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I have a List(List(15,21),List(10,18))
I want to get first count of total subList //here is 2
I want to get only last subList // List(10,18)
I am new in scala.
Does anyone help which approach is good here.
you can do this:
val listOfList = List(List(15,21),List(10,18))
val size = listOfList.length // 2
val lastList = listOfList.last // List(10,18)
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I have an array and I want to convert it into String but separated each element by '","
List<String> list = ["India","China","USA"];
var string = list.join(',');
print(string); //output = "India,China,USA"
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For example I have
[
["A",1]
["B",5]
["C",3]
]
How do i sort it so that it returns in Highest to lowest value B, C, A
You can do in following way:
a.sort {
return $0.last as! Int > $1.last as! Int
}
Don't forget to add additional checks while using this code, case where the last item is not an integer or there is an array not in the expected format. Otherwise, it will lead to a crash.
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I've been away from Scala for a while, so I'm trying to get back into the idioms. I have three database calls:
db.getInventory(inventoryId: UUID): Future[Option[Inventory]]
db.getInventoryFields(inventoryId: UUID): Future[Seq[InventoryField]]
db.allInputs: Future[Seq[Input]]
If db.getInventory is Some(inventory), I want to initialize my service by giving it a
CacheContext(inventory: Inventory, fields: Seq[InventoryField], inputs: Seq[Input])
but if it's None, I want to report and error and return.
What is the best combination of for/map/flatMap/fold etc to use here?
This will return a Future[Option[CacheContext]].
for {
optInv <- db.getInventory(theUuid)
invFlds <- db.getInventoryFields(theUuid)
inputs <- db.allInputs
} yield optInv.map(CacheContext(_,invFlds,inputs))
Unpacking the Future (i.e. waiting) should be done much later in the code (if ever), at which point you can .fold() over the Option and report the error.
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Look at this:
glueContext.getSinkWithFormat(connectionType = "s3",
options = JsonOptions(
Map("path" -> outputLgSingleDir,
"partitionKeys" -> List("org_name"))),
format = "parquet", transformationContext = "")
.writeDynamicFrame(lHistory)
What possible values for JsonOptions are?
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How can I search for a duplicate in a given string using a scriptlet?
ScripletInput= a,b,c,a
Here the letter 'a' is repeating. If it is repeating more than once, then it should exit, else it can go ahead.
Please see Remove occurrences of duplicate words in a string
The code below will remove duplicates in a string.
<script type="text/javascript">
str=prompt("Enter String::","");
arr=new Array();
arr=str.split(",");
unique=new Array();
for(i=0;i<arr.length;i++)
{
if((i==arr.indexOf(arr[i]))||(arr.indexOf(arr[i])==arr.lastIndexOf(arr[i])))
unique.push(arr[i]);
}
unique.join(",");
alert(unique);
</script>