21),List(10,18))
I want to get first count of total subList //here is 2
I want to get only last subList // List(10,18)
I am new in scala.
Does anyone help which approach is good here.
you can do this:
val listOfList = List(List(15,21),List(10,18))
val size = listOfList.length // 2
val lastList = listOfList.last // List(10,18)
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$sql=" SELECT *
FROM mt_volunteer_shift
WHERE volunteer_shift_sale_id =".$value['registered_sale_sale_id'] . "
AND volunteer_shift_id NOT IN".$value['registered_sale_volunteer_id'];
$query = $this->db->query($sql);
$active_volunteer = $query->result_array();
For example You can use like below format.
$registered_sale_volunteer_id= explode(',', $variable);
$sql= "SELECT * FROM mt_volunteer_shift WHERE volunteer_shift_sale_id =".$registered_sale_sale_id ."
AND volunteer_shift_id NOT IN (".$registered_sale_volunteer_id.")";
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I have an array and I want to convert it into String but separated each element by '","
List<String> list = ["India","China","USA"];
var string = list.join(',');
print(string); //output = "India,China,USA"
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For example I have
[
["A",1]
["B",5]
["C",3]
]
How do i sort it so that it returns in Highest to lowest value B, C, A
You can do in following way:
a.sort {
return $0.last as! Int > $1.last as! Int
}
Don't forget to add additional checks while using this code, case where the last item is not an integer or there is an array not in the expected format. Otherwise, it will lead to a crash.
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I want to fetch a part of string from a string. E.g. I have a string say sampleStringUrl which holds "http://some.something.net/update/user". So, I want to get only "some.something.net" from sampleStringUrl.
Like that you want to get Host URL.
var urlString = "https://stackoverflow.com/questions/6162522/get-the-domain-part-of-an-url-string"
var url = URL(string: urlString)
var domain = url?.host
print(domain!) //stackoverflow.com