How do I sort an array of an array in Swift 5 [closed] - swift

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For example I have
[
["A",1]
["B",5]
["C",3]
]
How do i sort it so that it returns in Highest to lowest value B, C, A

You can do in following way:
a.sort {
return $0.last as! Int > $1.last as! Int
}
Don't forget to add additional checks while using this code, case where the last item is not an integer or there is an array not in the expected format. Otherwise, it will lead to a crash.

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How can I get a count of Sublist inside list in scala? [closed]

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I have a List(List(15,21),List(10,18))
I want to get first count of total subList //here is 2
I want to get only last subList // List(10,18)
I am new in scala.
Does anyone help which approach is good here.
you can do this:
val listOfList = List(List(15,21),List(10,18))
val size = listOfList.length // 2
val lastList = listOfList.last // List(10,18)

Convert array into comma separated value of String [closed]

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I have an array and I want to convert it into String but separated each element by '","
List<String> list = ["India","China","USA"];
var string = list.join(',');
print(string); //output = "India,China,USA"

Drop Down GUI matlab [closed]

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function DoneButtonPushed(app, event)
assignin('base','roll_no_GUI1',app.StudentInfoDropDown.Value);
assignin('base','projname_GUI1',app.ProjectInfoDropDown.Value);
assignin('base','roll_no_GUI2',app.StudentInfoDropDown_2.Value);
assignin('base','projname_GUI2',app.ProjectInfoDropDown_2.Value);
assignin('base','roll_no_GUI3',app.StudentInfoDropDown_3.Value);
assignin('base','projname_GUI3',app.ProjectInfoDropDown_3.Value);
assignin('base','roll_no_GUI4',app.StudentInfoDropDown_4.Value);
assignin('base','projname_GUI4',app.ProjectInfoDropDown_4.Value);
assignin('base','roll_no_GUI5',app.StudentInfoDropDown_5.Value);
assignin('base','projname_GUI5',app.ProjectInfoDropDown_5.Value);
closereq
end
Hi, I am creating a GUI which contains DropDowns. They are 10 dropdowns as you can see from the code. And I am using assignin to save each one of them into base workspace. But I would like to club all of them into a 2 char array's or 2 cell array's and send only two variables into the base workspace viz, Roll_nos and Projnames_GUI
Create two cell arrays and assign them in the base workspace:
roll_nos = {
app.StudentInfoDropDown.Value,
app.StudentInfoDropDown_2.Value,
app.StudentInfoDropDown_3.Value,
app.StudentInfoDropDown_4.Value,
app.StudentInfoDropDown_5.Value
};
projnames_gui = {
app.ProjectInfoDropDown.Value,
app.ProjectInfoDropDown_2.Value,
app.ProjectInfoDropDown_3.Value,
app.ProjectInfoDropDown_4.Value,
app.ProjectInfoDropDown_5.Value
};
assignin('base','Roll_nos',roll_nos)
assignin('base','Projnames_GUI',projnames_gui)

How to search for a duplicate in a given string using scriptlet? [closed]

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How can I search for a duplicate in a given string using a scriptlet?
ScripletInput= a,b,c,a
Here the letter 'a' is repeating. If it is repeating more than once, then it should exit, else it can go ahead.
Please see Remove occurrences of duplicate words in a string
The code below will remove duplicates in a string.
<script type="text/javascript">
str=prompt("Enter String::","");
arr=new Array();
arr=str.split(",");
unique=new Array();
for(i=0;i<arr.length;i++)
{
if((i==arr.indexOf(arr[i]))||(arr.indexOf(arr[i])==arr.lastIndexOf(arr[i])))
unique.push(arr[i]);
}
unique.join(",");
alert(unique);
</script>

Getting weirdly formatted NSDictionary value [closed]

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var nsarray:[NSMutableDictionary] = [["object":["uid":["age":"26","gender":"male"]]]]
print(nsarray[0]["object"])
That is how it looks. I want to get the value "uid", so when it prints it is just "uid". Currently it is printing:
"uid":["age":"26","gender":"male"]
I want to get the "uid" value. Meaning when it prints it is just "uid". "uid" is a placeholder for a unique ID so I won't know what the uid is.
It looks like "object" key contains another dictionary, which has exactly one element. To get the first key, call allKeys to get keys, convert them to Array, and pick the the initial element:
let d = nsarray[0]["object"] as! NSDictionary
print(Array(d.allKeys)[0])